# 99 bottles of beer: Difference between revisions

99 bottles of beer
You are encouraged to solve this task according to the task description, using any language you may know.

Display the complete lyrics for the song:     99 Bottles of Beer on the Wall.

The beer song

99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall

98 bottles of beer on the wall
98 bottles of beer
Take one down, pass it around
97 bottles of beer on the wall

... and so on, until reaching   0     (zero).

Grammatical support for   1 bottle of beer   is optional.

As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).

## 11l

Translation of: Python
L(i) (99..1).step(-1)
print(i‘ bottles of beer on the wall’)
print(i‘ bottles of beer’)
print(‘Take one down, pass it around’)
print((i - 1)" bottles of beer on the wall\n")

## 8th

\ 99 bottles of beer on the wall:
: allout "no more bottles" ;
: just-one "1 bottle"  ;
: yeah!	 dup . " bottles" ;

[
' allout ,
' just-one ,
' yeah! ,
] var, bottles

: .bottles  dup 2 n:min bottles @ swap caseof ;
: .beer     .bottles . " of beer" . ;
: .wall     .beer " on the wall" . ;
: .take     "  Take one down and pass it around" . ;
: beers     .wall ", " . .beer '; putc cr
n:1- 0 max .take ", " .
.wall '. putc cr drop ;

' beers 1 99 loop- bye


## AArch64 Assembly

Works with: as version Raspberry Pi 3B version Buster 64 bits
/* ARM assembly AARCH64 Raspberry PI 3B */
/*  program bootleBeer64.s   */

/*******************************************/
/* Constantes file                         */
/*******************************************/
/* for this file see task include a file in language AArch64 assembly*/
.include "../includeConstantesARM64.inc"

.equ MAXI,   99

/*********************************/
/* Initialized data              */
/*********************************/
.data
szMessLine1:        .asciz "@ bottles of beer on the wall\n"
szMessLine2:        .ascii "@ bottles of beer\n"
.asciz "Take one down, pass it around\n"
szMessLine3:        .asciz "@ bottles of beer on the wall\n\n"

szMessLine4:       .ascii "\nNo more bottles of beer on the wall, no more bottles of beer.\n"
.asciz "Go to the store and buy some more, 99 bottles of beer on the wall.\n"

szCarriageReturn:   .asciz "\n"
/*********************************/
/* UnInitialized data            */
/*********************************/
.bss
sZoneConv:        .skip 24
/*********************************/
/*  code section                 */
/*********************************/
.text
.global main
main:                            // entry of program
mov x2,#MAXI
1:
mov x0,x2
bl conversion10              // call decimal conversion
ldr x1,qAdrsZoneConv         // insert conversion in message
bl strInsertAtCharInc
bl affichageMess

ldr x1,qAdrsZoneConv         // insert conversion in message
bl strInsertAtCharInc
bl affichageMess

subs x0,x2,#1
ble 2f
bl conversion10              // call decimal conversion
ldr x1,qAdrsZoneConv         // insert conversion in message
bl strInsertAtCharInc
bl affichageMess
2:
subs x2,x2,1
bgt 1b

bl affichageMess

100:                                  // standard end of the program
mov x0, #0                        // return code
mov x8, #EXIT                     // request to exit program
svc #0                            // perform the system call

/********************************************************/
/*        File Include fonctions                        */
/********************************************************/
/* for this file see task include a file in language AArch64 assembly */
.include "../includeARM64.inc"

## ABAP

REPORT z99bottles.

DATA lv_no_bottles(2) TYPE n VALUE 99.

DO lv_no_bottles TIMES.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer on the wall'.
NEW-LINE.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer'.
NEW-LINE.
WRITE 'Take one down, pass it around'.
NEW-LINE.
SUBTRACT 1 FROM lv_no_bottles.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer on the wall'.
WRITE /.
ENDDO.


or (With ABAP 7.40)

REPORT YCL_99_BOTTLES.

DATA it_99_bottles TYPE TABLE OF string WITH EMPTY KEY.
DATA(cr_lf) = cl_abap_char_utilities=>cr_lf.
it_99_bottles = VALUE #(
FOR i = 99 THEN i - 1 UNTIL i = 0 ( COND string( LET  lv = ( i - 1 )
lr = i && | bottles of beer on the wall|
&& cr_lf
&& i && | bottles of beer|
&& cr_lf
&& |Take one down, pass it around|
&& cr_lf
&& lv && | bottles of beer on the wall|
&& cr_lf IN WHEN 1 = 1 THEN lr )
)
).
cl_demo_output=>write( it_99_bottles ).
cl_demo_output=>display( ).


## Action!

PROC Bottles(BYTE i)
IF i=0 THEN
Print("No more")
ELSE
PrintB(i)
FI
Print(" bottle")
IF i#1 THEN
Print("s")
FI
RETURN

PROC Main()
BYTE i=[99]

WHILE i>0
DO
Bottles(i) PrintE(" of beer on the wall,")
Bottles(i) PrintE(" of beer,")
Print("Take ")
IF i>1 THEN
Print("one")
ELSE
Print("it")
FI
PrintE(" down and pass it around,")
i==-1
Bottles(i) PrintE(" of beer on the wall.")
IF i>0 THEN
PutE()
FI
OD
RETURN
Output:
99 bottles of beer on the wall,
99 bottles of beer,
Take one down and pass it around,
98 bottles of beer on the wall.

...

2 bottles of beer on the wall,
2 bottles of beer,
Take one down and pass it around,
1 bottle of beer on the wall.

1 bottle of beer on the wall,
1 bottle of beer,
Take it down and pass it around,
No more bottles of beer on the wall.


## ActionScript

for(var numBottles:uint = 99; numBottles > 0; numBottles--)
{
trace(numBottles, " bottles of beer on the wall");
trace(numBottles, " bottles of beer");
trace("Take one down, pass it around");
trace(numBottles - 1, " bottles of beer on the wall\n");
}


### Simple version

with Ada.Text_Io; use Ada.Text_Io;

procedure Bottles is
begin
for X in reverse 1..99 loop
Put_Line(Integer'Image(X) & " bottles of beer on the wall");
Put_Line(Integer'Image(X) & " bottles of beer");
Put_Line("Take one down, pass it around");
Put_Line(Integer'Image(X - 1) & " bottles of beer on the wall");
New_Line;
end loop;
end Bottles;


### Concurrent version

with 1 task to print out the information and 99 tasks to specify the number of bottles

with Ada.Text_Io; use Ada.Text_Io;

subtype Num_Bottles is Natural range 1..99;
entry Set (Num_Bottles);
end Print;
Num : Natural;
begin
for I in reverse Num_Bottles'range loop
select
accept
Set(I) do -- Rendezvous with Counter task I
Num := I;
end Set;
Put_Line(Integer'Image(Num) & " bottles of beer on the wall");
Put_Line(Integer'Image(Num) & " bottles of beer");
Put_Line("Take one down, pass it around");
Put_Line(Integer'Image(Num - 1) & " bottles of beer on the wall");
New_Line;
or terminate; -- end when all Counter tasks have completed
end select;
end loop;
end Print;
begin
Print.Set(I);
end Counter;

begin
end loop;


## Aime

integer bottles;

bottles = 99;

do {
o_(bottles, " bottles of beer on the wall\n");
o_(bottles, " bottles of beer\n");
o_("Take one down, pass it around\n");
o_(bottles -= 1, " bottles of beer on the wall\n\n");
} while (bottles);

## Algae

# 99 Bottles of Beer on the Wall
# in Algae
# bottles.A
for (i in 99:1:1) {
if (i != 1) {
printf("%d bottles of beer on the wall\n";i);
printf("%d bottles of beer...\n";i);
printf("you take on down and pass it around...\n");
if ( i == 2) {
printf("%d bottles of beer on the wall\n\n";i-1);
else
printf("%d bottles of beer on the wall\n\n";i-1);
}
else
printf("1 bottle of beer on the wall\n");
printf("1 bottle of beer...\n");
printf("you take on down and pass it around..\n");
printf("no more bottles of beer on the wall!\n\n");
}
}

## ALGOL 60

begin
integer n;

for n:= 99 step -1 until 2 do
begin
outinteger(1,n);
outstring(1,"bottles of beer on the wall,");
outinteger(1,n);
outstring(1,"bottles of beer.\nTake one down and pass it around,");
outstring(1,"of beer on the wall...\n\n")
end;

outstring(1," 1 bottle of beer on the wall, 1 bottle of beer.\n");
outstring(1,"Take one down and pass it around, no more bottles of beer on the wall...\n\n");

outstring(1,"No more bottles of beer on the wall, no more bottles of beer.\n");
outstring(1,"Go to the store and buy some more, 99 bottles of beer on the wall.")
end

## ALGOL 68

Works with: ALGOL 68 version Standard - no extensions to language used
Works with: ALGOL 68G version Any - tested with release mk15-0.8b.fc9.i386
main:(
FOR bottles FROM 99 TO 1 BY -1 DO
printf(($z-d" bottles of beer on the wall"l$, bottles));
printf(($z-d" bottles of beer"l$, bottles));
printf(($"Take one down, pass it around"l$));
printf(($z-d" bottles of beer on the wall"ll$, bottles-1))
OD
)

## ALGOL-M

BEGIN

COMMENT PRINT LYRICS TO "99 BOTTLES OF BEER ON THE WALL";

STRING FUNCTION BOTTLE(N); % GIVE CORRECT GRAMMATICAL FORM %
INTEGER N;
BEGIN
IF N = 1 THEN
BOTTLE := " BOTTLE"
ELSE
BOTTLE := " BOTTLES";
END;

INTEGER N;

N := 99;
WHILE N > 0 DO
BEGIN
WRITE(N, BOTTLE(N), " OF BEER ON THE WALL,");
WRITEON(N, BOTTLE(N), " OF BEER");
WRITE("TAKE ONE DOWN AND PASS IT AROUND, ");
N := N - 1;
IF N = 0 THEN
WRITEON("NO MORE")
ELSE
WRITEON(N);
WRITEON(BOTTLE(N), " OF BEER ON THE WALL");
WRITE(" "); % BLANK LINE BETWEEN STANZAS %
END;
WRITE("THANKS FOR SINGING ALONG!");

END

## AmigaE

PROC main()
DEF t: PTR TO CHAR,
s: PTR TO CHAR,
u: PTR TO CHAR, i, x
t := 'Take one down, pass it around\n'
s := '\d bottle\s of beer\s\n'
u := ' on the wall'
FOR i := 99 TO 0 STEP -1
ForAll({x}, [u, NIL], WriteF(s, i, IF i <> 1 THEN 's' ELSE NIL,
x))
IF i > 0 THEN WriteF(t)
ENDFOR
ENDPROC

## Apache Ant

Implementation in Apache Ant, due to the limitations of Ant, this requires ant-contrib for arithmetic operations and a dummy target to keep Ant from detecting the loop.

<?xml version="1.0"?>
<project name="n bottles" default="99_bottles">

<!-- ant-contrib.sourceforge.net for arithmetic and if -->

<!-- start count of bottles, you can set this with
e.g. ant -f 99.xml -Dcount=10 -->
<property name="count" value="99"/>

<target name="99_bottles">
<antcall target="bottle">
<param name="number" value="${count}"/> </antcall> </target> <target name="bottle"> <echo message="${number} bottles of beer on the wall"/>
<echo message="${number} bottles of beer"/> <echo message="Take one down, pass it around"/> <math result="result" operand1="${number}" operation="-" operand2="1" datatype="int"/>

<echo message="${result} bottles of beer on the wall"/> <if> <not><equals arg1="${result}" arg2="0" /></not>
<then>
<antcall target="bottleiterate">
<param name="number" value="${result}"/> </antcall> </then> </if> </target> <target name="bottleiterate"> <antcall target="bottle"> <param name="number" value="${number}"/>
</antcall>
</target>

</project>


## Apex

   for(Integer i = 99; i=0; i--){
system.debug(i + ' bottles of beer on the wall');
system.debug('\n');
system.debug(i + ' bottles of beer on the wall');
system.debug(i + ' bottles of beer');
system.debug('take one down, pass it around');
}

## APL

Works with: Dyalog APL
Works with: GNU APL

### Classic version

Translation of: J
     bob  ←  { (⍕⍵), ' bottle', (1=⍵)↓'s of beer'}
bobw ←  {(bob ⍵) , ' on the wall'}
beer ←  { (bobw ⍵) , ', ', (bob ⍵) , '; take one down and pass it around, ', bobw ⍵-1}

     ⍝ Dyalog APL invocation
99↑beer¨ ⌽(1-⎕IO)+⍳99

     ⍝ GNU APL invocation (↑ and ⊃ differ, traditional APL2 meanings)
⊃beer¨ ⌽(1-⎕IO)+⍳99


### One line version

     ⍝ Dyalog and GNU APL
⍪{(⍕⍵),' bottles of beer on the wall, take one down and pass it around, ',(⍕⍵-1),' bottles of beer on the wall'}¨⌽⍳99


## App Inventor

### Using a 'for each <number>' block (simplest)

Note that the output label text is not displayed until the entire lyrics text has been built and there is some delay between button press and display. <CLICK HERE TO VIEW THE BLOCKS AND OUTPUT>

### Using a Clock Timer block (preferrred)

Output can be sent directly to a label with this preferred method as there is no noticeable delay between button press and output. <CLICK HERE TO VIEW THE BLOCKS AND OUTPUT>

## AppleScript

### Iteration

repeat with beerCount from 99 to 1 by -1
set bottles to "bottles"
if beerCount < 99 then
if beerCount = 1 then
set bottles to "bottle"
end
log "" & beerCount & " " & bottles & " of beer on the wall"
log ""
end
log "" & beerCount & " " & bottles & " of beer on the wall"
log "" & beerCount & " " & bottles & " of beer"
log "Take one down, pass it around"
end
log "No more bottles of beer on the wall!"


### Declaration

-- BRIEF -----------------------------------------------------------------------
on run
set localisations to ¬
{"on the wall", ¬
"Take one down, pass it around", ¬
"Better go to the store to buy some more", "bottle"}

intercalate("\n\n", ¬
(map(curry(incantation)'s |λ|(localisations), enumFromTo(99, 0))))
end run

-- DECLARATIVE -----------------------------------------------------------------

-- incantation :: [String] -> Int -> String
on incantation(xs, n)
script asset
on |λ|(n)
unwords({(n as string), item -1 of xs & cond(n ≠ 1, "s", "")})
end |λ|
end script

script store
on |λ|(n)
unwords({asset's |λ|(n), item 1 of xs})
end |λ|
end script

set {distribute, solve} to items 2 thru 3 of xs
if n > 0 then
unlines({store's |λ|(n), asset's |λ|(n), distribute, store's |λ|(n - 1)})
else
solve
end if
end incantation

-- GENERICALLY DYSFUNCTIONAL ---------------------------------------------------

-- cond :: Bool -> a -> a -> a
on cond(bln, f, g)
if bln then
f
else
g
end if
end cond

-- curry :: (Script|Handler) -> Script
on curry(f)
script
on |λ|(a)
script
on |λ|(b)
|λ|(a, b) of mReturn(f)
end |λ|
end script
end |λ|
end script
end curry

-- enumFromTo :: Int -> Int -> [Int]
on enumFromTo(m, n)
if m > n then
set d to -1
else
set d to 1
end if
set lst to {}
repeat with i from m to n by d
set end of lst to i
end repeat
return lst
end enumFromTo

-- intercalate :: Text -> [Text] -> Text
on intercalate(strText, lstText)
set {dlm, my text item delimiters} to {my text item delimiters, strText}
set strJoined to lstText as text
set my text item delimiters to dlm
return strJoined
end intercalate

-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map

-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn

-- unlines :: [String] -> String
on unlines(xs)
intercalate(linefeed, xs)
end unlines

-- unwords :: [String] -> String
on unwords(xs)
intercalate(space, xs)
end unwords


## Arbre

bottle(x):
template: '
$x bottles of beer on the wall.$x bottles of beer.
Take one down and pass it around,
$y bottles of beer on the wall. ' if x==0 template~{x: 'No more', y: 'No more'} else if x==1 template~{x: x, y: 'No more'} else template~{x: x, y: x-1} bottles(n): for x in [n..0] bottle(x) 99bottles(): bottles(99) -> io ## Argile use std let X be an int for each X from 99 down to 1 prints X bottles of beer on the wall prints X bottles of beer prints "Take one down, pass it" around if X == 1 echo No more "beer." Call da "amber lamps" break X-- prints X bottles of beer on the wall "\n" X++ .:around :. -> text {X>59 ? "around", "to me"} .:bottles:. -> text {X> 5 ? "bottles", (X>1 ? "buttles", "wall")} .:of beer:. -> text {X>11 ? "of beer", "ov beeer"} .:on the wall:. -> text { X>17 ? "on the wall", (X>1 ? "on the bwall", "in the buttle") } ## ARM Assembly ## ArnoldC As ArnoldC does not feature string concatenation, the numbers of bottles and the rest of the parts of the lyrics are printed on separate lines. IT'S SHOWTIME HEY CHRISTMAS TREE is0 YOU SET US UP @NO PROBLEMO HEY CHRISTMAS TREE bottles YOU SET US UP 99 STICK AROUND is0 TALK TO THE HAND bottles TALK TO THE HAND " bottles of beer on the wall" TALK TO THE HAND bottles TALK TO THE HAND " bottles of beer" TALK TO THE HAND "Take one down, pass it around" GET TO THE CHOPPER bottles HERE IS MY INVITATION bottles GET DOWN 1 ENOUGH TALK TALK TO THE HAND bottles TALK TO THE HAND " bottles of beer on the wall" GET TO THE CHOPPER is0 HERE IS MY INVITATION bottles LET OFF SOME STEAM BENNET 0 ENOUGH TALK CHILL YOU HAVE BEEN TERMINATED ## Arturo s: "s" loop 99..1 'i [ print ~"|i| bottle|s| of beer on the wall," print ~"|i| bottle|s| of beer" print ~"Take one down, pass it around!" if 1=i-1 -> s: "" if? i>1 [ print ~"|i-1| bottle|s| of beer on the wall!" print "" ] else -> print "No more bottles of beer on the wall!" ]  ## AsciiDots  /-99#-. />*$_#-$_" bottles of beer on the wall, "-$_#-$" bottles of beer."\ |[-]1#-----" ,dnuora ti ssap dna nwod eno ekaT"_$-----------------/
| |
| | &-".llaw eht no reeb fo selttob 99 ,erom emos yub dna erots eht ot oG"$\ | |/$""-$"No more bottles of beer on the wall, no more bottles of beer."---/ | |\".llaw eht no reeb fo selttob erom on ,dnuora ti ssap dna nwod eno ekaT"$-".reeb fo elttob 1"$\ | | /-$"1 bottle of beer on the wall."-$""-$_"1 bottle of beer on the wall, "------------/
| | /-------\|
| \-*--{=}-\\~$_#-$" bottles of beer on the wall."\
|   \-#1/  \-/                                    |
\----------------------------------------------""$/ ## Astro fun bottles(n): match __args__: (0) => "No more bottles" (1) => "1 bottle" (_) => "$n bottles"

for n in 99..-1..1:
print @format"""
{bottles n} of beer on the wall
{bottles n} of beer
Take one down, pass it around
{bottles n-1} of beer on the wall\n
"""


## Asymptote

// Rosetta Code problem: http://rosettacode.org/wiki/99_bottles_of_beer
// by Jjuanhdez, 05/2022

int bottles = 99;

for (int i = bottles; i > 0; --i) {
write(string(i), " bottles of beer on the wall,");
write(string(i), " bottles of beer.");
write("Take one down and pass it around,");
if (i == 1) {
write("no more bottles of beer on the wall...");
} else {
write(string(i-1), " bottles of beer on the wall...");
}
}

write("No more bottles of beer on the wall,");
write("no more bottles of beer.");
write("Go to the store and buy some more,");
write(" 99 bottles of beer on the wall.");


## ATS

//
#include
//
(* ****** ****** *)

fun bottles
(n0: int): void = let
//
fun loop (n: int): void =
(
if n > 0 then
(
if n0 > n then println! ();
println! (n, " bottles of beer on the wall");
println! (n, " bottles of beer");
println! ("Take one down, pass it around");
println! (n-1, " bottles of beer on the wall");
loop (n - 1)
) (* end of [if] *)
)
//
in
loop (n0)
end // end of [bottles]

(* ****** ****** *)

implement main0 () = bottles (99)

## AWK

### Regular version

If you don't want so many beers, here you can specify the starting amount.
For example, just a sixpack:

# usage:  gawk  -v i=6  -f beersong.awk

function bb(n) {
b = " bottles of beer"
if( n==1 ) { sub("s","",b) }
if( n==0 ) { n="No more" }
return n b
}

BEGIN {
if( !i ) { i = 99 }
ow = "on the wall"
td = "Take one down, pass it around."
print "The beersong:\n"
while (i > 0) {
printf( "%s %s,\n%s.\n%s\n%s %s.\n\n",
bb(i), ow, bb(i), td, bb(--i), ow )
if( i==1 ) sub( "one","it", td )
}
print "Go to the store and buy some more!"
}

Output:
The beersong:

99 bottles of beer on the wall,
99 bottles of beer.
Take one down, pass it around.
98 bottles of beer on the wall.

