Loops/Continue
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Show the following output using one loop.
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Try to achieve the result by forcing the next iteration within the loop
upon a specific condition, if your language allows it.
- Related tasks
- Loop over multiple arrays simultaneously
- Loops/Break
- Loops/Continue
- Loops/Do-while
- Loops/Downward for
- Loops/For
- Loops/For with a specified step
- Loops/Foreach
- Loops/Increment loop index within loop body
- Loops/Infinite
- Loops/N plus one half
- Loops/Nested
- Loops/While
- Loops/with multiple ranges
- Loops/Wrong ranges
11l
L(i) 1..10
I i % 5 == 0
print(i)
L.continue
print(i, end' ‘, ’)- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
360 Assembly
* Loops/Continue 12/08/2015
LOOPCONT CSECT
USING LOOPCONT,R12
LR R12,R15
BEGIN LA R8,0
SR R5,R5
LA R6,1
LA R7,10
LOOPI BXH R5,R6,ELOOPI for i=1 to 10
LA R3,MVC(R8)
XDECO R5,XDEC
MVC 0(4,R3),XDEC+8
LA R8,4(R8)
LR R10,R5
LA R1,5
SRDA R10,32
DR R10,R1
LTR R10,R10
BNZ COMMA
XPRNT MVC,80
LA R8,0
B NEXTI
COMMA LA R3,MVC(R8)
MVC 0(2,R3),=C', '
LA R8,2(R8)
NEXTI B LOOPI next i
ELOOPI XR R15,R15
BR R14
MVC DC CL80' '
XDEC DS CL16
YREGS
END LOOPCONT- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Ada
Ada doesn't have a continue statement, so we have to use a goto statement. The previous submitter said continue is not needed. In this example it is indeed not needed, but that is not always the case. An example is a loop where a number of interdependent conditions are checked before executing the main body of the loop. Without a continue statement (or goto), one ends up with nested statements with the main body to the far right of the page.
B.N. You should always try to avoid using a goto, but if you really must, it's there in Ada.
P.S. it is often simplest to place the label on top of the loop, as in real life the need occurs when reading input, so there is no range condition in the loop and we can forgo the null statement.
with Ada.Text_IO;
use Ada.Text_IO;
procedure Loop_Continue is
begin
for I in 1..10 loop
Put (Integer'Image(I));
if I = 5 or I = 10 then
New_Line;
goto Continue;
end if;
Put (",");
<<Continue>> --Ada 2012 no longer requires a statement after the label
end loop;
end Loop_Continue;
N. This is a more true-to-Ada strategy for 'continue' comprising of an outer iteration loop and an inner labeled single-pass loop. This is a safer strategy than using goto which could be problematic when dealing with complex nested loops.
with Ada.Text_IO;
use Ada.Text_IO;
procedure Loop_Continue is
begin
Print_All:
for I in 1 .. 10 loop
Print_Element: loop
Put (Integer'Image(I));
if I = 5 or I = 10 then
New_Line;
exit Print_Element;
end if;
Put (",");
exit Print_Element;
end loop Print_Element;
end loop Print_All;
end Loop_Continue;
Agena
Agena doesn't have a continue statement, conditional statements can be used instead.
for i to 10 do
write( i );
if i % 5 = 0
then write( "\n" )
else write( ", " )
fi
odAikido
foreach i 1..10 {
print (i)
if ((i % 5) == 0) {
println()
continue
}
print (", ")
}ALGOL 60
begin
integer i;
for i:=1 step 1 until 10 do begin
outinteger(i);
if i=(i div 5)*5 then
outimage
else
outstring(", ")
end
end
- Output:
+1 , +2 , +3 , +4 , +5
+6 , +7 , +8 , +9 , +10
ALGOL 68
ALGOL 68 has no continue reserved word, nor does it need one. The continue reserved word is only syntactic sugar for operations that can be achieved without it as in the following example:
FOR i FROM 1 TO 10 DO
print ((i,
IF i MOD 5 = 0 THEN
new line
ELSE
","
FI
))
OD- Output:
+1, +2, +3, +4, +5
+6, +7, +8, +9, +10
ALGOL W
Algol W doesn't have a continue statement - conditional statements can be used instead.
begin
i_w := 1; s_w := 0; % set output format %
for i := 1 until 10 do begin
writeon( i );
if i rem 5 = 0
then write()
else writeon( ", " )
end for_i
end.AppleScript
set table to {return}
repeat with i from 1 to 10
if i < 5 or (i ≥ 6 and i < 10) then
set end of table to i & ", "
else if i = 5 or i = 10 then
set end of table to i & return
end if
end repeat
return table as string
- Output:
" 1, 2, 3, 4, 5 6, 7, 8, 9, 10 "
Arturo
loop 1..10 'i [
prints i
if 0 = i%5 [
print ""
continue
]
prints ", "
]
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Asymptote
Asymptote's control structures are similar to those in C/C++
for(int i = 1; i <= 10; ++i) {
write(i, suffix=none);
if(i % 5 == 0) {
write("");
continue;
} else {
write(", ", suffix=none);
}
}
AutoHotkey
Loop, 10 {
Delimiter := (A_Index = 5) || (A_Index = 10) ? "`n":", "
Index .= A_Index . Delimiter
}
MsgBox %Index%
AWK
BEGIN {
for(i=1; i <= 10; i++) {
printf("%d", i)
if ( i % 5 == 0 ) {
print
continue
}
printf(", ")
}
}
BASIC
Applesoft BASIC
10 FOR I = 1 TO 10
20 PRINT I;
30 IF I - INT (I / 5) * 5 = 0 THEN PRINT : GOTO 50"CONTINUE
40 PRINT ", ";
50 NEXTBASIC256
for i = 1 to 10
print string(i);
if i mod 5 = 0 then
print
continue for
end if
print ", ";
next
print
endBBC BASIC
BBC BASIC doesn't have a 'continue' statement so the remainder of the loop must be made conditional.
FOR i% = 1 TO 10
PRINT ; i% ;
IF i% MOD 5 = 0 PRINT ELSE PRINT ", ";
NEXT
Commodore BASIC
Commodore BASIC also doesn't have a 'continue' statement. In this example, a GOTO statement is used to simulate 'CONTINUE'. However, Commodore BASIC doesn't have a modulo (remainder) operator, so value of I/5 is check against INT(I/5). If they are the same, the remainder is zero.
