Execute a Markov algorithm
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You are encouraged to solve this task according to the task description, using any language you may know.
Create an interpreter for a Markov Algorithm. Rules have the syntax:
<comment> ::= # {<any character>} <rule> ::= <pattern> <whitespace> -> <whitespace> [.] <replacement> <whitespace> ::= (<tab> | <space>) [<whitespace>]
There is one rule per line. If there is a . present before the <replacement>, then this is a terminating rule in which case the interpreter must halt execution.
There are two tests you can make:
# This rules file is extracted from Wikipedia: # http://en.wikipedia.org/wiki/Markov_Algorithm A -> apple B -> bag S -> shop T -> the the shop -> my brother a never used -> .terminating rule
If you input "I bought a B of As from T S." this code should output "I bought a bag of apples from my brother."
If you use these set of rules:
# Slightly modified from the rules on Wikipedia A -> apple B -> bag S -> .shop T -> the the shop -> my brother a never used -> .terminating rule
If you input "I bought a B of As from T S." this code should output "I bought a bag of apples from T shop." This one tests that terminating rules work.
J
Solution:<lang j>require'strings regex'
NB. Lex a Markov program markovLexer =: verb define rules =. LF cut TAB&=`(,:&' ')}y rules =. a: -.~ (dltb@:{.~ i:&'#')&.> rules 0 _1 {"1 '\s+->\s+' (rxmatch rxcut ])S:0 rules )
NB. Given ruleset and target string, output NB. result. markov =: markovLexer@[ stringreplace^:_ ]
NB. Same as above, but output all intermediate NB. evaluations markovDebug =: markovLexer@[ stringreplace^:a: ]</lang>
Example:<lang j> m1 =. noun define # This rules file is extracted from Wikipedia: # http://en.wikipedia.org/wiki/Markov_Algorithm A -> apple B -> bag S -> shop T -> the the shop -> my brother a never used -> .terminating rule )
m1 markov 'I bought a B of As from T S.'
I bought a bag of apples from my brother.
m1 markovDebug 'I bought a B of As from T S.'
I bought a B of As from T S. I bought a bag of apples from the shop. I bought a bag of apples from my brother.</lang> Discussion: This solution implemented in 20 seconds and doesn't fully implement a Markov algorithm. More details on the talk page.
Ruby
<lang Ruby>raise "Please input an input code file, an input data file, and an output file." if ARGV.size < 3
rules = File.readlines(ARGV[0]).inject([]) do |rules, line|
if line =~ /^\s*#/ rules elsif line =~ /^(.+)\s+->\s+(\.?)(.*)$/ rules << [$1, $3, $2 != ""] else raise "Syntax error: #{line}" end
end
File.open(ARGV[2], "w") do |file|
file.write(File.read(ARGV[1]).tap { |input_data| while (matched = rules.find { |match, replace, term| input_data[match] and input_data.sub!(match, replace) }) and !matched[2] end })
end</lang>
Tcl
<lang tcl>package require Tcl 8.5 if {$argc < 3} {error "usage: $argv0 ruleFile inputFile outputFile"} lassign $argv ruleFile inputFile outputFile
- Read the file of rules
set rules {} set f [open $ruleFile] foreach line [split [read $f] \n[close $f]] {
if {[string match "#*" $line] || $line eq ""} continue if {[regexp {^(.+)\s+->\s+(\.?)(.*)$} $line -> from final to]} {
lappend rules $from $to [string equal "." $to] [string length $from]
} else {
error "Syntax error: \"$line\""
}
}
- Apply the rules
set f [open $inputFile] set out [open $outputFile w] foreach line [split [read $f] \n[close $f]] {
set any 1 while {$any} {
set any 0 foreach {from to stop fl} $rules { # If we match the 'from' pattern... if {[set idx [string first $from $line]] < 0} { continue }
# Change for the 'to' replacement set line [string replace $line $idx [expr {$idx+$fl-1}] $to]
# Stop if we terminate, otherwise note that we've more work to do if {$stop} { set any 0 break } else { set any 1 } }
}
# Output the processed line puts $out $line
} close $out</lang>