...

3 bottles of beer on the wall,
3 bottles of beer.
Take one down, pass it around.
2 bottles of beer on the wall.

2 bottles of beer on the wall,
2 bottles of beer.
Take one down, pass it around.
1 bottle of beer on the wall.

1 bottle of beer on the wall,
1 bottle of beer.
Take it down, pass it around.
No more bottles of beer on the wall.

Go to the store and buy some more!


## Axe

Pauses are added to accommodate the small calculator screen so all of the text can be read.

99→B
While B
Disp B▶Dec," BOTTLES OF","BEER ON THE WALL"
Disp B▶Dec," BOTTLES OF","BEER",i,i
getKeyʳ
Disp "TAKE ONE DOWN",i,"PASS IT AROUND",i
B--
Disp B▶Dec," BOTTLES OF","BEER ON THE WALL",i
getKeyʳ
End

## Babel

-- beer.sp

{b  " bottles of beer"         <
bi { itoa << }                <
bb { bi ! b << w << "\n" << } <
w  " on the wall"             <
beer
{<-
{ iter 1 + dup
<- bb ! ->
bi ! b << "\n" <<
"Take one down, pass it around\n" <<
iter bb ! "\n" << }
->
times}
< }

-- At the prompt, type 'N beer !' (no quotes), where N is the number of stanzas you desire

## Battlestar

const bottle = " bottle"
const plural = "s"
const ofbeer = " of beer"
const wall = " on the wall"
const sep = ", "
const takedown = "Take one down and pass it around, "
const u_no = "No"
const l_no = "no"
const more = " more bottles of beer"
const store = "Go to the store and buy some more, "
const dotnl = ".\n"
const nl = "\n"

// Reserve 1024 bytes in the .bss section
var x 1024

// Write two digits, based on the value in a
fun printnum
b = a
a >= 10
a /= 10
// modulo is in the d register after idiv
b = d
a += 48 // ASCII value for '0'
print(chr(a))
end
a = b
a += 48 // ASCII value for '0'
print(chr(a))
end

fun main
loop 99
// Save loop counter for later, twice
c -> stack
c -> stack

// Print the loop counter (passed in the a register)
a = c
printnum()

// N, "bottles of beer on the wall, "
x = bottle
x += plural
x += ofbeer
x += wall
x += sep
print(x)

// Retrieve and print the number
stack -> a
printnum()

// N, "bottles of beer.\nTake one down and pass it around,"
x = bottle
x += plural
x += ofbeer
x += dotnl
x += takedown
print(x)

// N-1, "bottles of beer on the wall."
stack -> a
a--

// Store N-1, used just a few lines down
a -> stack
printnum()
print(bottle)

// Retrieve N-1
stack -> a

// Write an "s" if the count is not 1
a != 1
print(plural)
end

// Write the rest + a blank line
x = ofbeer
x += wall
x += dotnl
x += nl
print(x)

// Skip to the top of the loop while the counter is >= 2
continue (c >= 2)

// At the last two

// "1 bottle of beer on the wall,"
a = 1
printnum()
x = bottle
x += ofbeer
x += wall
x += sep
print(x)

// "1"
a = 1
printnum()

// "bottle of beer. Take one down and pass it around,"
// "no more bottles of beer on the wall."
// Blank line
// "No more bottles of beer on the wall,"
// "no more bottles of beer."
// "Go to the store and buy some more,"
x = bottle
x += ofbeer
x += dotnl
x += takedown
x += l_no
x += more
x += wall
x += dotnl
x += nl
x += u_no
x += more
x += wall
x += sep
x += l_no
x += more
x += dotnl
x += store
print(x)

// "99"
a = 99
printnum()

// "bottles of beer on the wall."
x = bottle
x += plural
x += ofbeer
x += wall
x += dotnl
print(x)
end
end

// vim: set syntax=c ts=4 sw=4 et:


## Bc

Works with: GNU bc version 1.06
i = 99;
while ( 1 ) {
print i , " bottles of beer on the wall\n";
print i , " bottles of beer\nTake one down, pass it around\n";
if (i == 2) {
break
}
print --i , " bottles of beer on the wall\n";
}

print --i , " bottle of beer on the wall\n";
print   i , " bottle of beer on the wall\n";
print   i , " bottle of beer\nTake it down, pass it around\nno more bottles of beer on the wall\n";
quit


## BCPL

get "libhdr"

let number(n) be
test n=0
then writes("No more")
else writen(n)

let plural(n) be
test n=1
then writes(" bottle")
else writes(" bottles")

let bottles(n) be
$( number(n) plural(n)$)

let verse(n) be
$( bottles(n) writes(" of beer on the wall,*N") bottles(n) writes(" of beer,*NTake ") test n=1 then writes("it") else writes("one") writes(" down and pass it around,*N") bottles(n-1) writes(" of beer on the wall!*N*N")$)

let start() be
for n = 99 to 1 by -1 do verse(n)

## beeswax

Straightforward implementation, displaying the full lyrics given on [ http://99-bottles-of-beer.net/ ]

  >       NN      p
> d#_8~2~(P~3~.~1~>{ bottles of beer on the wall, { bottles of beer.q
d.llaw eht no reeb fo selttob {pLM ,dnuora ti ssap dna nwod eno ekaTN<
q.llaw eht no reeb fo elttob  {<
>        NN       >{ bottle of beer on the wall, { bottle of beer.N  q
pN .llaw eht no reeb fo selttob erom on ,dnuora ti ssap dna nwod eno ekaT<
>NNo more bottles of beer on the wall, no more bottles of beer.N  q
;.llaw eht no reeb fo selttob 99 ,erom emos yub dna erots eht ot oG<

A much more “economic” version that tries to avoid repetition at the price of complicated conditional jumps and self-modifying code that takes up more place than the actual strings themselves. Output is the same as in the straightforward version.

#D@.9~2~@M.7~P9zE       Np
DMM@.9@.~2~.++~5zE      n>op
>0f1ff#             q   erom <           #h3~1z<           #h3~1z<    #h3~1z<
d_8~2~(P~3~.  ~1~>"b{>X^^^ bottle  of beer@g"pX on the wallg"pX   ,  @p #
> d   <#XL#^^^^^s#            #  ##      #        >    .NN@  X#
b                                             <            <  <
>~L#^^^^s#      #h3~1zX    #h3~1z<#      #  #      # #
d             #h3~1z<#            #> .   g"pXN @"p Take one down and p
>^^^^^^^^^;     .#   b              XgNN                    <       bM ,dnuora ti ssap<
d^^^^^^^^^^^^^^^^X~3~P(~2~8 ,erom emos yub dna erots eht ot oG<

## BlitzMax

local bot:int = 99

repeat
print string(bot)+" bottles of beer on the wall,"
print string(bot)+" bottles of beer."
print "Take one down, pass it around,"
bot:-1
print string(bot)+" bottles of beer on the wall."
print
until bot = 1

print "1 bottle of beer on the wall,"
print "1 bottle of beer."
print "Take it down, pass it around,"
print "No more bottles of beer on the wall!"


## BlooP

Output is always in caps in the interpreter I use, but I typed the input in correct case to spare those whose interpreter might do lowercase and don't want to have this song shouted at them ;D.

DEFINE PROCEDURE ''MINUS'' [A,B]:
BLOCK 0: BEGIN
IF A < B, THEN:
QUIT BLOCK 0;
LOOP AT MOST A TIMES:
BLOCK 1: BEGIN
IF OUTPUT + B = A, THEN:
QUIT BLOCK 0;
OUTPUT <= OUTPUT + 1;
BLOCK 1: END;
BLOCK 0: END.

DEFINE PROCEDURE ''BOTTLES'' [COUNT]:
BLOCK 0: BEGIN
CELL(0) <= COUNT;
LOOP COUNT + 1 TIMES:

BLOCK 1: BEGIN

IF CELL(0) > 1, THEN:
PRINT[CELL(0), ' bottles of beer on the wall, ', CELL(0), ' bottles of beer. Take one down, pass it around, ', MINUS[CELL(0), 1], ' bottles of beer on the wall.'];

IF CELL(0) = 1, THEN:
PRINT['1 botle of beer on the wall, 1 bottle of beer. Take one down, pass it around, No more bottles of beer on the wall.'];

IF CELL(0) = 0, THEN:
PRINT['No more bottles of beer on the wall, no more bottles of beer. Go to the store, buy 99 more, 99 bottles of beer on the wall!'];

CELL(0) <= MINUS[CELL(0), 1];

BLOCK 1: END;
BLOCK 0: END.

BOTTLES[99];

## Bracmat

Copy the code to a file called BottlesOfBeer.bra. Start Bracmat and after the {?} prompt write get$"BottlesOfBeer.bra" <Enter>. Then, after the next prompt, write !r <Enter>. Notice that the lyrics has two more lines at the end: No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall. Code to save to BottlesOfBeer.bra: {BottlesOfBeer.bra See http://99-bottles-of-beer.net/} X= new = n upper nbottles lyrics . 99:?n & ( upper = .@(!arg:%@?a ?z)&str$(upp$!a !z) ) & ( nbottles = . str$ ( (   !arg:>0
&   !arg
" bottle"
(!arg:1&|s)
| "no more bottles"
)
" of beer"
)
)
& ( lyrics
=   (upper$(nbottles$!n:?x) " on the wall, " !x ".\n")
(   !n+-1:?n:~<0
&   "Take one down and pass it around, "
nbottles$!n " on the wall. " !lyrics | "Go to the store and buy some more, " nbottles$99
" on the wall.
"
)
)
& put$(str$!lyrics);

