ABC problem: Difference between revisions
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True
</pre>
=={{header|ABC}}==
<syntaxhighlight lang="ABC">HOW TO REPORT word can.be.made.with blocks:
FOR letter IN upper word:
IF NO block IN blocks HAS letter in block: FAIL
REMOVE block FROM blocks
SUCCEED
PUT {"BO";"XK";"DQ";"CP";"NA";"GT";"RE";"TG";"QD";"FS"} IN blocks
PUT {"JW";"HU";"VI";"AN";"OB";"ER";"FS";"LY";"PC";"ZM"} IN blocks2
FOR block IN blocks2: INSERT block IN blocks
PUT {"A";"BARK";"BOOK";"treat";"common";"Squad";"CoNfUsE"} IN words
FOR word IN words:
WRITE word, ": "
SELECT:
word can.be.made.with blocks: WRITE "yes"/
ELSE: WRITE "no"/</syntaxhighlight>
{{out}}
<pre>A: yes
BARK: yes
BOOK: no
CoNfUsE: yes
Squad: yes
common: no
treat: yes</pre>
=={{header|Action!}}==
Line 3,697 ⟶ 3,724:
"sQuAd" can be spelled with blocks.
"Confuse" can be spelled with blocks.</pre>
=={{header|EasyLang}}==
<syntaxhighlight lang="easylang">
b$[][] = [ [ "B" "O" ] [ "X" "K" ] [ "D" "Q" ] [ "C" "P" ] [ "N" "A" ] [ "G" "T" ] [ "R" "E" ] [ "T" "G" ] [ "Q" "D" ] [ "F" "S" ] [ "J" "W" ] [ "H" "U" ] [ "V" "I" ] [ "A" "N" ] [ "O" "B" ] [ "E" "R" ] [ "F" "S" ] [ "L" "Y" ] [ "P" "C" ] [ "Z" "M" ] ]
len b[] len b$[][]
global w$[] cnt .
#
proc backtr wi . .
if wi > len w$[]
cnt += 1
return
.
for i = 1 to len b$[][]
if b[i] = 0 and (b$[i][1] = w$[wi] or b$[i][2] = w$[wi])
b[i] = 1
backtr wi + 1
b[i] = 0
.
.
.
for s$ in [ "A" "BARK" "BOOK" "TREAT" "COMMON" "SQUAD" "CONFUSE" ]
w$[] = strchars s$
cnt = 0
backtr 1
print s$ & " can be spelled in " & cnt & " ways"
.
</syntaxhighlight>
{{out}}
<pre>
A can be spelled in 2 ways
BARK can be spelled in 8 ways
BOOK can be spelled in 0 ways
TREAT can be spelled in 8 ways
COMMON can be spelled in 0 ways
SQUAD can be spelled in 8 ways
CONFUSE can be spelled in 32 ways
</pre>
=={{header|EchoLisp}}==
Line 3,777 ⟶ 3,842:
var list := ArrayList.load(blocks);
^ nil == (cast string(self)).toUpper().seekEach::(ch)
{
var index := list.indexOfElement
Line 3,806 ⟶ 3,871:
e.next();
words.forEach::(word)
{
console.printLine("can make '",word,"' : ",word.canMakeWordFrom(blocks));
Line 9,157 ⟶ 9,222:
conFUsE : true
</pre>
=={{header|Refal}}==
<syntaxhighlight lang="refal">$ENTRY Go {
= <Each Show (<Blocks>) <Words>>;
};
Each {
s.F (e.Arg) = ;
s.F (e.Arg) t.I e.R = <Mu s.F t.I e.Arg> <Each s.F (e.Arg) e.R>;
};
Show {
(e.Word) e.Blocks = <Prout e.Word ': ' <CanMakeWord (e.Word) e.Blocks>>;
};
Blocks {
= ('BO') ('XK') ('DQ') ('CP') ('NA')
('GT') ('RE') ('TG') ('QD') ('FS')
('JW') ('HU') ('VI') ('AN') ('OB')
('ER') ('FS') ('LY') ('PC') ('ZM');
};
Words {
= ('A') ('BARK') ('BOOK') ('TREAT')
('common') ('squad') ('CoNfUsE');
};
CanMakeWord {
(e.Word) e.Blocks = <CanMakeWord1 (<Upper e.Word>) e.Blocks>;
}
CanMakeWord1 {
() e.Blocks = T;
(s.Ltr e.Word) e.Blocks1 (e.X s.Ltr e.Y) e.Blocks2
= <CanMakeWord1 (e.Word) e.Blocks1 e.Blocks2>;
(e.Word) e.Blocks = F;
};</syntaxhighlight>
{{out}}
<pre>A: T
BARK: T
BOOK: F
TREAT: T
common: F
squad: T
CoNfUsE: T</pre>
=={{header|REXX}}==
Line 9,827 ⟶ 9,937:
end repeat</syntaxhighlight>
=={{header|SETL}}==
<syntaxhighlight lang="setl">program ABC_problem;
blocks := ["BO","XK","DQ","CP","NA","GT","RE","TG","QD","FS",
"JW","HU","VI","AN","OB","ER","FS","LY","PC","ZM"];
words := ["A","BARK","BOOK","treat","common","Squad","CoNfUsE"];
loop for word in words do
print(rpad(word, 8), can_make_word(word, blocks));
end loop;
proc can_make_word(word, blocks);
loop for letter in word do
if exists block = blocks(i) | to_upper(letter) in block then
blocks(i) := "";
else
return false;
end if;
end loop;
return true;
end proc;
end program;</syntaxhighlight>
{{out}}
<pre>A #T
BARK #T
BOOK #F
treat #T
common #F
Squad #T
CoNfUsE #T</pre>
=={{header|SequenceL}}==
===Recursive Search Version===
Line 10,540 ⟶ 10,680:
For x = 0 To Len (a)-1 : @b(x) = Or(Peek(a, x), Ord(" ")) : Next
' push words onto stack
Push
Do While Used() ' as long as words on the stack
Line 10,927 ⟶ 11,066:
{{trans|Go}}
{{libheader|Wren-fmt}}
<syntaxhighlight lang="
var r // recursive
Line 10,954 ⟶ 11,093:
var sp = newSpeller.call("BO XK DQ CP NA GT RE TG QD FS JW HU VI AN OB ER FS LY PC ZM")
for (word in ["A", "BARK", "BOOK", "TREAT", "COMMON", "SQUAD", "CONFUSE"]) {
}</syntaxhighlight>
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