10 FOR I = 1 to 10
20 PRINT I;
30 IF INT(I/5) = I/5 THEN PRINT : GOTO 50
40 PRINT ", ";
50 NEXT
FreeBASIC
' FB 1.05.0 Win64
For i As Integer = 1 To 10
Print Str(i);
If i Mod 5 = 0 Then
Print
Continue For
End If
Print ", ";
Next
Print
Sleep
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
IS-BASIC
100 FOR I=1 TO 10
110 PRINT STR$(I);
120 IF MOD(I,5)=0 THEN
130 PRINT
140 ELSE
150 PRINT ", ";
160 END IF
170 NEXTLiberty BASIC
for i =1 to 10
if i mod 5 <>0 then print i; ", "; else print i
next i
endOxygenBasic
uses console
int i
for i = 1 to 10
print str(i);
if i mod 5 = 0 then
printl
continue for
end if
print ", ";
next
printl cr "Enter ..."
waitkey
PureBasic
OpenConsole()
For i.i = 1 To 10
Print(Str(i))
If i % 5 = 0
PrintN("")
Continue
EndIf
Print(",")
Next
Repeat: Until Inkey() <> ""
QBasic
FOR i = 1 TO 10
PRINT STR$(i);
IF (i MOD 5) THEN PRINT ", "; ELSE PRINT
NEXT i
PRINT
END
QB64
Dim i As Integer
For i = 1 To 10
Print LTrim$(Str$(i));
If i Mod 5 = 0 Then
Print
_Continue
End If
Print ", ";
NextRun BASIC
for i = 1 to 10
if i mod 5 <> 0 then print i;", "; else print i
next iSinclair ZX81 BASIC
This probably isn't the most idiomatic way to produce the specified output—but it does illustrate ZX81 BASIC's equivalent of if <condition> continue, which is IF <condition> THEN NEXT <loop-control variable>.
10 FOR I=1 TO 10
20 PRINT I;
30 IF I/5=INT (I/5) THEN PRINT
40 IF I/5=INT (I/5) THEN NEXT I
50 PRINT ", ";
60 NEXT I
TI-89 BASIC
count()
Prgm
""→s
For i,1,10
s&string(i)→s
If mod(i,5)=0 Then
Disp s
""→s
Cycle
EndIf
s&", "→s
EndFor
EndPrgmTi-89 lacks support for multi-argument display command or controlling the print position so that one can print several data on the same line. The display command (Disp) only accepts one argument and prints it on a single line (causing a line a feed at the end, so that the next Disp command will print in the next line). The solution is appending data to a string (s), using the concatenator operator (&), by converting numbers to strings, and then printing the string at the end of the line.
True BASIC
FOR i = 1 TO 10
PRINT STR$(i);
IF REMAINDER(i, 5) = 0 THEN
PRINT
ELSE !No existe el comando CONTINUE
PRINT ", ";
END IF
NEXT i
PRINT
END
VB-DOS, PDS
OPTION EXPLICIT
DIM i AS INTEGER
CLS
FOR i = 1 TO 10
PRINT STR$(i);
IF (i MOD 5) THEN PRINT ","; ELSE PRINT
NEXT i
END
Visual Basic .NET
For i = 1 To 10
Console.Write(i)
If i Mod 5 = 0 Then
Console.WriteLine()
Else
Console.Write(", ")
End If
Next
bc
Requires a bc with the print and continue statements. POSIX bc has not these statements.
for (i = 1; i <= 10; i++) {
print i
if (i % 5) {
print ", "
continue
}
print "\n"
}
quit
BCPL
In BCPL, the continue statement is named loop.
get "libhdr"
let start() be
for i = 1 to 10
$( writen(i)
if i rem 5 = 0
$( wrch('*N')
loop
$)
writes(", ")
$)- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Befunge
Befunge outputs numbers with a space after them, so the formatting is slightly off in this version.
1>:56+\`#v_@
+v %5:.:<
1>#v_55+,v
^ <
>" ,",,v
^ <
This version outputs a 'backspace' ASCII character to try to correct the format, but it may or may not work depending on if the character is accounted for by the output
1>:56+\`#v_@
+v5:,8.:<
1>%#v_55+,v
^ <
>" ,",v
^ ,<
Bracmat
Bracmat has no continue statement.
( 0:?i
& whl
' ( 1+!i:~>10:?i
& put
$ ( str
$ ( !i
(mod$(!i.5):0&\n|", ")
)
)
)
);C
for(int i = 1;i <= 10; i++){
printf("%d", i);
if(i % 5 == 0){
printf("\n");
continue;
}
printf(", ");
}
C#
using System;
class Program {
static void Main(string[] args) {
for (int i = 1; i <= 10; i++) {
Console.Write(i);
if (i % 5 == 0) {
Console.WriteLine();
continue;
}
Console.Write(", ");
}
}
}
C++
for(int i = 1;i <= 10; i++){
cout << i;
if(i % 5 == 0){
cout << endl;
continue;
}
cout << ", ";
}
C3
for (int i = 1; i <= 10; i++)
{
io::print(i);
if (i % 5 == 0)
{
io::printn();
continue;
}
io::print(", ");
}Chapel
for i in 1..10 {
write(i);
if i % 5 == 0 then {
writeln();
continue;
}
write(", ");
}
Clipper
LOOP keyword is used here instead of continue.
Works as is with Harbour 3.0.0 (Rev. 16951)
FOR i := 1 TO 10
?? i
IF i % 5 == 0
?
LOOP
ENDIF
?? ", "
NEXT
Clojure
Clojure doesn't have a continue keyword. It has a recur keyword, although I prefer to work with ranges in this case.
(doseq [n (range 1 11)]
(print n)
(if (zero? (rem n 5))
(println)
(print ", ")))
To address the task, however, here's an example loop/recur:
(loop [xs (range 1 11)]
(when-let [x (first xs)]
(print x)
(if (zero? (rem x 5))
(println)
(print ", "))
(recur (rest xs))))
COBOL
IDENTIFICATION DIVISION.
PROGRAM-ID. loop-continue.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 i PIC 99.
PROCEDURE DIVISION.
PERFORM VARYING i FROM 1 BY 1 UNTIL 10 < i
DISPLAY i WITH NO ADVANCING
IF FUNCTION MOD(i, 5) = 0
DISPLAY SPACE
EXIT PERFORM CYCLE
END-IF
DISPLAY ", " WITH NO ADVANCING
END-PERFORM
GOBACK
.
Note: COBOL does have a CONTINUE verb, but this is a no-operation statement used in IF and EVALUATE statements.
ColdFusion
Remove the leading space from the line break tag.
<cfscript>
for( i = 1; i <= 10; i++ )
{
writeOutput( i );
if( 0 == i % 5 )
{
writeOutput( "< br />" );
continue;
}
writeOutput( "," );
}
</cfscript>
Common Lisp
Common Lisp doesn't have a continue keyword, but the do iteration construct does use an implicit tagbody, so it's easy to go to any label.
Four solutions follow.
The first pushes the conditional (whether to print a comma and a space or a newline) into the format string.
The second uses the implicit tagbody and go.
The third is a do loop with conditionals outside of the output functions.
(do ((i 1 (1+ i)))
((> i 10))
(format t "~a~:[, ~;~%~]" i (zerop (mod i 5))))
(do ((i 1 (1+ i)))
((> i 10))
(write i)
(when (zerop (mod i 5))
(terpri)
(go end))
(write-string ", ")
end)
(do ((i 1 (1+ i)))
((> i 10))
(write i)
(if (zerop (mod i 5))
(terpri)
(write-string ", ")))
These use the loop iteration form, which does not contain an implicit tagbody (though one could be explicitly included).
The first uses an explicit condition to omit the rest of the loop;
the second uses block/return-from to obtain the effect of skipping the rest of the code in the block which makes up the entire loop body.