r=
get'"BottlesOfBeer.bra"
& rmv$(str$(BottlesOfBeer ".bak"))
& ren$("BottlesOfBeer.bra".str$(BottlesOfBeer ".bak"))
&   put
$( "{BottlesOfBeer.bra See http://99-bottles-of-beer.net/} " , "BottlesOfBeer.bra" , NEW ) & lst'(X,"BottlesOfBeer.bra",APP) & put'(\n,"BottlesOfBeer.bra",APP) & lst'(r,"BottlesOfBeer.bra",APP) & put$(str$("\nnew'" X ";\n"),"BottlesOfBeer.bra",APP); new'X; ## Brainf*** ## Brat 99.to 2 { n | p "#{n} bottles of beer on the wall, #{n} bottles of beer!" p "Take one down, pass it around, #{n - 1} bottle#{true? n > 2 's' ''} of beer on the wall." } p "One bottle of beer on the wall, one bottle of beer!" p "Take one down, pass it around, no more bottles of beer on the wall." ## BQN Pl ← {(𝕩≠1)/"s"} {𝕨∾(@+10)∾𝕩}´{(•Fmt 𝕨)∾" "∾𝕩}´¨∾{ ⟨ ⟨𝕩,"bottle"∾(Pl 𝕩)∾" of beer on the wall"⟩ ⟨𝕩,"bottle"∾(Pl 𝕩)∾" of beer"⟩ ⟨"Take one down, pass it around"⟩ ⟨𝕩-1,"bottle"∾(Pl 𝕩-1)∾" of beer on the wall"∾@+10⟩ ⟩ }¨⌽1+↕99 •Fmt is used to convert numbers to strings. Pl tells whether the number is singular or plural. Then, the two folds join all the individual lines together. ## C Translation of: C++ ### The simple solution /* * 99 Bottles, C, KISS (i.e. keep it simple and straightforward) version */ #include <stdio.h> int main(void) { int n; for( n = 99; n > 2; n-- ) printf( "%d bottles of beer on the wall, %d bottles of beer.\n" "Take one down and pass it around, %d bottles of beer on the wall.\n\n", n, n, n - 1); printf( "2 bottles of beer on the wall, 2 bottles of beer.\n" "Take one down and pass it around, 1 bottle of beer on the wall.\n\n" "1 bottle of beer on the wall, 1 bottle of beer.\n" "Take one down and pass it around, no more bottles of beer on the wall.\n\n" "No more bottles of beer on the wall, no more bottles of beer.\n" "Go to the store and buy some more, 99 bottles of beer on the wall.\n"); return 0; }  ### A recursive solution #include <stdio.h> int main(int argc, char *argv[]) { if(argc == 99) return 99; if(argv[0] != NULL){ argv[0] = NULL; argc = 0; } argc = main(argc + 1, argv); printf("%d bottle%c of beer on the wall\n", argc, argc == 1?'\0': 's'); printf("%d bottle%c of beer\n", argc, argc == 1?'\0': 's'); printf("Take one down, pass it around\n"); printf("%d bottle%c of beer on the wall\n\n", argc - 1, (argc - 1) == 1?'\0': 's'); return argc - 1; }  ### Code golf #include <stdio.h> main(){_=100;while(--_)printf("%i bottle%s of beer in the wall,\n%i bottle%" "s of beer.\nTake one down, pass it round,\n%s%s\n\n",_,_-1?"s":"",_,_-1?"s" :"",_-1?(char[]){(_-1)/10?(_-1)/10+48:(_-1)%10+48,(_-1)/10?(_-1)%10+48:2+30, (_-1)/10?32:0,0}:"",_-1?"bottles of beer in the wall":"No more beers");}  ### A preprocessor solution Of course, with the template metaprogramming solution, the program has still do the conversion of numbers to strings at runtime, and those function calls also cost unnecessary time. Couldn't we just compose the complete text at compile time, and just output it at run time? Well, with the preprocessor, that's indeed possible: #include <stdlib.h> #include <stdio.h> #define BOTTLE(nstr) nstr " bottles of beer" #define WALL(nstr) BOTTLE(nstr) " on the wall" #define PART1(nstr) WALL(nstr) "\n" BOTTLE(nstr) \ "\nTake one down, pass it around\n" #define PART2(nstr) WALL(nstr) "\n\n" #define MIDDLE(nstr) PART2(nstr) PART1(nstr) #define SONG PART1("100") CD2 PART2("0") #define CD2 CD3("9") CD3("8") CD3("7") CD3("6") CD3("5") \ CD3("4") CD3("3") CD3("2") CD3("1") CD4("") #define CD3(pre) CD4(pre) MIDDLE(pre "0") #define CD4(pre) MIDDLE(pre "9") MIDDLE(pre "8") MIDDLE(pre "7") \ MIDDLE(pre "6") MIDDLE(pre "5") MIDDLE(pre "4") MIDDLE(pre "3") \ MIDDLE(pre "2") MIDDLE(pre "1") int main(void) { (void) printf(SONG); return EXIT_SUCCESS; }  An inspection of the generated executable proves that it indeed contains the complete text of the song in one block. ### The bottled version WYSIWYG (with correct plurals and can buy some more):  int b =99,u =1; #include<stdio.h> char *d[16],y[] = "#:ottle/ of" ":eer_ a_Go<o5" "st>y\x20some6" "_Take8;down4p" "a=1rou7_17 _<" "h;_ m?_nd_ on" "_085wal" "l_ " "b_e _ t_ss it" "_?4bu_ore_9, " "\060.""@, 9$";
# define x  c  ^=
#include <string.h>
#define or(t,z) else\
if(c==t && !(c = 0) &&\
(c =! z)); int p(char *t)
{ char *s = t; int c; for (
d[c = 0] = y; !t && (d[c +1
]= strchr(s = d[c], '_'));*
(d[++c]++) = 0); for(t = s?
s:t;(c= *s++); c && putchar
(c)) { if (!((( x 48)& ~0xf
) && ( x 48)) ) p(d[c]), c=
0 ; or('$', p(b - 99?".\n": "." ) && p(b - 99? t : "")) or ('\x40', c && p( d[!!b-- + 2])) or('/', c && p( b^1? "s": "")) or ('\043', b++ ? p("So6" + --b):!printf("%d" , b ? --b : (b += 99))) or( 'S',!(++u % 3) * 32+ 78) or ('.', puts("."))}return c;} int main() {return p(0);}  ## C# using System; class Program { static void Main(string[] args) { for (int i = 99; i > -1; i--) { if (i == 0) { Console.WriteLine("No more bottles of beer on the wall, no more bottles of beer."); Console.WriteLine("Go to the store and buy some more, 99 bottles of beer on the wall."); break; } if (i == 1) { Console.WriteLine("1 bottle of beer on the wall, 1 bottle of beer."); Console.WriteLine("Take one down and pass it around, no more bottles of beer on the wall."); Console.WriteLine(); } else { Console.WriteLine("{0} bottles of beer on the wall, {0} bottles of beer.", i); Console.WriteLine("Take one down and pass it around, {0} bottles of beer on the wall.", i - 1); Console.WriteLine(); } } } }  ### C#6 Implementation Works with: C# version 6+ using System; class Program { static void Main() { Func<int, bool, string> f = (x, y) =>$"{(x == 0 ? "No more" : x.ToString())} bottle{(x == 1 ? "" : "s")} of beer{(y ? " on the wall" : "")}\r\n";
for (int i = 99; i > 0; i--)
$"Take {(x == 1 ? "it" : "one")} down, pass it around, {(x == 1 ? "no more" : (x - 1).ToString())} bottles of beer on the wall!\n" ).ToList().ForEach(x => Console.WriteLine(x)); } }  ### Flexible Version using System; using System.Globalization; class Program { const string Vessel = "bottle"; const string Beverage = "beer"; const string Location = "on the wall"; private static string DefaultAction(ref int bottles) { bottles--; return "take one down, pass it around,"; } private static string FallbackAction(ref int bottles) { bottles += 99; return "go to the store, buy some more,"; } private static string Act(ref int bottles) { return bottles > 0 ? DefaultAction(ref bottles) : FallbackAction(ref bottles); } static void Main() { Func<int, string> plural = b => b == 1 ? "" : "s"; Func<int, string> describeCount = b => b == 0 ? "no more" : b.ToString(); Func<int, string> describeBottles = b => string.Format("{0} {1}{2} of {3}", describeCount(b), Vessel, plural(b), Beverage); Action<string> write = s => Console.WriteLine(CultureInfo.CurrentCulture.TextInfo.ToTitleCase(s)); int bottles = 99; while (true) { write(string.Format("{0} {1}, {0},", describeBottles(bottles), Location)); write(Act(ref bottles)); write(string.Format("{0} {1}.", describeBottles(bottles), Location)); write(string.Empty); } } }  ### Using Formatting Works with: C# version 3+ class songs { static void Main(string[] args) { beer(3); } private static void beer(int bottles) { for (int i = bottles; i > 0; i--) { if (i > 1) { Console.Write("{0}\n{1}\n{2}\n{3}\n\n", i + " bottles of beer on the wall", i + " bottles of beer", "Take one down, pass it around", (i - 1) + " bottles of beer on the wall"); } else Console.Write("{0}\n{1}\n{2}\n{3}\n\n", i + " bottle of beer on the wall", i + " bottle of beer", "Take one down, pass it around", (i - 1) + " bottles of beer on the wall...."); } } }  Output: 3 bottles of beer on the wall 3 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottles of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 0 bottles of beer on the wall....  ### Using iterator blocks Works with: C# version 3+ using System; using System.Linq; class Program { static void Main() { BeerBottles().Take(99).ToList().ForEach(Console.WriteLine); } static IEnumerable<String> BeerBottles() { int i = 100; String f = "{0}, {1}. Take one down, pass it around, {2}"; Func<int, bool, String> booze = (c , b) => String.Format("{0} bottle{1} of beer{2}", c>0 ? c.ToString() : "no more", (c==1 ? "" : "s"), b ? " on the wall" : ""); while (--i >= 1) yield return String.Format(f, booze(i, true), booze(i, false), booze(i - 1, true)); } }  ### A Fun One string[] bottles = { "80 Shilling", "Abita Amber", "Adams Broadside Ale", "Altenmünster Premium", "August Schell's SnowStorm", "Bah Humbug! Christmas Ale", "Beck's Oktoberfest", "Belhaven Wee Heavy", "Bison Chocolate Stout", "Blue Star Wheat Beer", "Bridgeport Black Strap Stout", "Brother Thelonius Belgian-Style Abbey Ale", "Capital Blonde Doppelbock", "Carta Blanca", "Celis Raspberry Wheat", "Christian Moerlein Select Lager", "Corona", "Czechvar", "Delirium Tremens", "Diamond Bear Southern Blonde", "Don De Dieu", "Eastside Dark", "Eliot Ness", "Flying Dog K-9 Cruiser Altitude Ale", "Fuller's London Porter", "Gaffel Kölsch", "Golden Horseshoe", "Guinness Pub Draught", "Hacker-Pschorr Weisse", "Hereford & Hops Black Spring Double Stout", "Highland Oatmeal Porter", "Ipswich Ale", "Iron City", "Jack Daniel's Amber Lager", "Jamaica Sunset India Pale Ale", "Killian's Red", "König Ludwig Weiss", "Kronenbourg 1664", "Lagunitas Hairy Eyball Ale", "Left Hand Juju Ginger", "Locktender Lager", "Magic Hat Blind Faith", "Missing Elf Double Bock", "Muskoka Cream Ale ", "New Glarus Cherry Stout", "Nostradamus Bruin", "Old Devil", "Ommegang Three Philosophers", "Paulaner Hefe-Weizen Dunkel", "Perla Chmielowa Pils", "Pete's Wicked Springfest", "Point White Biere", "Prostel Alkoholfrei", "Quilmes", "Rahr's Red", "Rebel Garnet", "Rickard's Red", "Rio Grande Elfego Bock", "Rogue Brutal Bitter", "Roswell Alien Amber Ale", "Russian River Pliny The Elder", "Samuel Adams Blackberry Witbier", "Samuel Smith's Taddy Porter", "Schlafly Pilsner", "Sea Dog Wild Blueberry Wheat Ale", "Sharp's", "Shiner 99", "Sierra Dorada", "Skullsplitter Orkney Ale", "Snake Chaser Irish Style Stout", "St. Arnold Bock", "St. Peter's Cream Stout", "Stag", "Stella Artois", "Stone Russian Imperial Stout", "Sweetwater Happy Ending Imperial Stout", "Taiwan Gold Medal", "Terrapin Big Hoppy Monster", "Thomas Hooker American Pale Ale", "Tie Die Red Ale", "Toohey's Premium", "Tsingtao", "Ugly Pug Black Lager", "Unibroue Qatre-Centieme", "Victoria Bitter", "Voll-Damm Doble Malta", "Wailing Wench Ale", "Warsteiner Dunkel", "Wellhead Crude Oil Stout", "Weyerbacher Blithering Idiot Barley-Wine Style Ale", "Wild Boar Amber", "Würzburger Oktoberfest", "Xingu Black Beer", "Yanjing", "Younger's Tartan Special", "Yuengling Black & Tan", "Zagorka Special", "Zig Zag River Lager", "Zywiec" }; int bottlesLeft = 99; const int FIRST_LINE_SINGULAR = 98; const int FINAL_LINE_SINGULAR = 97; string firstLine = ""; string finalLine = ""; for (int i = 0; i < 99; i++) { firstLine = bottlesLeft.ToString() + " bottle"; if (i != FIRST_LINE_SINGULAR) firstLine += "s"; firstLine += " of beer on the wall, " + bottlesLeft.ToString() + " bottle"; if (i != FIRST_LINE_SINGULAR) firstLine += "s"; firstLine += " of beer"; Console.WriteLine(firstLine); Console.WriteLine("Take the " + bottles[i] + " down, pass it around,"); bottlesLeft--; finalLine = bottlesLeft.ToString() + " bottle"; if (i != FINAL_LINE_SINGULAR) finalLine += "s"; finalLine += " of beer on the wall!"; Console.WriteLine(finalLine); Console.WriteLine(); Console.ReadLine(); }  ### Using recursion public static void BottlesSong(int numberOfBottles) { if (numberOfBottles > 0) { Console.WriteLine("{0} bottles of beer on the wall", numberOfBottles); Console.WriteLine("{0} bottles of beer ", numberOfBottles); Console.WriteLine("Take one down, pass it around"); Console.WriteLine("{0} bottles of beer ", numberOfBottles - 1); Console.WriteLine(); BottlesSong(--numberOfBottles); } }  ### Using a While Loop static void Main(string[] args) { int numBottles = 99; while (numBottles > 0) { if (numBottles > 1) { WriteLine("{0} bottles of beer on the wall, {0} bottles of beer.", numBottles); numBottles -= 1; WriteLine("Take one down, pass it around, {0} bottles of beer on the wall.\n", numBottles); } else { WriteLine("{0} bottle of beer on the wall, {0} bottle of beer.", numBottles); numBottles -= 1; WriteLine("Take one down, pass it around, no more bottles of beer on the wall.\n"); } } WriteLine("No more bottles of beer on the wall, no more bottles of beer."); WriteLine("Go to the store to buy some more, 99 bottles of beer on the wall..."); }  ## C++ ### The simple solution Works with: g++ version 4.8.1 #include <iostream> using std::cout; int main() { for(int bottles(99); bottles > 0; bottles -= 1){ cout << bottles << " bottles of beer on the wall\n" << bottles << " bottles of beer\n" << "Take one down, pass it around\n" << bottles - 1 << " bottles of beer on the wall\n\n"; } }  ### An object-oriented solution ### A template metaprogramming solution Of course, the output of the program always looks the same. One may therefore question why the program has to do all that tedious subtracting during runtime. Couldn't the compiler just generate the code to output the text, with ready-calculated constants? Indeed, it can, and the technique is called template metaprogramming. The following short code gives the text without containing a single variable, let alone a loop: #include <iostream> template<int max, int min> struct bottle_countdown { static const int middle = (min + max)/2; static void print() { bottle_countdown<max, middle+1>::print(); bottle_countdown<middle, min>::print(); } }; template<int value> struct bottle_countdown<value, value> { static void print() { std::cout << value << " bottles of beer on the wall\n" << value << " bottles of beer\n" << "Take one down, pass it around\n" << value-1 << " bottles of beer\n\n"; } }; int main() { bottle_countdown<100, 1>::print(); return 0; }  ### A function template solution Function templates are a different approach to template metaprogramming: #include <iostream> template<unsigned int N> void bottles(){ std::cout << N << " bottles of beer on the wall\n" << N << " bottles of beer\n" << "Take one down, pass it around\n" << N - 1 << " bottles of beer on the wall\n\n"; bottles<N-1>(); } template<> void bottles<0>(){ std::cout<<"No more bottles of beer on the wall\n" "No more bottles of beer\n" "Go to the store and buy some more\n" "99 bottles of beer on the wall...\n\n"; } int main(){ bottles<99>(); }  ### A Recursive solution #include <iostream> using namespace std; void rec(int bottles) { if ( bottles!=0) { cout << bottles << " bottles of beer on the wall" << endl; cout << bottles << " bottles of beer" << endl; cout << "Take one down, pass it around" << endl; cout << --bottles << " bottles of beer on the wall\n" << endl; rec(bottles); } } int main() { rec(99); system("pause"); return 0; }  ### A preprocessor solution Of course, with the template metaprogramming solution, the program has still do the conversion of numbers to strings at runtime, and those function calls also cost unnecessary time. Couldn't we just compose the complete text at compile time, and just output it at run time? Well, with the preprocessor, that's indeed possible: #include <iostream> #include <ostream> #define BOTTLE(nstr) nstr " bottles of beer" #define WALL(nstr) BOTTLE(nstr) " on the wall" #define PART1(nstr) WALL(nstr) "\n" BOTTLE(nstr) \ "\nTake one down, pass it around\n" #define PART2(nstr) WALL(nstr) "\n\n" #define MIDDLE(nstr) PART2(nstr) PART1(nstr) #define SONG PART1("100") CD2 PART2("0") #define CD2 CD3("9") CD3("8") CD3("7") CD3("6") CD3("5") \ CD3("4") CD3("3") CD3("2") CD3("1") CD4("") #define CD3(pre) CD4(pre) MIDDLE(pre "0") #define CD4(pre) MIDDLE(pre "9") MIDDLE(pre "8") MIDDLE(pre "7") \ MIDDLE(pre "6") MIDDLE(pre "5") MIDDLE(pre "4") MIDDLE(pre "3") \ MIDDLE(pre "2") MIDDLE(pre "1") int main() { std::cout << SONG; return 0; }  ### Bottled Version  //>,_ //Beer Song>,_ #include <iostream> using namespace std; int main(){ for( int b=-1; b<99; cout << '\n') for ( int w=0; w<3; cout << ".\n"){ if (w==2) cout << (( b--) ?"Take one dow" "n and pass it arou" "nd":"Go to the sto" "re and buy some mo" "re"); if (b<0) b=99 ; do{ if (w) cout << ", "; if (b) cout << b; else cout << ( (w) ? 'n' : 'N') << "o more"; cout << " bottle" ; if (b!=1) cout << 's' ; cout << " of beer"; if (w!=1) cout << " on th" "e wall" ;} while (!w++);} return 0 ; } // // by barrym 2011-05-01 // no bottles were harmed in the // making of this program!!!  ## Ceylon shared void ninetyNineBottles() { String bottles(Integer count) => "count == 0 then "No" else count bottlecount == 1 then "" else "s"".normalized; for(i in 99..1) { print("bottles(i) of beer on the wall bottles(i) of beer! Take one down, pass it around bottles(i - 1) of beer on the wall!\n"); } }  ## Chapel copied from http://99-bottles-of-beer.net/language-chapel-1215.html, with minor modifications for chapel 1.7 Works with: Chapel version 1.7.0 /*********************************************************************** * Chapel implementation of "99 bottles of beer" * * by Brad Chamberlain and Steve Deitz * 07/13/2006 in Knoxville airport while waiting for flight home from * HPLS workshop * compiles and runs with chpl compiler version 1.7.0 * for more information, contact: chapel_info@cray.com * * * Notes: * o as in all good parallel computations, boundary conditions * constitute the vast bulk of complexity in this code (invite Brad to * tell you about his zany boundary condition simplification scheme) * o uses type inference for variables, arguments * o relies on integer->string coercions * o uses named argument passing (for documentation purposes only) ***********************************************************************/ // allow executable command-line specification of number of bottles // (e.g., ./a.out -snumBottles=999999) config const numBottles = 99; const numVerses = numBottles+1; // a domain to describe the space of lyrics var LyricsSpace: domain(1) = {1..numVerses}; // array of lyrics var Lyrics: [LyricsSpace] string; // parallel computation of lyrics array [verse in LyricsSpace] Lyrics(verse) = computeLyric(verse); // as in any good parallel language, I/O to stdout is serialized. // (Note that I/O to a file could be parallelized using a parallel // prefix computation on the verse strings' lengths with file seeking) writeln(Lyrics); // HELPER FUNCTIONS: proc computeLyric(verseNum) { var bottleNum = numBottles - (verseNum - 1); var nextBottle = (bottleNum + numVerses - 1)%numVerses; return "\n" // disguise space used to separate elements in array I/O + describeBottles(bottleNum, startOfVerse=true) + " on the wall, " + describeBottles(bottleNum) + ".\n" + computeAction(bottleNum) + describeBottles(nextBottle) + " on the wall.\n"; } proc describeBottles(bottleNum, startOfVerse:bool = false) { // NOTE: bool should not be necessary here (^^^^); working around bug var bottleDescription = if (bottleNum) then bottleNum:string else (if startOfVerse then "N" else "n") + "o more"; return bottleDescription + " bottle" + (if (bottleNum == 1) then "" else "s") + " of beer"; } proc computeAction(bottleNum) { return if (bottleNum == 0) then "Go to the store and buy some more, " else "Take one down and pass it around, "; }  ## Chef ## Cind execute() { // this class provides synchronization // to get unique number of the bottle class monitor giver { int number = 100; .get() { return --number; } } var g = new giver(); // start 99 concurrently worked threads // each thread gets own number of the bottle and prints out his own verse // (notice that the output lines from the threads will be mixed together) {#[99] int nr = g.get(); // get own number host.println(nr," bottles of beer on the wall, "+nr+" bottles of beer"); host.print("Take one down, pass it around,"); if (nr > 1) { host.println((nr-1)," bottles of beer on the wall."); } else { host.println("no more bottles of beer on the wall."); } } host.println("No more bottles of beer on the wall, no more bottles of beer."); host.println("Go to the store and buy some more, 99 bottles of beer on the wall."); return 0; } ## Clay /* A few options here: I could give n type Int; or specify that n is of any numeric type; but here I just let it go -- that way it'll work with anything that compares with 1 and that printTo knows how to convert to a string. And all checked at compile time, remember. */ getRound(n) { var s = String(); var bottle = if (n == 1) " bottle " else " bottles "; printTo(s, n, bottle, "of beer on the wall\n", n, bottle, "of beer\n", "take one down, pass it around\n", n, bottle, "of beer on the wall!\n"); return s; } main() { println(join("\n", mapped(getRound, reversed(range(100))))); }  ## Clio fn bottle n: n -> if = 0: 'no more bottles' elif = 1: n + ' bottle' else: n + ' bottles' [99:0] -> * (@eager) fn i: i -> bottle -> print (transform i: sentence-case) 'of beer on the wall,' @ 'of beer.' if i = 0: 'Go to the store, buy some more, 99 bottles of beer on the wall.' -> print else: i - 1 -> bottle -> print 'Take one down and pass it around,' @ 'of beer on the wall.\n' ## CLIPS (deffacts beer-bottles (bottles 99)) (deffunction bottle-count (?count) (switch ?count (case 0 then "No more bottles of beer") (case 1 then "1 more bottle of beer") (default (str-cat ?count " bottles of beer")))) (defrule stanza ?bottles <- (bottles ?count) => (retract ?bottles) (printout t (bottle-count ?count) " on the wall," crlf) (printout t (bottle-count ?count) "." crlf) (printout t "Take one down, pass it around," crlf) (printout t (bottle-count (- ?count 1)) " on the wall." crlf crlf) (if (> ?count 1) then (assert (bottles (- ?count 1))))) ## Clojure (defn paragraph [num] (str num " bottles of beer on the wall\n" num " bottles of beer\n" "Take one down, pass it around\n" (dec num) " bottles of beer on the wall.\n")) (defn lyrics [] (let [numbers (range 99 0 -1) paragraphs (map paragraph numbers)] (clojure.string/join "\n" paragraphs))) (print (lyrics))  Or, using cl-format: Translation of: Common Lisp (clojure.pprint/cl-format true "~{~[~^~]~:*~D bottle~:P of beer on the wall~%~:*~D bottle~:P of beer Take one down, pass it around,~%~D bottle~:P~:* of beer on the wall.~2%~}" (range 99 0 -1))  ## CLU bottles = proc (n: int) returns (string) if n<0 then return("99 bottles") elseif n=0 then return("No more bottles") elseif n=1 then return("1 bottle") else return(int$unparse(n) || " bottles")
end
end bottles

thirdline = proc (n: int) returns (string)
if n=0 then
return("Go to the store and buy some more,\n")
else
s: string
if n=1 then s := "it"
else s := "one"
end
return("Take " || s || " down and pass it around,\n");
end
end thirdline

verse = proc (n: int) returns (string)
v: string := bottles(n) || " bottles of beer on the wall,\n"
v := v || bottles(n) || " bottles of beer,\n"
v := v || thirdline(n)
v := v || bottles(n-1) || " bottles of beer on the wall.\n\n"
return(v)
end verse

