Count in octal
Arturo
<lang rebol>loop 1..40 'i -> print ["number in base 10:" pad to :string i 2 "number in octal:" pad as.octal i 2] </lang>
- Output:
number in base 10: 1 number in octal: 1 number in base 10: 2 number in octal: 2 number in base 10: 3 number in octal: 3 number in base 10: 4 number in octal: 4 number in base 10: 5 number in octal: 5 number in base 10: 6 number in octal: 6 number in base 10: 7 number in octal: 7 number in base 10: 8 number in octal: 10 number in base 10: 9 number in octal: 11 number in base 10: 10 number in octal: 12 number in base 10: 11 number in octal: 13 number in base 10: 12 number in octal: 14 number in base 10: 13 number in octal: 15 number in base 10: 14 number in octal: 16 number in base 10: 15 number in octal: 17 number in base 10: 16 number in octal: 20 number in base 10: 17 number in octal: 21 number in base 10: 18 number in octal: 22 number in base 10: 19 number in octal: 23 number in base 10: 20 number in octal: 24 number in base 10: 21 number in octal: 25 number in base 10: 22 number in octal: 26 number in base 10: 23 number in octal: 27 number in base 10: 24 number in octal: 30 number in base 10: 25 number in octal: 31 number in base 10: 26 number in octal: 32 number in base 10: 27 number in octal: 33 number in base 10: 28 number in octal: 34 number in base 10: 29 number in octal: 35 number in base 10: 30 number in octal: 36 number in base 10: 31 number in octal: 37 number in base 10: 32 number in octal: 40 number in base 10: 33 number in octal: 41 number in base 10: 34 number in octal: 42 number in base 10: 35 number in octal: 43 number in base 10: 36 number in octal: 44 number in base 10: 37 number in octal: 45 number in base 10: 38 number in octal: 46 number in base 10: 39 number in octal: 47 number in base 10: 40 number in octal: 50