Abundant odd numbers: Difference between revisions
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if(tcnt==brk2,print("The 1000th odd abundant number is ",n," with sigma = ",sigma(n) );next);
print(n," with sigma = ",sigma(n)));}
'''Output:'''
(11:14) gp > genit(25,1000,1000000000 )
First 25 abundant odd numbers:
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