# Pangram checker: Difference between revisions

Pangram checker
You are encouraged to solve this task according to the task description, using any language you may know.

A pangram is a sentence that contains all the letters of the English alphabet at least once.

For example:   The quick brown fox jumps over the lazy dog.

Write a function or method to check a sentence to see if it is a   pangram   (or not)   and show its use.

## 11l

```F is_pangram(sentence)
R Set(sentence.lowercase().filter(ch -> ch C ‘a’..‘z’)).len == 26

L(sentence) [‘The quick brown fox jumps over the lazy dog.’,
‘The quick brown fox jumped over the lazy dog.’]
print(‘'#.' is #.a pangram’.format(sentence, ‘not ’ * !is_pangram(sentence)))```
Output:
```'The quick brown fox jumps over the lazy dog.' is a pangram
'The quick brown fox jumped over the lazy dog.' is not a pangram
```

## 360 Assembly

```*        Pangram RC                11/08/2015
PANGRAM  CSECT
USING  PANGRAM,R12
LR     R12,R15
BEGIN    LA     R9,SENTENCE
LA     R6,4
LOOPI    LA     R10,ALPHABET       loop on sentences
LA     R7,26
LOOPJ    LA     R5,0               loop on letters
LR     R11,R9
LA     R8,60
LOOPK    MVC    BUFFER+1(1),0(R10) loop in sentence
CLC    0(1,R10),0(R11)    if alphabet[j=sentence[i]
BNE    NEXTK
LA     R5,1               found
NEXTK    LA     R11,1(R11)         next character
BCT    R8,LOOPK
LTR    R5,R5              if found
BNZ    NEXTJ
B      PRINT
NEXTJ    LA     R10,1(R10)         next letter
BCT    R7,LOOPJ
MVC    BUFFER(2),=CL2'OK'
PRINT    MVC    BUFFER+3(60),0(R9)
XPRNT  BUFFER,80
NEXTI    LA     R9,60(R9)          next sentence
BCT    R6,LOOPI
RETURN   XR     R15,R15
BR     R14
ALPHABET DC     CL26'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
SENTENCE DC     CL60'THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.'
DC     CL60'THE FIVE BOXING WIZARDS DUMP QUICKLY.'
DC     CL60'HEAVY BOXES PERFORM WALTZES AND JIGS.'
DC     CL60'PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS.'
BUFFER   DC     CL80' '
YREGS
END    PANGRAM```
Output:
```OK THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.
?J THE FIVE BOXING WIZARDS DUMP QUICKLY.
?C HEAVY BOXES PERFORM WALTZES AND JIGS.
OK PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS.```

## ACL2

```(defun contains-each (needles haystack)
(if (endp needles)
t
(and (member (first needles) haystack)
(contains-each (rest needles) haystack))))

(defun pangramp (str)
(contains-each (coerce "abcdefghijklmnopqrstuvwxyz" 'list)
(coerce (string-downcase str) 'list)))
```

## Action!

```INCLUDE "D2:CHARTEST.ACT" ;from the Action! Tool Kit

DEFINE CHAR_COUNT="26"

BYTE FUNC IsPangram(CHAR ARRAY t)
BYTE ARRAY tab(CHAR_COUNT)
BYTE i,c

FOR i=0 TO CHAR_COUNT-1
DO tab(i)=0 OD

FOR i=1 TO t(0)
DO
c=ToLower(t(i))
IF c>='a AND c<='z THEN
tab(c-'a)=1
FI
OD

FOR i=0 TO CHAR_COUNT-1
DO
IF tab(i)=0 THEN
RETURN (0)
FI
OD
RETURN (1)

PROC Test(CHAR ARRAY t)
BYTE res

res=IsPangram(t)
PrintF("""%S"" is ",t)
IF res=0 THEN
Print("not ")
FI
PrintE("a pangram.")
PutE()
RETURN

PROC Main()
Put(125) PutE() ;clear screen
Test("The quick brown fox jumps over the lazy dog.")
Test("QwErTyUiOpAsDfGhJkLzXcVbNm")
Test("Not a pangram")
Test("")
RETURN```
Output:
```"The quick brown fox jumps over the lazy dog." is a pangram.

"QwErTyUiOpAsDfGhJkLzXcVbNm" is a pangram.

"Not a pangram" is not a pangram.

"" is not a pangram.
```

## ActionScript

Works with: ActionScript version 2.0
```function pangram(k:string):Boolean {
var lowerK:String = k.toLowerCase();
var has:Object = {}

for (var i:Number=0; i<=k.length-1; i++) {
has[lowerK.charAt(i)] = true;
}

var result:Boolean = true;

for (var ch:String='a'; ch <= 'z'; ch=String.fromCharCode(ch.charCodeAt(0)+1)) {
result = result && has[ch]
}

return result || false;
}
```

### Using character sets

```with Ada.Text_IO; use Ada.Text_IO;
procedure pangram is

function ispangram(txt: String) return Boolean is
(Is_Subset(To_Set(Span => ('a','z')), To_Set(To_Lower(txt))));

begin
put_line(Boolean'Image(ispangram("This is a test")));
put_line(Boolean'Image(ispangram("The quick brown fox jumps over the lazy dog")));
put_line(Boolean'Image(ispangram("NOPQRSTUVWXYZ  abcdefghijklm")));
put_line(Boolean'Image(ispangram("abcdefghijklopqrstuvwxyz"))); --Missing m, n
end pangram;
```

### Using quantified expressions

```with Ada.Text_IO; use Ada.Text_IO;
procedure pangram is

function ispangram(txt : in String) return Boolean is
(for all Letter in Character range 'a'..'z' =>
(for some Char of txt => To_Lower(Char) = Letter));

begin
put_line(Boolean'Image(ispangram("This is a test")));
put_line(Boolean'Image(ispangram("The quick brown fox jumps over the lazy dog")));
put_line(Boolean'Image(ispangram("NOPQRSTUVWXYZ  abcdefghijklm")));
put_line(Boolean'Image(ispangram("abcdefghijklopqrstuvwxyz"))); --Missing m, n
end pangram;
```
Output:
```FALSE
TRUE
TRUE
FALSE
```

## ALGOL 68

Works with: ALGOL 68 version Standard - no extensions to language used
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny
Works with: ELLA ALGOL 68 version Any (with appropriate job cards)
```# init pangram: #
INT la = ABS "a", lz = ABS "z";
INT ua = ABS "A", uz = ABS "Z";
IF lz-la+1 > bits width THEN
put(stand error, "Exception: insufficient bits in word for task");
stop
FI;

PROC is a pangram = (STRING test)BOOL: (
BITS a2z := BIN(ABS(2r1 SHL (lz-la))-1); # assume: ASCII & Binary #
FOR i TO UPB test WHILE
INT c = ABS test[i];
IF la <= c AND c <= lz THEN
a2z := a2z AND NOT(2r1 SHL (c-la))
ELIF ua <= c AND c <= uz THEN
a2z := a2z AND NOT(2r1 SHL (c-ua))
FI;
# WHILE # a2z /= 2r0 DO
SKIP
OD;
a2z = 2r0
);

main:(
[]STRING test list = (
"Big fjiords vex quick waltz nymph",
"The quick brown fox jumps over a lazy dog",
"A quick brown fox jumps over a lazy dog"
);
FOR key TO UPB test list DO
STRING test = test list[key];
IF is a pangram(test) THEN
print(("""",test,""" is a pangram!", new line))
FI
OD
)```
Output:
```"Big fjiords vex quick waltz nymph" is a pangram!
"The quick brown fox jumps over a lazy dog" is a pangram!
```

## APL

```    a←'abcdefghijklmnopqrstuvwxyz' ⍝ or ⎕ucs 96 + ⍳26 in GNU/Dyalog
A←'ABCDEFGHIJKLMNOPQRSTUVWXYZ' ⍝ or ⎕ucs 64 + ⍳26, or just ⎕a in Dyalog

Pangram ← {∧/ ∨⌿ 2 26⍴(a,A) ∊ ⍵}
Pangram 'This should fail'
0
Pangram 'The quick brown fox jumps over the lazy dog'
1
```

## AppleScript

### AppleScriptObjC

Out of the box, AppleScript lacks many library basics – no regex, no higher order functions, not even string functions for mapping to upper or lower case.

From OSX 10.10 onwards, we can, however, use ObjC functions from AppleScript by importing the Foundation framework. We do this below to get a toLowerCase() function. If we also add generic filter and map functions, we can write and test a simple isPangram() function as follows:

```use framework "Foundation" -- ( for case conversion function )

--------------------- PANGRAM CHECKER --------------------

-- isPangram :: String -> Bool
on isPangram(s)
script charUnUsed
property lowerCaseString : my toLower(s)
on |λ|(c)
lowerCaseString does not contain c
end |λ|
end script

0 = length of filter(charUnUsed, ¬
"abcdefghijklmnopqrstuvwxyz")
end isPangram

--------------------------- TEST -------------------------
on run
map(isPangram, {¬
"is this a pangram", ¬
"The quick brown fox jumps over the lazy dog"})

--> {false, true}
end run

-------------------- GENERIC FUNCTIONS -------------------

-- filter :: (a -> Bool) -> [a] -> [a]
on filter(f, xs)
tell mReturn(f)
set lst to {}
set lng to length of xs
repeat with i from 1 to lng
set v to item i of xs
if |λ|(v, i, xs) then set end of lst to v
end repeat
return lst
end tell
end filter

-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map

-- Lift 2nd class handler function into
-- 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn

-- toLower :: String -> String
on toLower(str)
set ca to current application
((ca's NSString's stringWithString:(str))'s ¬
lowercaseStringWithLocale:(ca's NSLocale's currentLocale())) as text
end toLower
```
Output:
```{false, true}
```

### Core language

Contrary to the impression given above, AppleScript is perfectly capable of handling this task very simply and without the need for imported libraries.

```on isPangram(txt)
set alphabet to "abcedfghijklmnopqrstuvwxyz"
ignoring case -- The default, but ensure it here.
repeat with letter in alphabet
if (txt does not contain letter) then return false
end repeat
end ignoring

return true
end isPangram

local result1, result2
set result1 to isPangram("The Quick Brown Fox Jumps Over The Lazy Dog")
set result2 to isPangram("This is not a pangram")
return {result1, result2}
```
Output:
```{true, false}
```

## Arturo

```chars: map 97..122 => [to :string to :char &]
pangram?: function [sentence][
every? chars 'ch ->
in? ch sentence
]

print pangram? "this is a sentence"
print pangram? "The quick brown fox jumps over the lazy dog."
```
Output:
```false
true```

## ATS

```(* ****** ****** *)
//
#include
#include
//
(* ****** ****** *)
//
fun
letter_check
(
cs: string, c0: char
) : bool = cs.exists()(lam(c) => c0 = c)
//
(* ****** ****** *)

fun
Pangram_check
(text: string): bool = let
//
val
alphabet = "abcdefghijklmnopqrstuvwxyz"
val
((*void*)) = assertloc(length(alphabet) = 26)
//
in
alphabet.forall()(lam(c) => letter_check(text, c) || letter_check(text, toupper(c)))
end // end of [Pangram_check]

(* ****** ****** *)

implement
main0 () =
{
//
val
text0 = "The quick brown fox jumps over the lazy dog."
//
val-true = Pangram_check(text0)
val-false = Pangram_check("This is not a pangram sentence.")
//
} (* end of [main0] *)

(* ****** ****** *)```

An alternate implementation that makes a single pass through the string:

```fn is_pangram{n:nat}(s: string(n)): bool = loop(s, i2sz(0)) where {
val letters: arrayref(bool, 26) = arrayref_make_elt<bool>(i2sz(26), false)
fn check(): bool = loop(0) where {
fun loop{i:int | i >= 0 && i <= 26}(i: int(i)) =
if i < 26 then
if letters[i] then loop(i+1) else
false
else true
}
fun add{c:int}(c: char(c)): void =
if (c >= 'A') * (c <= 'Z') then letters[char2int1(c) - char2int1('A')] := true else
if (c >= 'a') * (c <= 'z') then letters[char2int1(c) - char2int1('a')] := true
fun loop{i:nat | i <= n}.<n-i>.(s: string(n), i: size_t(i)): bool =
if string_is_atend(s, i) then check() else
begin
loop(s, succ(i))
end
}```

## AutoHotkey

```Gui, -MinimizeBox
Gui, Add, Edit, w300 r5 vText
Gui, Add, Button, x105 w100 Default, Check Pangram
Gui, Show,, Pangram Checker
Return

GuiClose:
ExitApp
Return

ButtonCheckPangram:
Gui, Submit, NoHide
Loop, 26
If Not InStr(Text, Char := Chr(64 + A_Index)) {
MsgBox,, Pangram, Character %Char% is missing!
Return
}
MsgBox,, Pangram, OK`, this is a Pangram!
Return
```

## AutoIt

```Pangram("The quick brown fox jumps over the lazy dog")
Func Pangram(\$s_String)
For \$i = 1 To 26
IF Not StringInStr(\$s_String, Chr(64 + \$i)) Then
Return MsgBox(0,"No Pangram", "Character " & Chr(64 + \$i) &" is missing")
EndIf
Next
Return MsgBox(0,"Pangram", "Sentence is a Pangram")
EndFunc
```

