Talk:Detect division by zero

Many of the solutions here simply check that the result is infinite. This will fail if the numerator is 0 too, since 0 / 0 is mathematically incalculable (many languages return NaN here).

A correct pseudocode solution is:

result = numerator / denominator
if numerator equals 0
   if result is not a number
      divide by zero action
   end
else 
   if result is infinite
      divide by zero action
   end
end

0 / 0 is NOT mathematically incalculable -- it is trivially calculable. The problem with 0 / 0 is that any numerical answer is a valid answer. In other words NaN is not a valid result for 0 / 0 but is a description of the character of those answers. (The result can be any of an infinite variety of numbers and not just "a" single number.) This is a problem in mathematics because the result, by itself, is not sufficient to prove anything. Thus, we at times use limits and other constructs to reason about cases involving 0 / 0. A less deceptive result than NaN for 0 / 0 would be "Any Number", but to my knowledge no languages implement that. --Rdm 18:19, 18 June 2010 (UTC)

Maybe it's correct as multiple numbers are Not a Number :-)
(Being pedantic seems to be catching). --Paddy3118 18:37, 18 June 2010 (UTC)

"In other words NaN is not a valid result for 0 / 0 but is a description of the character of those answers." --Rdm 19:17, 18 June 2010 (UTC)