(loop for i from 1 to 10
do (write i)
if (zerop (mod i 5))
do (terpri)
else
do (write-string ", "))
(loop for i from 1 to 10 do
(block continue
(write i)
(when (zerop (mod i 5))
(terpri)
(return-from continue))
(write-string ", ")))
Cowgol
include "cowgol.coh";
var n: uint8 := 0;
while n < 10 loop
n := n + 1;
print_i8(n);
if n % 5 == 0 then
print_nl();
continue;
end if;
print(", ");
end loop;- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
D
import std.stdio;
void main() {
foreach (i; 1 .. 11) {
write(i);
if (i % 5 == 0) {
writeln();
continue;
}
write(", ");
}
}
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Shorter version
import std.stdio;
void main()
{
foreach(i; 1..11) i % 5 ? writef("%s, ", i) : writeln(i);
}
dc
The four commands # n J M are special to OpenBSD dc. The # command starts a comment. The n command prints a number without a newline.
1 si # i = 1
[2Q]sA # A = code to break loop
[[, ]P 1J]sB # B = code to print comma, continue loop
[
li n # print i
li 5 % 0 !=B # call B if i % 5
[
]P # print newline
M # mark from calling B
li 1 + si # i += 1
li 10!<C # continue loop if 10 >= i
]sC li 10!<C # enter loop if 10 >= iThis program uses J and M to force the next iteration of a loop. The nJ command breaks n levels of brackets (like nQ does so), but then skips to the next M command. One can place M at the end of the iteration.
Delphi
program DoLoop(output);
var
i: integer;
begin
for i := 1 to 10 do
begin
write(i);
if i mod 5 = 0 then
begin
writeln;
continue;
end;
write(', ');
end;
end.
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
DWScript
var i : Integer;
for i := 1 to 10 do begin
Print(i);
if i mod 5 = 0 then begin
PrintLn('');
continue;
end;
Print(', ');
end;
Dyalect
for i in 1..10 {
print(i, terminator: "")
if i % 5 == 0 {
print()
continue
}
print(", ", terminator: "")
}- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Ela
Direct Approach
open monad io
loop n =
if n > 10 then do
return ()
else do
putStr (show n)
putStr f
loop (n + 1)
where f | n % 5 == 0 = "\r\n"
| else = ", "
_ = loop 1 ::: IOUsing list
open monad io
loop [] = return ()
loop (x::xs) = do
putStr (show x)
putStr f
loop xs
where f | x % 5 == 0 = "\r\n"
| else = ", "
_ = loop [1..10] ::: IOThis version is more generic and can work for any given range of values.
Elixir
defmodule Loops do
def continue do
Enum.each(1..10, fn i ->
IO.write i
IO.write if rem(i,5)==0, do: "\n", else: ", "
end)
end
end
Loops.continue
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
EMal
for int i = 1; i <= 10; ++i
write(i)
if i % 5 == 0
writeLine()
continue
end
write(", ")
end- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Erlang
%% Implemented by Arjun Sunel
-module(continue).
-export([main/0, for_loop/1]).
main() ->
for_loop(1).
for_loop(N) when N /= 5 , N <10 ->
io:format("~p, ",[N] ),
for_loop(N+1);
for_loop(N) when N >=10->
if N=:=10 ->
io:format("~p\n",[N] )
end;
for_loop(N) ->
if N=:=5 ->
io:format("~p\n",[N] ),
for_loop(N+1)
end.
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10 ok
ERRE
FOR I=1 TO 10 DO
PRINT(I;CHR$(29);) ! printing a numeric value leaves a blank after it
! chr$(29) delete it.....
IF I MOD 5=0 THEN
PRINT
CONTINUE FOR
END IF
PRINT(",";)
END FOR
PRINTEuphoria
include std\console.e --only for any_key to make running command window easier on windows
for i = 1 to 10 do
if remainder(i,5) = 0 then
printf(1, "%d\n", i)
else
printf(1,"%d, ", i)
continue
end if
end for
any_key()Version without newline after 10 below.
include std\console.e --only for any_key to make running command window easier on windows
for i = 1 to 10 do
if remainder(i,5) = 0 then
switch i do
case 10 then
printf(1,"%d ",i)
break --new to euphoria 4.0.0+
case else
printf(1,"%d\n", i)
end switch
else
printf(1,"%d, ", i)
continue --new to euphoria 4.0.0+
end if
end for
any_key()F#
continue is a reserved word, but it has no function.
In any case, it is not needed to complete this task.
for i in 1 .. 10 do
printf "%d" i
if i % 5 = 0 then
printf "\n"
else
printf ", "
Using Comma quibbling#The Function
let fN g=quibble (Seq.initInfinite(fun n ->if (n+1)%5=0 || (n+1)=List.length g then "\n" else ", ")) g
fN [1] |> Seq.iter(fun(n,g)->printf "%d%s" n g)
fN [1..9] |> Seq.iter(fun(n,g)->printf "%d%s" n g)
fN [1..10] |> Seq.iter(fun(n,g)->printf "%d%s" n g)
fN [1..11] |> Seq.iter(fun(n,g)->printf "%d%s" n g)
- Output:
1 1, 2, 3, 4, 5 6, 7, 8, 9 1, 2, 3, 4, 5 6, 7, 8, 9, 10 1, 2, 3, 4, 5 6, 7, 8, 9, 10 11
Factor
There is no built-in continue in Factor.
1 10 [a,b] [
[ number>string write ]
[ 5 mod 0 = "\n" ", " ? write ] bi
] each
Fantom
While and for loops support continue to jump back to begin the next iteration of the loop.
class LoopsContinue
{
public static Void main ()
{
for (Int i := 1; i <= 10; ++i)
{
Env.cur.out.print (i)
if (i % 5 == 0)
{
Env.cur.out.printLine ("")
continue
}
Env.cur.out.print (", ")
}
Env.cur.out.printLine ("")
}
}Forth
Although this code solves the task, there is no portable equivalent to "continue" for either DO-LOOPs or BEGIN loops.
: main
11 1 do
i dup 1 r.
5 mod 0= if cr else [char] , emit space then
loop ;
Fortran
do i = 1, 10
write(*, '(I0)', advance='no') i
if ( mod(i, 5) == 0 ) then
write(*,*)
cycle
end if
write(*, '(A)', advance='no') ', '
end do
C WARNING: This program is not valid ANSI FORTRAN 77 code. It uses
C one nonstandard character on the line labelled 5001. Many F77
C compilers should be okay with it, but it is *not* standard.
C
C It is also worth noting that FORTRAN 77 uses the command CONTINUE,
C but not in the semantic, looping sense of the word. In FORTRAN,
C CONTINUE means "do absolutely nothing." It is a placeholder. If
C anything, it means "continue to the next line."
C
C Python does the same thing with `pass`; C and its family of
C languages, with `{/* do nothing */}`. Write CONTINUE when you need
C to write something but have nothing to write.
C
C This page on Rosetta Code is about a very different "continue"
C statement that tells a loop to go back to the beginning. In
C FORTRAN, we use (you guessed it!) a GOTO to accomplish this.