## AWK

### Solution using string-operations

```#!/usr/bin/awk -f
BEGIN {
allChars="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
print isPangram("The quick brown fox jumps over the lazy dog.");
print isPangram("The quick brown fo.");
}

function isPangram(string) {
delete X;
for (k=1; k<length(string); k++) {
X[toupper(substr(string,k,1))]++;  # histogram
}
for (k=1; k<=length(allChars); k++) {
if (!X[substr(allChars,k,1)]) return 0;
}
return 1;
}
```
Output:
```1
0```

### Solution using associative arrays and split

Works with: gawk version 4.1.0
Works with: mawk version 1.3.3
```# usage: awk -f pangram.awk -v p="The five boxing wizards dump quickly." input.txt
#
# Pangram-checker, using associative arrays and split
BEGIN {
alfa="ABCDEFGHIJKLMNOPQRSTUVWXYZ"; ac=split(alfa,A,"")
print "# Checking for all",ac,"chars in '" alfa "' :"

print testPangram("The quick brown fox jumps over the lazy dog.");
print testPangram(p);
}

{ print testPangram(\$0) }

function testPangram(str,   c,i,S,H,hit,miss) {
print str  						##
split( toupper(str), S, "")
for (c in S) {
H[ S[c] ]++
#print c, S[c], H[ S[c] ]				##
}
for (i=1; i<=ac; i++) {
c = A[i]
#printf("%2d %c : %4d\n", i, c, H[c] )  		##
if (H[c]) { hit=hit c } else { miss=miss c }
}
print "# hit:",hit, "# miss:",miss, "."		##
if (miss) return 0
return 1
}
```
Output:
```# Checking for all 26 chars in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' :
The quick brown fox jumps over the lazy dog.
# hit: ABCDEFGHIJKLMNOPQRSTUVWXYZ # miss:  .
1
The five boxing wizards dump quickly.
# hit: ABCDEFGHIKLMNOPQRSTUVWXYZ # miss: J .
0
Heavy boxes perform waltzes and jigs
# hit: ABDEFGHIJLMNOPRSTVWXYZ # miss: CKQU .
0
The quick onyx goblin jumps over the lazy dwarf.
# hit: ABCDEFGHIJKLMNOPQRSTUVWXYZ # miss:  .
1
Pack my box with five dozen liquor jugs
# hit: ABCDEFGHIJKLMNOPQRSTUVWXYZ # miss:  .
1
```

## BASIC

### Applesoft BASIC

``` 100  P\$ = "11111111111111111111111111"
110  FOR Q = 1 TO 3
130      GOSUB 200"IS PANGRAM?
140      PRINT  MID\$ ("NO  YES ",P * 4 + 1,4)S\$
150  NEXT Q
160  END
170  DATA"THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG."
180  DATA"THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG."
190  DATA"THE FIVE BOXING WIZARDS JUMP QUICKLY."
200  P = 0:L =  LEN (S\$): IF  NOT L THEN  RETURN
210  F\$ = "00000000000000000000000000"
220  FOR I = 1 TO L
230      C =  ASC ( MID\$ (S\$,I,1)):C = C - 32 * (C > 95): IF C > 64 AND C < 91 THEN J = C - 64:F\$ =  MID\$ (F\$,1,J - 1) + "1" +  MID\$ (F\$,J + 1):P = F\$ = P\$: IF P THEN  RETURN
240  NEXT I
250  RETURN
```
Output:
```YES THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.
NO  THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG.
YES THE FIVE BOXING WIZARDS JUMP QUICKLY.
```

### BaCon

This can be done in a one-liner.

```DEF FN Pangram(x) = IIF(AMOUNT(UNIQ\$(EXPLODE\$(EXTRACT\$(LCASE\$(x), "[^[:alpha:]]", TRUE), 1))) = 26, TRUE, FALSE)

PRINT Pangram("The quick brown fox jumps over the lazy dog.")
PRINT Pangram("Jackdaws love my big sphinx of quartz.")
PRINT Pangram("My dog has fleas.")
PRINT Pangram("What's a jackdaw?")
PRINT Pangram("The five boxing wizards jump quickly")```
Output:
```1
1
0
0
1
```

### BASIC256

```function isPangram\$(texto\$)
longitud = Length(texto\$)
if longitud < 26 then return "is not a pangram"
t\$ = lower(texto\$)
print "'"; texto\$; "' ";
for i = 97 to 122
if instr(t\$, chr(i)) = 0 then return "is not a pangram"
next i
return "is a pangram"
end function

print isPangram\$("The quick brown fox jumps over the lazy dog.")   # --> true
print isPangram\$("The quick brown fox jumped over the lazy dog.")  # --> false
print isPangram\$("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ")          # --> true
```

### BBC BASIC

```      FOR test% = 1 TO 2
PRINT """" test\$ """ " ;
IF FNpangram(test\$) THEN
PRINT "is a pangram"
ELSE
PRINT "is not a pangram"
ENDIF
NEXT test%
END

DATA "The quick brown fox jumped over the lazy dog"
DATA "The five boxing wizards jump quickly"

DEF FNpangram(A\$)
LOCAL C%
A\$ = FNlower(A\$)
FOR C% = ASC("a") TO ASC("z")
IF INSTR(A\$, CHR\$(C%)) = 0 THEN = FALSE
NEXT
= TRUE

DEF FNlower(A\$)
LOCAL A%, C%
FOR A% = 1 TO LEN(A\$)
C% = ASCMID\$(A\$,A%)
IF C% >= 65 IF C% <= 90 MID\$(A\$,A%,1) = CHR\$(C%+32)
NEXT
= A\$
```
Output:
```"The quick brown fox jumped over the lazy dog" is not a pangram
"The five boxing wizards jump quickly" is a pangram```

String manipulation is expensive, especially in loops, so it may be better to buffer the string and use character values:

```DEFFNisPangram(text\$)
LOCAL size%,text%,char%,bits%
size%=LENtext\$
IF size%<27 THEN =FALSE:REM too few characters
DIM text% LOCAL size%:REM BB4W and RISC OS 5 only
\$text%=text\$:REM buffer the string
FOR text%=text% TO text%+size%-1:REM each character
char%=?text% OR 32:REM to lower case
IF 96<char% AND char%<123 THEN bits%=bits% OR 1<<(char%-97):REM set ordinal bit
IF bits%=&3FFFFFF THEN =TRUE:REM all ordinal bits set
NEXT text%
=FALSE```

### Commodore BASIC

```10 rem detect model for title display
20 mx=peek(213): if mx=21 or mx=39 or mx=79 then 50:rem pet, vic, c64
30 mx=peek(238): if mx=39 or mx=79 then 50: rem c128
40 mx=39:color 4,1:rem assume plus/4 or c-16
50 if mx=21 then poke 36879,30:rem fix color on vic-20
60 print chr\$(147);chr\$(14);chr\$(18);"**";:for i=2 to (mx-15)/2:print " ";:next
70 print "Pangram Checker";
80 for i=(mx-15)/2+16 to mx-2: print " ";: next: print "**"
110 if len(s\$)=0 then end
120 gosub 1000:print
130 print "'"s\$"' is";
140 if p=0 then print " not";
150 print " a pangram."
160 goto 100
500 data "The quick brown fox jumps over the lazy dog."
510 data "The quick brown fox jumped over the lazy dog."
520 data "The five boxing wizards jump quickly."
530 data
900 rem pangram checker
1000 if f=0 then f=1:dim seen(25),a(2):a(0)=65:a(1)=97:a(2)=193:goto 1020
1010 for i=0 to 25:seen(i)=0:next
1020 for i=1 to len(s\$)
1030 : c=asc(mid\$(s\$,i))
1040 : for a = 0 to 2
1050 :   if c>=a(a) and c<=a(a)+25 then seen(c-a(a))=seen(c-a(a))+1
1060 : next a
1070 next i
1080 p=-1
1090 for i=0 to 25
1100 : if seen(i)=0 then p=0:i=25
1110 next i
1120 return
```
Output:
```**                               Pangram Checker                              **

'The quick brown fox jumps over the lazy dog.' is a pangram.

'The quick brown fox jumped over the lazy dog.' is not a pangram.

'The five boxing wizards jump quickly.' is a pangram.

### FreeBASIC

```' FB 1.05.0 Win64

Function isPangram(s As Const String) As Boolean
Dim As Integer length = Len(s)
If length < 26 Then Return False
Dim p As String = LCase(s)
For i As Integer = 97 To 122
If Instr(p, Chr(i)) = 0 Then Return False
Next
Return True
End Function

Dim s(1 To 3) As String = _
{ _
"The quick brown fox jumps over the lazy dog", _
"abbdefghijklmnopqrstuVwxYz", _ '' no c!
"How vexingly quick daft zebras jump!" _
}

For i As Integer = 1 To 3:
Print "'"; s(i); "' is "; IIf(isPangram(s(i)), "a", "not a"); " pangram"
Print
Next

Print
Print "Press nay key to quit"
Sleep
```
Output:
```'The quick brown fox jumps over the lazy dog' is a pangram

'abbdefghijklmnopqrstuVwxYz' is not a pangram

'How vexingly quick daft zebras jump!' is a pangram
```

### Liberty BASIC

```'Returns 0 if the string is NOT a pangram or >0 if it IS a pangram
string\$ = "The quick brown fox jumps over the lazy dog."

Print isPangram(string\$)

Function isPangram(string\$)
string\$ = Lower\$(string\$)
For i = Asc("a") To Asc("z")
isPangram = Instr(string\$, chr\$(i))
If isPangram = 0 Then Exit Function
Next i
End Function```

### PureBasic

```Procedure IsPangram_fast(String\$)
String\$ = LCase(string\$)
char_a=Asc("a")
; sets bits in a variable if a letter is found, reads string only once
For a = 1 To Len(string\$)
char\$ = Mid(String\$, a, 1)
pos   = Asc(char\$) - char_a
check.l |  1 << pos
Next
If check & \$3FFFFFF = \$3FFFFFF
ProcedureReturn 1
EndIf
ProcedureReturn 0
EndProcedure

Procedure IsPangram_simple(String\$)
String\$ = LCase(string\$)
found   = 1
For a = Asc("a") To Asc("z")
; searches for every letter in whole string
If FindString(String\$, Chr(a), 0) = 0
found = 0
EndIf
Next
ProcedureReturn found
EndProcedure

Debug IsPangram_fast("The quick brown fox jumps over lazy dogs.")
Debug IsPangram_simple("The quick brown fox jumps over lazy dogs.")
Debug IsPangram_fast("No pangram")
Debug IsPangram_simple("No pangram")
```

### QBasic

```DECLARE FUNCTION IsPangram! (sentence AS STRING)

DIM x AS STRING

x = "My dog has fleas."
GOSUB doIt
x = "The lazy dog jumps over the quick brown fox."
GOSUB doIt
x = "Jackdaws love my big sphinx of quartz."
GOSUB doIt
x = "What's a jackdaw?"
GOSUB doIt

END

doIt:
PRINT IsPangram!(x), x
RETURN

FUNCTION IsPangram! (sentence AS STRING)
'returns -1 (true) if sentence is a pangram, 0 (false) otherwise
DIM l AS INTEGER, s AS STRING, t AS INTEGER
DIM letters(25) AS INTEGER

FOR l = 1 TO LEN(sentence)
s = UCASE\$(MID\$(sentence, l, 1))
SELECT CASE s
CASE "A" TO "Z"
t = ASC(s) - 65
letters(t) = 1
END SELECT
NEXT

FOR l = 0 TO 25
IF letters(l) < 1 THEN
IsPangram! = 0
EXIT FUNCTION
END IF
NEXT

IsPangram! = -1
END FUNCTION
```
Output:
```  0            My dog has fleas.
-1            The quick brown fox jumps over the lazy dog.
-1            Jackdaws love my big sphinx of quartz.
0            What's a jackdaw?
```

### Run BASIC

```s\$ = "The quick brown fox jumps over the lazy dog."
Print pangram(s\$);" ";s\$

s\$ = "My dog has fleas."
Print pangram(s\$);" ";s\$

function pangram(str\$)
str\$  = lower\$(str\$)
for i = asc("a") to asc("z")
pangram = pangram + (instr(str\$, chr\$(i)) <> 0)
next i
pangram = (pangram = 26)
end function```
```1 The quick brown fox jumps over the lazy dog.
0 My dog has fleas.```

### Sinclair ZX81 BASIC

Works (just) with the 1k RAM model. The "37" that crops up a couple of times stops being a mystery if we remember that the ZX81 character code for `A` is 38 and that strings (like arrays) are indexed from 1, not from 0.

``` 10 LET A\$="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
20 LET L=26
30 INPUT P\$
40 IF LEN P\$<26 THEN GOTO 170
50 FAST
60 LET C=1
70 IF P\$(C)<"A" OR P\$(C)>"Z" THEN GOTO 120
80 IF A\$(CODE P\$(C)-37)=" " THEN GOTO 120
90 LET A\$(CODE P\$(C)-37)=" "
100 LET L=L-1
110 IF L=0 THEN GOTO 150
120 IF C=LEN P\$ THEN GOTO 170
130 LET C=C+1
140 GOTO 70
150 PRINT "PANGRAM"
160 GOTO 180
170 PRINT "NOT A PANGRAM"
180 SLOW
```
Input:
`THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.`
Output:
`PANGRAM`
Input:
`AND DARK THE SUN AND MOON, AND THE ALMANACH DE GOTHA`
Output:
`NOT A PANGRAM`

### Yabasic

```sub isPangram\$(t\$, l1\$)
local lt, ll, r\$, i, cc, ic

if numparams = 1 then
l1\$ = "abcdefghijklmnopqrstuvwxyz"
end if

t\$ = lower\$(t\$)
ll = len(l1\$)
for i = 1 to ll
r\$ = r\$ + " "
next
lt = len(t\$)
cc = asc("a")

for i = 1 to lt
ic = asc(mid\$(t\$, i, 1)) - cc + 1
if ic > 0 and ic <= ll then
mid\$(r\$, ic, 1) = chr\$(ic + cc - 1)
end if
next i

if l1\$ = r\$ then return "true" else return "false" end if

end sub

print isPangram\$("The quick brown fox jumps over the lazy dog.")   // --> true
print isPangram\$("The quick brown fox jumped over the lazy dog.")  // --> false
print isPangram\$("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ")          // --> true```

## Batch File

```@echo off
setlocal enabledelayedexpansion

%===The Main Thing===%
call :pangram "The quick brown fox jumps over the lazy dog."
call :pangram "The quick brown fox jumped over the lazy dog."
echo.
pause
exit /b 0

%===The Function===%
:pangram
set letters=abcdefgihjklmnopqrstuvwxyz
set cnt=0
set inp=%~1
set str=!inp: =!