start_up = proc ()
po: stream := stream$primary_output() for n: int in int$from_to_by(99, 0, -1) do
stream$puts(po, verse(n)) end end start_up ## COBOL Works with: OpenCOBOL version 1.1 Free form version. identification division. program-id. ninety-nine. environment division. data division. working-storage section. 01 counter pic 99. 88 no-bottles-left value 0. 88 one-bottle-left value 1. 01 parts-of-counter redefines counter. 05 tens pic 9. 05 digits pic 9. 01 after-ten-words. 05 filler pic x(7) value spaces. 05 filler pic x(7) value "Twenty". 05 filler pic x(7) value "Thirty". 05 filler pic x(7) value "Forty". 05 filler pic x(7) value "Fifty". 05 filler pic x(7) value "Sixty". 05 filler pic x(7) value "Seventy". 05 filler pic x(7) value "Eighty". 05 filler pic x(7) value "Ninety". 05 filler pic x(7) value spaces. 01 after-ten-array redefines after-ten-words. 05 atens occurs 10 times pic x(7). 01 digit-words. 05 filler pic x(9) value "One". 05 filler pic x(9) value "Two". 05 filler pic x(9) value "Three". 05 filler pic x(9) value "Four". 05 filler pic x(9) value "Five". 05 filler pic x(9) value "Six". 05 filler pic x(9) value "Seven". 05 filler pic x(9) value "Eight". 05 filler pic x(9) value "Nine". 05 filler pic x(9) value "Ten". 05 filler pic x(9) value "Eleven". 05 filler pic x(9) value "Twelve". 05 filler pic x(9) value "Thirteen". 05 filler pic x(9) value "Fourteen". 05 filler pic x(9) value "Fifteen". 05 filler pic x(9) value "Sixteen". 05 filler pic x(9) value "Seventeen". 05 filler pic x(9) value "Eighteen". 05 filler pic x(9) value "Nineteen". 05 filler pic x(9) value spaces. 01 digit-array redefines digit-words. 05 adigits occurs 20 times pic x(9). 01 number-name pic x(15). procedure division. 100-main section. 100-setup. perform varying counter from 99 by -1 until no-bottles-left perform 100-show-number display " of beer on the wall" perform 100-show-number display " of beer" display "Take " with no advancing if one-bottle-left display "it " with no advancing else display "one " with no advancing end-if display "down and pass it round" subtract 1 from counter giving counter perform 100-show-number display " of beer on the wall" add 1 to counter giving counter display space end-perform. display "No more bottles of beer on the wall" display "No more bottles of beer" display "Go to the store and buy some more" display "Ninety Nine bottles of beer on the wall" stop run. 100-show-number. if no-bottles-left display "No more" with no advancing else if counter < 20 display function trim( adigits( counter ) ) with no advancing else if counter < 100 move spaces to number-name string atens( tens ) delimited by space, space delimited by size, adigits( digits ) delimited by space into number-name display function trim( number-name) with no advancing end-if end-if end-if. if one-bottle-left display " bottle" with no advancing else display " bottles" with no advancing end-if. 100-end. end-program.  Another free-form version, without using DISPLAY NO ADVANCING. identification division. program-id. ninety-nine. environment division. data division. working-storage section. 01 counter pic 99. 88 no-bottles-left value 0. 88 one-bottle-left value 1. 01 parts-of-counter redefines counter. 05 tens pic 9. 05 digits pic 9. 01 after-ten-words. 05 filler pic x(7) value spaces. 05 filler pic x(7) value "Twenty". 05 filler pic x(7) value "Thirty". 05 filler pic x(7) value "Forty". 05 filler pic x(7) value "Fifty". 05 filler pic x(7) value "Sixty". 05 filler pic x(7) value "Seventy". 05 filler pic x(7) value "Eighty". 05 filler pic x(7) value "Ninety". 05 filler pic x(7) value spaces. 01 after-ten-array redefines after-ten-words. 05 atens occurs 10 times pic x(7). 01 digit-words. 05 filler pic x(9) value "One". 05 filler pic x(9) value "Two". 05 filler pic x(9) value "Three". 05 filler pic x(9) value "Four". 05 filler pic x(9) value "Five". 05 filler pic x(9) value "Six". 05 filler pic x(9) value "Seven". 05 filler pic x(9) value "Eight". 05 filler pic x(9) value "Nine". 05 filler pic x(9) value "Ten". 05 filler pic x(9) value "Eleven". 05 filler pic x(9) value "Twelve". 05 filler pic x(9) value "Thirteen". 05 filler pic x(9) value "Fourteen". 05 filler pic x(9) value "Fifteen". 05 filler pic x(9) value "Sixteen". 05 filler pic x(9) value "Seventeen". 05 filler pic x(9) value "Eighteen". 05 filler pic x(9) value "Nineteen". 05 filler pic x(9) value spaces. 01 digit-array redefines digit-words. 05 adigits occurs 20 times pic x(9). 01 number-name pic x(15). 01 stringified pic x(30). 01 outline pic x(50). 01 other-numbers. 03 n pic 999. 03 r pic 999. procedure division. 100-main section. 100-setup. perform varying counter from 99 by -1 until no-bottles-left move spaces to outline perform 100-show-number string stringified delimited by "|", space, "of beer on the wall" into outline end-string display outline end-display move spaces to outline string stringified delimited by "|", space, "of beer" into outline end-string display outline end-display move spaces to outline move "Take" to outline if one-bottle-left string outline delimited by space, space, "it" delimited by size, space, "|" into outline end-string else string outline delimited by space, space, "one" delimited by size, space, "|" into outline end-string end-if string outline delimited by "|", "down and pass it round" delimited by size into outline end-string display outline end-display move spaces to outline subtract 1 from counter giving counter end-subtract perform 100-show-number string stringified delimited by "|", space, "of beer on the wall" into outline end-string display outline end-display add 1 to counter giving counter end-add display space end-display end-perform. display "No more bottles of beer on the wall" display "No more bottles of beer" display "Go to the store and buy some more" display "Ninety-Nine bottles of beer on the wall" stop run. 100-show-number. if no-bottles-left move "No more|" to stringified else if counter < 20 string function trim( adigits( counter ) ), "|" into stringified else if counter < 100 move spaces to number-name string atens( tens ) delimited by space, space delimited by size, adigits( digits ) delimited by space into number-name end-string move function trim( number-name) to stringified divide counter by 10 giving n remainder r end-divide if r not = zero inspect stringified replacing first space by "-" end-if inspect stringified replacing first space by "|" end-if end-if end-if. if one-bottle-left string stringified delimited by "|", space, "bottle|" delimited by size into stringified end-string else string stringified delimited by "|", space, "bottles|" delimited by size into stringified end-string end-if. 100-end. end-program.  A more concise version that adheres to the minimum guidelines. Leading zeros are not suppressed. (OpenCOBOL - 1.1.0) program-id. ninety-nine. data division. working-storage section. 01 cnt pic 99. procedure division. perform varying cnt from 99 by -1 until cnt < 1 display cnt " bottles of beer on the wall" display cnt " bottles of beer" display "Take one down, pass it around" subtract 1 from cnt display cnt " bottles of beer on the wall" add 1 to cnt display space end-perform.  ## CoffeeScript bottlesOfBeer = (n) -> "#{n} bottle#{if n is 1 then '' else 's'} of beer" console.log """ #{bottlesOfBeer n} on the wall #{bottlesOfBeer n} Take one down, pass it around #{bottlesOfBeer n - 1} on the wall \n""" for n in [99..1]  With completely different approach... for j in [99..1] x='' x += [j,j-1,'\nTake one down, pass it around\n'," bottles of beer",' on the wall\n'][i] for i in [0,3,4,0,3,2,1,3,4] console.log x.replace /(1.+)s/g, '$1'


or as a one liner...

console.log( if (j+2)%4 then (x=Math.round j/4)+" bottle#{if x-1 then 's' else ''} of beer#{if (j+1)%4 then ' on the wall' else ''}" else "Take one down, pass it around" ) for j in [396..1]


or another completely different one liner

((console.log if i is 2 then "Take one down, pass it around" else "#{b-!(i-1%4)} bottle#{if 4*b+i<10 and b-i then '' else 's'} of beer#{if i%3 then ' on the wall' else ''}") for i in [4..1]) for b in [99..1]


## ColdFusion

### Classic tag based CFML

<cfoutput>
<cfloop index="x" from="99" to="0" step="-1">
<cfset plur = iif(x is 1,"",DE("s"))>
#x# bottle#plur# of beer on the wall<br>
#x# bottle#plur# of beer<br>
Take one down, pass it around<br>
#iif(x is 1,DE("No more"),"x-1")# bottle#iif(x is 2,"",DE("s"))# of beer on the wall<br><br>
</cfloop>
</cfoutput>


or if you prefer: (identical output, grammatically correct to the last stanza)

### CFScript

<cfscript>
for (x=99; x gte 1; x--) {
plur = iif(x==1,'',DE('s'));
WriteOutput("#x# bottle#plur# of beer on the wall<br>#x# bottle#plur# of beer<br>Take one down, pass it around<br>#iif(x is 1,DE('No more'),'x-1')# bottle#iif(x is 2,'',DE('s'))# of beer on the wall<br><br>");
}
</cfscript>


## Comal

0010 DIM itone$(0:1) 0020 itone$(0):="one";itone$(1):="it" 0030 FOR b#:=99 TO 1 STEP -1 DO 0040 bottles(b#) 0050 PRINT "of beer on the wall," 0060 bottles(b#) 0070 PRINT "of beer," 0080 PRINT "Take ",itone$(b#=1)," down and pass it around,"
0090   bottles(b#-1)
0100   PRINT "of beer on the wall!"
0110   PRINT
0120 ENDFOR b#
0130 PROC bottles(b#) CLOSED
0140   CASE b# OF
0150   WHEN 0
0160     PRINT "No more bottles ",
0170   WHEN 1
0180     PRINT "1 bottle ",
0190   OTHERWISE
0200     PRINT b#," bottles ",
0210   ENDCASE
0220 ENDPROC bottles
0230 END

## Comefrom0x10

bottles = ' bottles '
remaining = 99
one_less_bottle = remaining
depluralize
comefrom drinking if one_less_bottle is 1
bottles = ' bottle '

drinking
comefrom if remaining is one_less_bottle
remaining bottles 'of beer on the wall'
remaining bottles 'of beer'
'Take one down, pass it around'
one_less_bottle = remaining - 1
one_less_bottle bottles 'of beer on the walln'
remaining = remaining - 1

comefrom if one_less_bottle is 0
'No more bottles of beer on the wall'
Output:
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall

1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No more bottles of beer on the wall


## Cowgol

include "cowgol.coh";

sub Bottles(n: uint8) is
if n == 0 then
print("No more");
else
print_i8(n);
end if;

print(" bottle");
if n != 1 then
print("s");
end if;
end sub;

sub Verse(n: uint8) is
Bottles(n);
print(" of beer on the wall,\n");
Bottles(n);
print(" of beer,\n");
print("Take ");
if n == 1 then
print("it");
else
print("one");
end if;
print(" down and pass it around,\n");
Bottles(n-1);
print(" of beer on the wall.\n\n");
end sub;

var verse: uint8 := 99;
while verse > 0 loop
Verse(verse);
verse := verse - 1;
end loop;
Output:
99 bottles of beer on the wall,
99 bottles of beer,
Take one down and pass it around,
98 bottles of beer on the wall.

98 bottles of beer on the wall,
98 bottles of beer,
Take one down and pass it around,
97 bottles of beer on the wall.

97 bottles of beer on the wall,
97 bottles of beer,
Take one down and pass it around,
96 bottles of beer on the wall.

96 bottles of beer on the wall,
96 bottles of beer,
Take one down and pass it around,
95 bottles of beer on the wall.

95 bottles of beer on the wall,
95 bottles of beer,
Take one down and pass it around,
94 bottles of beer on the wall.

94 bottles of beer on the wall,
94 bottles of beer,
Take one down and pass it around,
93 bottles of beer on the wall.

93 bottles of beer on the wall,
93 bottles of beer,
Take one down and pass it around,
92 bottles of beer on the wall.

92 bottles of beer on the wall,
92 bottles of beer,
Take one down and pass it around,
91 bottles of beer on the wall.

91 bottles of beer on the wall,
91 bottles of beer,
Take one down and pass it around,
90 bottles of beer on the wall.

90 bottles of beer on the wall,
90 bottles of beer,
Take one down and pass it around,
89 bottles of beer on the wall.

89 bottles of beer on the wall,
89 bottles of beer,
Take one down and pass it around,
88 bottles of beer on the wall.

88 bottles of beer on the wall,
88 bottles of beer,
Take one down and pass it around,
87 bottles of beer on the wall.

87 bottles of beer on the wall,
87 bottles of beer,
Take one down and pass it around,
86 bottles of beer on the wall.

86 bottles of beer on the wall,
86 bottles of beer,
Take one down and pass it around,
85 bottles of beer on the wall.

85 bottles of beer on the wall,
85 bottles of beer,
Take one down and pass it around,
84 bottles of beer on the wall.

84 bottles of beer on the wall,
84 bottles of beer,
Take one down and pass it around,
83 bottles of beer on the wall.

83 bottles of beer on the wall,
83 bottles of beer,
Take one down and pass it around,
82 bottles of beer on the wall.

82 bottles of beer on the wall,
82 bottles of beer,
Take one down and pass it around,
81 bottles of beer on the wall.

81 bottles of beer on the wall,
81 bottles of beer,
Take one down and pass it around,
80 bottles of beer on the wall.

80 bottles of beer on the wall,
80 bottles of beer,
Take one down and pass it around,
79 bottles of beer on the wall.

79 bottles of beer on the wall,
79 bottles of beer,
Take one down and pass it around,
78 bottles of beer on the wall.

78 bottles of beer on the wall,
78 bottles of beer,
Take one down and pass it around,
77 bottles of beer on the wall.

77 bottles of beer on the wall,
77 bottles of beer,
Take one down and pass it around,
76 bottles of beer on the wall.

76 bottles of beer on the wall,
76 bottles of beer,
Take one down and pass it around,
75 bottles of beer on the wall.

75 bottles of beer on the wall,
75 bottles of beer,
Take one down and pass it around,
74 bottles of beer on the wall.

74 bottles of beer on the wall,
74 bottles of beer,
Take one down and pass it around,
73 bottles of beer on the wall.

73 bottles of beer on the wall,
73 bottles of beer,
Take one down and pass it around,
72 bottles of beer on the wall.

72 bottles of beer on the wall,
72 bottles of beer,
Take one down and pass it around,
71 bottles of beer on the wall.

71 bottles of beer on the wall,
71 bottles of beer,
Take one down and pass it around,
70 bottles of beer on the wall.

70 bottles of beer on the wall,
70 bottles of beer,
Take one down and pass it around,
69 bottles of beer on the wall.

69 bottles of beer on the wall,
69 bottles of beer,
Take one down and pass it around,
68 bottles of beer on the wall.

68 bottles of beer on the wall,
68 bottles of beer,
Take one down and pass it around,
67 bottles of beer on the wall.

67 bottles of beer on the wall,
67 bottles of beer,
Take one down and pass it around,
66 bottles of beer on the wall.

66 bottles of beer on the wall,
66 bottles of beer,
Take one down and pass it around,
65 bottles of beer on the wall.

65 bottles of beer on the wall,
65 bottles of beer,
Take one down and pass it around,
64 bottles of beer on the wall.

64 bottles of beer on the wall,
64 bottles of beer,
Take one down and pass it around,
63 bottles of beer on the wall.

63 bottles of beer on the wall,
63 bottles of beer,
Take one down and pass it around,
62 bottles of beer on the wall.

62 bottles of beer on the wall,
62 bottles of beer,
Take one down and pass it around,
61 bottles of beer on the wall.

61 bottles of beer on the wall,
61 bottles of beer,
Take one down and pass it around,
60 bottles of beer on the wall.

60 bottles of beer on the wall,
60 bottles of beer,
Take one down and pass it around,
59 bottles of beer on the wall.

59 bottles of beer on the wall,
59 bottles of beer,
Take one down and pass it around,
58 bottles of beer on the wall.

58 bottles of beer on the wall,
58 bottles of beer,
Take one down and pass it around,
57 bottles of beer on the wall.

57 bottles of beer on the wall,
57 bottles of beer,
Take one down and pass it around,
56 bottles of beer on the wall.

56 bottles of beer on the wall,
56 bottles of beer,
Take one down and pass it around,
55 bottles of beer on the wall.

55 bottles of beer on the wall,
55 bottles of beer,
Take one down and pass it around,
54 bottles of beer on the wall.

54 bottles of beer on the wall,
54 bottles of beer,
Take one down and pass it around,
53 bottles of beer on the wall.

53 bottles of beer on the wall,
53 bottles of beer,
Take one down and pass it around,
52 bottles of beer on the wall.

52 bottles of beer on the wall,
52 bottles of beer,
Take one down and pass it around,
51 bottles of beer on the wall.

51 bottles of beer on the wall,
51 bottles of beer,
Take one down and pass it around,
50 bottles of beer on the wall.

50 bottles of beer on the wall,
50 bottles of beer,
Take one down and pass it around,
49 bottles of beer on the wall.

49 bottles of beer on the wall,
49 bottles of beer,
Take one down and pass it around,
48 bottles of beer on the wall.

48 bottles of beer on the wall,
48 bottles of beer,
Take one down and pass it around,
47 bottles of beer on the wall.

47 bottles of beer on the wall,
47 bottles of beer,
Take one down and pass it around,
46 bottles of beer on the wall.

46 bottles of beer on the wall,
46 bottles of beer,
Take one down and pass it around,
45 bottles of beer on the wall.

45 bottles of beer on the wall,
45 bottles of beer,
Take one down and pass it around,
44 bottles of beer on the wall.

44 bottles of beer on the wall,
44 bottles of beer,
Take one down and pass it around,
43 bottles of beer on the wall.

43 bottles of beer on the wall,
43 bottles of beer,
Take one down and pass it around,
42 bottles of beer on the wall.

42 bottles of beer on the wall,
42 bottles of beer,
Take one down and pass it around,
41 bottles of beer on the wall.

41 bottles of beer on the wall,
41 bottles of beer,
Take one down and pass it around,
40 bottles of beer on the wall.

40 bottles of beer on the wall,
40 bottles of beer,
Take one down and pass it around,
39 bottles of beer on the wall.

39 bottles of beer on the wall,
39 bottles of beer,
Take one down and pass it around,
38 bottles of beer on the wall.

38 bottles of beer on the wall,
38 bottles of beer,
Take one down and pass it around,
37 bottles of beer on the wall.

37 bottles of beer on the wall,
37 bottles of beer,
Take one down and pass it around,
36 bottles of beer on the wall.

36 bottles of beer on the wall,
36 bottles of beer,
Take one down and pass it around,
35 bottles of beer on the wall.

35 bottles of beer on the wall,
35 bottles of beer,
Take one down and pass it around,
34 bottles of beer on the wall.

34 bottles of beer on the wall,
34 bottles of beer,
Take one down and pass it around,
33 bottles of beer on the wall.

33 bottles of beer on the wall,
33 bottles of beer,
Take one down and pass it around,
32 bottles of beer on the wall.

32 bottles of beer on the wall,
32 bottles of beer,
Take one down and pass it around,
31 bottles of beer on the wall.

31 bottles of beer on the wall,
31 bottles of beer,
Take one down and pass it around,
30 bottles of beer on the wall.

30 bottles of beer on the wall,
30 bottles of beer,
Take one down and pass it around,
29 bottles of beer on the wall.

29 bottles of beer on the wall,
29 bottles of beer,
Take one down and pass it around,
28 bottles of beer on the wall.

28 bottles of beer on the wall,
28 bottles of beer,
Take one down and pass it around,
27 bottles of beer on the wall.

27 bottles of beer on the wall,
27 bottles of beer,
Take one down and pass it around,
26 bottles of beer on the wall.

26 bottles of beer on the wall,
26 bottles of beer,
Take one down and pass it around,
25 bottles of beer on the wall.

25 bottles of beer on the wall,
25 bottles of beer,
Take one down and pass it around,
24 bottles of beer on the wall.

24 bottles of beer on the wall,
24 bottles of beer,
Take one down and pass it around,
23 bottles of beer on the wall.

23 bottles of beer on the wall,
23 bottles of beer,
Take one down and pass it around,
22 bottles of beer on the wall.

22 bottles of beer on the wall,
22 bottles of beer,
Take one down and pass it around,
21 bottles of beer on the wall.

21 bottles of beer on the wall,
21 bottles of beer,
Take one down and pass it around,
20 bottles of beer on the wall.

20 bottles of beer on the wall,
20 bottles of beer,
Take one down and pass it around,
19 bottles of beer on the wall.

19 bottles of beer on the wall,
19 bottles of beer,
Take one down and pass it around,
18 bottles of beer on the wall.

18 bottles of beer on the wall,
18 bottles of beer,
Take one down and pass it around,
17 bottles of beer on the wall.

17 bottles of beer on the wall,
17 bottles of beer,
Take one down and pass it around,
16 bottles of beer on the wall.

16 bottles of beer on the wall,
16 bottles of beer,
Take one down and pass it around,
15 bottles of beer on the wall.

15 bottles of beer on the wall,
15 bottles of beer,
Take one down and pass it around,
14 bottles of beer on the wall.

14 bottles of beer on the wall,
14 bottles of beer,
Take one down and pass it around,
13 bottles of beer on the wall.

13 bottles of beer on the wall,
13 bottles of beer,
Take one down and pass it around,
12 bottles of beer on the wall.

12 bottles of beer on the wall,
12 bottles of beer,
Take one down and pass it around,
11 bottles of beer on the wall.

11 bottles of beer on the wall,
11 bottles of beer,
Take one down and pass it around,
10 bottles of beer on the wall.

10 bottles of beer on the wall,
10 bottles of beer,
Take one down and pass it around,
9 bottles of beer on the wall.

9 bottles of beer on the wall,
9 bottles of beer,
Take one down and pass it around,
8 bottles of beer on the wall.

8 bottles of beer on the wall,
8 bottles of beer,
Take one down and pass it around,
7 bottles of beer on the wall.

7 bottles of beer on the wall,
7 bottles of beer,
Take one down and pass it around,
6 bottles of beer on the wall.

6 bottles of beer on the wall,
6 bottles of beer,
Take one down and pass it around,
5 bottles of beer on the wall.

5 bottles of beer on the wall,
5 bottles of beer,
Take one down and pass it around,
4 bottles of beer on the wall.

4 bottles of beer on the wall,
4 bottles of beer,
Take one down and pass it around,
3 bottles of beer on the wall.

3 bottles of beer on the wall,
3 bottles of beer,
Take one down and pass it around,
2 bottles of beer on the wall.

2 bottles of beer on the wall,
2 bottles of beer,
Take one down and pass it around,
1 bottle of beer on the wall.

1 bottle of beer on the wall,
1 bottle of beer,
Take it down and pass it around,
No more bottles of beer on the wall.