PROGRAM CONTINUELOOP
INTEGER I
DO 10 I = 1, 10
C Is it five or ten?
IF (MOD(I, 5) .EQ. 0) THEN
C If it is, write a newline and no comma.
WRITE (*,5000) I
C Continue the loop; that is, skip to the end of the loop.
GOTO 10
ENDIF
C Write I with a comma and no newline.
WRITE (*,5001) I
C Again, in this case, CONTINUE is completely unrelated to the
C semantic, looping sense of the word.
10 CONTINUE
STOP
C This will print an integer and a newline (no comma).
5000 FORMAT (I3)
C Standard FORTRAN 77 is completely incapable of completing a
C WRITE statement without printing a newline. If you want to print
C five integers in standard code, you have to do something like
C this:
C
C FORMAT (I3, ',', I3, ',', I3, ',', I3, ',', I3)
C
C Writing `1, 2, 3, 4, 5` and then `6, 7, 8, 9, 10` to that format
C would produce the following two lines:
C
C 1, 2, 3, 4, 5
C 6, 7, 8, 9, 10
C
C However, this code exists to demonstrate continuing a FORTRAN 77
C loop and not to demonstrate how to get around its rigidity about
C newlines.
C
C The dollar sign at the end of the format is a nonstandard
C character. It tells the compiler not to print a newline. If you
C are actually using FORTRAN 77, you should figure out what your
C particular compiler accepts. If you are actually using Fortran
C 90 or later, you should replace this line with the commented
C line that follows it.
5001 FORMAT (I3, ',', $)
C5001 FORMAT (I3, ',', ADVANCE='NO')
END
Relying instead upon the looping features of FORMAT
For historical reasons, 6 is often the default unit number for standard output.
WRITE (6,1) (I,I = 1,10)
1 FORMAT (4(1X,I0,","),1X,I0)
END
Here the break and continuation comes through the workings of the FORMAT interpreter. The feature 4(etc) means four repetitions of the format items within the brackets, and as each datum from the WRITE statement arrives, it is aligned with the next format item that can receive a datum, the I-format specifier (here I0, which means an integer of only as many digits as are needed for the value) and until such a reciever is encountered, intervening format items are acted upon - 1X means "one space", and the quotes surround a text literal. Accordingly, the first datum generates a space, a one-digit value, and a comma, as does the second and so on. When the sixth datum is received, the end of the format statement has been reached, and the convention is to write the current line and start a new line of output, and further, go back in the FORMAT specification to the first-encountered open-bracket symbol (the rightmost) which in this case is not the beginning of the FORMAT statement but the one that has a repetition count of four in front of it, and, resume interpretation. When the last datum has been accepted, naturally, the line is printed.
An alternative might be FORMAT (4(I2,","),I2) but that would generate
1, 2, 3, 4, 5 6, 7, 8, 9,10
Alternatively, FORMAT (4(I2,","),I2,/,4(I2,","),I3) would do the trick but there would no longer be the loop, break, continue aspect to the interpretation of the FORMAT statement, merely a grinding through a list.
This sort of scheme facilitates a compact way of printing a table with a heading, where the WRITE statement simply pours forth the data and relies on something like FORMAT("heading",/,(complex details for one line)) - thus printing the table line-by-line with only the first line having the heading, a saving on having a write and format statement pair for the heading and a second pair for the table body.
FutureBasic
include "NSLog.incl"
long num
for num = 1 to 10
if ( num mod 5 )
NSLog(@"%ld, \b",num)
else
NSLog(@"%ld",num)
end if
next
HandleEventsGambas
Click this link to run this code
Public Sub Main()
Dim siCount As Short
For siCount = 1 To 10
Print siCount;
If siCount <> 5 And siCount <> 10 Then Print ",";
If siCount = 5 Then Print gb.NewLine;
Next
End
Output:
1,2,3,4,5 6,7,8,9,10
GAP
for i in [1 .. 11] do
if RemInt(i, 5) = 0 then
Print(i, "\n");
continue;
fi;
Print(i, ", ");
od;
# 1, 2, 3, 4, 5
# 6, 7, 8, 9, 10
GDScript
extends MainLoop
func _process(_delta: float) -> bool:
for i in range(1,11):
if i % 5 == 0:
print(i)
continue
printraw(i, ", ")
return true # Exit
GML
for(i = 1; i <= 10; i += 1)
{
show_message(string(i))
i += 1
if(i <= 10)
continue
}Go
package main
import "fmt"
func main() {
for i := 1; i <= 10; i++ {
fmt.Printf("%d", i)
if i%5 == 0 {
fmt.Printf("\n")
continue
}
fmt.Printf(", ")
}
}
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Groovy
for (i in 1..10) {
print i
if (i % 5 == 0) {
println ()
continue
}
print ', '
}
Haskell
As a functional language, it is not idiomatic to have true loops - recursion is used instead. Below is one of many possible implementations of the task. The below code uses a guard (| symbol) to compose functions differently for the two alternative output paths, instead of using continue like in an imperative language.
import Control.Monad (forM)
main = forM [1..10] out
where
out x | x `mod` 5 == 0 = print x
| otherwise = (putStr . (++", ") . show) x
Haxe
for (i in 1...11) {
Sys.print(i);
if (i % 5 == 0) {
Sys.print('\n');
continue;
}
Sys.print(', ');
}
HicEst
DO i = 1, 10
IF( MOD(i, 5) == 1 ) THEN
WRITE(Format="i3") i
ELSE
WRITE(APPend, Format=" ',', i3 ") i
ENDIF
ENDDOIcon and Unicon
The following code demonstrates the use of 'next' (the reserved word for 'continue'):
However, the output sequence can be written without 'next' and far more succinctly as:
Io
for(i,1,10,
write(i)
if(i%5 == 0, writeln() ; continue)
write(" ,")
)
J
J is array-oriented, so there is very little need for loops. For example, one could satisfy this task this way:
_2}."1'lq<, >'8!:2>:i.2 5
J does support loops for those times they can't be avoided (just like many languages support gotos for those time they can't be avoided).
3 : 0 ] 10
z=.''
for_i. 1 + i.y do.
z =. z , ": i
if. 0 = 5 | i do.
z 1!:2 ]2
z =. ''
continue.
end.
z =. z , ', '
end.
i.0 0
)
Though it's rare to see J code like this.
Jakt
fn main() {
for i in 1..11 {
if i % 5 == 0 {
println("{}", i)
continue
}
print("{}, ", i)
}
}Java
for(int i = 1;i <= 10; i++){
System.out.print(i);
if(i % 5 == 0){
System.out.println();
continue;
}
System.out.print(", ");
}
JavaScript
Using the print() function from Rhino or SpiderMonkey.
var output = "";
for (var i = 1; i <= 10; i++) {
output += i;
if (i % 5 == 0) {
print(output);
output = "";
continue;
}
output += ", ";
}
Stepping back from any assumption that repetitive patterns of computation necessarily entail 'loops', and using a functional idiom of JavaScript, we can make the value of one or more subexpressions in a reduce() fold conditional on any special cases that we define.