:loop
set chr=!str:~%cnt%,1!
if "!letters!"=="" (
echo %1 is a pangram^^!
goto :EOF
)
if "!chr!"=="" (
echo %1 is not a pangram.
goto :EOF
)
set letters=!letters:%chr%=!
set /a cnt+=1
goto loop
```
Output:
```"The quick brown fox jumps over the lazy dog." is a pangram!
"The quick brown fox jumped over the lazy dog." is not a pangram.

Press any key to continue . . .```

## BCPL

```get "libhdr"

// Test if s is a pangram. The ASCII character set is assumed.
let pangram(s) = valof
\$(  let letters = vec 25
for i=0 to 25 do letters!i := false
for i=1 to s%0 do
\$(  let c = (s%i | 32) - 'a'
if c >= 0 & c < 26 then
letters!c := true
\$)
for i=0 to 25 unless letters!i resultis false
resultis true
\$)

// Display s and whether or not it is a pangram.
let check(s) be
\$(  writes(s)
writes(" -> ")
test pangram(s)
then writes("yes*N")
else writes("no*N")
\$)

let start() be
\$(  check("The quick brown fox jumps over the lazy dog.")
check("The five boxing wizards dump quickly.")
\$)```
Output:
```The quick brown fox jumps over the lazy dog. -> yes
The five boxing wizards dump quickly. -> no```

## Befunge

Reads the sentence to test from stdin.

```>~>:65*`!#v_:"`"`48*v>g+04p1\4p
^#*`\*93\`0<::-"@"-*<^40!%2g4:_
"pangram."<v*84<_v#-":"g40\" a"
>>:#,_55+,@>"ton">48*>"si tahT"
```
Input:
`The quick brown fox jumps over the lazy dog.`
Output:
`That is a pangram.`

## Bracmat

```(isPangram=
k
.   low\$!arg:?arg
& a:?k
&   whl
' ( @(!arg:? !k ?)
& chr\$(1+asc\$!k):?k:~>z
)
& !k:>z
&
);```

Some examples:

```isPangram\$("the Quick brown FOX jumps over the lazy do")
no
isPangram\$("the Quick brown FOX jumps over the lazy dog")
yes
isPangram\$"My dog has fleas."
no
isPangram\$"The quick brown fox jumps over the lazy dog."
yes
isPangram\$"Jackdaws love my big sphinx of quartz."
yes
isPangram\$"What's a jackdaw?"
no
isPangram\$"Lynx c.q. vos prikt bh: dag zwemjuf!"
yes```

## Brat

```pangram? = { sentence |
letters = [:a :b :c :d :e :f :g :h :i :j :k :l :m
:n :o :p :q :r :s :t :u :v :w :x :y :z]

sentence.downcase!

letters.reject! { l |
sentence.include? l
}

letters.empty?
}

p pangram? 'The quick brown fox jumps over the lazy dog.' #Prints true
p pangram? 'Probably not a pangram.'  #Prints false```

Alternative version:

```pangram? = { sentence |
sentence.downcase.dice.unique.select(:alpha?).length == 26
}```

## C

```#include <stdio.h>

int is_pangram(const char *s)
{
const char *alpha = ""
"abcdefghjiklmnopqrstuvwxyz"
"ABCDEFGHIJKLMNOPQRSTUVWXYZ";

char ch, wasused[26] = {0};
int total = 0;

while ((ch = *s++) != '\0') {
const char *p;
int idx;

if ((p = strchr(alpha, ch)) == NULL)
continue;

idx = (p - alpha) % 26;

total += !wasused[idx];
wasused[idx] = 1;
if (total == 26)
return 1;
}
return 0;
}

int main(void)
{
int i;
const char *tests[] = {
"The quick brown fox jumps over the lazy dog.",
"The qu1ck brown fox jumps over the lazy d0g."
};

for (i = 0; i < 2; i++)
printf("\"%s\" is %sa pangram\n",
tests[i], is_pangram(tests[i])?"":"not ");
return 0;
}
```

Assumes an execution environment using the ASCII character set (will invoke undefined behavior on other systems).

```#include <stdio.h>

int pangram(const char *s)
{
int c, mask = (1 << 26) - 1;
while ((c = (*s++)) != '\0') /* 0x20 converts lowercase to upper */
if ((c &= ~0x20) <= 'Z' && c >= 'A')
mask &= ~(1 << (c - 'A'));

}

int main()
{
int i;
const char *s[] = {	"The quick brown fox jumps over lazy dogs.",
"The five boxing wizards dump quickly.",  };

for (i = 0; i < 2; i++)
printf("%s: %s\n", pangram(s[i]) ? "yes" : "no ", s[i]);

return 0;
}
```
Output:
```yes: The quick brown fox jumps over lazy dogs.
no : The five boxing wizards dump quickly.```

## C#

C# 3.0 or higher (.NET Framework 3.5 or higher)

```using System;
using System.Linq;

static class Program
{
static bool IsPangram(this string text, string alphabet = "abcdefghijklmnopqrstuvwxyz")
{
return alphabet.All(text.ToLower().Contains);
}

static void Main(string[] arguments)
{
Console.WriteLine(arguments.Any() && arguments.First().IsPangram());
}
}
```

Any version of C# language and .NET Framework

```using System;

namespace PangrammChecker
{
public class PangrammChecker
{
public static bool IsPangram(string str)
{
bool[] isUsed = new bool[26];
int ai = (int)'a';
int total = 0;
for (CharEnumerator en = str.ToLower().GetEnumerator(); en.MoveNext(); )
{
int d = (int)en.Current - ai;
if (d >= 0 && d < 26)
if (!isUsed[d])
{
isUsed[d] = true;
total++;
}
}
return (total == 26);
}
}

class Program
{
static void Main(string[] args)
{
string str1 = "The quick brown fox jumps over the lazy dog.";
string str2 = "The qu1ck brown fox jumps over the lazy d0g.";
Console.WriteLine("{0} is {1}a pangram", str1,
PangrammChecker.IsPangram(str1)?"":"not ");
Console.WriteLine("{0} is {1}a pangram", str2,
PangrammChecker.IsPangram(str2)?"":"not ");
}
}
}
```

## C++

```#include <algorithm>
#include <cctype>
#include <string>
#include <iostream>

const std::string alphabet("abcdefghijklmnopqrstuvwxyz");

bool is_pangram(std::string s)
{
std::transform(s.begin(), s.end(), s.begin(), ::tolower);
std::sort(s.begin(), s.end());
return std::includes(s.begin(), s.end(), alphabet.begin(), alphabet.end());
}

int main()
{
const auto examples = {"The quick brown fox jumps over the lazy dog",
"The quick white cat jumps over the lazy dog"};

std::cout.setf(std::ios::boolalpha);
for (auto& text : examples) {
std::cout << "Is \"" << text << "\" a pangram? - " << is_pangram(text) << std::endl;
}
}
```

## Ceylon

```shared void run() {

function pangram(String sentence) =>
let(alphabet = set('a'..'z'),
letters = set(sentence.lowercased.filter(alphabet.contains)))
letters == alphabet;

value sentences = [
"The quick brown fox jumps over the lazy dog",
"""Watch "Jeopardy!", Alex Trebek's fun TV quiz game.""",
"Pack my box with five dozen liquor jugs.",
"blah blah blah"
];
for(sentence in sentences) {
print("\"``sentence``\" is a pangram? ``pangram(sentence)``");
}
}
```

## Clojure

```(defn pangram? [s]
(let [letters (into #{} "abcdefghijklmnopqrstuvwxyz")]
(= (->> s .toLowerCase (filter letters) (into #{})) letters)))
```

## CLU

```pangram = proc (s: string) returns (bool)
letters: array[bool] := array[bool]\$fill(0,26,false)
for c: char in string\$chars(s) do
if c>='a' & c<='z' then
c := char\$i2c(char\$c2i(c) - 32)
end
if c>='A' & c<='Z' then
letters[char\$c2i(c) - 65] := true
end
end
for seen: bool in array[bool]\$elements(letters) do
if ~seen then return(false) end
end
return(true)
end pangram

start_up = proc ()
po: stream := stream\$primary_output()
examples: array[string] := array[string]\$[
"The quick brown fox jumps over the lazy dog.",
"The five boxing wizards dump quickly.",
"abcdefghijklmnopqrstuvwxyz"
]

for example: string in array[string]\$elements(examples) do
stream\$puts(po, "\"" || example || "\" is")
if ~pangram(example) then
stream\$puts(po, " not")
end
stream\$putl(po, " a pangram.")
end
end start_up```
Output:
```"The quick brown fox jumps over the lazy dog." is a pangram.
"The five boxing wizards dump quickly." is not a pangram.
"abcdefghijklmnopqrstuvwxyz" is a pangram.```

## COBOL

```       identification division.
program-id. pan-test.
data division.
working-storage section.
1 text-string pic x(80).
1 len binary pic 9(4).
1 trailing-spaces binary pic 9(4).
1 pangram-flag pic x value "n".
88 is-not-pangram value "n".
88 is-pangram value "y".
procedure division.
begin.
display "Enter text string:"
accept text-string
set is-not-pangram to true
initialize trailing-spaces len
inspect function reverse (text-string)
tallying trailing-spaces for leading space
len for characters after space
call "pangram" using pangram-flag len text-string
cancel "pangram"
if is-pangram
display "is a pangram"
else
display "is not a pangram"
end-if
stop run
.
end program pan-test.

identification division.
program-id. pangram.
data division.
1 lc-alphabet pic x(26) value "abcdefghijklmnopqrstuvwxyz".
1 pangram-flag pic x.
88 is-not-pangram value "n".
88 is-pangram value "y".
1 len binary pic 9(4).
1 text-string pic x(80).
procedure division using pangram-flag len text-string.
begin.
inspect lc-alphabet converting
function lower-case (text-string (1:len))
to space
if lc-alphabet = space
set is-pangram to true
end-if
exit program
.
end program pangram.
```

## CoffeeScript

```is_pangram = (s) ->
# This is optimized for longish strings--as soon as all 26 letters
# are encountered, we will be done.  Our worst case scenario is a really
# long non-pangram, or a really long pangram with at least one letter
# only appearing toward the end of the string.
a_code = 'a'.charCodeAt(0)
required_letters = {}
for i in [a_code...a_code+26]
required_letters[String.fromCharCode(i)] = true

cnt = 0
for c in s
c = c.toLowerCase()
if required_letters[c]
cnt += 1
return true if cnt == 26
delete required_letters[c]
false

do ->
tests = [
["is this a pangram", false]
["The quick brown fox jumps over the lazy dog", true]
]

for test in tests
[s, exp_value] = test
throw Error("fail") if is_pangram(s) != exp_value
# try long strings
long_str = ''
for i in [1..500000]
long_str += s
throw Error("fail") if is_pangram(long_str) != exp_value
console.log "Passed tests: #{s}"
```

## Comal

```0010 FUNC pangram#(s\$) CLOSED
0020   FOR i#:=ORD("A") TO ORD("Z") DO
0030     IF NOT (CHR\$(i#) IN s\$ OR CHR\$(i#+32) IN s\$) THEN RETURN FALSE
0040   ENDFOR i#
0050   RETURN TRUE
0060 ENDFUNC
0070 //
0080 WHILE NOT EOD DO
0100   PRINT "'",s\$,"' is ",
0110   IF NOT pangram#(s\$) THEN PRINT "not ",
0120   PRINT "a pangram"
0130 ENDWHILE
0140 END
0150 DATA "The quick brown fox jumps over the lazy dog."
0160 DATA "The five boxing wizards dump quickly."```
Output:
```'The quick brown fox jumps over the lazy dog.' is a pangram
'The five boxing wizards dump quickly.' is not a pangram```

## Common Lisp

```(defun pangramp (s)
(null (set-difference
(loop for c from (char-code #\A) upto (char-code #\Z) collect (code-char c))
(coerce (string-upcase s) 'list))))
```

## Component Pascal

BlackBox Component Builder

```MODULE BbtPangramChecker;
IMPORT StdLog,DevCommanders,TextMappers;

PROCEDURE Check(str: ARRAY OF CHAR): BOOLEAN;
CONST
letters = 26;
VAR
i,j: INTEGER;
status: ARRAY letters OF BOOLEAN;
resp : BOOLEAN;
BEGIN
FOR i := 0 TO LEN(status) -1 DO status[i] := FALSE END;

