100 doors: Difference between revisions
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Added Transact-SQL solution |
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for(%a = 1; %a <= 100; %a++) |
for(%a = 1; %a <= 100; %a++) |
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echo("Door #" @ %a @ " is" SPC %door[%current] ? "Open" : "Closed" @ ".");</lang> |
echo("Door #" @ %a @ " is" SPC %door[%current] ? "Open" : "Closed" @ ".");</lang> |
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=={{header|Transact-SQL}}== |
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<lang sql> |
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WITH OneToTen (N) |
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AS ( SELECT N |
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FROM ( VALUES (0), (1), (2), (3), (4), (5), (6), (7), (8), (9) |
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) V(N) |
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) |
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, InitDoors (Num, IsOpen) |
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AS ( SELECT 1 |
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+ 1 * Units.N |
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+ 10 * Tens.N As Num |
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, Convert(Bit, 0) As IsOpen |
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FROM OneToTen As Units |
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CROSS JOIN OneToTen As Tens |
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) -- This part could be easier with a tally table or equivalent table-valued function |
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, States (NbStep, Num, IsOpen) |
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AS ( SELECT 0 As NbStep |
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, Num |
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, IsOpen |
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FROM InitDoors As InitState |
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UNION ALL |
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SELECT 1 + NbStep |
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, Num |
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, CASE Num % (1 + NbStep) |
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WHEN 0 THEN ~IsOpen |
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ELSE IsOpen |
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END |
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FROM States |
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WHERE NbStep < 100 |
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) |
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SELECT Num As DoorNumber |
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, Concat( 'Door number ', Num, ' is ' |
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, CASE IsOpen |
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WHEN 1 THEN ' open' |
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ELSE ' closed' |
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END ) As Result -- Concat needs SQL Server 2012 |
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FROM States |
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WHERE NbStep = 100 |
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ORDER By Num |
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; -- Fortunately, maximum recursion is 100 in SQL Server. |
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-- For more doors, the MAXRECURSION hint should be used. |
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-- More doors would also need an InitDoors with more rows. |
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</lang> |
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=={{header|True BASIC}}== |
=={{header|True BASIC}}== |
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