Find common directory path

From Rosetta Code
Task
Find common directory path
You are encouraged to solve this task according to the task description, using any language you may know.

Create a routine that, given a set of strings representing directory paths and a single character directory separator, will return a string representing that part of the directory tree that is common to all the directories.

Test your routine using the forward slash '/' character as the directory separator and the following three strings as input paths:

 '/home/user1/tmp/coverage/test'
 '/home/user1/tmp/covert/operator'
 '/home/user1/tmp/coven/members'

Note: The resultant path should be the valid directory '/home/user1/tmp' and not the longest common string '/home/user1/tmp/cove'.
If your language has a routine that performs this function (even if it does not have a changeable separator character, then mention it as part of the task)

Clojure

<lang clojure>(defn common-prefix [sep paths]

 (let [parts-per-path (map #(.split (re-pattern sep) %) paths)
       common-parts (for [part-list (apply map vector parts-per-path)
                          :when (apply = part-list)] (first part-list))]
       (apply str (interpose sep common-parts))))

(println

(common-prefix "/"
               ["/home/user1/tmp/coverage/test"
                "/home/user1/tmp/covert/operator"
                "/home/user1/tmp/coven/members"]))</lang>

Factor

<lang factor>: common-head ( seq1 seq2 -- head )

   dupd mismatch head ;
common-prefix ( file1 file2 -- prefix )
   common-head parent-directory ;</lang>
( scratchpad ) "/home/user1/tmp/coverage/test" "/home/user1/tmp/covert/operator" common-prefix .
"/home/user1/tmp/"

J

Solution: <lang j>parseDirs =: = <;.2 ] getCommonPrefix =: ([: *./\ *./@({. ="1 }.)) ;@# {.

getCommonDirPath=: [: getCommonPrefix parseDirs&></lang>

Example: <lang j> paths=: '/home/user1/tmp/coverage/test';'/home/user1/tmp/covert/operator';'/home/user1/tmp/coven/members'

  getCommonPrefix >paths

/home/user1/tmp/cove

  '/' getCommonDirPath paths

/home/user1/tmp/</lang>

Note: This alternative formulation of parseDirs provides cross-platform support, without the need to specify the path separator. <lang j>parseDirs =: (PATHSEP_j_&= <;.2 ])@jhostpath</lang>

OCaml

<lang ocaml>let rec aux acc paths =

 let heads = List.map List.hd paths in
 let item = List.hd heads in
 let all_the_same =
   List.for_all ((=) item) (List.tl heads)
 in
 if all_the_same
 then aux (item::acc) (List.map List.tl paths)
 else (List.rev acc)

let common_prefix sep = function

 | [] -> invalid_arg "common_prefix"
 | dirs ->
     let paths = List.map (Str.split (Str.regexp_string sep)) dirs in
     let res = aux [] paths in
     (sep ^ (String.concat sep res))

let () =

 let dirs = [
   "/home/user1/tmp/coverage/test";
   "/home/user1/tmp/covert/operator";
   "/home/user1/tmp/coven/members";
 ] in
 print_endline (common_prefix "/" dirs);
</lang>

(uses the module Str, str.cma)

Oz

With a few helper functions, we can express the solution like this in Oz: <lang oz>declare

 fun {CommonPrefix Sep Paths}
    fun {GetParts P} {String.tokens P Sep} end
    Parts = {ZipN {Map Paths GetParts}}
    EqualParts = {List.takeWhile Parts fun {$ X|Xr} {All Xr {Equals X}} end}
 in
    {Join Sep {Map EqualParts Head}}
 end
 fun {ZipN Xs}
    if {Some Xs {Equals nil}} then nil
    else
       {Map Xs Head} | {ZipN {Map Xs Tail}}
    end
 end
 fun {Join Sep Xs}
    {FoldR Xs fun {$ X Z} {Append X Sep|Z} end nil}
 end
 fun {Equals C}
    fun {$ X} X == C end
 end
 fun {Head X|_} X end
 fun {Tail _|Xr} Xr end

in

 {System.showInfo {CommonPrefix &/
                   ["/home/user1/tmp/coverage/test"
                    "/home/user1/tmp/covert/operator"
                    "/home/user1/tmp/coven/members"]}}</lang>

PureBasic

PureBasic don't have a path comparator directly but instead have powerful string tools.

Simply by checking the catalog names until they mismatch and add up the correct parts, the task is accomplished. <lang PureBasic>Procedure.s CommonPath(Array InPaths.s(1),separator.s="/")

 Protected SOut$=""
 Protected i, j, toggle
 
 If ArraySize(InPaths())=0
   ProcedureReturn InPaths(0)  ; Special case, only one path
 EndIf
 
 Repeat
   i+1
   toggle=#False
   For j=1 To ArraySize(InPaths())
     If (StringField(InPaths(j-1),i,separator)=StringField(InPaths(j),i,separator))
       If Not toggle
         SOut$+StringField(InPaths(j-1),i,separator)+separator
         toggle=#True
       EndIf
     Else
       ProcedureReturn SOut$
     EndIf      
   Next
 ForEver

EndProcedure</lang>

Example of implementation <lang PureBasic>Dim t.s(2) t(0)="/home/user1/tmp/coverage/test" t(1)="/home/user1/tmp/covert/operator" t(2)="/home/user1/tmp/coven/members"

Debug CommonPath(t(),"/"))</lang>

Python

The Python os.path.commonprefix function is broken as it returns common characters that may not form a valid directory path: <lang python>>>> import os >>> os.path.commonprefix(['/home/user1/tmp/coverage/test', '/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members']) '/home/user1/tmp/cove'</lang>

This result can be fixed: <lang python>>>> def commonprefix(*args, sep='/'): return os.path.commonprefix(*args).rpartition(sep)[0]

>>> commonprefix(['/home/user1/tmp/coverage/test', '/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members']) '/home/user1/tmp'</lang>

But it may be better to not rely on the faulty implementation at all: <lang python>>>> from itertools import takewhile >>> def allnamesequal(name): return all(n==name[0] for n in name[1:])

>>> def commonprefix(paths, sep='/'): bydirectorylevels = zip(*[p.split(sep) for p in paths]) return sep.join(x[0] for x in takewhile(allnamesequal, bydirectorylevels))

>>> commonprefix(['/home/user1/tmp/coverage/test', '/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members']) '/home/user1/tmp'</lang>

Tcl

<lang tcl>package require Tcl 8.5 proc pop {varname} {

   upvar 1 $varname var
   set var [lassign $var head]
   return $head

}

proc common_prefix {dirs {separator "/"}} {

   set parts [split [pop dirs] $separator]
   while {[llength $dirs]} {
       set r {}
       foreach cmp $parts elt [split [pop dirs] $separator] {
           if {$cmp ne $elt} break
           lappend r $cmp
       }
       set parts $r
   }
   return [join $parts $separator]

}</lang>

% common_prefix {/home/user1/tmp/coverage/test /home/user1/tmp/covert/operator /home/user1/tmp/coven/members}
/home/user1/tmp