Find words which contains more than 3 e vowels

From Rosetta Code
Revision as of 06:52, 9 February 2021 by rosettacode>Gerard Schildberger (→‎{{header|REXX}}: added the computer programming language REXX.)
Find words which contains more than 3 e vowels is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
Task

Use the dictionary   unixdict.txt

Find words which contains more than three   e   vowels and contains only   e   vowels.

REXX

This REXX version doesn't care what order the words in the dictionary are in,   nor does it care what
case  (lower/upper/mixed)  the words are in,   the search for the words and vowels is   caseless.

It also allows the minimum number of vowels to be specified on the command line (CL) as well as the dictionary file identifier. <lang rexx>/*REXX pgm finds words (within an identified dict.) which contain more than three "e"s.*/ parse arg char many iFID . /*obtain optional arguments from the CL*/ if char== | char=="," then char= 'e' /*Not specified? Then use the default.*/ if many== | many=="," then many= 4 /* " " " " " " */ if iFID== | iFID=="," then iFID='unixdict.txt' /* " " " " " " */ chrU= char; upper chrU /*obtain an uppercase version of char.*/

          do #=1  while lines(iFID)\==0         /*read each word in the file  (word=X).*/
          x= strip( linein( iFID) )             /*pick off a word from the input line. */
          @.#= x                                /*save:  the original case of the word.*/
          end   /*#*/                           /* [↑]   semaphore name is uppercased. */
  1. = # - 1 /*adjust word count because of DO loop.*/

say copies('─', 30) # "words in the dictionary file: " iFID finds= 0 /*count of the "eeee" words found. */

    do j=1  for #;      $= @.j                  /*process all the words that were found*/
    upper $                                     /*uppercase it for caseless finds.     */
    if pos(chrU, $)==0  then iterate            /*At least 1 vowel found? No, then skip*/
    if countstr(chrU, $) < many  then iterate   /*Have enough vowels?      "    "    " */
    finds= finds + 1                            /*bump the count of "ABC" words found. */
    say right(left(@.j, 30), 40)                /*indent original word for readability.*/
    end        /*j*/
                                                /*stick a fork in it,  we're all done. */

say copies('─', 30) finds ' "e" words found using the characters: ' many "'e'"</lang>

output   when using the default inputs:
────────────────────────────── 25104 words in the dictionary file:  unixdict.txt
          accelerometer
          belvedere
          betelgeuse
          centerpiece
          cheerleader
          cheesecake
          decelerate
          degenerate
          dereference
          desegregate
          electroencephalogram
          electroencephalograph
          electroencephalography
          elsewhere
          entrepreneur
          entrepreneurial
          ephemerides
          erlenmeyer
          evergreen
          everywhere
          exegete
          experience
          eyepiece
          freewheel
          genevieve
          heterogeneity
          heterogeneous
          inexperience
          interference
          interferometer
          interviewee
          irredeemable
          leeuwenhoek
          minesweeper
          nevertheless
          perseverance
          persevere
          preference
          referee
          refereeing
          reprehensible
          representative
          reverberate
          seventeen
          seventeenth
          speedometer
          squeegee
          steeplechase
          teleconference
          telemeter
          teletypesetting
          teletypewrite
          tennessee
          weatherbeaten
          wheresoever
────────────────────────────── 55  "e" words found using the characters:  4 'e'

Ring

<lang ring> load "stdlib.ring"

cStr = read("unixdict.txt") wordList = str2list(cStr) char = list(9) nextwords = [] nr = 0 num = 0

see "working..." + nl

ln = len(wordList) for n = ln to 1 step -1

   if len(wordList[n]) < 6
      del(wordList,n)
   ok

next

see "Words are:" + nl

for n = 1 to len(wordList)

   num = 0
   flag = 1
   for m = 1 to len(wordList[n])
       if isvowel(wordList[n][m])
          if wordList[n][m] != "e"
             flag = 0
             exit
          else
             num = num + 1
          ok
       ok
   next
   if flag = 1 and num > 3
      nr = nr + 1
      see "" + nr + ". " + wordList[n] + nl
   ok

next

see "done..." + nl </lang> Output:

working...
Words are:
1. belvedere
2. dereference
3. elsewhere
4. erlenmeyer
5. evergreen
6. everywhere
7. exegete
8. freewheel
9. nevertheless
10. persevere
11. preference
12. referee
13. seventeen
14. seventeenth
15. telemeter
16. tennessee
done...