Addition-chain exponentiation/Achain.c

From Rosetta Code
Revision as of 03:31, 8 September 2011 by rosettacode>Ledrug (required include)
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<lang c>#include <stdio.h>

  1. include <stdlib.h>

/* adapted from

       http://www-cs-faculty.stanford.edu/~knuth/programs/achain4.w
   with some severe loss of efficiency
*/
  1. define ASK_KNUTH 0
  2. if ASK_KNUTH

unsigned char knuth[20001] = {0};

  1. endif
  1. define N 32
  2. define NMAX 40000

/* u: upper bounds; l: lower bounds */ int u[N] = {1, 2}, l[N] = {1, 2}, out[N], sum[N], tail[N], cache[NMAX + 1] = {0, 0, 1}, known = 2, stack;

typedef struct { int *p, v; } save_t; save_t undo[N*N];

  1. define replace(u, l, n)\

{ undo[stack].v = *(undo[stack].p = u + l); u[l] = n; stack++;}

  1. define restore(n)\

while (stack > n) { stack--;*(undo[stack].p) = undo[stack].v; }

void show(int len) { int i, n, j; printf("\033[H"); for (i = 0; i <= len; i++) { n = l[i], j = 1; printf("%s%5d %5d\033[m %2d ", out[i] ? "\033[32m" : "", l[i], u[i], i); while (j <= n) { putchar((n & j) ? '#':'_'); j <<= 1; } while (j < (1 << 16)) putchar(' '), j *= 2; n = u[i]; for (j = 1; j <= n; j *= 2) putchar((n & j) ? '#':'_');

while (j < (1 << 16)) putchar(' '), j*= 2; putchar('\n'); } }

/* lower and upper bounds */ int lower(int n, int *up) { int i, o, q; if (n <= 2 || (n <= NMAX && cache[n])) { if (up) *up = cache[n]; return cache[n]; }

for (i = -1, o = 0; n; n >>= 1, i++) if (n & 1) o++;

if (up) *up = o + --i; do { i++; } while (o >>= 1); if (!up) return i;

for (o = 2; o * o < n; o++) { if (n % o) continue; q = cache[o] + cache[n / o]; if (q < *up) if ((*up = q) == i) break; } if (n > 2) { if (*up > cache[n-2] + 1) *up = cache[n-1] + 1; if (*up > cache[n-2] + 1) *up = cache[n-2] + 1; }

return i; }

int insert(int x, int pos) { int save = stack, i, t;

if (l[pos] > x || u[pos] < x) return 0;

if (l[pos] == x) goto repl_u; replace(l, pos, x); for (i = pos - 1; u[i] * 2 < u[i+1]; i--) { if ((t = l[i+1] + 1) * 2 > u[i]) goto bail; replace(l, i, t); }

for (i = pos + 1; l[i] <= l[i-1]; i++) { if ((t = l[i-1] + 1) > u[i]) goto bail; replace(l, i, t); }

repl_u: if (u[pos] == x) return 1; replace(u, pos, x); for (i = pos - 1; u[i] >= u[i+1]; i--) { if ((t = u[i+1] - 1) < l[i]) goto bail; replace(u, i, t); }

for (i = pos + 1; u[i] > u[i-1] * 2; i++) { if ((t = u[i-1] * 2) < l[i]) goto bail; replace(u, i, t); }

return 1;

bail: restore(save); return 0; }

int seq_recur(int); int seq_len(int);

inline int try_pq(int p, int q, int len) { int ps, qs, pl, ql, pu, qu, j;

pl = cache[p]; if (pl >= len) return 0;

ql = cache[q]; if (ql >= len) return 0;

while (pl < len && u[pl] < p) pl++; for (pu = pl - 1; pu < len - 1 && u[pu + 1] >= p; pu++);

while (ql < len && u[ql] < q) ql++; for (qu = ql - 1; qu < len - 1 && u[qu + 1] >= q; qu++);

if (p != q && pl <= ql) pl = ql + 1; if (pl > pu || ql > qu || ql > pu) return 0; if (!out[len]) pl = pu = len - 1;

ps = stack;

for (; pu >= pl; pu--) { if (!insert(p, pu)) continue; out[pu]++, sum[pu] += len; if (p != q) { qs = stack; j = qu; if (j >= pu) j = pu - 1; for (; j >= ql; j--) { if (!insert(q, j)) continue; out[j]++, sum[j] += len, tail[len] = q;

if (seq_recur(len - 1)) return 1;

restore(qs); out[j]--, sum[j] -= len; } } else { out[pu]++, sum[pu] += len, tail[len] = p;

if (seq_recur(len - 1)) return 1;

out[pu]--, sum[pu] -= len; }

out[pu]--, sum[pu] -= len; restore(ps); } return 0; }

int seq_recur(int len) { int p, q, n, limit; n = l[len];

if (len < 2) return 1;

limit = out[len] == 1 ? n - tail[sum[len]] : n - 1; if (limit > u[len - 1]) limit = u[len - 1];

/* try to break n into p + q, and see if we can insert p, q into list while satisfying bounds */ for (p = limit, q = n - p; q <= p; q++, p--) if (try_pq(p, q, len)) return 1;

return 0; }

int seq(int n, int len, int *buf) { int i;

if (!len) len = seq_len(n);

stack = 0; u[len] = l[len] = n;

for (i = 0; i <= len; i++) out[i] = sum[i] = 0; for (i = 2; i < len; i++) { l[i] = l[i-1] + 1; u[i] = u[i-1] * 2; } for (i = len - 1; i > 2; i--) { if (l[i] * 2 < l[i+1]) l[i] = (1 + l[i+1]) / 2; if (u[i] >= u[i+1]) u[i] = u[i+1] - 1; }

if (!seq_recur(len)) return 0; if (buf) for (i = 0; i <= len; i++) buf[i] = u[i]; return len; }

int seq_len(int n) { int lb, ub;

if (n <= known) return cache[n];

/* need all lower n to compute sequence */ while (known + 1 < n) seq_len(known + 1);

lb = lower(n, &ub); while (lb < ub && !seq(n, lb, 0)) ++lb;

  1. if ASK_KNUTH

if (n < 20000 && lb != knuth[n] - 32) { printf("bad %d: %d %d\n", n, lb, knuth[n] - 32); fflush(stdout); abort(); }

  1. endif

known = n; if (!(n & 1023)) fprintf(stderr, "cached %d\n", known);

return cache[n] = lb; }

void init(void) {

  1. if ASK_KNUTH

FILE *fp = fopen("out", "r"); fread(knuth + 1, 1, 20000, fp); fclose(fp);

  1. endif

}</lang>