## Crystal

99.downto(1) do |n|
puts "#{n} bottle#{n > 1 ? "s" : ""} of beer on the wall"
puts "#{n} bottle#{n > 1 ? "s" : ""} of beer"
puts "Take one down, pass it around"
puts "#{n-1} bottle#{n > 2 ? "s" : ""} of beer on the wall\n\n" if n > 1
end
puts "No more bottles of beer on the wall"


## D

### Simple Solution

Works with: D version 2

Based on Steward Gordon's code at: 99-bottles-of-beer.net.

import std.stdio;

void main() {
int bottles = 99;

while (bottles > 1) {
writeln(bottles, " bottles of beer on the wall,");
writeln(bottles, " bottles of beer.");
writeln("Take one down, pass it around,");
if (--bottles > 1) {
writeln(bottles, " bottles of beer on the wall.\n");
}
}
writeln("1 bottle of beer on the wall.\n");

writeln("No more bottles of beer on the wall,");
writeln("no more bottles of beer.");
writeln("Go to the store and buy some more,");
writeln("99 bottles of beer on the wall.");
}


### CTFE Solution

CTFE (Compile-Time Function Execution) is a feature of D that allows for pure functions of arbitrary complexity to be completely evaluated at compile time when every parameter is known. Note that this is distinct from the template meta-programming tricks used by some other languages, and this bottles() function could just as easily be executed during run-time. The compiled result of this program simply prints the pre-generated lyrics to the song, using a standard compiler pragma directive.

import std.stdio, std.conv;

string bottles(in size_t num) pure {
static string bottlesRecurse(in size_t num) pure {
return num.text ~ " bottles of beer on the wall,\n"
~ num.text ~ " bottles of beer!\n"
~ "Take one down, pass it around,\n"
~ (num - 1).text ~ " bottle" ~ ((num - 1 == 1) ? "" : "s")
~ " of beer on the wall.\n\n"
~ ((num > 2)
? bottlesRecurse(num - 1)
: "1 bottle of beer on the wall,\n"
~ "1 bottle of beer!\n"
~ "Take one down, pass it around,\n"
~ "No bottles of beer on the wall!\n\n");
}

return bottlesRecurse(num)
~ "Go to the store and buy some more...\n"
~ num.text ~ " bottles of beer on the wall!";
}

pragma(msg, 99.bottles);
void main() {}


### Template Meta-Programming Solution

Uses D template meta-programming and recursion to pre-generate the song lyrics and prints it at compile via pragma(msg,...)

module bottles;

template BeerSong(int Bottles)
{
static if (Bottles == 1)
{
enum BeerSong = "1 bottle of beer on the wall\n" ~
"1 bottle of beer\ntake it down, pass it around\n" ~ "
no more bottles of beer on the wall\n";
}
else
{
enum BeerSong = Bottles.stringof ~ " bottles of beer on the wall\n" ~
Bottles.stringof ~ " bottles of beer\ntake it down, pass it around\n" ~
BeerSong!(Bottles-1);
}
}

pragma(msg,BeerSong!99);

void main(){}


## Dart

// Making use of polymorphism

main() {
BeerSong beerSong = BeerSong();
//pass a 'starting point' and 'end point' as parameters respectively
String printTheLyrics = beerSong.recite(99, 1).join('\n');
print(printTheLyrics);
}

class Song {
String bottleOnTheWall(int index) {
String bottleOnTheWallText =
'$index bottles of beer on the wall,$index bottles of beer,';
return bottleOnTheWallText;
}

String bottleTakenDown(int index) {
String englishGrammar = (index >= 2) ? 'bottle' : 'bottles';
String bottleTakenDownText =
'Take one down and pass it around, ${index - 1}$englishGrammar of beer on the wall.';
return bottleTakenDownText;
}
}

class BeerSong extends Song {
@override
String bottleOnTheWall(int index) {
String originalText = super.bottleOnTheWall(index);
if (index < 2) {
String bottleOnTheWallText =
'$index bottle of beer on the wall,$index bottle of beer,';
return bottleOnTheWallText;
}
return originalText;
}

@override
String bottleTakenDown(int index) {
if (index < 2) {
String bottleTakenDownText =
'Take it down and pass it around, no more bottles of beer on the wall.';
return bottleTakenDownText;
}
String originalText = super.bottleTakenDown(index);
return originalText;
}

List<String> recite(int actualBottleOnTheWall, int remainingBottleOnTheWall) {
List<String> theLyrics = [];
for (int index = actualBottleOnTheWall;
index >= remainingBottleOnTheWall;
index--) {
String onTheWall = bottleOnTheWall(index);
String takenDown = bottleTakenDown(index);
}
return theLyrics;
}
}

}


## Dc

Works with: GNU dc
Works with: OpenBSD dc
[
dnrpr
dnlBP
lCP
1-dnrp
rd2r >L
]sL

[Take one down, pass it around
]sC
[ bottles of beer
]sB
[ bottles of beer on the wall]
99

lLx

dnrpsA
dnlBP
lCP
1-
dn[ bottle of beer on the wall]p
rdnrpsA
n[ bottle of beer
]P
[Take it down, pass it around
]P
[no more bottles of beer on the wall
]P

Similar to the program above, but without 'n' and 'r' commands. It prints the numbers on separate lines than the strings.

Works with: AT&T dc
[
plAP
plBP
lCP
1-dplAP
d2r >L
]sL

[Take one down, pass it around
]sC
[bottles of beer
]sB
[bottles of beer on the wall
]sA
99

lLx

plAP
plBP
lCP
1-
p
[bottle of beer on the wall
]P
p
[bottle of beer
]P
[Take it down, pass it around
]P
[no more bottles of beer on the wall
]P

## DBL

;
;===============================================================================
;       Oringinal Author: Bob Welton (welton@pui.com)
;       Language: DIBOL or DBL
;
;       Modified to work with DBL version 4
;       by Dario B.
;===============================================================================

RECORD

NRBOT,D2,99                  ;Default # of bottles to 99
A2,     A2

PROC
;-------------------------------------------------------------------------------

XCALL FLAGS (0007000000,1)      ;Suppress STOP message
OPEN (1,O,"TT:")                ;Open the terminal/display

DO FOREVER
BEGIN
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer on the wall,",10)

A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer,",10)
DISPLAY (1,"   Take one down, pass it around,",10)

DECR NRBOT                      ;Reduce # of bottles by 1
IF (NRBOT.LE.1) EXITLOOP        ;If just 1 bottle left, get out

A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer on the wall.",10,10)
END

A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottle of Beer on the wall,",10,10)

A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottle of Beer,",10)

DISPLAY (1,"   Take one down, pass it around,",10)
DISPLAY (1,"0 Bottles of Beer on the wall,",10)
DISPLAY (1,"0 Bottles of Beer,",10)
DISPLAY (1,"Go to the store and buy some more,",10)
DISPLAY (1,"99 Bottles of Beer on the wall,",10,10,10)
CLOSE 1
STOP


## Draco

proc nonrec bottles(byte b) void:
if b=0 then write("No more") else write(b) fi;
write(" bottle");
if b~=1 then write("s") fi
corp;

proc nonrec verse(byte v) void:
bottles(v);
writeln(" of beer on the wall,");
bottles(v);
writeln(" of beer,");
writeln("Take ",
if v=1 then "it" else "one" fi,
" down and pass it around");
bottles(v-1);
writeln(" of beer on the wall!\n");
corp;

proc nonrec main() void:
byte v;
for v from 99 downto 1 do verse(v) od
corp

## Dyalect

Translation of: Swift
for i in 99^-1..1 {
print("\(i) bottles of beer on the wall, \(i) bottles of beer.")
let next = i is 1 ? "no" : i - 1
print("Take one down and pass it around, \(next) bottles of beer on the wall.")
}

## Dylan

Module: bottles
define method bottles (n :: <integer>)
for (n from 99 to 1 by -1)
format-out("%d bottles of beer on the wall,\n"
"%d bottles of beer\n"
"Take one down, pass it around\n"
"%d bottles of beer on the wall\n",
n, n, n - 1);
end
end method


## Déjà Vu

plural i:
if = 1 i "" "s"

bottles i:
local :s plural i
!print( to-str i " bottle"s" of beer on the wall, " to-str i " bottle"s" of beer," )
!print\ "You take one down, pass it around, "
set :i -- i
if i:
set :s plural i
!print( to-str i " bottle"s" of beer on the wall." )
bottles i
else:
!print "no more bottles of beer on the wall, no more bottles of beer."
!print "Go to the store and buy some more, 99 bottles of beer on the wall."

bottles 99

## DIBOL-11

;
;===============================================================================
========================
;       Oringinal Author: Bob Welton (welton@pui.com)
;       Language: DIBOL or DBL
;
;       Modified to work with DEC DIBOL-11
;       by Bill Gunshannon
;===============================================================================
========================

RECORD MISC
NUMBOTTLES  ,D2,99                  ;Default # of bottles to 99

RECORD LINE1
ANUMBOTTLES, A2
,   A32, " Bottles of Beer on the wall,"

RECORD LINE2
BNUMBOTTLES, A2
,    A32, " Bottles of Beer,"

RECORD LINE3
CNUMBOTTLES, A2
,    A32, " Bottles of Beer on the wall."

RECORD LINE4
DNUMBOTTLES, A2
,    A32, " Bottle of Beer on the wall,"

RECORD LINE5
ENUMBOTTLES, A2
,    A32, " Bottle of Beer,"

.PROC
XCALL FLAGS (0007000000,1)          ;Suppress STOP message
OPEN (8,O:C,"TT:")                  ;Open the terminal/display
REPEAT
BEGIN
ANUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE1)
BNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE2)
WRITES (8,"   Take one down, pass it around,")
DECR NUMBOTTLES                 ;Reduce # of bottles by 1
IF (NUMBOTTLES .LE. 1) EXITLOOP ;If just 1 bottle left, get out
CNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE3)
WRITES (8," ")
END
DNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES(8,LINE4)
WRITES (8," ")
ENUMBOTTLES = NUMBOTTLES,'ZX'
WRITES(8,LINE5)
WRITES (8,"   Take one down, pass it around,")
WRITES(8,"0 Bottles of Beer on the wall,")
WRITES(8,"0 Bottles of Beer,")
WRITES(8,"Go to the store and buy some more,")
WRITES(8,"99 Bottles of Beer on the wall,")

WRITES (8," ")
WRITES (8," ")
SLEEP 2
CLOSE 8
STOP
.END

## E

def bottles(n) {
return switch (n) {
match ==0 { "No bottles" }
match ==1 { "1 bottle" }
match _   { $n bottles } } } for n in (1..99).descending() { println(${bottles(n)} of beer on the wall,
${bottles(n)} of beer. Take one down, pass it around,${bottles(n.previous())} of beer on the wall.
)
}

## ECL

Layout := RECORD
UNSIGNED1 RecID1;
UNSIGNED1 RecID2;
STRING30  txt;
END;
Beers := DATASET(99,TRANSFORM(Layout,
SELF.RecID1 := COUNTER,SELF.RecID2 := 0,SELF.txt := ''));

Layout XF(Layout L,INTEGER C) := TRANSFORM
IsOneNext := L.RecID1-1 = 1;
IsOne := L.RecID1 = 1;
SELF.txt := CHOOSE(C,
(STRING)(L.RecID1-1) + ' bottle'+IF(IsOneNext,'','s')+' of beer on the wall',
'Take one down, pass it around',
(STRING)(L.RecID1) + ' bottle'+IF(IsOne,'','s')+' of beer',
(STRING)(L.RecID1) + ' bottle'+IF(IsOne,'','s')+' of beer on the wall','');
SELF.RecID2 := C;
SELF := L;
END;

Rev := NORMALIZE(Beers,5,XF(LEFT,COUNTER));
OUTPUT(SORT(Rev,-Recid1,-RecID2),{txt},ALL);


## Egel

import "prelude.eg"
import "io.ego"

using System
using IO

def print_rhyme =
[ 0 ->
print "better go to the store, and buy some more\n"
| N ->
let _ = print N " bottles of beer on the wall\n" in
let _ = print N " bottles of beer\n" in
let _ = print "take one down, pass it around\n" in
print_rhyme (N - 1) ]

def main = print_rhyme 99

## EGL

program TestProgram type BasicProgram {}

function main()
for (count int from 99 to 1 decrement by 1)
SysLib.writeStdout( bottleStr( count ) :: " of beer on the wall." );
SysLib.writeStdout( bottleStr( count ) :: " of beer." );
SysLib.writeStdout( "Take one down, pass it around." );
SysLib.writeStdout( bottleStr( count - 1) :: " of beer on the wall.\n");
end
end

private function bottleStr( count int in) returns( string )
case ( count )
when ( 1 )
return( "1 bottle" );
when ( 0 )
return( "No more bottles" );
otherwise
return( count :: " bottles" );
end
end
end

## Eiffel

class
APPLICATION

create
make

feature {NONE} -- Initialization

make
local
bottles: INTEGER
do
from
bottles := 99
invariant
bottles <= 99 and bottles >= 1
until
bottles = 1
loop
print (bottles)
print (" bottles of beer on the wall,%N")
print (bottles)
print (" bottles of beer.%N")
print ("Take one down, pass it around,%N")
bottles := bottles - 1
if bottles > 1 then
print (bottles)
print (" bottles of beer on the wall.%N%N")
end
variant
bottles
end
print ("1 bottle of beer on the wall.%N%N");
print ("No more bottles of beer on the wall,%N");
print ("no more bottles of beer.%N");
print ("Go to the store and buy some more,%N");
print ("99 bottles of beer on the wall.%N");
end

end


An alternative version written using the across-loop construct.

	output_lyrics
-- Output the lyrics to 99-bottles-of-beer.
local
do
create l_bottles.make
across (1 |..| 99) as ic loop l_bottles.force (ic.item) end
across l_bottles.new_cursor.reversed as ic_bottles loop
print (ic_bottles.item)
print (" bottles of beer on the wall, ")
print (ic_bottles.item)
print (" bottles of beer.%N")
print ("Take one down, pass it around, ")
if ic_bottles.item > 1 then
print (ic_bottles.item)
print (" bottles of beer on the wall.%N%N")
end
end
print ("1 bottle of beer on the wall.%N")
print ("No more bottles of beer on the wall, no more bottles of beer.%N")
print ("Go to the store and buy some more, 99 bottles of beer on the wall.%N")
end


## Ela

open list

beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++" bottles of beer\nTake one down, pass it around\n"

map beer [99,98..0]

## Elena

ELENA 5.0 :

import system'routines;
import extensions;
import extensions'routines;
import extensions'text;

extension bottleOp
{
bottleDescription()
= self.toPrintable() + (self != 1).iif(" bottles"," bottle");

bottleEnumerator() = new Variable(self).doWith:(n)
{
^ new Enumerator
{
bool next() = n > 0;

get() = new StringWriter()
.printLine(n.bottleDescription()," of beer on the wall")
.printLine(n.bottleDescription()," of beer")
.printLine("Take one down, pass it around")
.printLine((n.reduce:1).bottleDescription()," of beer on the wall");

reset() {}

enumerable() = __target;
}
};
}

public program()
{
var bottles := 99;

bottles.bottleEnumerator().forEach:printingLn
}
Output:
5 bottles of beer on the wall
5 bottles of beer
Take one down, pass it around
4 bottles of beer on the wall

4 bottles of beer on the wall
4 bottles of beer
Take one down, pass it around
3 bottles of beer on the wall

3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall

2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall

1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
0 bottles of beer on the wall


## Elixir

defmodule Bottles do
def run do
Enum.each 99..1, fn idx ->
IO.puts "#{idx} bottle#{plural(idx)} of beer on the wall"
IO.puts "#{idx} bottle#{plural(idx)} of beer"
IO.puts "Take one down, pass it around"
IO.puts "#{idx - 1} bottle#{plural(idx-1)} of beer on the wall"
IO.puts ""
end
end

def plural(1), do: ""
def plural(num), do: "s"
end

Bottles.run


## Elm

module Main exposing (main)

import Html

main =
List.range 1 100
|> List.reverse
|> List.map
(\n ->
let
nString =
String.fromInt n

n1String =
String.fromInt (n - 1)
in
[ nString ++ " bottles of beer on the wall"
, nString ++ " bottles of beer"
, "Take one down, pass it around"
, n1String ++ " bottles of beer on the wall"
]
|> List.map Html.text
|> List.intersperse (Html.br [] [])
|> Html.p []
)
|> Html.div []


## Emacs Lisp

(let ((i 99))
(while (> i 0)
(message "%d bottles of beer on the wall" i)
(message "%d bottles of beer" i)
(message "Take one down, pass it around")
(message "%d bottles of beer on the wall" (1- i))
(setq i (1- i))))


## Erlang

-module(beersong).
-export([sing/0]).
-define(TEMPLATE_0, "~s of beer on the wall, ~s of beer.~nGo to the store and buy some more, 99
bottles of beer on the wall.~n").
-define(TEMPLATE_N, "~s of beer on the wall, ~s of beer.~nTake one down and pass it around, ~s of
beer on the wall.~n~n").

create_verse(0)      -> {0, io_lib:format(?TEMPLATE_0, phrase(0))};
create_verse(Bottle) -> {Bottle, io_lib:format(?TEMPLATE_N, phrase(Bottle))}.

phrase(0)      -> ["No more bottles", "no more bottles"];
phrase(1)      -> ["1 bottle", "1 bottle", "no more bottles"];
phrase(2)      -> ["2 bottles", "2 bottles", "1 bottle"];
phrase(Bottle) -> lists:duplicate(2, integer_to_list(Bottle) ++ " bottles") ++
[integer_to_list(Bottle-1) ++ " bottles"].

bottles() -> lists:reverse(lists:seq(0,99)).

sing() ->
lists:foreach(fun spawn_singer/1, bottles()),
sing_verse(99).

spawn_singer(Bottle) ->
Pid = self(),
spawn(fun() -> Pid ! create_verse(Bottle) end).

sing_verse(Bottle) ->
{_, Verse} when Bottle == 0 ->
io:format(Verse);
{N, Verse} when Bottle == N ->
io:format(Verse),
sing_verse(Bottle-1)
after
3000 ->
io:format("Verse not received - re-starting singer~n"),
spawn_singer(Bottle),
sing_verse(Bottle)
end.