FOR i := 0 TO LEN(str) -  1 DO
j := ORD(CAP(str[i])) - ORD('A');
IF (0 <= j) & (25 >= j) & ~status[j] THEN status[j] := TRUE END
END;

resp := TRUE;
FOR i := 0 TO LEN(status) - 1 DO;
resp := resp & status[i]
END;
RETURN resp;
END Check;

PROCEDURE Do*;
VAR
params: DevCommanders.Par;
s: TextMappers.Scanner;
BEGIN
params := DevCommanders.par;
s.ConnectTo(params.text);
s.SetPos(params.beg);
s.Scan;
WHILE (~s.rider.eot) DO
IF (s.type = TextMappers.char) & (s.char = '~') THEN
RETURN
ELSIF (s.type # TextMappers.string) THEN
StdLog.String("Invalid parameter");StdLog.Ln
ELSE
StdLog.Char("'");StdLog.String(s.string + "' is pangram?:> ");
StdLog.Bool(Check(s.string));StdLog.Ln
END;
s.Scan
END
END Do;

END BbtPangramChecker.
```

Execute: ^Q BbtPangramChecker.Do "The quick brown fox jumps over the lazy dog"~
^Q BbtPangramChecker.Do "abcdefghijklmnopqrstuvwxyz"~
^Q BbtPangramChecker.Do "A simple text"~

Output:
```'The quick brown fox jumps over the lazy dog' is pangram?:>  \$TRUE
'abcdefghijklmnopqrstuvwxyz' is pangram?:>  \$TRUE
'A simple text' is pangram?:>  \$FALSE
```

## Cowgol

```include "cowgol.coh";

sub pangram(str: [uint8]): (r: uint8) is
var letters: uint8[26];
MemZero(&letters[0], 26);

loop
var chr := [str];
if chr == 0 then break; end if;
str := @next str;
chr := (chr | 32) - 'a';
if chr >= 26 then continue; end if;
letters[chr] := letters[chr] | 1;
end loop;

r := 1;
chr := 0;
while chr < 26 loop
r := r & letters[chr];
if r == 0 then break; end if;
chr := chr + 1;
end loop;
end sub;

var yesno: [uint8][] := {": no\n", ": yes\n"};
var test: [uint8][] := {
"The quick brown fox jumps over the lazy dog.",
"The five boxing wizards dump quickly."
};

var i: @indexof test := 0;
while i < @sizeof test loop
print(test[i]);
print(yesno[pangram(test[i])]);
i := i + 1;
end loop;```
Output:
```The quick brown fox jumps over the lazy dog.: yes
The five boxing wizards dump quickly.: no```

## Crystal

Copied and modified from the Ruby version.

```def pangram?(sentence)
('a'..'z').all? {|c| sentence.downcase.includes?(c) }
end

p pangram?("not a pangram")
p pangram?("The quick brown fox jumps over the lazy dog.")
```
```false
true
```

## D

### ASCII Bitmask version

```bool isPangram(in string text) pure nothrow @safe @nogc {
uint bitset;

foreach (immutable c; text) {
if (c >= 'a' && c <= 'z')
bitset |= (1u << (c - 'a'));
else if (c >= 'A' && c <= 'Z')
bitset |= (1u << (c - 'A'));
}

return bitset == 0b11_11111111_11111111_11111111;
}

void main() {
assert("the quick brown fox jumps over the lazy dog".isPangram);
assert(!"ABCDEFGHIJKLMNOPQSTUVWXYZ".isPangram);
assert(!"ABCDEFGHIJKL.NOPQRSTUVWXYZ".isPangram);
assert("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ".isPangram);
}
```

### Unicode version

```import std.string, std.traits, std.uni;

// Do not compile with -g (debug info).
enum Alphabet : dstring {
DE = "abcdefghijklmnopqrstuvwxyzßäöü",
EN = "abcdefghijklmnopqrstuvwxyz",
SV = "abcdefghijklmnopqrstuvwxyzåäö"
}

bool isPangram(S)(in S s, dstring alpha = Alphabet.EN)
pure /*nothrow*/ if (isSomeString!S) {
foreach (dchar c; alpha)
if (indexOf(s, c) == -1 && indexOf(s, std.uni.toUpper(c)) == -1)
return false;
return true;
}

void main() {
assert(isPangram("the quick brown fox jumps over the lazy dog".dup, Alphabet.EN));
assert(isPangram("Falsches Üben von Xylophonmusik quält jeden größeren Zwerg"d, Alphabet.DE));
assert(isPangram("Yxskaftbud, ge vår wczonmö iqhjälp"w, Alphabet.SV));
}
```

## Delphi

```program PangramChecker;

{\$APPTYPE CONSOLE}

uses StrUtils;

function IsPangram(const aString: string): Boolean;
var
c: char;
begin
for c := 'a' to 'z' do
if not ContainsText(aString, c) then
Exit(False);

Result := True;
end;

begin
Writeln(IsPangram('The quick brown fox jumps over the lazy dog')); // true
Writeln(IsPangram('Not a panagram')); // false
end.
```

## Draco

```proc nonrec pangram(*char s) bool:
ulong letters;
char c;
byte b;
byte A = pretend('a', byte);
byte Z = pretend('z', byte);

letters := 0L0;
while
c := s*;
s := s + 1;
c /= '\e'
do
b := pretend(c, byte) | 32;
if b >= A and b <= Z then
letters := letters | 0L1 << (b-A)
fi
od;
letters = 0x3FFFFFF
corp

proc nonrec test(*char s) void:
writeln("\"", s, "\": ",
if pangram(s) then "yes" else "no" fi)
corp

proc nonrec main() void:
test("The quick brown fox jumps over the lazy dog.");
test("The five boxing wizards jump quickly.");
test("Not a pangram")
corp```
Output:
```"The quick brown fox jumps over the lazy dog.": yes
"The five boxing wizards jump quickly.": yes
"Not a pangram": no```

## E

```def isPangram(sentence :String) {
return ("abcdefghijklmnopqrstuvwxyz".asSet() &! sentence.toLowerCase().asSet()).size() == 0
}```

`&!` is the “but-not” or set difference operator.

## EDSAC order code

The program includes a test string (at the end). If the program is running in the EdsacPC simulator, the user can enter another string by storing it in a text file, making that file the active file, and clicking Reset. The string must be terminated by a blank row of tape (represented by '.' in EdsacPC).

``` [Pangram checker for Rosetta Code.
EDSAC program, Initial Orders 2.]

[Outline: Make a table, one entry per 5-bit character code.
Initialize entry for each letter to 1.
When a letter is read, convert its entry to 0.]

[Subroutine to read string from the input and
store it with character codes in low 5 bits.
String is terminated by blank row of tape, which is stored.
Input: 0F holds address of string in address field (bits 1..11).
21 locations; workspace: 4F]
T   56 K
GKA3FT17@AFA18@T7@I4FA4FUFS19@G12@S20@G16@T4FA7@A2FE4@T4FEFUFP8FPD

[*************** Rosetta Code task ***************
Subroutine to test whether string is a pangram.
Input:  0F = address of string, characters in low 5 bits,
terminated by blank row of tape.
Output: 1F = (number of missing letters) - 1.
87 memory locations; workspace 4F.]
T   88 K
G      K
A    3 F  [make and plant link for return]
T   48 @
[Fill letter table with 1's.
The code is a bit neater if we work backwards.]
A   54 @  [index of last entry]
[3]   A   51 @  [make T order for table entry]
T    6 @  [plant in code]
A   53 @  [acc := 1]
[6]   T      F  [table entry := 1]
A    6 @  [dec address in table]
S    2 F
S   51 @  [finished table?]
E    3 @  [loop back if not]
[Set non-letters to 0, except blank row := -1]
T    4 F  [clear acc]
T   66 @  [figures shift]
T   70 @  [letters shift]
T   73 @  [carriage return]
T   75 @  [space]
T   79 @  [line feed]
S   53 @  [acc := -1]
T   71 @  [blank row of tape]
[Loop to read characters from string.
Terminated by blank row of tape.
Assume acc = 0 here.]
A   49 @  [make order to read first char]
[21]   T   22 @  [plant in code]
[22]   A      F  [char to acc]
L      D  [shift to address field]
A   50 @  [make A order for this char in table]
U   28 @  [plant in code]
A   52 @  [convert to T order]
T   31 @  [plant in code]
[28]   A      F  [load table entry]
G   35 @  [jump out if it's -1, i.e. blank row]
T    4 F  [clear acc]
[31]   T      F  [table entry := 0 to flag that letter is present]
A   22 @  [inc address in input string]
A    2 F
G   21 @  [back to read next char]
[Get total of table entries, again working backwards.
The number of missing letters is (total + 1).]
[35]   T    4 F  [clear acc]
T    1 F  [initialize total := 0]
A   54 @  [index of last entry]
[38]   A   50 @  [make A order for table entry]
T   41 @  [plant in code]
A    1 F  [load total so far]
[41]   A      F  [add table entry]
T    1 F  [update total]
A   41 @  [load A order]
S    2 F  [dec address]
S   50 @  [finished table?]
E   38 @  [loop back if not]
T    4 F  [clear acc before exit]
[48]   E      F
[Constants]
[49]   A      F  [to make A order referring to input]
[50]   A   55 @  [to make A order referring to table]
[51]   T   55 @  [to make T order referring to table]
[52]   O      F  [add to A order to convert to T order]
[53]   P      D  [constant 1]
[54]   P   31 F  [to change address by 31]
[Table]
[55]   PFPFPFPFPFPFPFPFPFPFPF
[66]   PFPFPFPF               [11 = figures shift]
[70]   PF                     [15 = letters shift]
[71]   PFPF                   [16 = blank row of tape]
[73]   PFPF                   [18 = carriage return]
[75]   PFPFPFPF               [20 = space]
[79]   PFPFPFPFPFPFPFPF       [24 = line feed]

[Main routine to demonstrate pangram-checking subroutine]
T  200 K
G      K
[Constants]
[0]   P   25 @  [address for input string]
[1]   N      F  [letter N]
[2]   Y      F  [letter Y]
[3]   K 2048 F  [letter shift]
[4]   @      F  [carriage return]
[5]   &      F  [line feed]
[6]   K 4096 F  [null char]
[Enter with acc = 0]
[7]   O    3 @  [set letters shift]
[8]   A      @  [load address of input]
T      F  [pass to input subroutine in 0F]
[10]   A   10 @  [call input subroutine, doesn't change 0F]
G   56 F
[12]   A   12 @  [call pangram subroutine]
G   88 F
[We could print the number of missing letters,
but we'll just print 'Y' or 'N'.]
A    1 F  [load (number missing) - 1]
E   18 @  [jump if not pangram]
O    2 @  [print 'Y']
G   19 @  [exit]
[18]   O    1 @  [print 'N']
[19]   O    4 @  [print CR, LF]
O    5 @
O    6 @  [print null to flush printer buffer]
Z      F  [stop]
T      F  [on Reset, clear acc]
E    8 @  [and test another string]
[25]             [input string goes here]
E    7 Z  [define entry point]
P      F  [acc = 0 on entry]
THE!QUICK!BROWN!FOX!JUMPS!OVER!THE!LAZY!DOG.```
Output:
```Y
```

## Elixir

```defmodule Pangram do
def checker(str) do
unused = Enum.to_list(?a..?z) -- to_char_list(String.downcase(str))
Enum.empty?(unused)
end
end

text = "The quick brown fox jumps over the lazy dog."
IO.puts "#{Pangram.checker(text)}\t#{text}"
text = (Enum.to_list(?A..?Z) -- 'Test') |> to_string
IO.puts "#{Pangram.checker(text)}\t#{text}"
```
Output:
```true    The quick brown fox jumps over the lazy dog.
false   ABCDEFGHIJKLMNOPQRSUVWXYZ
```

## Erlang

```-module(pangram).
-export([is_pangram/1]).

is_pangram(String) ->
ordsets:is_subset(lists:seq(\$a, \$z), ordsets:from_list(string:to_lower(String))).
```

## Excel

### LAMBDA

With the following lambda bound to the name ISPANGRAM in the Excel Workbook Name Manager:

```ISPANGRAM
=LAMBDA(s,
LET(
abc, CHARS(LOWER("abcdefghijklmnopqrstuvwxyz")),
AND(
LAMBDA(c,
ISNUMBER(SEARCH(c, s, 1))
)(
abc
)
)
)
)
```

And assuming that the name CHARS is also bound in the Name Manager

to the generic (String -> Array Char) lambda:

```CHARS
=LAMBDA(s,
MID(s, ROW(INDIRECT("1:" & LEN(s))), 1)
)
```
Output:
 =ISPANGRAM(A2) fx A B 1 Test strings Verdicts 2 The quick brown fox jumps over the lazy dog TRUE 3 Is this a pangram FALSE 4 How vexingly quick daft zebras jump! TRUE 5 The five boxing wizards jumped quickly. TRUE

## F#

If the difference between the set of letters in the alphabet and the set of letters in the given string (after conversion to lower case) is the empty set then every letter appears somewhere in the given string:

```let isPangram (str: string) = (set['a'..'z'] - set(str.ToLower())).IsEmpty
```

## Factor

Translation of: E
```: pangram? ( str -- ? )
[ "abcdefghijklmnopqrstuvwxyz" ] dip >lower diff length 0 = ;

"How razorback-jumping frogs can level six piqued gymnasts!" pangram? .
```

## Forth