For example:
function rng(n) {
return n ? rng(n - 1).concat(n) : [];
}
console.log(
rng(10).reduce(
function (a, x) {
return a + x.toString() + (x % 5 ? ', ' : '\n');
}, ''
)
);
Output:
1, 2, 3, 4, 5
6, 7, 8, 9, 10
jq
jq does not have a "continue" statement. In jq 1.4, the simplest way to accomplish the given task is probably as follows:
reduce range(1;11) as $i
(""; . + "\($i)" + (if $i % 5 == 0 then "\n" else ", " end))Jsish
/* Loop/continue in jsish */
for (var i = 1; i <= 10; i++) {
printf("%d", i);
if (i % 5 == 0) {
printf("\n");
continue;
}
printf(", ");
}
- Output:
prompt$ jsish loop-continue.jsi 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Julia
for i in 1:10
print(i)
if i%5 == 0
println()
continue
end
print(", ")
end
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Kotlin
// version 1.1.2
fun main(args: Array<String>) {
for(i in 1 .. 10) {
if (i % 5 == 0) {
println(i)
continue
}
print("$i, ")
}
}
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Lambdatalk
{def loops_continue
{lambda {:i}
{if {> :i 10}
then (end of loop)
else {if {= :i 6} then {br}:i else :i}
{if {= :i 10} then . else ,}
{loops_continue {+ :i 1}}}}}
-> loops_continue
{loops_continue 0}
-> 0, 1, 2, 3, 4, 5,
6, 7, 8, 9, 10. (end of loop)
Lang
$i = 0
while($i < 10) {
$i += 1
if($i % 5 === 0) {
fn.println($i)
con.continue
}
fn.print($i\,\s)
}- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
langur
for i of 10 {
write i
if i div 5 { writeln(); next }
write ", "
}Lasso
loop(10) => {^
loop_count
loop_count % 5 ? ', ' | '\r'
loop_count < 100 ? loop_continue
'Hello, World!' // never gets executed
^}
LDPL
data:
i is number
n is number
procedure:
for i from 1 to 11 step 1 do
display i
modulo i by 5 in n
if n is equal to 0 then
display lf
continue
end if
display ", "
repeat1, 2, 3, 4, 5 6, 7, 8, 9, 10
Lingo
str = ""
repeat with i = 1 to 10
put i after str
if i mod 5 = 0 then
put RETURN after str
next repeat
end if
put ", " after str
end repeat
put strLisaac
1.to 10 do { i : INTEGER;
i.print;
(i % 5 = 0).if { '\n'.print; } else { ','.print; };
};LiveCode
repeat with n = 1 to 10
put n
if n is 5 then put return
if n < 10 and n is not 5 then put ","
end repeatLua
for i = 1, 10 do
io.write( i )
if i % 5 == 0 then
io.write( "\n" )
else
io.write( ", " )
end
end
or
for i = 1, 10 do
io.write( i )
if i % 5 == 0 then
io.write( "\n" )
goto continue
end
io.write( ", " )
::continue::
end
M2000 Interpreter
Module Checkit {
\\ A For {} loop
For i=1 to 10 {
Print i;
if i mod 5 Else Print : continue
Print ",";
}
Print i=11
\\ A For Next loop
For i=1 to 10
Print i;
if i mod 5 Else Print : continue
Print ",";
Next i
Print i=11
\\ A for loop using a block and a Loop statement
i=0
{ i++
if i>10 then Exit
loop
Print i;
if i mod 5 Else Print : continue
Print ",";
}
Print i=11
\\ as above but end value for i=10 not 11
i=0
{ i++
if i<10 then loop
Print i;
if i mod 5 Else Print : continue
Print ",";
}
Print i=10 ' not 11 but 10
}
CheckitMaple
for i from 1 to 10 do
printf( "%d", i );
if irem( i, 5 ) = 0 then
printf( "\n" );
next
end if;
printf( ", " )
end do:This can also be done as follows, but without the use of "next".
for i to 10 do
printf( "%d%s", i, `if`( irem( i, 5 ) = 0, "\n", ", " ) )
end do:Mathematica /Wolfram Language
tmp = "";
For[i = 1, i <= 10, i++,
tmp = tmp <> ToString[i];
If[Mod[i, 5] == 0,
tmp = tmp <> "\n";
,
tmp = tmp <> ", ";
];
];
Print[tmp]
MATLAB / Octave
Loops are considered slow in Matlab and Octave, it is preferable to vectorize the code.
disp([1:5; 6:10])
or
disp(reshape([1:10],5,2)')
A non-vectorized version of the code is shown below in Octave
for i = 1:10
printf(' %2d', i);
if ( mod(i, 5) == 0 )
printf('\n');
continue
end
end
Maxima
/* There is no "continue" in Maxima, the easiest is using a "if" instead */
block(
[s: ""],
for n thru 10 do (
s: sconcat(s, n),
if mod(n, 5) = 0 then (
ldisp(s),
s: ""
) else (
s: sconcat(s, ", ")
)
)
)$
Using sprint and newline
for n:1 thru 10 do (
sprint(n),
if n=5 then newline())$
MAXScript
for i in 1 to 10 do
(
format "%" i
if mod i 5 == 0 then
(
format "\n"
continue
) continue
format ", "
)Insert non-formatted text here
Metafont
Metafont has no a continue (or similar) keyword. As the Ada solution, we can complete the task just with conditional.
string s; s := "";
for i = 1 step 1 until 10:
if i mod 5 = 0:
s := s & decimal i & char10;
else:
s := s & decimal i & ", "
fi; endfor
message s;
endSince message append always a newline at the end, we need to build a string and output it at the end, instead of writing the output step by step.
Note: mod is not a built in; like TeX, "bare Metafont" is rather primitive, and normally a set of basic macros is preloaded to make it more usable; in particular mod is defined as
primarydef x mod y = (x-y*floor(x/y)) enddef;Modula-3
Modula-3 defines the keyword RETURN as an exception, but when it is used with no arguments it works just like continue in C.
Note, however, that RETURN only works inside a procedure or a function procedure; use EXIT otherwise.
Module code and imports are omitted.