## Euphoria

Works with: Euphoria version 4.0.0
constant
bottles = "bottles",
bottle = "bottle"

procedure beers (integer how_much)
sequence word1 = bottles, word2 = bottles
switch how_much do
case 2 then
word2 = bottle
case 1 then
word1 = bottle
word2 = bottle
end switch

printf (1,
"%d %s of beer on the wall \n" &
"%d %s of beer \n" &
"Take one down, and pass it around \n" &
"%d %s of beer on the wall \n\n",
{ how_much, word1,
how_much, word1,
how_much-1, word2 }
)
end procedure

for a = 99 to 1 by -1 do
beers (a)
end for
-- An alternate version

include std/console.e

sequence howmany = {"No more bottles","%d bottle","","s"}

for beer = 99 to 1 by -1 do
display(
[1] bottles of beer on the wall,
[1] bottles of beer.
Take one down, drink it right down,
[2][3] of beer.
,{beer,
sprintf(howmany[(beer>1)+1],beer-1),
howmany[(beer>2)+3]
})
end for
-- yet another version:

include std/console.e

object stanza = {
"[] bottles of beer on the wall,",
"[] bottles of beer,",
"take one down, and pass it around,"
}

object bottles = 99

loop do
display(stanza[1],bottles)
display(stanza[2],bottles)
display(stanza[3])
bottles -= 1
display(stanza[1]&"\n",{bottles})
until bottles = 0
end loop

## F#

#light
let rec bottles n =
let (before, after) = match n with
| 1 -> ("bottle", "bottles")
| 2 -> ("bottles", "bottle")
| n -> ("bottles", "bottles")
printfn "%d %s of beer on the wall" n before
printfn "%d %s of beer" n before
printfn "Take one down, pass it around"
printfn "%d %s of beer on the wall\n" (n - 1) after
if n > 1 then
bottles (n - 1)


## Factor

USING: io kernel make math math.parser math.ranges sequences ;

: bottle ( -- quot )
[
[
[
[ # " bottles of beer on the wall,\n" % ]
[ # " bottles of beer.\n" % ] bi
] keep
"Take one down, pass it around,\n" %
1 - # " bottles of beer on the wall\n" %
] " " make print
] ; inline

: last-verse ( -- )
"Go to the store and buy some more,"
"no more bottles of beer on the wall!" [ print ] bi@ ;

: bottles ( n -- )
1 [a,b] bottle each last-verse ;

! Usage: 99 bottles


## Falcon

for i in [99:1]
> i, " bottles of beer on the wall"
> i, " bottles of beer"
> "Take one down, pass it around"
> i-1, " bottles of beer on the wall\n"
end

A more robust version to handle plural/not plural conditions

for i in [99:1]
plural = (i != 1) ? 's' : ""
> @ "$i bottle$plural of beer on the wall"
> @ "$i bottle$plural of beer"
> "Take one down, pass it around"
> i-1, @ " bottle$plural of beer on the wall\n" end ## FALSE ## ferite copied from 99-bottles-of-beer.net. uses "console"; number bottles = 99; boolean looping = true; object counter = closure { if (--bottles > 0) { return true; } else { return false; } }; while (looping) { Console.println("${bottles} bottles of beer on the wall,");
Console.println("${bottles} bottles of beer,"); Console.println("Take one down, pass it around,"); looping = counter.invoke(); Console.println("${bottles} bottles of beer on the wall.");

## Fexl

\suffix=(\n eq n 1 "" "s")
\sing_count=(\n put [n " bottle" (suffix n) " of beer"])
\sing_line1=(\n sing_count n say " on the wall")
\sing_line2=(\n sing_count n nl)
\sing==
(\n
le n 0 ();
sing_line1 n
sing_line2 n
say "Take one down, pass it around"
\n=(- n 1)
sing_line1 n
nl
sing n
)
sing 3
Output:
3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall

2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall

1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
0 bottles of beer on the wall



## FOCAL

01.10 S N=99
01.15 D 2;T " OF BEER ON THE WALL,",!
01.20 D 2;T " OF BEER,",!
01.24 S N=N-1
01.25 T "TAKE ";I (N),1.3,1.4,1.3
01.30 T "IT";G 1.5
01.40 T "ONE"
01.50 T " DOWN AND PASS IT AROUND,",!
01.60 D 2;T " OF BEER ON THE WALL!",!!
01.70 I (N),1.8,1.15
01.80 Q

02.01 C-PRINT N BOTTLE(S)
02.10 I (N)2.2,2.2,2.3
02.20 T "NO MORE";G 2.4
02.30 D 3
02.40 T " BOTTLE";I (N-1)2.5,2.6,2.5
02.50 T "S"
02.60 R

03.01 C-PRINT 2-DIGIT NUMBER IN N
03.02 C-THIS IS NECESSARY BECAUSE T ALWAYS PREPENDS = TO NUMBERS
03.10 S A=FITR(N/10);I (A),3.3,3.2
03.20 D 4
03.30 S A=N-FITR(N/10)*10;D 4

04.01 C-PRINT DIGIT IN A
04.10 I (A-0),4.20,4.11
04.11 I (A-1),4.21,4.12
04.12 I (A-2),4.22,4.13
04.13 I (A-3),4.23,4.14
04.14 I (A-4),4.24,4.15
04.15 I (A-5),4.25,4.16
04.16 I (A-6),4.26,4.17
04.17 I (A-7),4.27,4.18
04.18 I (A-8),4.28,4.19
04.19 T "9";R
04.20 T "0";R
04.21 T "1";R
04.22 T "2";R
04.23 T "3";R
04.24 T "4";R
04.25 T "5";R
04.26 T "6";R
04.27 T "7";R
04.28 T "8";R

## Forth

:noname   dup . ." bottles" ;
:noname       ." 1 bottle"  ;
:noname ." no more bottles" ;
create bottles , , ,

: .bottles  dup 2 min cells bottles + @ execute ;
: .beer     .bottles ."  of beer" ;
: .wall     .beer ."  on the wall" ;
: .take     ." Take one down, pass it around" ;
: .verse    .wall cr .beer cr
1- .take cr .wall cr ;
: verses    begin cr .verse ?dup 0= until ;

99 verses


Version 2: create a beer language and write the program

DECIMAL
: BOTTLES ( n -- )
DUP
CASE
1 OF    ." One more bottle " DROP ENDOF
0 OF    ." NO MORE bottles " DROP ENDOF
. ." bottles "    \ DEFAULT CASE
ENDCASE ;

: ,   [CHAR] , EMIT  SPACE 100 MS CR ;
: .   [CHAR] . EMIT  300 MS  CR CR CR ;

: OF       ." of "   ;     : BEER     ." beer " ;
: ON       ." on "   ;     : THE      ." the "  ;
: WALL     ." wall" ;      : TAKE     ." take " ;
: ONE      ." one "  ;     : DOWN     ." down, " ;
: PASS     ." pass " ;     : IT       ." it "   ;
: AROUND   ." around" ;

: POPONE    1 SWAP CR ;
: DRINK     POSTPONE DO ; IMMEDIATE
: ANOTHER   S" -1 +LOOP" EVALUATE ; IMMEDIATE
: HOWMANY   S" I " EVALUATE ; IMMEDIATE
: ONELESS   S" I 1- " EVALUATE ; IMMEDIATE
: HANGOVER    ." :-("  CR QUIT ;

: BEERS ( n -- )   \ Usage:  99 BEERS
POPONE
DRINK
HOWMANY BOTTLES OF BEER ON THE WALL ,
HOWMANY BOTTLES OF BEER ,
TAKE ONE DOWN PASS IT AROUND ,
ONELESS BOTTLES OF BEER ON THE WALL .
ANOTHER
HANGOVER ;


Forth Console Output

2 beers
2 bottles of beer on the wall,
2 bottles of beer ,
take one down, pass it around,
One more bottle of beer on the wall.

One more bottle of beer on the wall,
One more bottle of beer ,
take one down, pass it around,
No more bottles of beer on the wall.

ok


## Fortran

### F90 version

program bottlestest

implicit none

integer :: i

character(len=*), parameter   :: bwall = " on the wall", &
bottles = "bottles of beer", &
bottle  = "bottle of beer", &
take = "Take one down, pass it around", &
form = "(I0, ' ', A)"

do i = 99,0,-1
if ( i /= 1 ) then
write (*,form)  i, bottles // bwall
if ( i > 0 ) write (*,form)  i, bottles
else
write (*,form)  i, bottle // bwall
write (*,form)  i, bottle
end if
if ( i > 0 ) write (*,*) take
end do

end program bottlestest


### MPI version

program bottlesMPI

implicit none

integer :: ierr,rank,nproc

character(len=*), parameter   :: bwall = " on the wall", &
bottles = "bottles of beer", &
bottle  = "bottle of beer", &
take = "Take one down, pass it around", &
form = "(I0, ' ', A)"

call mpi_init(ierr)
call mpi_comm_size(MPI_COMM_WORLD,nproc, ierr)
call mpi_comm_rank(MPI_COMM_WORLD,rank,ierr)

if ( rank /= 1 ) then
write (*,form)  rank, bottles // bwall
if ( rank > 0 ) write (*,form)  rank, bottles
else
write (*,form)  rank, bottle // bwall
write (*,form)  rank, bottle
end if
if ( rank > 0 ) write (*,*) take

call mpi_finalize(ierr)

end program bottlesMPI


Usage:

mpif90 filename.f90
mpiexec -np 99 a.out

### Fortran 2003/2008 OOP version

Works with GNU gfortran 5.0.0 and Intel ifort 15.0.2

module song_typedefs
implicit none

private ! all
public :: TBottles

type, abstract :: TContainer
integer :: quantity
contains
! deferred method i.e. abstract method =  must be overridden in extended type
procedure(take_one), deferred, pass :: take_one
procedure(show_quantity), deferred, pass :: show_quantity
end type TContainer

abstract interface
subroutine  take_one(this)
import TContainer
implicit none
class(TContainer) :: this
end subroutine take_one
subroutine  show_quantity(this)
import TContainer
implicit none
class(TContainer) :: this
end subroutine show_quantity
end interface

! extended derived type
type, extends(TContainer) :: TBottles
contains
procedure, pass :: take_one => take_one_bottle
procedure, pass :: show_quantity => show_bottles
final :: finalize_bottles
end type TBottles

contains

subroutine  show_bottles(this)
implicit none
class(TBottles) :: this
! integer :: show_bottles
character(len=*), parameter :: bw0 = "No more bottles of beer on the wall,"
character(len=*), parameter :: bwx = "bottles of beer on the wall,"
character(len=*), parameter :: bw1 = "bottle of beer on the wall,"
character(len=*), parameter :: bb0 = "no more bottles of beer."
character(len=*), parameter :: bbx = "bottles of beer."
character(len=*), parameter :: bb1 = "bottle of beer."
character(len=*), parameter :: fmtxdd = "(I2,1X,A28,1X,I2,1X,A16)"
character(len=*), parameter :: fmtxd = "(I1,1X,A28,1X,I1,1X,A16)"
character(len=*), parameter :: fmt1 = "(I1,1X,A27,1X,I1,1X,A15)"
character(len=*), parameter :: fmt0 = "(A36,1X,A24)"

select case (this % quantity)
case (10:)
write(*,fmtxdd) this % quantity, bwx, this % quantity, bbx
case (2:9)
write(*,fmtxd) this % quantity, bwx, this % quantity, bbx
case (1)
write(*,fmt1) this % quantity, bw1, this % quantity, bb1
case (0)
write(*,*)
write(*,fmt0) bw0, bb0
case default
write(*,*)"Warning!  Number of bottles exception, error 42. STOP"
stop
end select
!    show_bottles = this % quantity
end subroutine show_bottles

subroutine  take_one_bottle(this) ! bind(c, name='take_one_bottle')
implicit none
class(TBottles) :: this
! integer :: take_one_bottle
character(len=*), parameter :: t1 = "Take one down and pass it around,"
character(len=*), parameter :: remx = "bottles of beer on the wall."
character(len=*), parameter :: rem1 = "bottle of beer on the wall."
character(len=*), parameter :: rem0 = "no more bottles of beer on the wall."
character(len=*), parameter :: fmtx = "(A33,1X,I2,1X,A28)"
character(len=*), parameter :: fmt1 = "(A33,1X,I2,1X,A27)"
character(len=*), parameter :: fmt0 = "(A33,1X,A36)"

this % quantity = this % quantity -1

select case (this%quantity)
case (2:)
write(*,fmtx) t1, this%quantity, remx
case (1)
write(*,fmt1) t1, this%quantity, rem1
case (0)
write(*,fmt0) t1, rem0
case (-1)
write(*,'(A66)') "Go to the store and buy some more, 99 bottles of beer on the wall."
case default
write(*,*)"Warning!  Number of bottles exception, error 42. STOP"
stop
end select

end subroutine take_one_bottle

subroutine  finalize_bottles(bottles)
implicit none
type(TBottles) :: bottles
! here can be more code
end subroutine finalize_bottles

end module song_typedefs

!-----------------------------------------------------------------------
!Main program
!-----------------------------------------------------------------------
program    bottles_song
use song_typedefs
implicit none
integer, parameter :: MAGIC_NUMBER = 99
type(TBottles), target :: BTLS

BTLS = TBottles(MAGIC_NUMBER)

call make_song(BTLS)

contains

subroutine make_song(bottles)
type(TBottles) :: bottles
do while(bottles%quantity >= 0)
call bottles%show_quantity()
call bottles%take_one()
enddo
end subroutine make_song

end program bottles_song


## Frege

Works with: Frege version 3.21.586-g026e8d7
module Beer where

main = mapM_ (putStrLn . beer) [99, 98 .. 0]
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++ " bottles of beer\nTake one down, pass it around\n"
++ head (lines $beer$ v-1) ++ "\n"

## Frink

Frink tracks units of measure through all calculations. It has a large library of built-in units of measure, including volume. The following program prints out the remaining volume of beer (assuming we start with 99 bottles of beer, each containing 12 fluid ounces) in different random units of volume, never repeating a unit.

units = array[units[volume]]
showApproximations[false]

for n = 99 to 0 step -1
{
unit = units.removeRandom[]
str = getBottleString[n, unit]

println["$str of beer on the wall,$str."]

if (n == 0)
println["Go to the store and buy some more, 99 bottles of beer on the wall."]
else
println["Take one down and pass it around, " + getBottleString[n-1, unit] + " on the wall.\n"]
}

getBottleString[n, unit] := format[n*12 floz, unit, 6] + "s"

Sample randomized output:

0.019386 facecords of beer on the wall, 0.019386 facecords.
Take one down and pass it around, 0.019190 facecords on the wall.

36.750000 quarts of beer on the wall, 36.750000 quarts.
Take one down and pass it around, 36.375000 quarts on the wall.

581539.650545 brminims of beer on the wall, 581539.650545 brminims.
Take one down and pass it around, 575544.396416 brminims on the wall.

10.377148 scotsoatlippys of beer on the wall, 10.377148 scotsoatlippys.
Take one down and pass it around, 10.269053 scotsoatlippys on the wall.

7.416004 cangallons of beer on the wall, 7.416004 cangallons.
Take one down and pass it around, 7.337941 cangallons on the wall.

3335.894135 dessertspoons of beer on the wall, 3335.894135 dessertspoons.
Take one down and pass it around, 3300.405899 dessertspoons on the wall.

0.233105 barrelbulks of beer on the wall, 0.233105 barrelbulks.
Take one down and pass it around, 0.230599 barrelbulks on the wall.

21.766118 magnums of beer on the wall, 21.766118 magnums.
Take one down and pass it around, 21.529530 magnums on the wall.

1092.000000 fluidounces of beer on the wall, 1092.000000 fluidounces.
Take one down and pass it around, 1080.000000 fluidounces on the wall.
...
12.000000 ponys of beer on the wall, 12.000000 ponys.
Take one down and pass it around, 0.000000 ponys on the wall.

0.000000 brfluidounces of beer on the wall, 0.000000 brfluidounces.
Go to the store and buy some more, 99 bottles of beer on the wall.


## FunL

val
numbers = {1:'one', 2:'two', 3:'three', 4:'four', 5:'five', 6:'six', 7:'seven',
8:'eight', 9:'nine', 10:'ten', 11:'eleven', 12:'twelve'}
alt = {3:'thir', 5:'fif'}

def
suffix( a, b ) = (if a.endsWith( 't' ) then a.substring( 0, a.length()-1 ) else a) + b

number( n@(13 | 15) ) = suffix( alt(n%10), 'teen' )
number( 20 ) = 'twenty'
number( n@(30 | 50) ) = suffix( alt(n\10), 'ty' )
number( n )
| n <= 12 = numbers(n)
| n <= 19 = suffix( numbers(n%10), 'teen' )
| 10|n = suffix( numbers(n\10), 'ty' )
| otherwise = number( n\10*10 ) + '-' + number( n%10 )

cap( s ) = s.substring( 0, 1 ).toUpperCase() + s.substring( 1, s.length() )

bottles( 0 ) = 'no more bottles'
bottles( 1 ) = 'one bottle'
bottles( n ) = number( n ) + ' bottles'

verse( 0 )   = ('No more bottles of beer on the wall, no more bottles of beer.\n'
+ 'Go to the store and buy some more, ninety-nine bottles of beer on the wall.')
verse( n )   = (cap( bottles(n) ) + ' of beer on the wall, ' + bottles( n ) + ' of beer.\n'
+ 'Take one down and pass it around, ' + bottles( n-1 )
+ ' of beer on the wall.\n')

for i <- 99..0 by -1 do println( verse(i) )

## FutureBasic

include "NSLog.incl"

NSUInteger  i
CFStringRef a, b, c

a = @" bottles of beer on the wall,\n"
b = @" bottles of beer.\n"
c = @"Take one down, pass it around,\n"

for i = 99 to 1 step -1
NSLog( @"%ld%@%ld%@%@%ld%@\n", i, a, i, b, c, i -1, a )
next

HandleEvents

## Gambas

Implementation of the code '99 bottles of beer' written in Visual Basic. Code tested in Gambas 3.15.2

' Gambas module file

Public Const bottlesofbeer As String = " bottles of beer."
Public Const onthewall As String = " on the wall."
Public Const takeonedown As String = "Take one down, pass it around."
Public Const onebeer As String = "1 bottle of beer"

Public Sub Main()

Dim bottles As Byte

For bottles = 99 To 3 Step -1
Print CStr(bottles) & bottlesofbeer & onthewall
Print CStr(bottles) & bottlesofbeer
Print takeonedown
Print CStr(bottles - 1) & bottlesofbeer & onthewall
Print
Next

Print "2" & bottlesofbeer & onthewall
Print "2" & bottlesofbeer
Print takeonedown
Print onebeer & onthewall
Print

Print onebeer & onthewall
Print onebeer
Print takeonedown
Print "No more" & bottlesofbeer & onthewall
Print

Print "No" & bottlesofbeer & onthewall
Print "No" & bottlesofbeer
Print "Go to the store, buy some more."
Print "99" & bottlesofbeer & onthewall

End


## GAP

Bottles := function(n)
local line, i, j, u;
line := function(n)
s := String(n);
if n < 2 then
return Concatenation(String(n), " bottle of beer");
else
return Concatenation(String(n), " bottles of beer");
fi;
end;
for i in [1 .. n] do
j := n - i + 1;
u := line(j);
Display(Concatenation(u, " on the wall"));
Display(u);
Display("Take one down, pass it around");
Display(Concatenation(line(j - 1), " on the wall"));
if i <> n then
Display("");
fi;
od;
end;


## Genie

[indent=4]
def plural(n:uint):string
return (n == 1) ? "" : "s"
def no(n:uint):string
return (n == 0) ? "No" : n.to_string()
init
bottles:uint = 99;
do
print "%u bottle%s of beer on the wall", bottles, plural(bottles)
print "%u bottle%s of beer", bottles, plural(bottles)
print "Take one down, pass it around"
--bottles
print "%s bottle%s of beer on the wall\n", no(bottles), plural(bottles)
while bottles != 0
Output:
prompt$valac 99bottles.gs prompt$ ./99bottles | tail -10
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall

1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No bottles of beer on the wall

## gnuplot

if (!exists("bottles")) bottles = 99
print sprintf("%i bottles of beer on the wall", bottles)
print sprintf("%i bottles of beer", bottles)
print "Take one down, pass it around"
bottles = bottles - 1
print sprintf("%i bottles of beer on the wall", bottles)
print ""


## Go

### No sense of humor

package main

import "fmt"

func main() {
bottles := func(i int) string {
switch i {
case 0:
return "No more bottles"
case 1:
return "1 bottle"
default:
return fmt.Sprintf("%d bottles", i)
}
}

for i := 99; i > 0; i-- {
fmt.Printf("%s of beer on the wall\n", bottles(i))
fmt.Printf("%s of beer\n", bottles(i))
fmt.Printf("Take one down, pass it around\n")
fmt.Printf("%s of beer on the wall\n", bottles(i-1))
}
}


### Typoglycemic

With code from RC tasks Number names, Knuth shuffle.

package main

import (
"fmt"
"math/rand"
"strings"
"time"
)

func main() {
rand.Seed(time.Now().UnixNano())
for i := 99; i > 0; i-- {
fmt.Printf("%s %s %s\n",
slur(numberName(i), i),
pluralizeFirst(slur("bottle of", i), i),
slur("beer on the wall", i))
fmt.Printf("%s %s %s\n",
slur(numberName(i), i),
pluralizeFirst(slur("bottle of", i), i),
slur("beer", i))
fmt.Printf("%s %s %s\n",
slur("take one", i),
slur("down", i),
slur("pass it around", i))
fmt.Printf("%s %s %s\n",
slur(numberName(i-1), i),
pluralizeFirst(slur("bottle of", i), i-1),
slur("beer on the wall", i))
}
}

func numberName(n int) string {
switch {
case n < 0:
case n < 20:
return small[n]
case n < 100:
t := tens[n/10]
s := n % 10
if s > 0 {
t += " " + small[s]
}
return t
}
return ""
}

var small = []string{"no", "one", "two", "three", "four", "five", "six",
"seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen",
"fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}
var tens = []string{"ones", "ten", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"}

// pluralize first word of s by adding an s, but only if n is not 1.
func pluralizeFirst(s string, n int) string {
if n == 1 {
return s
}
w := strings.Fields(s)
w[0] += "s"
return strings.Join(w, " ")
}

// p is string to slur, d is drunkenness, from 0 to 99
func slur(p string, d int) string {
// shuffle only interior letters
a := []byte(p[1 : len(p)-1])
// shuffle letters with probability d/100.
for i := len(a) - 1; i >= 1; i-- {
if rand.Intn(100) >= d {
j := rand.Intn(i + 1)
a[i], a[j] = a[j], a[i]
}
}
// condense spaces
w := strings.Fields(p[:1] + string(a) + p[len(p)-1:])
return strings.Join(w, " ")
}

Output:

Things start out pretty well...

ninety nine bottles of beer on the wall
ninety nine bottles of beer
take one down pass it around
ninety eight bottles of beer on the wall
ninety eight bottles of beer on the wall
ninety eight bottles of beer
take one down pass it around
ninety seven bottles of beer on the wall
ninety seven boetlts of beer on the wall
ninety seven bottles of beer
take one down pass it around
ninety six botelts of beer on the wall


Soon,

eighty four bottles of bere wn the oall
ehigty four bottles of beer
eihhty tgree bttoles of beer en tho wall
eighty three blottes of beet on rhe wall
eighty three bottles of beer
taen oke down pass it around
eiwyth tgo bttoles of beew on lhr eatl


It ends very well, if you're drinking along.

two btloots ef bre enehta wo ll
two bs tleootf beer
tnoeka e dwon pts ou nsaaird
one bolote tf betwr le ao enhl
one beoo ttlf blwtenr ehoa el
one bltooe tf beer
tne okae down pasaostiu rnd
no bletts oof beloethw r ea nl


## Go!

Copied from The 99 Bottles of Beer web site with a minor bug fix.