```: pangram? ( addr len -- ? )
0 -rot bounds do
i c@ 32 or [char] a -
dup 0 26 within if
1 swap lshift or
else drop then
loop
1 26 lshift 1- = ;

s" The five boxing wizards jump quickly." pangram? .   \ -1
```

## Fortran

Works with: Fortran version 90 and later
```module pangram

implicit none
private
public :: is_pangram
character (*), parameter :: lower_case = 'abcdefghijklmnopqrstuvwxyz'
character (*), parameter :: upper_case = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'

contains

function to_lower_case (input) result (output)

implicit none
character (*), intent (in) :: input
character (len (input)) :: output
integer :: i
integer :: j

output = input
do i = 1, len (output)
j = index (upper_case, output (i : i))
if (j /= 0) then
output (i : i) = lower_case (j : j)
end if
end do

end function to_lower_case

function is_pangram (input) result (output)

implicit none
character (*), intent (in) :: input
character (len (input)) :: lower_case_input
logical :: output
integer :: i

lower_case_input = to_lower_case (input)
output = .true.
do i = 1, len (lower_case)
if (index (lower_case_input, lower_case (i : i)) == 0) then
output = .false.
exit
end if
end do

end function is_pangram

end module pangram
```

Example:

```program test

use pangram, only: is_pangram

implicit none
character (256) :: string

string = 'This is a sentence.'
write (*, '(a)') trim (string)
write (*, '(l1)') is_pangram (string)
string = 'The five boxing wizards jumped quickly.'
write (*, '(a)') trim (string)
write (*, '(l1)') is_pangram (string)

end program test
```
Output:
```This is a sentence.
F
The five boxing wizards jumped quickly.
T```

## Frink

```s = "The quick brown fox jumps over the lazy dog."
println["\"\$s\" is" + (isPangram[s] ? "" : " not") + " a pangram."]

isPangram[s] :=
{
charSet = toSet[charList[lc[s]]]
for c = "a" to "z"
if ! charSet.contains[c]
return false

return true
}```
Output:
```"The quick brown fox jumps over the lazy dog." is a pangram.
```

## FutureBasic

```include "NSLog.incl"

local fn IsPangram( pangramString as CFStringRef ) as BOOL
NSUInteger  i, count
BOOL        result

CFStringRef   lcPanStr = fn StringLowerCaseString( pangramString )
CFMutableSetRef mutSet = fn MutableSetWithCapacity( 0 )

count = len(lcPanStr)
for i = 0 to count - 1
if ( fn CharacterSetCharacterIsMember( fn CharacterSetLowercaseLetterSet, fn StringCharacterAtIndex( lcPanStr, i ) ) )
MutableSetAddObject( mutSet, fn StringWithFormat( @"%c", fn StringCharacterAtIndex( lcPanStr, i ) ) )
end if
next
if fn SetCount( mutSet ) >= 26 then result = YES else result = NO
end fn = result

CFStringRef testStr, trueStr, falseStr
CFArrayRef  array

trueStr  = @"Is a pangram"
falseStr = @"Not a pangram"

array = @[¬
@"My dog has fleas.",¬
@"The quick brown fox jumps over the lazy do.",¬
@"The quick brown fox jumped over the lazy dog.",¬
@"The quick brown fox jumps over the lazy dog.",¬
@"Jackdaws love my big sphinx of quartz.",¬
@"What's a jackdaw?",¬
@"Watch \"Jeopardy!\", Alex Trebek's fun TV quiz game.",¬
@"Pack my box with five dozen liquor jugs.",¬
@"This definitely is not a pangram.",¬
@"This is a random long sentence just for testing purposes."]

for testStr in array
if ( fn IsPangram( testStr ) )
NSLog( @"%13s : %@", fn StringUTF8String( trueStr ), testStr ) else NSLog( @"%s : %@", fn StringUTF8String( falseStr ), testStr )
end if
next

HandleEvents```
Output:
```Not a pangram : My dog has fleas.
Not a pangram : The quick brown fox jumps over the lazy do.
Not a pangram : The quick brown fox jumped over the lazy dog.
Is a pangram : The quick brown fox jumps over the lazy dog.
Is a pangram : Jackdaws love my big sphinx of quartz.
Not a pangram : What's a jackdaw?
Is a pangram : Watch "Jeopardy!", Alex Trebek's fun TV quiz game.
Is a pangram : Pack my box with five dozen liquor jugs.
Not a pangram : This definitely is not a pangram.
Not a pangram : This is a random long sentence just for testing purposes.
```

## Fōrmulæ

Fōrmulæ programs are not textual, visualization/edition of programs is done showing/manipulating structures but not text. Moreover, there can be multiple visual representations of the same program. Even though it is possible to have textual representation —i.e. XML, JSON— they are intended for storage and transfer purposes more than visualization and edition.

Programs in Fōrmulæ are created/edited online in its website, However they run on execution servers. By default remote servers are used, but they are limited in memory and processing power, since they are intended for demonstration and casual use. A local server can be downloaded and installed, it has no limitations (it runs in your own computer). Because of that, example programs can be fully visualized and edited, but some of them will not run if they require a moderate or heavy computation/memory resources, and no local server is being used.

In this page you can see the program(s) related to this task and their results.

## Go

```package main

import "fmt"

func main() {
for _, s := range []string{
"The quick brown fox jumps over the lazy dog.",
`Watch "Jeopardy!", Alex Trebek's fun TV quiz game.`,
"Not a pangram.",
} {
if pangram(s) {
fmt.Println("Yes:", s)
} else {
fmt.Println("No: ", s)
}
}
}

func pangram(s string) bool {
var missing uint32 = (1 << 26) - 1
for _, c := range s {
var index uint32
if 'a' <= c && c <= 'z' {
index = uint32(c - 'a')
} else if 'A' <= c && c <= 'Z' {
index = uint32(c - 'A')
} else {
continue
}

missing &^= 1 << index
if missing == 0 {
return true
}
}
return false
}
```
Output:
```Yes: The quick brown fox jumps over the lazy dog.
Yes: Watch "Jeopardy!", Alex Trebek's fun TV quiz game.
No:  Not a pangram.
```

```import Data.Char (toLower)
import Data.List ((\\))

pangram :: String -> Bool
pangram = null . (['a' .. 'z'] \\) . map toLower

main = print \$ pangram "How razorback-jumping frogs can level six piqued gymnasts!"
```

## HicEst

```PangramBrokenAt("This is a Pangram.") ! => 2 (b is missing)
PangramBrokenAt("The quick Brown Fox jumps over the Lazy Dog") ! => 0 (OK)

FUNCTION PangramBrokenAt(string)
CHARACTER string, Alfabet="abcdefghijklmnopqrstuvwxyz"
PangramBrokenAt = INDEX(Alfabet, string, 64)
! option 64: verify = 1st letter of string not in Alfabet
END```

## Icon and Unicon

A panagram procedure:

```procedure panagram(s)     #: return s if s is a panagram and fail otherwise
if (map(s) ** &lcase) === &lcase then return s
end
```

And a main to drive it:

```procedure main(arglist)

if *arglist > 0 then
every ( s := "" ) ||:= !arglist || " "
else
s := "The quick brown fox jumps over the lazy dog."

writes(image(s), " -- is")
writes(if not panagram(s) then "n't")
write(" a panagram.")
end
```

## Io

```Sequence isPangram := method(
letters := " " repeated(26)
ia := "a" at(0)
foreach(ichar,
if(ichar isLetter,
letters atPut((ichar asLowercase) - ia, ichar)
)
)
letters contains(" " at(0)) not     // true only if no " " in letters
)

"The quick brown fox jumps over the lazy dog." isPangram println    // --> true
"The quick brown fox jumped over the lazy dog." isPangram println   // --> false
"ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ" isPangram println           // --> true
```

## Ioke

```Text isPangram? = method(
letters = "abcdefghijklmnopqrstuvwxyz" chars
text = self lower chars
letters map(x, text include?(x)) reduce(&&)
)
```

Here is an example of it's use in the Ioke REPL:

```iik> "The quick brown fox jumps over the lazy dog" isPangram?
"The quick brown fox jumps over the lazy dog" isPangram?
+> true

iik> "The quick brown fox jumps over the" isPangram?
"The quick brown fox jumps over the" isPangram?
+> false
```

## J

Solution:

```require 'strings'
isPangram=: (a. {~ 97+i.26) */@e. tolower
```

Example use:

```   isPangram 'The quick brown fox jumps over the lazy dog.'
1
isPangram 'The quick brown fox falls over the lazy dog.'
0
```

## Java

Works with: Java version 1.5+
```public class Pangram {
public static boolean isPangram(String test){
for (char a = 'A'; a <= 'Z'; a++)
if ((test.indexOf(a) < 0) && (test.indexOf((char)(a + 32)) < 0))
return false;
return true;
}

public static void main(String[] args){
System.out.println(isPangram("the quick brown fox jumps over the lazy dog"));//true
System.out.println(isPangram("the quick brown fox jumped over the lazy dog"));//false, no s
System.out.println(isPangram("ABCDEFGHIJKLMNOPQRSTUVWXYZ"));//true
System.out.println(isPangram("ABCDEFGHIJKLMNOPQSTUVWXYZ"));//false, no r
System.out.println(isPangram("ABCDEFGHIJKL.NOPQRSTUVWXYZ"));//false, no m
System.out.println(isPangram("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ"));//true
System.out.println(isPangram(""));//false
}
}
```
Output:
```true
false
true
false
false
true
false```

## JavaScript

### ES5

#### Iterative

```function isPangram(s) {
var letters = "zqxjkvbpygfwmucldrhsnioate"
// sorted by frequency ascending (http://en.wikipedia.org/wiki/Letter_frequency)
s = s.toLowerCase().replace(/[^a-z]/g,'')
for (var i = 0; i < 26; i++)
if (s.indexOf(letters[i]) < 0) return false
return true
}

console.log(isPangram("is this a pangram"))  // false
console.log(isPangram("The quick brown fox jumps over the lazy dog"))  // true
```

### ES6

#### Functional

```(() => {
"use strict";

// ----------------- PANGRAM CHECKER -----------------

// isPangram :: String -> Bool
const isPangram = s =>
0 === "abcdefghijklmnopqrstuvwxyz"
.split("")
.filter(c => -1 === s.toLowerCase().indexOf(c))
.length;

// ---------------------- TEST -----------------------
return [
"is this a pangram",
"The quick brown fox jumps over the lazy dog"
].map(isPangram);
})();
```
Output:
`[false, true]`

## jq

```def is_pangram:
explode
| map( if 65 <= . and . <= 90 then . + 32 # uppercase
elif 97 <= . and . <= 122 then .   # lowercase
else empty
end )
| unique
| length == 26;

# Example:
"The quick brown fox jumps over the lazy dog" | is_pangram```
Output:
```\$ jq -M -n -f pangram.jq
true
```

## Julia

makepangramchecker creates a function to test for pangramity based upon the contents of its input string, allowing one to create arbitrary pangram checkers.

```function makepangramchecker(alphabet)
alphabet = Set(uppercase.(alphabet))
function ispangram(s)
lengthcheck = length(s) ≥ length(alphabet)
return lengthcheck && all(c in uppercase(s) for c in alphabet)
end
return ispangram
end

const tests = ["Pack my box with five dozen liquor jugs.",
"The quick brown fox jumps over a lazy dog.",
"The quick brown fox jumps\u2323over the lazy dog.",
"The five boxing wizards jump quickly.",
"This sentence contains A-Z but not the whole alphabet."]

is_english_pangram = makepangramchecker('a':'z')

for s in tests
println("The sentence \"", s, "\" is ", is_english_pangram(s) ? "" : "not ", "a pangram.")
end
```
Output:
```The sentence "Pack my box with five dozen liquor jugs." is a pangram.
The sentence "The quick brown fox jumps over a lazy dog." is a pangram.
The sentence "The quick brown fox jumps⌣over the lazy dog." is a pangram.
The sentence "The five boxing wizards jump quickly." is a pangram.
The sentence "This sentence contains A-Z but not the whole alphabet." is not a pangram.
```

## K

```lcase   : _ci 97+!26
ucase   : _ci 65+!26
tolower : {@[x;p;:;lcase@n@p:&26>n:ucase?/:x]}
panagram: {&/lcase _lin tolower x}```

Example:

```  panagram "The quick brown fox jumps over the lazy dog"
1
panagram "Panagram test"
0```

## Kotlin

```// version 1.0.6

fun isPangram(s: String): Boolean {
if (s.length < 26) return false
val t = s.toLowerCase()
for (c in 'a' .. 'z')
if (c !in t) return false
return true
}

fun main(args: Array<String>) {
val candidates = arrayOf(
"The quick brown fox jumps over the lazy dog",
"New job: fix Mr. Gluck's hazy TV, PDQ!",
"A very bad quack might jinx zippy fowls",
"A very mad quack might jinx zippy fowls"   // no 'b' now!
)
for (candidate in candidates)
println("'\$candidate' is \${if (isPangram(candidate)) "a" else "not a"} pangram")
}
```
Output:
```'The quick brown fox jumps over the lazy dog' is a pangram
'New job: fix Mr. Gluck's hazy TV, PDQ!' is a pangram
'A very bad quack might jinx zippy fowls' is a pangram
'A very mad quack might jinx zippy fowls' is not a pangram
```

## Ksh

```#!/bin/ksh

# Pangram checker

#	# Variables:
#
alphabet='abcdefghijklmnopqrstuvwxyz'

typeset -a strs
strs+=( 'Mr. Jock, TV quiz PhD., bags few lynx.' )
strs+=( 'A very mad quack might jinx zippy fowls.' )

