Sum multiples of 3 and 5: Difference between revisions

→‎{{header|Uiua}}: Alternative solution.
(Added UIUA)
(→‎{{header|Uiua}}: Alternative solution.)
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=={{header|UIUAUiua}}==
<syntaxhighlight>
End ← 1000
Line 4,898:
IndicesFive ← MultOffive ↘1⇡End
 
/+ ⊏⊂◴⊏⊂ Indicesthree IndicesFive ↘1⇡End # join, select and sum
</syntaxhighlight>
{{out}}
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</pre>
 
Alternatively, leaving the 0th element in place means index of n == n, so a simpler solution would be:
<syntaxhighlight>
End ← 1000
MultOf ← ⊚=0◿
/+◴⊂⊃(MultOf3)(MultOf5)⇡End
</syntaxhighlight>
 
=={{header|UNIX Shell}}==
107

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