FOR i := 1 TO 10 DO
IO.PutInt(i);
IF i MOD 5 = 0 THEN
IO.Put("\n");
RETURN;
END;
IO.Put(", ");
END;
MOO
s = "";
for i in [1..10]
s += tostr(i);
if (i % 5 == 0)
player:tell(s);
s = "";
continue;
endif
s += ", ";
endfor
Neko
/**
Loops/Continue in Neko
Tectonics:
nekoc loops-continue.neko
neko loops-continue
*/
var index = 0;
while index < 10 {
index += 1;
$print(index);
if $not($istrue(index % 5)) {
$print("\n");
continue;
}
$print(", ");
}
- Output:
prompt$ nekoc loops-continue.neko prompt$ neko loops-continue.n 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Nemerle
using System;
using System.Console;
using Nemerle.Imperative;
module Continue
{
Main() : void
{
foreach (i in [1 .. 10])
{
Write(i);
when (i % 5 == 0) {WriteLine(); continue;}
Write(", ");
}
}
}
NetRexx
/* NetRexx */
options replace format comments java crossref savelog symbols nobinary
say
say 'Loops/Continue'
nul = '\-'
loop i_ = 1 to 10
say i_.right(2) || nul
if i_ // 5 = 0 then do
say
iterate i_
end
say ', ' || nul
end i_
NewLISP
(for (i 1 10)
(print i)
(if (= 0 (% i 5))
(println)
(print ", ")))
Nim
for i in 1..10:
if i mod 5 == 0:
echo i
continue
stdout.write i, ", "
NS-HUBASIC
10 FOR I=1 TO 10
20 PRINT I;
30 IF I-I/5*5=0 THEN PRINT :GOTO 50"CONTINUE
40 PRINT ",";
50 NEXTNu
for i in 1..10 {
print -n $i
if $i mod 5 == 0 {
print ""
continue
}
print -n ", "
}Objeck
class Continue {
function : Main(args : String[]) ~ Nil {
for(i := 1; i <= 10; i += 1;) {
if(i = 5) {
"{$i}, "->PrintLine();
continue;
};
"{$i}, "->Print();
};
}
}OCaml
There is no continue statement for for loops in OCaml, but it is possible to achieve the same effect with an exception.
# for i = 1 to 10 do
try
print_int i;
if (i mod 5) = 0 then raise Exit;
print_string ", "
with Exit ->
print_newline()
done
;;
1, 2, 3, 4, 5
6, 7, 8, 9, 10
- : unit = ()
Though even if the continue statement does not exist, it is possible to add it with camlp4.
Octave
v = "";
for i = 1:10
v = sprintf("%s%d", v, i);
if ( mod(i, 5) == 0 )
disp(v)
v = "";
continue
endif
v = sprintf("%s, ", v);
endfor
Oforth
: loopCont
| i |
10 loop: i [
i dup print 5 mod ifZero: [ printcr continue ]
"," .
] ;Ol
We use continuation to break the execution of the inner body.
(let loop ((i 1))
(when (less? i 11)
(call/cc (lambda (continue)
(display i)
(when (zero? (mod i 5))
(print)
(continue #f))
(display ", ")))
(loop (+ i 1))))
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Oz
By using the "continue" feature of the for-loop, we bind C to a nullary procedure which, when invoked, immediately goes on to the next iteration of the loop.
for I in 1..10 continue:C do
{System.print I}
if I mod 5 == 0 then
{System.printInfo "\n"}
{C}
end
{System.printInfo ", "}
endPARI/GP
for(n=1,10,
print1(n);
if(n%5 == 0, print();continue);
print1(", ")
)Pascal
See Delphi
PascalABC.NET
begin
for var i:=1 to 10 do
begin
Write(i);
if i mod 5 = 0 then
begin
Writeln;
continue
end;
Write(', ');
end;
end.
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Perl
foreach (1..10) {
print $_;
if ($_ % 5 == 0) {
print "\n";
next;
}
print ', ';
}
It is also possible to use a goto statement to jump over the iterative code section for a particular loop:
foreach (1..10) {
print $_;
if ($_ % 5 == 0) {
print "\n";
goto MYLABEL;
}
print ', ';
MYLABEL:
}
Phix
with javascript_semantics for i=1 to 10 do printf(1,"%d", i) if remainder(i,5)=0 then printf(1, "\n") continue end if printf(1,", ") end for
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
The following works just as well, with identical output
with javascript_semantics for i=1 to 10 do printf(1,"%d", i) if remainder(i,5)=0 then printf(1, "\n") else printf(1,", ") end if end for
PHP
for ($i = 1; $i <= 10; $i++) {
echo $i;
if ($i % 5 == 0) {
echo "\n";
continue;
}
echo ', ';
}
Picat
Picat doesn't have a continue statement. So I just use a conditional that ends the body of the predicate.
main =>
foreach (I in 1..10)
printf("%d", I),
if (I mod 5 == 0) then
nl
else
printf(", ")
end,
end.- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
PicoLisp
PicoLisp doesn't have an explicit 'continue' functionality. It can always be emulated with a conditional expression.
(for I 10
(print I)
(if (=0 (% I 5))
(prinl)
(prin ", ") ) )Pike
int main(){
for(int i = 1; i <= 10; i++){
write(sprintf("%d",i));
if(i % 5 == 0){
write("\n");
continue;
}
write(", ");
}
}
PL/I
loop:
do i = 1 to 10;
put edit (i) (f(3));
if mod(i,5) = 0 then do; put skip; iterate loop; end;
put edit (', ') (a);
end;Plain English
In Plain English, continue is spelled repeat and is the only way to specify an end of a loop.
To run:
Start up.
Demonstrate continue.
Wait for the escape key.
Shut down.
To demonstrate continue:
If a counter is past 10, exit.
Convert the counter to a string.
Write the string on the console without advancing.
If the counter is evenly divisible by 5, write "" on the console; repeat.
Write ", " on the console without advancing.
Repeat.Pop11
lvars i;
for i from 1 to 10 do
printf(i, '%p');
if i rem 5 = 0 then
printf('\n');
nextloop;
endif;
printf(', ')
endfor;PowerShell
for ($i = 1; $i -le 10; $i++) {
Write-Host -NoNewline $i
if ($i % 5 -eq 0) {
Write-Host
continue
}
Write-Host -NoNewline ", "
}
Prolog
Prolog doesn't have a continue statement. So I just use a conditional that ends the body of the predicate.
:- initialization(main).
print_list(Min, Max) :-
Min < Max,
write(Min),
Min1 is Min + 1,
(
Min mod 5 =:= 0
-> nl
; write(',')
),
print_list(Min1, Max).
print_list(Max, Max) :-
write(Max),
nl.
main :-
print_list(1, 10).
- Output:
1,2,3,4,5 6,7,8,9,10
Python
for i in range(1, 11):
if i % 5 == 0:
print(i)
continue
print(i, end=', ')
Quackery
10 times
[ i^ 1+ dup echo
5 mod 0 = iff
cr done
say ", " ]R
for(i in 1:10)
{
cat(i)
if(i %% 5 == 0)
{
cat("\n")
next
}
cat(", ")
}
Racket
It is possible to skip loop iterations in Racket, but an explicit continue construct is rarely used:
#lang racket
;; Idiomatic way
(for ([i (in-range 1 11)])
(if (= (remainder i 5) 0)
(printf "~a~n" i)
(printf "~a, " i)))
;; Forces a skip, but not idiomatic because
;; the logic is less obvious
(for ([i (in-range 1 11)]
#:unless (and (= (remainder i 5) 0)
(printf "~a~n" i)))
(printf "~a, " i))
Raku
(formerly Perl 6)
for 1 .. 10 {
.print;
if $_ %% 5 {
print "\n";
next;
}
print ', ';
}
or without using a loop:
$_.join(", ").say for [1..5], [6..10];
REBOL
REBOL [
Title: "Loop/Continue"
URL: http://rosettacode.org/wiki/Loop/Continue
]
; REBOL does not provide a 'continue' word for loop constructs,
; however, you may not even miss it:
print "One liner (compare to ALGOL 68 solution):"
repeat i 10 [prin rejoin [i either 0 = mod i 5 [crlf][", "]]]
print [crlf "Port of ADA solution:"]
for i 1 10 1 [
prin i
either 0 = mod i 5 [
prin newline
][
prin ", "
]
]
- Output:
One liner (compare to ALGOL 68 solution): 1, 2, 3, 4, 5 6, 7, 8, 9, 10 Port of ADA solution: 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Red
repeat i 10 [
prin i
if i = 10 [break]
either i = 5 [print ""][prin ","]
]
1,2,3,4,5
6,7,8,9,10
REXX
version 1
(This program could be simpler by using a then/else construct, but an iterate was used to conform to the task.)