#	# Functions:
#

#	# Function _ispangram(str) - return 0 if str is a pangram
#
function _ispangram {
typeset _str ; typeset -l _str="\$1"
typeset _buff ; _buff="\${alphabet}"
typeset _i ; typeset -si _i

for ((_i=0; _i<\${#_str} && \${#_buff}>0; _i++)); do
_buff=\${_buff/\${_str:\${_i}:1}/}
done
return \${#_buff}
}

######
# main #
######

typeset -si i
for ((i=0; i<\${#strs[*]}; i++)); do
_ispangram "\${strs[i]}"
if (( ! \$? )); then
print "\${strs[i]}   <<< IS A PANGRAM."
else
print "\${strs[i]} <<< Is not a pangram."
fi
done
```
Output:
```
Mr. Jock, TV quiz PhD., bags few lynx.   <<< IS A PANGRAM.
A very mad quack might jinx zippy fowls. <<< Is not a pangram.

```

## Logo

```to remove.all :s :set
if empty? :s [output :set]
if word? :s [output remove.all butfirst :s remove first :s :set]
output remove.all butfirst :s remove.all first :s :set
end
to pangram? :s
output empty? remove.all :s "abcdefghijklmnopqrstuvwxyz
end

show pangram? [The five boxing wizards jump quickly.]   ; true```

## Lua

```require"lpeg"
S, C = lpeg.S, lpeg.C
function ispangram(s)
return #(C(S(s)^0):match"abcdefghijklmnopqrstuvwxyz") == 26
end

print(ispangram"waltz, bad nymph, for quick jigs vex")
print(ispangram"bobby")
print(ispangram"long sentence")
```

## Maple

```#Used built-in StringTools package
is_pangram := proc(str)
local present := StringTools:-LowerCase~(select(StringTools:-HasAlpha, StringTools:-Explode(str)));
local alphabets := {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
present := convert(present, set);
return evalb(present = alphabets);
end proc;```
Usage:
```is_pangram("The quick brown fox jumps over the lazy dog.");
is_pangram("The 2 QUIck brown foxes jumped over the lazy DOG!!");
is_pangram(""The quick brown fox jumps over the lay dog.");
```
Output:
```true
true
false
```

## Mathematica/Wolfram Language

```pangramQ[msg_]:=Complement[CharacterRange["a", "z"], Characters[ToLowerCase[msg]]]=== {}
```

Usage:

```pangramQ["The quick brown fox jumps over the lazy dog."]
True```

Or a slightly more verbose version that outputs the missing characters if the string is not a pangram:

```pangramQ[msg_] :=
Function[If[# === {}, Print["The string is a pangram!"],
Print["The string is not a pangram. It's missing the letters " <>
ToString[#]]]][
Complement[CharacterRange["a", "z"], Characters[ToLowerCase[msg]]]]
```

Usage:

```pangramQ["The quick brown fox jumps over the lazy dog."]
The string is a pangram!```
```pangramQ["Not a pangram"]
The string is not a pangram. It's missing the letters {b, c, d, e, f, h, i, j, k, l, q, s, u, v, w, x, y, z}```

## MATLAB

```function trueFalse = isPangram(string)

%This works by histogramming the ascii character codes for lower case
%letters contained in the string (which is first converted to all
%lower case letters). Then it finds the index of the first letter that
%is not contained in the string (this is faster than using the find
%without the second parameter). If the find returns an empty array then
%the original string is a pangram, if not then it isn't.

trueFalse = isempty(find( histc(lower(string),(97:122))==0,1 ));

end
```
Output:
```isPangram('The quick brown fox jumps over the lazy dog.')

ans =

1
```

## MATLAB / Octave

```function trueFalse = isPangram(string)
% X is a histogram of letters
X = sparse(abs(lower(string)),1,1,128,1);
trueFalse = full(all(X('a':'z') > 0));
end
```
Output:
```>>isPangram('The quick brown fox jumps over the lazy dog.')
ans = 1
```

## min

Works with: min version 0.19.3
```"abcdefghijklmnopqrstuvwxyz" "" split =alphabet
('alphabet dip lowercase (swap match) prepend all?) :pangram?

"The quick brown fox jumps over the lazy dog." pangram? puts```

## MiniScript

```sentences = ["The quick brown fox jumps over the lazy dog.",
"Peter Piper picked a peck of pickled peppers.",
"Waltz job vexed quick frog nymphs."]

alphabet = "abcdefghijklmnopqrstuvwxyz"

pangram = function (toCheck)
sentence = toCheck.lower
fail = false
for c in alphabet
if sentence.indexOf(c) == null then return false
end for
return true
end function

for sentence in sentences
if pangram(sentence) then
print """" + sentence + """ is a Pangram"
else
print """" + sentence + """ is not a Pangram"
end if
end for
```
Output:
```"The quick brown fox jumps over the lazy dog." is a Pangram
"Peter Piper picked a peck of pickled peppers." is not a Pangram
"Waltz job vexed quick frog nymphs." is a Pangram
```

## ML

### mLite

```fun to_locase s = implode ` map (c_downcase) ` explode s

fun is_pangram
(h :: t, T) =
let
val flen = len (filter (fn c = c eql h) T)
in
if (flen = 0) then
false
else
is_pangram (t, T)
end
|	([], T) = true
| 	S = is_pangram (explode "abcdefghijklmnopqrstuvwxyz", explode ` to_locase S)

fun is_pangram_i
(h :: t, T) =
let
val flen = len (filter (fn c = c eql h) T)
in
if (flen = 0) then
false
else
is_pangram (t, T)
end
|	([], T) = true
| 	(A,S) = is_pangram (explode A, explode ` to_locase S)

fun test (f, arg, res, ok, notok) = if (f arg eql res) then ("'" @ arg @ "' " @ ok) else ("'" @ arg @ "' " @ notok)
fun test2 (f, arg, res, ok, notok) = if (f arg eql res) then ("'" @ ref (arg,1) @ "' " @ ok) else ("'" @ ref (arg,1) @ "' " @ notok)

;
println ` test (is_pangram, "The quick brown fox jumps over the lazy dog", true, "is a pangram", "is not a pangram");
println ` test (is_pangram, "abcdefghijklopqrstuvwxyz", true, "is a pangram", "is not a pangram");
val SValphabet = "abcdefghijklmnopqrstuvwxyzåäö";
val SVsentence = "Yxskaftbud, ge vår wczonmö iq hjälp";
println ` test2 (is_pangram_i, (SValphabet, SVsentence), true, "is a Swedish pangram", "is not a Swedish pangram");
```
Output:
```'The quick brown fox jumps over the lazy dog' is a pangram
'abcdefghijklopqrstuvwxyz' is not a pangram
'Yxskaftbud, ge vår wczonmö iq hjälp' is a Swedish pangram
```

## Modula-2

```MODULE Pangrams;
FROM InOut IMPORT WriteString, WriteLn;
FROM Strings IMPORT Length;

(* Check if a string is a pangram *)
PROCEDURE pangram(s: ARRAY OF CHAR): BOOLEAN;
VAR letters: ARRAY [0..25] OF BOOLEAN;
i: CARDINAL;
BEGIN
FOR i := 0 TO 25 DO letters[i] := FALSE; END;
FOR i := 0 TO Length(s)-1 DO
IF (s[i] >= 'A') AND (s[i] <= 'Z') THEN
letters[ORD(s[i]) - ORD('A')] := TRUE;
ELSIF (s[i] >= 'a') AND (s[i] <= 'z') THEN
letters[ORD(s[i]) - ORD('a')] := TRUE;
END;
END;
FOR i := 0 TO 25 DO
IF NOT letters[i] THEN
RETURN FALSE;
END;
END;
RETURN TRUE;
END pangram;

PROCEDURE example(s: ARRAY OF CHAR);
BEGIN
WriteString("'");
WriteString(s);
WriteString("' is ");
IF NOT pangram(s) THEN
WriteString("not ");
END;
WriteString("a pangram.");
WriteLn();
END example;

BEGIN
example("The quick brown fox jumps over the lazy dog");
example("The five boxing wizards dump quickly");
example("abcdefghijklmnopqrstuvwxyz");
END Pangrams.
```
Output:
```'The quick brown fox jumps over the lazy dog' is a pangram.
'The five boxing wizards dump quickly' is not a pangram.
'abcdefghijklmnopqrstuvwxyz' is a pangram.```

## NetRexx

NetRexx's `verify` built–in method is all you need!

```/* NetRexx */
options replace format comments java crossref savelog symbols nobinary

A2Z = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'

pangrams = create_samples

loop p_ = 1 to pangrams[0]
pangram = pangrams[p_]
q_ = A2Z.verify(pangram.upper) -- <= it basically all happens in this function call!
say pangram.left(64)'\-'
if q_ == 0 then -
say ' [OK, a pangram]'
else -
say ' [Not a pangram.  Missing:' A2Z.substr(q_, 1)']'
end p_

method create_samples public static returns Rexx

pangrams = ''

x_ = 0
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'The quick brown fox jumps over a lazy dog.'    -- best/shortest pangram
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'The quick brown fox jumps over the lazy dog.'  -- not as short but at least it's still a pangram
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'The quick brown fox jumped over the lazy dog.' -- common misquote; not a pangram
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'The quick onyx goblin jumps over the lazy dwarf.'
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!' -- (Used to advertise a pub quiz in Bowness-on-Windermere)

return pangrams
```
Output:
```The quick brown fox jumps over a lazy dog.                       [OK, a pangram]
The quick brown fox jumps over the lazy dog.                     [OK, a pangram]
The quick brown fox jumped over the lazy dog.                    [Not a pangram.  Missing: S]
The quick onyx goblin jumps over the lazy dwarf.                 [OK, a pangram]
Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!  [OK, a pangram]
```

## NewLISP

```(context 'PGR)                              ;; Switch to context (say namespace) PGR
(define (is-pangram? str)
(setf chars (explode (upper-case str))) ;; Uppercase + convert string into a list of chars
(setf is-pangram-status true)           ;; Default return value of function
(for (c (char "A") (char "Z") 1 (nil? is-pangram-status)) ;; For loop with break condition
(if (not (find (char c) chars))     ;; If char not found in list, "is-pangram-status" becomes "nil"
(setf is-pangram-status nil)
)
)
is-pangram-status                       ;; Return current value of symbol "is-pangram-status"
)
(context 'MAIN)                             ;; Back to MAIN context

;; - - - - - - - - - -

(println (PGR:is-pangram? "abcdefghijklmnopqrstuvwxyz"))  ;; Print true
(println (PGR:is-pangram? "abcdef"))  ;; Print nil
(exit)
```

## Nim

```import rdstdin

proc isPangram(sentence: string, alphabet = {'a'..'z'}): bool =
var sentset: set[char] = {}
for c in sentence: sentset.incl c
alphabet <= sentset

echo isPangram(readLineFromStdin "Sentence: ")
```

Example usage:

```Sentence: The quick brown fox jumps over the lazy dog
true```

## Objeck

Translation of: Java
```bundle Default {
class Pangram {
function : native : IsPangram(test : String) ~ Bool {
for(a := 'A'; a <= 'Z'; a += 1;) {
if(test->Find(a) < 0 & test->Find(a->ToLower()) < 0) {
return false;
};
};

return true;
}

function : Main(args : String[]) ~ Nil {
IsPangram("the quick brown fox jumps over the lazy dog")->PrintLine(); # true
IsPangram("the quick brown fox jumped over the lazy dog")->PrintLine(); # false, no s
IsPangram("ABCDEFGHIJKLMNOPQRSTUVWXYZ")->PrintLine(); # true
IsPangram("ABCDEFGHIJKLMNOPQSTUVWXYZ")->PrintLine(); # false, no r
IsPangram("ABCDEFGHIJKL.NOPQRSTUVWXYZ")->PrintLine(); # false, no m
IsPangram("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ")->PrintLine(); # true
IsPangram("")->PrintLine(); # false
}
}
}```

## OCaml

```let pangram str =
let ar = Array.make 26 false in
String.iter (function
| 'a'..'z' as c -> ar.(Char.code c - Char.code 'a') <- true
| _ -> ()
) (String.lowercase str);
Array.fold_left ( && ) true ar
```
```let check str =
Printf.printf " %b -- %s\n" (pangram str) str

let () =
check "this is a sentence";
check "The quick brown fox jumps over the lazy dog.";
;;
```
Output:
```false -- this is a sentence
true -- The quick brown fox jumps over the lazy dog.
```

## Oz

```declare
fun {IsPangram Xs}
{List.sub
{List.number &a &z 1}
{Sort {Map Xs Char.toLower} Value.'<'}}
end
in
{Show {IsPangram "The quick brown fox jumps over the lazy dog."}}```

## PARI/GP

```pangram(s)={
s=vecsort(Vec(s),,8);
for(i=97,122,
if(!setsearch(s,Strchr(i)) && !setsearch(s,Strchr(i-32)),
return(0)
)
);
1
};

pangram("The quick brown fox jumps over the lazy dog.")
pangram("The quick brown fox jumps over the lazy doe.")```

See Delphi

## Perl

Get an answer with a module, or without.

```use strict;
use warnings;
use feature 'say';

sub pangram1 {
my(\$str,@set) = @_;
use List::MoreUtils 'all';
all { \$str =~ /\$_/i } @set;
}

sub pangram2 {
my(\$str,@set) = @_;
'' eq (join '',@set) =~ s/[\$str]//gir;
}

my @alpha = 'a' .. 'z';

for (
'Cozy Lummox Gives Smart Squid Who Asks For Job Pen.',
'Crabby Lummox Gives Smart Squid Who Asks For Job Pen.'
) {
say pangram1(\$_,@alpha) ? 'Yes' : 'No';
say pangram2(\$_,@alpha) ? 'Yes' : 'No';
}
```
Output:
```Yes
Yes
No
No```

## Phix

