4-rings or 4-squares puzzle: Difference between revisions
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→{{header|Koka}}
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Total unique solutions for HIGH 9, LOW 3: 4
Total solutions for HIGH 9, LOW 0: 2860
</pre>
=={{header|Koka}}==
{{trans|Rust}}
<syntaxhighlight lang="koka">
fun is_unique(a: int, b: int, c: int, d: int, e: int, f: int, g: int)
a != b && a != c && a != d && a != e && a != f && a != g &&
b != c && b != d && b != e && b != f && b != g &&
c != d && c != e && c != f && c != g &&
d != e && d != f && d != g &&
e != f && e != g &&
f != g
fun is_solution(a: int, b: int, c: int, d: int, e: int, f: int, g: int)
val bcd = b + c + d
val ab = a + b
if ab != bcd then return False
val def = d + e + f
if bcd != def then return False
val fg = f + g
return def == fg
fun four_squares(low: int, high: int, unique:bool=True)
var count := 0
for(low, high) fn(a)
for(low, high) fn(b)
for(low, high) fn(c)
for(low, high) fn(d)
for(low, high) fn(e)
for(low, high) fn(f)
for(low, high) fn(g)
if (!unique || is_unique(a, b, c, d, e, f, g)) && is_solution(a, b, c, d, e, f, g) then
count := count + 1
if unique then
println([a, b, c, d, e, f, g].show)
else
()
val uniquestr = if unique then "unique" else "non-unique"
println(count.show ++ " " ++ uniquestr ++ " solutions in " ++ low.show ++ " to " ++ high.show ++ " range\n")
fun main()
four_squares(1, 7)
four_squares(3, 9)
four_squares(0, 9, False)
</syntaxhighlight>
{{out}}
<pre>
[3,7,2,1,5,4,6]
[4,5,3,1,6,2,7]
[4,7,1,3,2,6,5]
[5,6,2,3,1,7,4]
[6,4,1,5,2,3,7]
[6,4,5,1,2,7,3]
[7,2,6,1,3,5,4]
[7,3,2,5,1,4,6]
8 unique solutions in 1 to 7 range
[7,8,3,4,5,6,9]
[8,7,3,5,4,6,9]
[9,6,4,5,3,7,8]
[9,6,5,4,3,8,7]
4 unique solutions in 3 to 9 range
2860 non-unique solutions in 0 to 9 range
</pre>
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