/*REXX program illustrates an example of a DO loop with an ITERATE (continue). */
do j=1 for 10 /*this is equivalent to: DO J=1 TO 10 */
call charout , j /*write the integer to the terminal. */
if j//5\==0 then do /*Not a multiple of five? Then ··· */
call charout , ", " /* write a comma to the terminal, ··· */
iterate /* ··· & then go back for next integer.*/
end
say /*force REXX to display on next line. */
end /*j*/
/*stick a fork in it, we're all done. */
Program note: the comma (,) immediately after the charout BIF indicates to use the terminal output stream.
output
1, 2, 3, 4, 5 6, 7, 8, 9, 10
version 2
/*REXX program illustrates an example of a DO loop with an ITERATE (continue). */
$= /*nullify the variable used for display*/
do j=1 for 10 /*this is equivalent to: DO J=1 TO 10 */
$=$ || j', ' /*append the integer to a placeholder. */
if j//5==0 then say left($, length($) - 2) /*Is J a multiple of five? Then SAY.*/
if j==5 then $= /*start the display line over again. */
end /*j*/
/*stick a fork in it, we're all done. */
output is the same as the 1st REXX version.
Ring
for i = 1 TO 10
see i
if i % 5 = 0
see nl
loop
ok
see ", "
nextRPL
You need an IF..THEN..ELSE structure to do that in RPL.
« ""
1 10 FOR j
j +
IF j 5 MOD THEN ", " + ELSE "" END
NEXT DROP
» 'TASK' STO
Ruby
for i in 1..10 do
print i
if i % 5 == 0 then
puts
next
end
print ', '
endThe "for" look could be written like this:
(1..10).each do |i| ...
1.upto(10) do |i| ...
10.times do |n| i=n+1; ...Without meeting the criteria (showing loop continuation), this task could be written as:
(1..10).each_slice(5){|ar| puts ar.join(", ")}Rust
fn main() {
for i in 1..=10 {
print!("{}", i);
if i % 5 == 0 {
println!();
continue;
}
print!(", ");
}
}Salmon
iterate (x; [1...10])
{
print(x);
if (x % 5 == 0)
{
print("\n");
continue;
};
print(", ");
};Sather
There's no continue! in Sather. The code solve the task without forcing a new iteration.
class MAIN is
main is
i:INT;
loop i := 1.upto!(10);
#OUT + i;
if i%5 = 0 then
#OUT + "\n";
else
#OUT + ", ";
end;
end;
end;
end;Scala
Scala doesn't have a continue keyword.
However, you may not even miss it, if could be used here.
The intuitive way
for (i <- 1 to 10) {
print(i)
if (i % 5 == 0) println() else print(", ")
}Functional solution
Thinking In Scala© says: we avoid for loops and handle it the Functional way:
- Create a Range 1..10 included
- Split the range after converting to a List to a pair of List's
- A List of the elements of pair of will be created: List(List(1,2,3,4,5),List(6,7,8,9,10))
- The map makes for both elements in the List a conversion to a comma separated String, yielding a List of two Strings.
- Both comma separated strings will be separated by an EOL
val a = (1 to 10 /*1.*/ ).toList.splitAt(5) //2.
println(List(a._1, a._2) /*3.*/ .map(_.mkString(", ") /*4.*/ ).mkString("\n") /*5.*/ )Scheme
For R7RS Scheme. In this functional solution, there is no "continue". Instead, the "loop" function is directly called in the tail end (this is Tail Recursion).
(import (scheme base)
(scheme write))
(define (loop-fn start end)
(define (loop i)
(if (> i end) #f
(begin
(display i)
(cond ((zero? (modulo i 5))
(newline) (loop (+ 1 i)))
(else
(display ", ")
(loop (+ 1 i)))))))
(loop start))
(loop-fn 1 10)Scilab
for i=1:10
printf("%2d ",i)
if modulo(i,5)~=0 then
printf(", ")
continue
end
printf("\n")
end- Output:
1 , 2 , 3 , 4 , 5 6 , 7 , 8 , 9 , 10
Sidef
for i in (1..10) {
print i
if (i %% 5) {
print "\n"
next
}
print ', '
}Simula
! Loops/Continue - simula67 - 07/03/2017;
begin
integer i;
for i:=1 step 1 until 10 do begin
outint(i,5);
if mod(i,5)=0 then begin
outimage;
goto loop
end;
outtext(", ");
loop:
end
end- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Smalltalk
actually works with all dialects ¹
1 to: 10 do: [ :i |
[ :continue |
i % 5 = 0 ifTrue: [
Transcript show: i; cr.
continue value ].
Transcript
show: i;
show: ', '.
] valueWithExit.
]¹ if valueWithExit is not present in the Block class, it can be added as:
valueWithExit
^ self value:[^ nil]SNOBOL4
SNOBOL4 has no looping statements or conditional statements. Indeed the only branching facilities it has are:
- Unconditional branch to label.
:(LABEL) - Branch to label on success.
:S(LABEL) - Branch to label on failure.
:F(LABEL)
(The success/failure labels can both be in the branching clause.)
Despite this, any looping structure can be performed by careful use of these.
line =
i = 1
LOOP le(i, 10) :F(LOOP.END)
line = line i
eq(remdr(i, 5), 0) :S(LOOP.OUT)
line = line ', ' :(LOOP.INC)
LOOP.OUT OUTPUT = line
line =
LOOP.INC i = i + 1 :(LOOP)
LOOP.END OUTPUT = line
END- Output:
$ snobol4 junk.sno 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Spin
con
_clkmode = xtal1 + pll16x
_clkfreq = 80_000_000
obj
ser : "FullDuplexSerial.spin"
pub main | i
ser.start(31, 30, 0, 115200)
repeat i from 1 to 10
ser.dec(i)
if i // 5
ser.str(string(", "))
next
ser.str(string(13,10))
waitcnt(_clkfreq + cnt)
ser.stop
cogstop(0)- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
SPL
> n, 1..10
s += n
? n%5, s += ", "
>> n%5
#.output(s)
s = ""
<- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
SQL PL
version 9.7 or higher.