```function pangram(string s)
sequence az = repeat(false,26)
integer count = 0
for i=1 to length(s) do
integer ch = lower(s[i])
if ch>='a'
and ch<='z'
and not az[ch-96] then
count += 1
if count=26 then return {true,0} end if
az[ch-96] = true
end if
end for
return {false,find(false,az)+96}
end function
```
```sequence checks = {"The quick brown fox jumped over the lazy dog",
"The quick brown fox jumps over the lazy dog",
".!\$\"AbCdEfghijklmnoprqstuvwxyz",
"THE FIVE BOXING WIZARDS DUMP QUICKLY.",
"THE FIVE BOXING WIZARDS JUMP QUICKLY.",
"HEAVY BOXES PERFORM WALTZES AND JIGS.",
"PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS.",
"Big fjiords vex quick waltz nymph",
"The quick onyx goblin jumps over the lazy dwarf.",
"no"}
for i=1 to length(checks) do
string ci = checks[i]
integer {r,ch} = pangram(ci)
printf(1,"%-50s - %s\n",{ci,iff(r?"yes":"no "&ch)})
end for
```
Output:
```The quick brown fox jumped over the lazy dog       - no s
The quick brown fox jumps over the lazy dog        - yes
.!\$"AbCdEfghijklmnoprqstuvwxyz                     - yes
THE FIVE BOXING WIZARDS DUMP QUICKLY.              - no j
THE FIVE BOXING WIZARDS JUMP QUICKLY.              - yes
HEAVY BOXES PERFORM WALTZES AND JIGS.              - no c
PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS.           - yes
Big fjiords vex quick waltz nymph                  - yes
The quick onyx goblin jumps over the lazy dwarf.   - yes
no                                                 - no a
```

## PHP

Translation of: D
```function isPangram(\$text) {
foreach (str_split(\$text) as \$c) {
if (\$c >= 'a' && \$c <= 'z')
\$bitset |= (1 << (ord(\$c) - ord('a')));
else if (\$c >= 'A' && \$c <= 'Z')
\$bitset |= (1 << (ord(\$c) - ord('A')));
}
return \$bitset == 0x3ffffff;
}

\$test = array(
"the quick brown fox jumps over the lazy dog",
"the quick brown fox jumped over the lazy dog",
"ABCDEFGHIJKLMNOPQSTUVWXYZ",
"ABCDEFGHIJKL.NOPQRSTUVWXYZ",
"ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ"
);

foreach (\$test as \$str)
echo "\$str : ", isPangram(\$str) ? 'T' : 'F', '</br>';
```
```the quick brown fox jumps over the lazy dog : T
the quick brown fox jumped over the lazy dog : F
ABCDEFGHIJKLMNOPQSTUVWXYZ : F
ABCDEFGHIJKL.NOPQRSTUVWXYZ : F
ABC.D.E.FGHI*J/KL-M+NO*PQ R STUVWXYZ : T
```

Using array

```function is_pangram( \$sentence ) {

// define "alphabet"
\$alpha = range( 'a', 'z' );

// split lowercased string into array
\$a_sentence = str_split( strtolower( \$sentence ) );

// check that there are no letters present in alpha not in sentence
return empty( array_diff( \$alpha, \$a_sentence ) );

}

\$tests = array(
"The quick brown fox jumps over the lazy dog.",
"The brown fox jumps over the lazy dog.",
"ABCDEFGHIJKL.NOPQRSTUVWXYZ",
"ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ",
"How vexingly quick daft zebras jump",
"Is hotdog?",
"How razorback-jumping frogs can level six piqued gymnasts!"
);

foreach ( \$tests as \$txt ) {
echo '"', \$txt, '"', PHP_EOL;
echo is_pangram( \$txt ) ? "Yes" : "No", PHP_EOL, PHP_EOL;
}
```
Output:
```"The quick brown fox jumps over the lazy dog."
Yes

"The brown fox jumps over the lazy dog."
No

"ABCDEFGHIJKL.NOPQRSTUVWXYZ"
No

"ABC.D.E.FGHI*J/KL-M+NO*PQ R
STUVWXYZ"
Yes

"How vexingly quick daft zebras jump"
Yes

"Is hotdog?"
No

"How razorback-jumping frogs can level six piqued gymnasts!"
Yes
```

## Picat

```go =>
S1 = "The quick brown fox jumps over the lazy dog",
S2 = "The slow brown fox jumps over the lazy dog",
println([S1, is_pangram(S1)]),
println([S2, is_pangram(S2)]),
nl,
println("With missing chars:"),
println([S1, is_pangram2(S1)]),
println([S2, is_pangram2(S2)]),
nl.

% Check if S is a pangram and get the missing chars
is_pangram(S) = P =>
Lower = S.to_lowercase,
Alpha = [chr(I+96) : I in 1..26],
foreach(A in Alpha) membchk(A,Lower) end -> P = true ; P = false.

% Check if S is a pangram and get the missing chars (if any)
is_pangram2(S) = [pangram=cond(Missing==[],true,false),missing=Missing] =>
Lower = S.to_lowercase,
Missing = [A : A in [chr(I+96) : I in 1..26], not membchk(A,Lower)].```
Output:
```[The quick brown fox jumps over the lazy dog,true]
[The slow brown fox jumps over the lazy dog,false]

With missing chars:
[The quick brown fox jumps over the lazy dog,[pangram = true,missing = []]]
[The slow brown fox jumps over the lazy dog,[pangram = false,missing = cikq]]```

## PicoLisp

```(de isPangram (Str)
(not
(diff
'`(chop "abcdefghijklmnopqrstuvwxyz")
(chop (lowc Str)) ) ) )```

## PL/I

```test_pangram: procedure options (main);

is_pangram: procedure() returns (bit(1) aligned);

declare text character (200) varying;
declare c character (1);

get edit (text) (L);
put skip list (text);

text = lowercase(text);

do c = 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k',
'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u',
'v', 'w', 'x', 'y', 'z';
if index(text, c) = 0 then return ('0'b);
end;
return ('1'b);
end is_pangram;

put skip list ('Please type a sentence');

if is_pangram() then
put skip list ('The sentence is a pangram.');
else
put skip list ('The sentence is not a pangram.');

end test_pangram;```
Output:
```Please type a sentence

the quick brown fox jumps over the lazy dog
The sentence is a pangram.
```

## PowerShell

Cyrillic test sample borrowed from Raku.

Works with: PowerShell version 2
```function Test-Pangram ( [string]\$Text, [string]\$Alphabet = 'abcdefghijklmnopqrstuvwxyz' )
{
\$Text = \$Text.ToLower()
\$Alphabet = \$Alphabet.ToLower()

\$IsPangram = @( \$Alphabet.ToCharArray() | Where-Object { \$Text.Contains( \$_ ) } ).Count -eq \$Alphabet.Length

return \$IsPangram
}

Test-Pangram 'The quick brown fox jumped over the lazy dog.'
Test-Pangram 'The quick brown fox jumps over the lazy dog.'
Test-Pangram 'Съешь же ещё этих мягких французских булок, да выпей чаю' 'абвгдежзийклмнопрстуфхцчшщъыьэюяё'
```
Output:
```False
True
True
```

A faster version can be created using .Net HashSet to do what the F# version does:

```Function Test-Pangram ( [string]\$Text, [string]\$Alphabet = 'abcdefghijklmnopqrstuvwxyz' )
{
\$alSet   = [Collections.Generic.HashSet[char]]::new(\$Alphabet.ToLower())
\$textSet = [Collections.Generic.HashSet[char]]::new(\$Text.ToLower())

\$alSet.ExceptWith(\$textSet)    # remove text chars from the alphabet

return \$alSet.Count -eq 0    # any alphabet letters still remaining?
}
```

## Prolog

Works with SWI-Prolog

```pangram(L) :-
numlist(0'a, 0'z, Alphabet),
forall(member(C, Alphabet), member(C, L)).

pangram_example :-
L1 = "the quick brown fox jumps over the lazy dog",
(   pangram(L1) -> R1= ok; R1 = ko),
format('~s --> ~w ~n', [L1,R1]),

L2 = "the quick brown fox jumped over the lazy dog",
(   pangram(L2) -> R2 = ok; R2 = ko),
format('~s --> ~w ~n', [L2, R2]).
```
Output:
```?- pangram_example.
the quick brown fox jumps over the lazy dog --> ok
the quick brown fox jumped over the lazy dog --> ko
true.```

## Python

Using set arithmetic:

```import string, sys
if sys.version_info[0] < 3:
input = raw_input

def ispangram(sentence, alphabet=string.ascii_lowercase):
alphaset = set(alphabet)
return alphaset <= set(sentence.lower())

print ( ispangram(input('Sentence: ')) )
```
Output:
```Sentence: The quick brown fox jumps over the lazy dog
True```

## Quackery

```  [ dup char A char [ within
swap char a char { within
or ]                        is letter  ( c --> b )

[ 0 26 of swap witheach
[ dup letter iff
[ 1 unrot lower
char a - poke ]
else drop ]
0 swap find 26 = ]          is pangram ( \$ --> b )

\$ "This is a sentence." pangram echo cr                     ( 0 )
\$ "The five boxing wizards jumped quickly." pangram echo cr ( 1 )```

## R

Using the built-in R vector "letters":

```checkPangram <- function(sentence){
my.letters <- tolower(unlist(strsplit(sentence, "")))
is.pangram <- all(letters %in% my.letters)

if (is.pangram){
cat("\"", sentence, "\" is a pangram! \n", sep="")
} else {
cat("\"", sentence, "\" is not a pangram! \n", sep="")
}
}
```
Output:
```s1 <- "The quick brown fox jumps over the lazy dog"
s2 <- "The quick brown fox jumps over the sluggish dog"
checkPangram(s1)
"The quick brown fox jumps over the lazy dog" is a pangram!
checkPangram(s2)
"The quick brown fox jumps over the sluggish dog" is not a pangram!
```

## Racket

```#lang racket
(define (pangram? str)
(define chars (regexp-replace* #rx"[^a-z]+" (string-downcase str) ""))
(= 26 (length (remove-duplicates (string->list chars)))))
(pangram? "The quick Brown Fox jumps over the Lazy Dog")
```

## Raku

(formerly Perl 6)

```constant Eng = set 'a' .. 'z';
constant Cyr = (set 'а' .. 'ё') (-) (set 'ъ', 'ѐ');
constant Hex = set 'a' .. 'f';

sub pangram(\$str, Set \$alpha = Eng) {
\$alpha ⊆ \$str.lc.comb
}

say pangram("The quick brown fox jumps over the lazy dog.");
say pangram("My dog has fleas.");
say pangram("My dog has fleas.", Hex);
say pangram("My dog backs fleas.", Hex);
say pangram "Съешь же ещё этих мягких французских булок, да выпей чаю", Cyr;
```
Output:
```True
False
False
True
True```

## Retro

```'abcdefghijklmnopqrstuvwxyz 'FULL s:const
'__________________________ 'TEST s:const
:s:pangram? (s-f)
'__________________________ &TEST #26 copy
s:to-lower [ c:letter? ] s:filter
[ dup \$a - &TEST + store ] s:for-each
&TEST &FULL s:eq? ;```

## REXX

```/*REXX program  verifies  if an  entered/supplied  string  (sentence)  is a pangram.    */
@abc= 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'               /*a list of all (Latin) capital letters*/

do forever;    say                           /*keep promoting 'til null (or blanks).*/
say '──────── Please enter a pangramic sentence   (or a blank to quit):';      say
pull y                                       /*this also uppercases the  Y variable.*/
if y=''  then leave                          /*if nothing entered,  then we're done.*/
absent= space( translate( @abc, , y), 0)     /*obtain a list of any absent letters. */
if absent==''  then say  "──────── Sentence is a pangram."
else say  "──────── Sentence isn't a pangram, missing: "    absent
say
end   /*forever*/

say '──────── PANGRAM program ended. ────────'   /*stick a fork in it,  we're all done. */
```
output:
```──────── Please enter a pangramic sentence   (or a blank to quit):
The quick brown fox jumped over the lazy dog.      ◄■■■■■■■■■■ user input.
──────── Sentence isn't a pangram, missing:  S

──────── Please enter a pangramic sentence   (or a blank to quit):
The quick brown fox JUMPS over the lazy dog!!!     ◄■■■■■■■■■■ user input.
──────── Sentence is a pangram.

──────── Please enter a pangramic sentence   (or a blank to quit):
◄■■■■■■■■■■ user input   (null  or  some blanks).

──────── PANGRAM program ended. ────────
```

## Ring

```pangram = 0
s = "The quick brown fox jumps over the lazy dog."
see "" + pangram(s) + " " + s + nl

s = "My dog has fleas."
see "" + pangram(s) + " " + s + nl

func pangram str
str  = lower(str)
for i = ascii("a") to ascii("z")
bool = substr(str, char(i)) > 0
pangram = pangram + bool
next
pan = (pangram = 26)
return pan```

## Ruby

```def pangram?(sentence)
s = sentence.downcase
('a'..'z').all? {|char| s.include? (char) }
end

p pangram?('this is a sentence')  # ==> false
p pangram?('The quick brown fox jumps over the lazy dog.')  # ==> true
```

## Rust

