Loops/Continue

Loops/Continue
You are encouraged to solve this task according to the task description, using any language you may know.

Show the following output using one loop.

1, 2, 3, 4, 5
6, 7, 8, 9, 10

Ada

Ada has no continue reserved word, nor does it need one. The continue reserved word is only syntactic sugar for operations that can be achieved without it as in the following example.

<lang ada> with Ada.Text_Io; use Ada.Text_Io;

procedure Loop_Continue is begin

  for I in 1..10 loop
     Put(Integer'Image(I));
     if I mod 5 = 0 then
        New_Line;
     else
        Put(",");
     end if;
  end loop;

end Loop_Continue; </lang>

ALGOL 68

ALGOL 68 has no continue reserved word, nor does it need one. The continue reserved word is only syntactic sugar for operations that can be achieved without it as in the following example:

FOR i FROM 1 TO 10 DO
  print ((i, 
    IF i MOD 5 = 0 THEN
      new line
    ELSE
      ","
    FI
  ))
OD

Output:

         +1,         +2,         +3,         +4,         +5
         +6,         +7,         +8,         +9,        +10

C

Translation of: C++

<lang c>for(int i = 1;i <= 10; i++){

  printf("%d", i);
  if(i % 5 == 0){
     printf("\n");
     continue;
  }
  printf(", ");

}</lang>

C++

Translation of: Java

<lang cpp>for(int i = 1;i <= 10; i++){

  cout << i;
  if(i % 5 == 0){
     cout << endl;
     continue;
  }
  cout << ", ";

}</lang>

ColdFusion

Remove the leading space from the line break tag.

<cfscript>
  for( i = 1; i <= 10; i++ )
  {
    writeOutput( i );
    if( 0 == i % 5 )
    {
      writeOutput( "< br />" );
      continue;
    }
    writeOutput( "," );
  }
</cfscript>

D

<lang d>for(int i = 1;i <= 10; i++){

 writef(i);
 if(i % 5 == 0){
   writefln();
   continue;
 }
 writef(", ");

}</lang>

Fortran

Works with: Fortran version 90 and later

DO i = 1, 10
  IF (MOD(i, 5) == 0) THEN
    WRITE(*, "(I0)") i
  ELSE
    WRITE(*, "(I0,A)", ADVANCE="NO") i, ", "
  ENDIF
END DO

J

J is array-oriented, so there is very little need for loops. For example, one could satisfy this task this way:

_2}."1'lq<, >'8!:2>:i.2 5

J does support loops for those times they can't be avoided (just like many languages support gotos for those time they can't be avoided).

   3 : 0 ] 10 
        z=.''
        for_i. 1 + i.y do.
            z =. z , ": i

             if. 0 = 5 | i do.
                  z 1!:2 ]2 
                  z =. ''
                  continue. 
             end. 

             z =. z , ', '
        end.
     i.0 0
   )

Though it's rare to see J code like this.

Java

<lang java>for(int i = 1;i <= 10; i++){

  System.out.print(i);
  if(i % 5 == 0){
     System.out.println();
     continue;
  }
  System.out.print(", ");

}</lang>

MAXScript

for i in 1 to 10 do
(
    format "%" i
    if mod i 5 == 0 then
    (
        format "\n"
        continue
    )   continue
    format ", "
)

Modula-3

Modula-3 defines the keyword RETURN as an exception, but when it is used with no arguments it works just like continue in C.

Note, however, that RETURN only works inside a procedure or a function procedure; use EXIT otherwise.

Module code and imports are omitted.

FOR i := 1 TO 10 DO
  IO.PutInt(i);
  IF i MOD 5 = 0 THEN
    IO.Put("\n");
    RETURN;
  END;
  IO.Put(", ");
END;

Perl

<lang perl>foreach (1..10) {

   print $_;
   if ($_ % 5 == 0) {
       print "\n";
       next;
   }
   print ', ';

}</lang>

PHP

<lang php>for ($i = 1; $i <= 10; $i++) {

   echo $i;
   if ($i % 5 == 0) {
       echo "\n";
       continue;
   }
   echo ', ';

}</lang>

Pop11

lvars i;
for i from 1 to 10 do
   printf(i, '%p');
   if i rem 5 = 0 then
       printf('\n');
       nextloop;
   endif;
   printf(', ')
endfor;

Python

<lang python>for i in xrange(1,11):

   if i % 5 == 0:
       print i
       continue
   print i, ",",</lang>

Ruby

<lang ruby>for i in 1..10 do

  print i
  if i % 5 == 0 then
     puts
     next
  end
  print ', '

end</lang>

UnixPipes

yes \ | cat -n | head -n 10 | xargs -n 5 echo | tr ' ' ,

Visual Basic .NET

       For i = 1 To 10
           Console.Write(i)
           If i Mod 5 = 0 Then
               Console.WriteLine()
           Else
               Console.Write(", ")
           End If
       Next