With SQL PL:
--#SET TERMINATOR @
SET SERVEROUTPUT ON @
BEGIN
DECLARE I SMALLINT DEFAULT 1;
Loop: WHILE (I <= 10) DO
CALL DBMS_OUTPUT.PUT(I);
SET I = I + 1;
IF (MOD(I - 1, 5) = 0) THEN
CALL DBMS_OUTPUT.PUT_LINE(' ');
ITERATE Loop;
END IF;
CALL DBMS_OUTPUT.PUT(', ');
END WHILE Loop;
END @Output:
db2 => BEGIN ... db2 (cont.) => END @ DB20000I The SQL command completed successfully. 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Stata
See continue in Stata help. Notice that the _continue option of display has another purpose: it suppresses the automatic newline at the end of the display command.
forvalues n=1/10 {
display `n' _continue
if mod(`n',5)==0 {
display
continue
}
display ", " _continue
}Suneido
ob = Object()
for (i = 1; i <= 10; ++i)
{
ob.Add(i)
if i is 5
{
Print(ob.Join(','))
ob = Object()
}
}
Print(ob.Join(','))- Output:
1,2,3,4,5
6,7,8,9,10
okSwift
for i in 1...10 {
print(i, terminator: "")
if i % 5 == 0 {
print()
continue
}
print(", ", terminator: "")
}- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Tcl
for {set i 1} {$i <= 10} {incr i} {
puts -nonewline $i
if {$i % 5 == 0} {
puts ""
continue
}
puts -nonewline ", "
}Transact-SQL
DECLARE @i INT = 0;
DECLARE @str VarChar(40) = '';
WHILE @i<10
BEGIN
SET @i = @i + 1;
SET @str = @str + CONVERT(varchar(2),@i);
IF @i % 5 = 0
BEGIN
PRINT @str;
SET @str =''
CONTINUE;
END
SET @str = @str +', ';
END;TUSCRIPT
$$ MODE TUSCRIPT
numbers=""
LOOP n=1,10
numbers=APPEND (numbers,", ",n)
rest=n%5
IF (rest!=0) CYCLE
PRINT numbers
numbers=""
ENDLOOP- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
UNIX Shell
Z=1
while (( Z<=10 )); do
echo -e "$Z\c"
if (( Z % 5 != 0 )); then
echo -e ", \c"
else
echo -e ""
fi
(( Z++ ))
donefor ((i=1;i<=10;i++)); do
echo -n $i
if [ $((i%5)) -eq 0 ]; then
echo
continue
fi
echo -n ", "
doneUnixPipes
yes \ | cat -n | head -n 10 | xargs -n 5 echo | tr ' ' ,Ursa
decl int i
for (set i 1) (< i 11) (inc i)
if (= (mod i 5) 0)
out i endl console
continue
end if
out i ", " console
end forUrsalang
let write = process.stdout.write
for i in range(10) {
let n = i + 1
write(n.toString())
if (n == 5) {
write("\n")
continue
}
if (n < 10) {write(", ")}
}Vala
for (int i = 1; i <= 10; i++) {
stdout.printf("%d", i);
if (i % 5 == 0) {
stdout.printf("\n");
continue;
}
stdout.printf(", ");
}VBA
Public Sub LoopContinue()
Dim value As Integer
For value = 1 To 10
Debug.Print value;
If value Mod 5 = 0 Then
'VBA does not have a continue statement
Debug.Print
Else
Debug.Print ",";
End If
Next value
End SubVedit macro language
for (#1 = 1; #1 <= 10; #1++) {
Num_Type(#1, LEFT+NOCR)
if (#1 % 5 == 0) {
Type_Newline
Continue
}
Message(", ")
}V (Vlang)
fn main() {
for i in 1..11 {
print(i)
if i%5==0{
println('')
continue
}
print(', ')
}
}- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Wren
From v0.4.0 Wren has a continue keyword which works in the expected fashion.
for (i in 1..10) {
System.write(i)
if (i%5 == 0) {
System.print()
continue
}
System.write(", ")
}
System.print()- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
X86 Assembly
The code got really long, because i manually convert the numbers to ASCII, which gets harder with multiple digits(the number 10). The way you implement continue in X86 Assembly is the same way as how you would create a loop: you just implement a (conditional) jump to another line of code.
extern _printf
section .data
output db 0,0,0,0
reversedOutput db 0,0
section .text
global _main
_main:
mov ecx, 0
looping:
inc ecx
mov eax, ecx
push ecx
cmp ecx, 5
je do5
cmp ecx, 10
je do10
don:
call createOutput
mov [eax+1], byte 0x2c
mov [eax+2], byte 0x20
push eax
call _printf
add esp, 4
pop ecx
jmp looping
do5:
call createOutput
mov [eax+1], byte 0x0a
push eax
call _printf
add esp, 4
pop ecx
jmp looping
do10:
call createOutput
mov [eax+2], byte 0x0a
push eax
call _printf
add esp, 4
pop ecx
xor eax, eax
ret
createOutput: ;parameter in eax
;eax between 1 and 99
push ebx
mov ecx, 0
clearOutput:
mov [output+ecx], byte 0
cmp ecx, 3
je next
inc ecx
jmp clearOutput
next:
mov ecx, 0
mov ebx, 10
cOlooping:
xor edx, edx
div ebx
mov [reversedOutput+ecx], dl
add [reversedOutput+ecx], byte 0x30
cmp eax, 0
je reverse
cmp ecx, 1
je reverse
inc ecx
jmp cOlooping
reverse:
mov ecx, -1
mov ebx, 0
name:
inc ecx
neg ecx
mov dl, [reversedOutput+ecx+1]
neg ecx
cmp dl, 0
je name
mov [output + ebx], dl
inc ebx
cmp ecx, 1
jl name
mov eax, output
pop ebx
ret- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
XBasic
PROGRAM "loopcontinue"
DECLARE FUNCTION Entry()
FUNCTION Entry()
FOR i% = 1 TO 10
PRINT i%;
IF i% MOD 5 = 0 THEN
PRINT
DO NEXT ' It looks like DO FOR backs to the FOR with the current value of i%
END IF
PRINT ", ";
NEXT i%
END FUNCTION
END PROGRAM- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
XPL0
Like Ada and ALGOL there's no 'continue' command. The task is solved very simply anyway. The commands 'int' and 'rem' are shown spelled out here. Only the first three characters of a command are required.
code CrLf=9, IntOut=11, Text=12;
integer N;
for N:= 1 to 10 do
[IntOut(0, N); if remainder(N/5) \#0\ then Text(0, ", ") else CrLf(0)]- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Yabasic
for i = 1 to 10
print str$(i);
if mod(i, 5) = 0 then
print
continue
end if
print ", ";
next
print
end
zkl
foreach n in ([1..10]){print(n); if(n%5==0){println(); continue;} print(", ")}
// or foreach n in ([1..10]){print(n,(n%5) and ", " or "\n")}Zig
const std = @import("std");
pub fn main() !void {
const stdout_wr = std.io.getStdOut().writer();
var i: i8 = 1;
while (i <= 10) : (i += 1) {
try stdout_wr.print("{d}", .{i});
if (i == 5) {
try stdout_wr.writeAll("\n");
continue;
}
try stdout_wr.writeAll(", ");
}
}- Programming Tasks
- Iteration
- Loop modifiers
- EasyLang/Omit
- GUISS/Omit
- M4/Omit
- 11l
- 360 Assembly
- Ada
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