```#![feature(test)]

extern crate test;

use std::collections::HashSet;

pub fn is_pangram_via_bitmask(s: &str) -> bool {

// Create a mask of set bits and convert to false as we find characters.
let mut mask = (1 << 26) - 1;

for chr in s.chars() {
let val = chr as u32 & !0x20; /* 0x20 converts lowercase to upper */
if val <= 'Z' as u32 && val >= 'A' as u32 {
mask = mask & !(1 << (val - 'A' as u32));
}
}

}

pub fn is_pangram_via_hashset(s: &str) -> bool {

// Insert lowercase letters into a HashSet, then check if we have at least 26.
let letters = s.chars()
.flat_map(|chr| chr.to_lowercase())
.filter(|&chr| chr >= 'a' && chr <= 'z')
.fold(HashSet::new(), |mut letters, chr| {
letters.insert(chr);
letters
});

letters.len() == 26
}

pub fn is_pangram_via_sort(s: &str) -> bool {

// Copy chars into a vector, convert to lowercase, sort, and remove duplicates.
let mut chars: Vec<char> = s.chars()
.flat_map(|chr| chr.to_lowercase())
.filter(|&chr| chr >= 'a' && chr <= 'z')
.collect();

chars.sort();
chars.dedup();

chars.len() == 26
}

fn main() {

let examples = ["The quick brown fox jumps over the lazy dog",
"The quick white cat jumps over the lazy dog"];

for &text in examples.iter() {
let is_pangram_sort = is_pangram_via_sort(text);
println!("Is \"{}\" a pangram via sort? - {}", text, is_pangram_sort);

println!("Is \"{}\" a pangram via bitmask? - {}",
text,

let is_pangram_hashset = is_pangram_via_hashset(text);
println!("Is \"{}\" a pangram via bitmask? - {}",
text,
is_pangram_hashset);
}
}
```

## Scala

```def is_pangram(sentence: String) = sentence.toLowerCase.filter(c => c >= 'a' && c <= 'z').toSet.size == 26
```
```scala> is_pangram("This is a sentence")
res0: Boolean = false

scala> is_pangram("The quick brown fox jumps over the lazy dog")
res1: Boolean = true
```

## Seed7

```\$ include "seed7_05.s7i";

const func boolean: isPangram (in string: stri) is func
result
var boolean: isPangram is FALSE;
local
var char: ch is ' ';
var set of char: usedChars is (set of char).value;
begin
for ch range lower(stri) do
if ch in {'a' .. 'z'} then
incl(usedChars, ch);
end if;
end for;
isPangram := usedChars = {'a' .. 'z'};
end func;

const proc: main is func
begin
writeln(isPangram("This is a test"));
writeln(isPangram("The quick brown fox jumps over the lazy dog"));
writeln(isPangram("NOPQRSTUVWXYZ  abcdefghijklm"));
writeln(isPangram("abcdefghijklopqrstuvwxyz"));  # Missing m, n
end func;```
Output:
```FALSE
TRUE
TRUE
FALSE
```

## Sidef

Translation of: Raku
```define Eng = 'a'..'z';
define Hex = 'a'..'f';
define Cyr = %w(а б в г д е ж з и й к л м н о п р с т у ф х ц ч ш щ ъ ы ь э ю я ё);

func pangram(str, alpha=Eng) {
var lstr = str.lc;
alpha.all {|c| lstr.contains(c) };
}

say pangram("The quick brown fox jumps over the lazy dog.");
say pangram("My dog has fleas.");
say pangram("My dog has fleas.", Hex);
say pangram("My dog backs fleas.", Hex);
say pangram("Съешь же ещё этих мягких французских булок, да выпей чаю", Cyr);
```
Output:
```true
false
false
true
true
```

## Smalltalk

```!String methodsFor: 'testing'!
isPangram
^((self collect: [:c | c asUppercase]) select: [:c | c >= \$A and: [c <= \$Z]]) asSet size = 26
```
```'The quick brown fox jumps over the lazy dog.' isPangram
```

## SNOBOL4

Works with: Macro Spitbol
Works with: Snobol4+
Works with: CSnobol
```        define('pangram(str)alfa,c') :(pangram_end)
pangram str = replace(str,&ucase,&lcase)
alfa = &lcase
pgr_1   alfa len(1) . c = :f(return)
str c :s(pgr_1)f(freturn)
pangram_end

define('panchk(str)tf') :(panchk_end)
panchk  output = str
tf = 'False'; tf = pangram(str) 'True'
output = 'Pangram: ' tf :(return)
panchk_end

*       # Test and display
panchk("The quick brown fox jumped over the lazy dogs.")
panchk("My girl wove six dozen plaid jackets before she quit.")
panchk("This 41-character string: it's a pangram!")
end```
Output:
```The quick brown fox jumped over the lazy dogs.
Pangram: True
My girl wove six dozen plaid jackets before she quit.
Pangram: True
This 41-character string: it's a pangram!
Pangram: False```

## Swift

```import Foundation

let str = "the quick brown fox jumps over the lazy dog"

func isPangram(str:String) -> Bool {
let stringArray = Array(str.lowercaseString)
for char in "abcdefghijklmnopqrstuvwxyz" {
if (find(stringArray, char) == nil) {
return false
}
}
return true
}

isPangram(str) // True
isPangram("Test string") // False
```

Swift 2.0:

```func isPangram(str: String) -> Bool {
let (char, alph) = (Set(str.characters), "abcdefghijklmnopqrstuvwxyz".characters)
return !alph.contains {!char.contains(\$0)}
}
```

## Tcl

```proc pangram? {sentence} {
set letters [regexp -all -inline {[a-z]} [string tolower \$sentence]]
expr {
[llength [lsort -unique \$letters]] == 26
}
}
puts [pangram? "This is a sentence"];  # ==> false
puts [pangram? "The quick brown fox jumps over the lazy dog."]; # ==> true
```

## TI-83 BASIC

```:Prompt Str1
:For(L,1,26
:If not(inString(Str1,sub("ABCDEFGHIJKLMNOPQRSTUVWXYZ",L,1))
:L=28
:End
:If L<28
:Disp "IS A PANGRAM"```

(not tested yet)

## TUSCRIPT

```\$\$ MODE TUSCRIPT,{}
alfabet="abcdefghijklmnopqrstuvwxyz"
sentences = *
DATA The quick brown fox jumps over the lazy dog
DATA the quick brown fox falls over the lazy dog
LOOP s=sentences
getchars      =STRINGS    (s," {&a} ")
sortchars     =ALPHA_SORT (getchars)
reducechars   =REDUCE     (sortchars)
chars_in_s    =EXCHANGE   (reducechars," '  ")
IF (chars_in_s==alfabet) PRINT "   pangram: ",s
IF (chars_in_s!=alfabet) PRINT "no pangram: ",s
ENDLOOP```
Output:
```   pangram: The quick brown fox jumps over the lazy dog
no pangram: the quick brown fox falls over the lazy dog
```

## TXR

```@/.*[Aa].*&.*[Bb].*&.*[Cc].*&.*[Dd].*& \
.*[Ee].*&.*[Ff].*&.*[Gg].*&.*[Hh].*& \
.*[Ii].*&.*[Jj].*&.*[Kk].*&.*[Ll].*& \
.*[Mm].*&.*[Nn].*&.*[Oo].*&.*[Pp].*& \
.*[Qq].*&.*[Rr].*&.*[Ss].*&.*[Tt].*& \
.*[Uu].*&.*[Vv].*&.*[Ww].*&.*[Xx].*& \
.*[Yy].*&.*[Zz].*/```
Run:
```\$ echo "The quick brown fox jumped over the lazy dog." | txr is-pangram.txr -
\$echo \$? # failed termination
1
\$ echo "The quick brown fox jumped over the lazy dogs." | txr is-pangram.txr -
\$ echo \$?   # successful termination
0```

## UNIX Shell

Works with: Bourne Again SHell
Works with: Korn Shell
Works with: Z Shell
```function is_pangram {
typeset alphabet=abcdefghijklmnopqrstuvwxyz
typeset -l string=\$*
while [[ -n \$string && -n \$alphabet ]]; do
typeset ch=\${string%%\${string#?}}
string=\${string#?}
alphabet=\${alphabet/\$ch}
done
[[ -z \$alphabet ]]
}
```

## Ursala

```#import std

is_pangram = ^jZ^(!@l,*+ @rlp -:~&) ~=`A-~ letters```

example usage:

```#cast %bL

test =

is_pangram* <
'The quick brown fox jumps over the lazy dog',
'this is not a pangram'>```
Output:
```<true,false>
```

## VBA

The function pangram() in the VBScript section below will do just fine.

Here is an alternative version:

```Function pangram2(s As String) As Boolean
Const sKey As String = "abcdefghijklmnopqrstuvwxyz"
Dim sLow As String
Dim i As Integer

sLow = LCase(s)
For i = 1 To 26
If InStr(sLow, Mid(sKey, i, 1)) = 0 Then
pangram2 = False
Exit Function
End If
Next
pangram2 = True
End Function
```

Invocation e.g. (typed in the Immediate window):

```print pangram2("the quick brown dog jumps over a lazy fox")
print pangram2("it is time to say goodbye!")
```

## VBScript

#### Implementation

```function pangram( s )
dim i
dim sKey
dim sChar
dim nOffset
sKey = "abcdefghijklmnopqrstuvwxyz"
for i = 1 to len( s )
sChar = lcase(mid(s,i,1))
if sChar <> " "  then
if instr(sKey, sChar) then
nOffset = asc( sChar ) - asc("a")  + 1
if nOffset > 1 then
sKey = left(sKey, nOffset - 1) & " " & mid( sKey, nOffset + 1)
else
sKey = " " & mid( sKey, nOffset + 1)
end if
end if
end if
next
pangram = ( ltrim(sKey) = vbnullstring )
end function

function eef( bCond, exp1, exp2 )
if bCond then
eef = exp1
else
eef = exp2
end if
end function
```

#### Invocation

```wscript.echo eef(pangram("a quick brown fox jumps over the lazy dog"), "is a pangram", "is not a pangram")
wscript.echo eef(pangram(""), "is a pangram", "is not a pangram")"
```

## VTL-2

```10 I=1
20 :I)=0
30 I=I+1
40 #=26>I*20
50 ?="Enter sentence: ";
60 C=\$
70 #=C=13*120
80 C=C<97*32+C-96
90 #=C>27*60
100 :C)=1
110 #=60
120 ?=""
130 I=1
140 N=0
150 N=N+:I)
160 I=I+1
170 #=26>I*150
180 #=N=26*200
190 ?="not ";
200 ?="a pangram"```
Output:
```#=1
Enter sentence: The quick brown fox jumps over the lazy dog.
a pangram

OK
#=1
Enter sentence: This is not a pangram.
not a pangram

OK```

## Wren

Library: Wren-str
```import "/str" for Str

var isPangram = Fn.new { |s|
s = Str.lower(s)
var used = List.filled(26, false)
for (cp in s.codePoints) {
if (cp >= 97 && cp <= 122) used[cp-97] = true
}
for (u in used) if (!u) return false
return true
}

var candidates = [
"The quick brown fox jumps over the lazy dog.",
"New job: fix Mr. Gluck's hazy TV, PDQ!",
"Peter Piper picked a peck of pickled peppers.",
"Sphinx of black quartz, judge my vow.",
"Foxy diva Jennifer Lopez wasn’t baking my quiche.",
"Grumpy wizards make a toxic stew for the jovial queen."
]

System.print("Are the following pangrams?")
for (candidate in candidates) {
System.print("  %(candidate) -> %(isPangram.call(candidate))")
}
```
Output:
```Are the following pangrams?
The quick brown fox jumps over the lazy dog. -> true
New job: fix Mr. Gluck's hazy TV, PDQ! -> true
Peter Piper picked a peck of pickled peppers. -> false
Sphinx of black quartz, judge my vow. -> true
Foxy diva Jennifer Lopez wasn’t baking my quiche. -> true
Grumpy wizards make a toxic stew for the jovial queen. -> false
```

## XPL0

```include c:\cxpl\codes;          \intrinsic 'code' declarations
string 0;                       \use zero-terminated strings

func StrLen(Str);               \Return number of characters in an ASCIIZ string
char Str;
int  I;
for I:= 0 to -1>>1-1 do
if Str(I) = 0 then return I;

func Pangram(S);
char S;
int  A, I, C;
[A:= 0;
for I:= 0 to StrLen(S)-1 do
[C:= S(I);
if C>=^A & C<=^Z then C:= C or \$20;
if C>=^a & C<=^z then [C:= C - ^a;  A:= A or 1<<C];
];
return A = \$3FFFFFF;
]; \Pangram

int Sentence, I;
[Sentence:=
["The quick brown fox jumps over the lazy dog.",
"Pack my box with five dozen liquor jugs.",
"Now is the time for all good men to come to the aid of their country."];
for I:= 0 to 3-1 do
[Text(0, if Pangram(Sentence(I)) then "yes" else "no");
CrLf(0);
];
]```
Output:
```yes
yes
no
```

## zkl

```var letters=["a".."z"].pump(String); //-->"abcdefghijklmnopqrstuvwxyz"
fcn isPangram(text){(not (letters-text.toLower()))}```
Output:
```isPangram("The quick brown fox jumps over the lazy dog.")
True
isPangram("Pack my box with five dozen liquor jugs.")
True
isPangram("Now is the time for all good men to come to the aid of their country.")
False
```