--
-- 99 Bottles of Beer in Go!
-- John Knottenbelt
--
-- Go! is a multi-paradigm programming language that is oriented
-- to the needs of programming secure, production quality, agent
-- based applications.
--
--    http://www.doc.ic.ac.uk/~klc/dalt03.html
--

main .. {
include "sys:go/io.gof".
include "sys:go/stdlib.gof".

main() ->
drink(99);
stdout.outLine("Time to buy some more beer...").

drink(0) -> {}.
drink(i) -> stdout.outLine(
bottles(i) <> " on the wall,\n" <>
bottles(i) <> ".\n" <>
"take one down, pass it around,\n" <>
bottles(i-1) <> " on the wall.\n");
drink(i-1).

bottles(0) => "no bottles of beer".
bottles(1) => "1 bottle of beer".
bottles(i) => i^0 <> " bottles of beer".
}

[296,{3/)}%-1%["No more"]+[" bottles":b]294*[b-1<]2*+[b]+[" of beer on the wall\n".8<"\nTake one down, pass it around\n"+1$n+]99*]zip ## Golo module Bottles augment java.lang.Integer { function bottles = |self| -> match { when self == 0 then "No bottles" when self == 1 then "One bottle" otherwise self + " bottles" } } function main = |args| { 99: downTo(1, |i| { println(i: bottles() + " of beer on the wall,") println(i: bottles() + " of beer!") println("Take one down, pass it around,") println((i - 1): bottles() + " of beer on the wall!") println("--------------------------------------") }) }  ## Gosu for (i in 99..0) { print("${i} bottles of beer on the wall")

if (i > 0) {
print("${i} bottles of beer") print("Take one down, pass it around") } print(""); }  ## Groovy ### Basic Solution With a closure to handle special cardinalities of bottles. def bottles = { "${it==0 ? 'No more' : it} bottle${it==1 ? '' : 's' }" } 99.downto(1) { i -> print """${bottles(i)} of beer on the wall
${bottles(i)} of beer Take one down, pass it around${bottles(i-1)} of beer on the wall
"""
}


### Single Print Version

Uses a single print algorithm for all four lines. Handles cardinality on bottles, uses 'No more' instead of 0.

298.downto(2) {
def (m,d) = [it%3,(int)it/3]
print "${m==1?'\n':''}${d?:'No more'} bottle${d!=1?'s':''} of beer" + "${m?' on the wall':'\nTake one down, pass it around'}\n"
}


### Bottomless Beer Solution

Using more closures to create a richer lyrical experience.

def bottles = { "${it==0 ? 'No more' : it} bottle${it==1 ? '' : 's' }" }

def initialState = {
"""${result(it)}${resultShort(it)}"""
}

def act = {
it > 0 ?
"Take ${it==1 ? 'it' : 'one'} down, pass it around" : "Go to the store, buy some more" } def delta = { it > 0 ? -1 : 99 } def resultShort = { "${bottles(it)} of beer" }

def result = { "${resultShort(it)} on the wall" } // //// uncomment commented lines to create endless drunken binge //// // // while (true) { 99.downto(0) { i -> print """${initialState(i)}
${act(i)}${result(i+delta(i))}
"""
}
// }


## GUISS

We will just use the calculator and keep taking one off. We do not get the full text here, but the number of the calculator shows how many bottles we still have left to drink:

Start,Programs,Accessories,Calculator,Button:9,Button:9,
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals]

We haven't drank all of the bottles at this point, but we can keep going, if we want.

## Halon

$plural = "s";$x = 99;
while ($x > 0) { echo "$x bottle$plural of beer on the wall"; echo "$x bottle$plural of beer"; echo "Take one down, pass it around";$x -= 1;
if ($x == 1)$plural = "";
if ($x > 0) echo "$x bottle$plural of beer on the wall\n"; else echo "No more bottles of beer on the wall!"; } ## Haskell #### Brevity A relatively concise solution: main = mapM_ (putStrLn . beer) [99, 98 .. 0] beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around" beer 0 = "better go to the store and buy some more." beer v = show v ++ " bottles of beer on the wall\n" ++ show v ++" bottles of beer\nTake one down, pass it around\n" ++ head (lines$ beer $v-1) ++ "\n"  #### List comprehension As a list comprehension: import qualified Char main = putStr$ concat
[up (bob n) ++ wall ++ ", " ++ bob n ++ ".\n" ++
pass n ++ bob (n - 1) ++ wall ++ ".\n\n" |
n <- [99, 98 .. 0]]
where bob n = (num n) ++ " bottle" ++ (s n) ++ " of beer"
wall = " on the wall"
pass 0 = "Go to the store and buy some more, "
pass _ = "Take one down and pass it around, "
up (x : xs) = Char.toUpper x : xs
num (-1) = "99"
num 0    = "no more"
num n    = show n
s 1 = ""
s _ = "s"


Another version, which uses a Writer monad to collect each part of the song. It also uses Template Haskell to generate the song at compile time.

{-# LANGUAGE TemplateHaskell #-}
-- build with "ghc --make beer.hs"
module Main where

-- This is calculated at compile time, and is equivalent to
-- songString = "99 bottles of beer on the wall\n99 bottles..."
songString =
$(let sing = tell -- we can't sing very well... someBottles 1 = "1 bottle of beer " someBottles n = show n ++ " bottles of beer " bottlesOfBeer n = (someBottles n ++) verse n = do sing$ n bottlesOfBeer "on the wall\n"
sing $n bottlesOfBeer "\n" sing$ "Take one down, pass it around\n"
sing $(n - 1) bottlesOfBeer "on the wall\n\n" song = execWriter$ mapM_ verse [99,98..1]

in return $LitE$ StringL $song) main = putStr songString  #### Avoiding append by spelling bottle backwards Is there something just a little prickly and displeasing about (++) ? Monoid (<>) is less spiky, but neither is needed when 'bottle' is written backwards. location, distribution, solution :: String [location, distribution, solution] = [ "on the wall", "Take one down, pass it around", "Better go to the store to buy some more" ] incantation :: Int -> String incantation n | 0 == n = solution | otherwise = unlines [ inventory n, asset n, distribution, inventory$ pred n
]

inventory :: Int -> String
inventory = unwords . (: [location]) . asset

asset :: Int -> String
asset n =
let suffix n
| 1 == n = []
| otherwise = ['s']
in unwords
[show n, (reverse . concat) $suffix n : ["elttob"]] main :: IO () main = putStrLn$ unlines (incantation <$> [99, 98 .. 0])  ## Haxe ### Simple solution class RosettaDemo { static public function main() { singBottlesOfBeer(100); } static function singBottlesOfBeer(bottles : Int) { var plural : String = 's'; while (bottles >= 1) { Sys.println(bottles + " bottle" + plural + " of beer on the wall,"); Sys.println(bottles + " bottle" + plural + " of beer!"); Sys.println("Take one down, pass it around,"); if (bottles - 1 == 1) { plural = ''; } if (bottles > 1) { Sys.println(bottles-1 + " bottle" + plural + " of beer on the wall!\n"); } else { Sys.println("No more bottles of beer on the wall!"); } bottles--; } } }  ### Macro solution All those counters, loops and conditinal blocks are pretty expensive in runtime compared to single print of fully inlined text of the song. Let's generate that print with macro. class Bottles { static public function main () : Void { singBottlesOfBeer(100); } macro static public function singBottlesOfBeer (bottles:Int) { var lines = []; var s : String = 's'; var song : String = ''; while( bottles >= 1 ){ song += '$bottles bottle$s of beer on the wall,\n'; song += '$bottles bottle$s of beer!\n'; song += 'Take one down, pass it around,\n'; bottles --; if( bottles > 1 ){ song += '$bottles bottles of beer on the wall!\n\n';
}else if( bottles == 1 ){
s = '';
song += '$bottles bottle of beer on the wall!\n\n'; }else{ song += 'No more bottles of beer on the wall!\n'; } } return macro Sys.print($v{song});
}

}


## hexiscript

fun bottles amount beverage location
let bottle " bottles of "
if   amount = 0; let amount "No more"
elif amount = 1; let bottle " bottle of "; endif
return amount + bottle + beverage + " " + location
endfun

fun take amount location
return "Take " + amount + " " + location
endfun

fun pass entity destination
return ", pass " + entity + " " + destination
endfun

let amount 99
while amount > 0
println bottles amount "beer" "on the wall"
println bottles amount "beer" ""
println take "one" "down" + pass "it" "around"
println bottles (--amount) "beer" "on the wall\n"
endwhile

## HicEst

DO x = 99, 1, -1
WRITE()   x       , "bottles of beer on the wall"
BEEP("T16 be be be   bH bH   bH be   be be  2be ")

WRITE()   x       , "bottles of beer"
BEEP("2p  f f f      c  c    c  2f  ")

WRITE()  "take one down,  pass it around"
BEEP("2p  2d   d   d   2p d    d  d 2d  ")

WRITE()   x     , "bottles of beer on the wall"
BEEP("2p  #A #A #A c  c    d  #d   #d #d  2#d 2p")
ENDDO

## HolyC

The default is 99 bottles, but it can be modified by the parameter.

U0 BottlesOfBeer (I64 initial=99) {
// This is made I64 rather than U64
// Because, a U64 would overflow
// At the end of the loop, thus it would loop forever (i-- would be 0-1 so it overflows and is always  greater than or equal to 0)
I64 i = initial;

for (; i >= 0; i--) {
if (i == 1) {
// Just a string on it's own will pass it to an inbuilt HolyC function that puts it to terminal
"1 Bottle of Beer on the wall, 1 bottle of beer.\n";
"Take one down and pass it around, no more bottles of beer on the wall.\n";
} else if (i == 0) {
"No more bottles of beer on the wall, no more bottles of beer.\n";
"Go to the store and buy some more, 99 bottles of beer on the wall.\n";
} else {
"%d bottles of beer on the wall, %d bottles of beer.\n",i,i;
"Take one down and pass it around, %d bottle",(i-1);
// Only add the s if it's not 1
if ((i-1) != 1) {
"s";
}

" of beer on the wall.\n";
}
}
}

// Calls the function, which goes to the default parameters
BottlesOfBeer;

## Hoon

:-  %say
|=  [* * [bottles=_99 ~]]
:-  %noun
^-  wall
=/  output  (list tape)~
|-
?:  =(1 bottles)
%-  flop
:-  "1 bottle of beer on the wall"
:-  "Take one down, pass it around"
:-  "1 bottle of beer"
:-  "1 bottle of beer on the wall"
output
%=  $bottles (dec bottles) output :- "{<bottles>} bottles of beer on the wall" :- "Take one down, pass it around" :- "{<bottles>} bottles of beer" :- "{<bottles>} bottles of beer on the wall" output == ## Hope El código es de Wolfgang Lohmann (wlohmann@informatik.uni-rostock.de) dec app :( list ( char ) X list ( char )) -> list ( char ) ; dec i2c : num -> char; dec i2s : num -> list(char); dec beer : num -> list(char); --- app ( nil , w ) <= w ; --- app (( a :: v ), w ) <=( a :: app ( v , w )) ; --- i2c(0) <= '0'; --- i2c(1) <= '1'; --- i2c(2) <= '2'; --- i2c(3) <= '3'; --- i2c(4) <= '4'; --- i2c(5) <= '5'; --- i2c(6) <= '6'; --- i2c(7) <= '7'; --- i2c(8) <= '8'; --- i2c(9) <= '9'; --- i2s(x) <= if x < 10 then [i2c(x)] else app(i2s(x div 10), i2s( x mod 10)); --- beer(x) <= if x = 1 then app( i2s(x), " bottle of beer. No more beer on the wall.") else app( app( app( app( app( i2s(x), " bottles of beer on the wall, "), i2s(x)), " bottles of beer. "), "Take one down, pass it around. "), beer(y)) where y== x-1; ## HQ9+ ## Huginn #! /bin/sh exec huginn --no-argv -E "${0}" "${@}" #! huginn import Algorithms as algo; main() { x = "{} bottle{} of beer on the wall,\n" "{} bottle{} of beer.\n" "Take one down, pass it around,\n" "{} bottle{} of beer on the wall.\n\n"; for ( n : algo.range( 99, 0, -1 ) ) { bot = n > 0 ? n : "No"; plu = n != 1 ? "s" : ""; print( x.format( bot, plu, bot, plu, n > 1 ? n - 1 : "No", n != 2 ? "s" : "" ) ); } print( "No bottles of beer on the wall,\n" "No bottles of beer.\n" "Go to the store, buy some more,\n" "99 bottles of beer on the wall.\n" ); return ( 0 ); } ## HyperTalk El código es de Eric Carlson eric@bungdabba.com on BeerSong99 BottlesOfBeer 99 end BeerSong99 on OutputBeerLyric beerString if ( beerString is "<reset>" ) then put empty into cd fld "beer song" else put beerString & return after cd fld "beer song" end if end OutputBeerLyric on BottlesOfBeer bottleCount put bottleCount into initialCount OutputBeerLyric "<reset>" repeat until ( bottleCount < 1 ) set cursor to busy -- let 'em know this might take a while put BottleString(bottleCount) into currentString OutputBeerLyric currentString && "of beer on the wall," OutputBeerLyric currentString && "of beer." OutputBeerLyric "Take one down, and pass it around," subtract one from bottleCount OutputBeerLyric BottleString(bottleCount) && "of beer on the wall." & return end repeat OutputBeerLyric "Go to the store and buy some more..." OutputBeerLyric initialCount & " bottles of beer on the wall." end BottlesOfBeer function BottleString bottleCount if ( bottleCount is 1 ) then return "1 bottle" else if ( bottleCount is 0 ) then return "no more bottles" else return bottleCount && "bottles" end if end BottleString ## Icon and Unicon The default is 99 bottles, but you can change this on the command line for really long trips... procedure main(args) numBeers := integer(args[1]) | 99 drinkUp(numBeers) end procedure drinkUp(beerMax) static beerMap initial { beerMap := table(" bottles") beerMap[1] := " bottle" } every beerCount := beerMax to 1 by -1 do { writes( beerCount,beerMap[beerCount]," of beer on the wall, ") write( beerCount,beerMap[beerCount]," of beer.") writes("Take one down and pass it around, ") write(case x := beerCount-1 of { 0 : "no more bottles" default : x||beerMap[x] }," of beer on the wall.\n") } write("No more bottles of beer on the wall, no more bottles of beer.") write("Go to the store and buy some more, ", beerMax," bottles of beer on the wall.") end  ## IDL Pro bottles for i=1,99 do begin print, 100-i, " bottles of beer on the wall.", 100-i,$
" bottles of beer.", " Take one down, pass it around," , $99-i, " bottles of beer on the wall." endfor End  Since in IDL "FOR"-loops are the embodiment of pure evil (see http://www.idlcoyote.com/tips/forloops.html and http://www.idlcoyote.com/tips/forloops2.html) there is also a loop free IDL way: Pro bottles_noloop b=(reverse(shift(sindgen(100),-1)))[1:99] b2=reverse(sindgen(99)) wallT=replicate(' bottles of beer on the wall.', 100) wallT2=replicate(' bottles of beer.', 100) takeT=replicate('Take one down, pass it around,', 100) print, b+wallT+string(10B)+b+wallT2+string(10B)+takeT+string(10B)+b2+wallT+string(10B) End  I found the above example very helpful but overdone. This is a more simple version: Pro bottles_noloop2 n_bottles=99 b1 = reverse(SINDGEN(n_bottles,START=1)) b2= reverse(SINDGEN(n_bottles)) wallT=replicate(' bottles of beer on the wall.', n_bottles) wallT2=replicate(' bottles of beer.', n_bottles) takeT=replicate('Take one down, pass it around,', n_bottles) print, b1+wallT+string(10B)+b1+wallT2+string(10B)+takeT+string(10B)+b2+wallT+string(10B) End  ## Idris beerSong : Fin 100 -> String beerSong x = verses x where bottlesOfBeer : Fin n -> String bottlesOfBeer fZ = "No more bottles of beer" bottlesOfBeer (fS fZ) = "1 bottle of beer" bottlesOfBeer k = (show (finToInteger k)) ++ " bottles of beer" verse : Fin n -> String verse fZ = "" verse (fS n) = (bottlesOfBeer (fS n)) ++ " on the wall,\n" ++ (bottlesOfBeer (fS n)) ++ "\n" ++ "Take one down, pass it around\n" ++ (bottlesOfBeer n) ++ " on the wall\n" verses : Fin n -> String verses fZ = "" verses (fS n) = (verse (fS n)) ++ (verses n)  ## Inform 6 [ Bottles i; if(i == 1) return "bottle"; return "bottles"; ]; [ Beer i; print i, " ", (string) Bottles(i), " of beer on the wall^"; print i, " ", (string) Bottles(i), " of beer^"; print "Take one down, pass it around^"; i--; print i, " ", (string) Bottles(i), " of beer on the wall^^"; if(i ~= 0) Beer(i); ]; [ Main; Beer(99); ];  ## Inform 7 ### Programmatic solution Beer Hall is a room. When play begins: repeat with iteration running from 1 to 99: let N be 100 - iteration; say "[N] bottle[s] of beer on the wall[line break]"; say "[N] bottle[s] of beer[line break]"; say "Take one down, pass it around[line break]"; say "[N - 1] bottle[s] of beer on the wall[paragraph break]"; end the story.  ### World model solution This solution uses in-game objects to represent the wall and the bottles. Beer Hall is a room. The plural of bottle of beer is bottles of beer. A bottle of beer is a kind of thing. The wall is a scenery supporter in Beer Hall. 99 bottles of beer are on the wall. When play begins: while something is on the wall: say "[what's on the wall] on the wall[line break]"; say "[what's on the wall][line break]"; say "Take one down, pass it around[line break]"; remove a random thing on the wall from play; say "[what's on the wall] on the wall[paragraph break]"; end the story. To say what's on the wall: if more than one thing is on the wall, say list of things on the wall; otherwise say "[number of things on the wall in words] bottle[s] of beer".  ## Io bottles := method(i, if(i==0, return "no more bottles of beer") if(i==1, return "1 bottle of beer") "" .. i .. " bottles of beer" ) for(i, 99, 1, -1, write( bottles(i), " on the wall, ", bottles(i), ",\n", "take one down, pass it around,\n", bottles(i - 1), " on the wall.\n\n" ) )  ## Ioke bottle = method(i, case(i, 0, "no more bottles of beer", 1, "1 bottle of beer", "#{i} bottles of beer")) (99..1) each(i, "#{bottle(i)} on the wall, " println "take one down, pass it around," println "#{bottle(i - 1)} on the wall.\n" println )  ## J As posted at the J wiki bob =: ": , ' bottle' , (1 = ]) }. 's of beer'"_ bobw=: bob , ' on the wall'"_ beer=: bobw , ', ' , bob , '; take one down and pass it around, ' , bobw@<: beer"0 >:i.-99  Output: 99 bottles of beer on the wall, 99 bottles of beer; take one down and pass it around, 98 bottles of beer on the wall 98 bottles of beer on the wall, 98 bottles of beer; take one down and pass it around, 97 bottles of beer on the wall ... 3 bottles of beer on the wall, 3 bottles of beer; take one down and pass it around, 2 bottles of beer on the wall 2 bottles of beer on the wall, 2 bottles of beer; take one down and pass it around, 1 bottle of beer on the wall 1 bottle of beer on the wall, 1 bottle of beer; take one down and pass it around, 0 bottles of beer on the wall  ## Java ### Console MessageFormat's choice operator is used to properly format plurals. import java.text.MessageFormat; public class Beer { static String bottles(int n) { return MessageFormat.format("{0,choice,0#No more bottles|1#One bottle|2#{0} bottles} of beer", n); } public static void main(String[] args) { String bottles = bottles(99); for (int n = 99; n > 0; ) { System.out.println(bottles + " on the wall"); System.out.println(bottles); System.out.println("Take one down, pass it around"); bottles = bottles(--n); System.out.println(bottles + " on the wall"); System.out.println(); } } }  Optimized for speed and few I/O operations public class Beer { public static void main(String[] args) { int bottles = 99; StringBuilder sb = new StringBuilder(); String verse1 = " bottles of beer on the wall\n"; String verse2 = " bottles of beer.\nTake one down, pass it around,\n"; String verse3 = "Better go to the store and buy some more."; while (bottles > 0) sb.append(bottles).append(verse1).append(bottles).append(verse2).append(--bottles).append(verse1).append("\n"); System.out.println(sb.append(verse3)); } }  Recursive public class Beer { public static void main(String args[]) { song(99); } public static void song(int bottles) { if (bottles >= 0) { if (bottles > 1) System.out.println(bottles + " bottles of beer on the wall\n" + bottles + " bottles of beer\nTake one down, pass it around\n" + (bottles - 1) + " bottles of beer on the wall.\n"); else if (bottles == 1) System.out.println(bottles + " bottle of beer on the wall\n" + bottles + " bottle of beer\nTake one down, pass it around\n" + (bottles - 1) + " bottles of beer on the wall.\n"); else System.out.println(bottles + " bottles of beer on the wall\n" + bottles + " bottles of beer\nBetter go to the store and buy some more!"); song(bottles - 1); } } }  ### An object-oriented solution Translation of: C++ ### GUI Library: Swing Library: AWT This version requires user interaction. The first two lines are shown in a text area on a window. The third line is shown on a button which you need to click to see the fourth line in a message box. The numbers update and the process repeats until "0 bottles of beer on the wall" is shown in a message box, when the program ends. import java.awt.BorderLayout; import java.awt.event.ActionEvent; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JOptionPane; import javax.swing.JTextArea; public class Beer extends JFrame { private int x; private JTextArea text; public static void main(String[] args) { new Beer().setVisible(true); } public Beer() { x = 99; JButton take = new JButton("Take one down, pass it around"); take.addActionListener(this::onTakeClick); text = new JTextArea(4, 30); text.setText(x + " bottles of beer on the wall\n" + x + " bottles of beer"); text.setEditable(false); setLayout(new BorderLayout()); add(text, BorderLayout.CENTER); add(take, BorderLayout.PAGE_END); pack(); setLocationRelativeTo(null); setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE); } private void onTakeClick(ActionEvent event) { JOptionPane.showMessageDialog(null, --x + " bottles of beer on the wall"); text.setText(x + " bottles of beer on the wall\n" + x + " bottles of beer"); if (x == 0) { dispose(); } } }  ## JavaScript ### ES3-5 var beer = 99; while (beer > 0) { var verse = [ beer + " bottles of beer on the wall,", beer + " bottles of beer!", "Take one down, pass it around", (beer - 1) + " bottles of beer on the wall!" ].join("\n"); console.log(verse); beer--; }  ### ES6 let beer = 99; while (beer > 0) { let verse = ${beer} bottles of beer on the wall,
${beer} bottles of beer! Take one down, pass it around${beer-1} bottles of beer on the wall;

