Runtime evaluation/In an environment: Difference between revisions
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my $first = eval $code; |
my $first = eval $code; |
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local $x = shift; |
local $x = shift; |
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return |
return eval($code) - $first;} |
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print eval_with_x('3 * $x', 5, 10), "\n"; # Prints "15\n".</lang> |
print eval_with_x('3 * $x', 5, 10), "\n"; # Prints "15\n".</lang> |
Revision as of 21:56, 17 February 2009
You are encouraged to solve this task according to the task description, using any language you may know.
Given a program in the language representing a function, evaluate it with the variable x (or another name if that is not valid) bound to a provided value, then evaluate it again with x bound to another provided value, then subtract the result of the first from the second and return or print it.
Preferably, do so in a way which does not involve string manipulation of source code, and is plausibly extensible to a runtime-chosen set of bindings.
For more general examples and language-specific details, see Eval.
Common Lisp
<lang lisp> (defun eval-with-x (program a b)
(let ((at-a (eval `(let ((x ',a)) ,program))) (at-b (eval `(let ((x ',b)) ,program)))) (- at-b at-a)))
</lang>
<lang lisp> (eval-with-x '(exp x) 0 1) => 1.7182817 </lang>
This version ensures that the program is compiled, once, for more efficient execution:
<lang lisp> (defun eval-with-x (program a b)
(let* ((f (compile nil `(lambda (x) ,program))) (at-a (funcall f a)) (at-b (funcall f b))) (- at-b at-a)))
</lang>
Perl
<lang perl>our $x;
# Only necessary if "use strict" is in effect or a # lexical $x (declared with "my") exists in this scope.
sub eval_with_x
{my $code = shift; local $x = shift; my $first = eval $code; local $x = shift; return eval($code) - $first;}
print eval_with_x('3 * $x', 5, 10), "\n"; # Prints "15\n".</lang>
Note that this is a dynamic, not lexical, binding of $x
.
Python
<lang python>code = raw_input('f(x): ') x = [input('x[%i]: ' % i) for i in [0,1]] fx = [eval(code, {"x": xv}) for xv in x] print "f({x[0]}) = {f0}; f({x[1]}) = {f1}; f({x[1]}) - f({x[0]}) = {ans}".format(
x=x, f0=fx[0], f1=fx[1], ans= fx[1] - fx[0] )</lang>
Typical use would be (user input is after the initial colon in a line): <lang python>f(x): lambda x: 2**x x[0]: 3 x[1]: 5 f(3) = 8; f(5) = 32; f(5) - f(3) = 24</lang>