console.log(verse);
beer--;
}


### Functional / Recursive

var bottles = 99;
var songTemplate  = "{X} bottles of beer on the wall \n" +
"{X} bottles of beer \n"+
"Take one down, pass it around \n"+
"{X-1} bottles of beer on the wall \n";

function song(x, txt) {
return txt.replace(/\{X\}/gi, x).replace(/\{X-1\}/gi, x-1) + (x > 1 ? song(x-1, txt) : "");
}

console.log(song(bottles, songTemplate));


### Other Examples

More skilled solution "one-liner" with grammar check

Comment: This being a "one-liner" is arguable. The author has chosen not to put a line break after the declaration of the beer variable. By using the authors definition, most of the other solutions could pass as a "one-liner".

// Line breaks are in HTML
var beer; while ((beer = typeof beer === "undefined" ? 99 : beer) > 0) document.write( beer + " bottle" + (beer != 1 ? "s" : "") + " of beer on the wall<br>" + beer + " bottle" + (beer != 1 ? "s" : "") + " of beer<br>Take one down, pass it around<br>" + (--beer) + " bottle" + (beer != 1 ? "s" : "") + " of beer on the wall<br>" );


Legitimate "one-liner" with grammar check, using declarative methods.

Array.from(Array(100).keys()).splice(1).reverse().forEach(n => console.log(${n} bottle${n !== 1 ? 's' : ''} of beer on the wall\n${n} bottle${n !== 1 ? 's' : ''} of beer\nTake one down, pass it around\n${n - 1} bottle${n - 1 !== 1 ? 's' : ''} of beer on the wall\n\n));


Object Oriented

function Bottles(count) {
this.count = count || 99;
}

Bottles.prototype.take = function() {
var verse = [
this.count + " bottles of beer on the wall,",
this.count + " bottles of beer!",
"Take one down, pass it around",
(this.count - 1) + " bottles of beer on the wall!"
].join("\n");

console.log(verse);

this.count--;
};

Bottles.prototype.sing = function() {
while (this.count) {
this.take();
}
};

var bar = new Bottles(99);
bar.sing();


An alternative version:

function bottleSong(n) {
if (!isFinite(Number(n)) || n == 0) n = 100;
var a  = '%% bottles of beer',
b  = ' on the wall',
c  = 'Take one down, pass it around',
r  = '<br>'
p  = document.createElement('p'),
s  = [],
re = /%%/g;

while(n) {
s.push((a+b+r+a+r+c+r).replace(re, n) + (a+b).replace(re, --n));
}
p.innerHTML = s.join(r+r);
document.body.appendChild(p);
}



## Joy

LIBRA

_beerlib == true;

HIDE
beer == "of beer " putchars;
wall == "on the wall" putchars;
take1 == "Take one down and pass it around, " putchars;
dup3 == dup dup dup;
comma == ", " putchars;
period == ". " putchars;
bottles == [small]
[[null] [pop "no more bottles " putchars] [put "bottle " putchars] ifte]
[put "bottles " putchars] ifte;
sing-verse == dup3 bottles beer wall comma
bottles beer ".\n" putchars
take1 pred bottles beer wall period newline newline;
sing-verse-0 == "No more bottles of beer on the wall, no more bottles of beer\n" putchars
"Go to the store and buy some more, " putchars
99 bottles pop beer wall period newline

IN
(* n -- *)
sing-verses == [null]
[sing-verse-0]
[sing-verse pred] tailrec
END.

99 sing-verses.

## jq

Minimalist:

99
| (. - range(0;.+1) )
| "
\(.) bottles of beer on the wall
\(.) bottles of beer
Take one down, pass it around
\(.) bottles of beer on the wall"
Output:
$jq -n -r -f 99_bottles.jq ... 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 1 bottles of beer on the wall 1 bottles of beer Take one down, pass it around 1 bottles of beer on the wall 0 bottles of beer on the wall 0 bottles of beer Take one down, pass it around 0 bottles of beer on the wall  Variant: def sing: def s: if . == 1 then "" else "s" end; def bottles: if . == 0 then "No more" else "\(.)" end + " bottle\(s)"; (. - range(0;.+1) ) | " \(bottles) of beer on the wall \(bottles) of beer Take one down, pass it around \(bottles) of beer on the wall." ;$bottles | tonumber | sing
Output:
$jq -r --arg bottles 99 -f 99_bottles_variant.jq ... 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 2 bottles of beer on the wall. 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 1 bottle of beer on the wall. No more bottles of beer on the wall No more bottles of beer Take one down, pass it around No more bottles of beer on the wall.  ## Jsish /* 99 Bottles, in Jsish */ function plural(n:number):string { return (bottles == 1) ? "" : "s"; } function no(n:number):string { return (bottles == 0) ? "No" : n.toString(); } var bottles = 99; do { printf("%d bottle%s of beer on the wall\n", bottles, plural(bottles)); printf("%d bottle%s of beer\n", bottles, plural(bottles)); puts("Take one down, pass it around"); bottles--; printf("%s bottle%s of beer on the wall\n\n", no(bottles), plural(bottles)); } while (bottles > 0); ## Julia one-liner for i = 99:-1:1 print("\n$i bottles of beer on the wall\n$i bottles of beer\nTake one down, pass it around\n$(i-1) bottles of beer on the wall\n") end


another solution, handling grammar cases "No more bottles", "1 bottle", "<n> bottles"

bottles(n) = n==0 ? "No more bottles" :
n==1 ? "1 bottle" :
"$n bottles" for n = 99:-1:1 println("""$(bottles(n)) of beer on the wall
$(bottles(n)) of beer Take one down, pass it around$(bottles(n-1)) of beer on the wall
""")
end


shorter, but more cryptic, version of the previous bottles function

bottles(n) = "$(n==0 ? "No more" : n) bottle$(n==1 ? "" : "s")"


0:\:{x[z],y,a,x[z],a,"Take one down, pass it around",a,x[z-1],y,a,a:"\n"}[{($x)," bottle",:[x=1;"";"s"]," of beer"};" on the wall"]'|1_!100 ## Kabap // Loop that spits lyrics to "99 Bottles of Beer"$n = 99;
$out = ""; :loop;$out = $out <<$n << " bottles of beer on the wall, " << $n << " bottles of beer. Take one down, pass it around, " <<$n - 1 << " bottles of beer on the wall…  ";
$n =$n - 1;
if $n > 0; goto loop; return =$out;

## Kitten

99 bottles_of_beer_on_the_wall

define bottles_of_beer_on_the_wall (Int32 -> +IO):
-> n;
n th_verse
if (n > 1): (n - 1) bottles_of_beer_on_the_wall

define th_verse (Int32 -> +IO):
-> n;
n bottles_of_beer on_the_wall       say
n bottles_of_beer                   say
take_one_down_pass_it_around        say
(n - 1) bottles_of_beer on_the_wall say
newline

define bottles_of_beer (Int32 -> List<Char>):
bottles " of beer" cat

define on_the_wall (List<Char> -> List<Char>):
" on the wall" cat

define take_one_down_pass_it_around (-> List<Char>):
"take one down, pass it around"

define bottles (Int32 -> List<Char>):
-> n;
if (n = 0):
"no more bottles"
elif (n = 1):
"one bottle"
else:
n show " bottles" cat

## Klingphix

include ..\Utilitys.tlhy

:bottles
dup 0 ==
(
["no more bottles of beer"]
[ dup 1 ==
(
["1 bottle of beer"]
[dup tostr " bottles of beer" chain]
) if
]
) if
;

( 99 1 -1 )
[ bottles print " on the wall," ?
bottles "," chain ?
"take one down, pass it around," ?
1 - bottles print " on the wall." ? nl
drop] for

" " input


## Klong

bottles::{:[x=1;"bottle";"bottles"]}
itone::{:[x=1;"it";"one"]}
numno::{:[x=0;"no";x]}
drink::{.d(numno(x));
.d(" ");
.d(bottles(x));
.p(" of beer on the wall");
.d(numno(x));
.d(" ");
.d(bottles(x));
.p(" of beer");
.d("take ");
.d(itone(x));
.p(" down and pass it round");
.d(numno(x-1));
.d(" ");
.d(bottles(x-1));
.p(" of beer on the wall");.p("")}
drink'1+|!99

## Kotlin

fun main(args: Array<String>) {
for (i in 99.downTo(1)) {
println("$i bottles of beer on the wall") println("$i bottles of beer")
println("Take one down, pass it around")
}
println("No more bottles of beer on the wall!")
}


## Lambda Prolog

The signature file:

sig bottles.

type println      string -> o.
type round        int    -> o.
type bottles_song int    -> o.

The module file:

module bottles.

println Str :- print Str, print "\n".

round N :- M is N - 1,
NStr is int_to_string N,
MStr is int_to_string M,
BOB = " bottles of beer ",
Line1 is NStr ^ BOB ^ "on the wall",
Line2 is NStr ^ BOB,
Line3 is "take one down, pass it around",
Line4 is MStr ^ BOB ^ "on the wall",
println Line1,
println Line2,
println Line3,
println Line4.

bottles_song 0.
bottles_song N :- N > 0,
round N,
M is N - 1,
bottles_song M.

Then we produce the desired output by setting the system to solve for this goal:

[bottles] ?- bottles_song 99.

## Lambdatalk

{def beer
{lambda {:i}
{br}:i bottles of beer on the wall
{br}:i bottles of beer
{br}Take one down, pass it around
{br}{- :i 1} bottles of beer on the wall
{br}
}}

{S.map beer {S.serie 99 98 -1}}
...
{S.map beer {S.serie 2 1 -1}}
->
99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall

98 bottles of beer on the wall
98 bottles of beer
Take one down, pass it around
97 bottles of beer on the wall
...

2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottles of beer on the wall

1 bottles of beer on the wall
1 bottles of beer
Take one down, pass it around
0 bottles of beer on the wall


## lang5

: ~ 2 compress "" join ;
: verses(*)
dup " bottles of beer on the wall\n" ~ .
dup " bottles of beer\n" ~ .
"Take one down, pass it around\n" .
1 - " bottles of beer on the wall\n\n" ~ .
;

99 iota 1 + reverse verses

## Lasso

### Simple loop

local(
beer = 99,
song = ''
)
while(#beer > 0) => {
#song->append(
#beer + ' bottles of beer on the wall\n' +
#beer + ' bottles of beer\n' +
'Take one down, pass it around\n' +
(#beer-1) + ' bottles of beer on the wall\n\n'
)
#beer--
}

#song


### Query Expression

(with beer in 99 to 1 by -1 select
#beer + ' bottles of beer on the wall' +
#beer + ' bottles of beer\n' +
'Take one down, pass it around\n' +
--#beer + ' bottles of beer on the wall\n'
)->join('\n')


### Query Expression with Autocollect

// this example adds an "s" to bottle until there is only 1 bottle left on the wall

local(s = 's')
with n in 99 to 1 by -1 do {^
#n + ' bottle' + #s + ' of beer on the wall,<br>'
#n + ' bottle' + #s + ' of beer,<br>'
#n = #n - 1
#s = (#n != 1 ? 's' | '')
'Take one down, pass it around,<br>'
#n + ' bottle' + #s + ' of beer on the wall.<br><br>'
^}


## LaTeX

### Recursive

\documentclass{minimal}
\newcounter{beer}
\newcommand{\verses}[1]{
\setcounter{beer}{#1}
\par\noindent
\arabic{beer} bottles of beer on the wall,\\
\arabic{beer} bottles of beer!\\
Take one down, pass it around---\\
\arabic{beer} bottles of beer on the wall!\\
\ifnum#1>0
\verses{\value{beer}}
\fi
}
\begin{document}
\verses{99}
\end{document}


### Iterative

The \loop macro is tail-recursive (Knuth 1984, page 219). Just for fun, this version uses Roman numerals.

\documentclass{minimal}
\newcounter{beer}
\newcounter{showC}
\newcommand{\verses}[1]{
\setcounter{beer}{#1}
\loop
\par\noindent
\Roman{beer} bottles of beer on the wall,\\
\Roman{beer} bottles of beer!\\
Take one down, pass it around---\\
% Romans didn't know how to write zero ;-)
\ifnum\value{beer}=0 ZERO \else\Roman{beer} \fi
bottles of beer on the wall!\\
\ifnum\value{beer}>0
\repeat
}
\begin{document}
\verses{99}
\end{document}


### References

• Knuth, Donald E. (1984). The TeXbook, Addison Wesley.

## LDPL

DATA:
bottles-in-the-wall is number
plural is text

PROCEDURE:
store 99 in bottles-in-the-wall

sub-procedure check-plural
if bottles-in-the-wall is not equal to 1 then
store "s" in plural
else
store "" in plural
end if
end sub-procedure

while bottles-in-the-wall is greater than 0 do
call sub-procedure check-plural
display bottles-in-the-wall " bottle" plural " of beer on the wall," crlf
display bottles-in-the-wall " bottle" plural " of beer." crlf
display "Take one down, pass it around," crlf
subtract 1 from bottles-in-the-wall in bottles-in-the-wall
call sub-procedure check-plural
if bottles-in-the-wall is greater than 0 then
display bottles-in-the-wall " bottle" plural " of beer on the wall." crlf crlf
else
display "No bottles of beer on the wall." crlf
end if
repeat

## Lhogho

to bottle :i
if :i = 0 [output "|No more bottles of beer|]
if :i = 1 [output "|One bottle of beer|]
output word :i "| bottles of beer|
end

to it_one :n
if :n = 1 [output "it][output "one]
end

to verse :i
(print bottle :i "| on the wall,|)
(print word bottle :i ".)
(print "Take it_one :i "|down, pass it round|)
(print bottle :i - 1 "| on the wall.|)
print
end

to sing :i
if :i = 0
[
print "|No more bottles of beer on the wall,
No more bottles of beer.
Go to the store and buy some more.
99 bottles of beer on the wall.|
stop
]
verse :i
sing :i - 1
end

;Using it:
sing 99

## Limbo

implement Beer;

include "sys.m";
include "draw.m";

sys: Sys;

Beer : module
{
init : fn(ctxt : ref Draw->Context, args : list of string);
};

init (ctxt: ref Draw->Context, args: list of string)
{
beers := 99;
for (; beers > 1; --beers) {
sys->print("%d bottles of beer on the wall\n", beers);
sys->print("%d bottles of beer\n", beers);
sys->print("Take one down, pass it around,\n");
sys->print("%d bottles of beer on the wall\n\n", beers-1);
};
sys->print("1 bottle of beer on the wall\n1 bottle of beer\n");
sys->print("Take it down, pass it around\nand nothing is left!\n\n");

}


## Lingo

repeat with i = 99 down to 2
put i & " bottles of beer on the wall"
put i & " bottles of beer"
put "Take one down, pass it around"
put (i-1) & " bottles of beer on the wall"
put
end repeat

put "1 bottle of beer on the wall"
put "1 bottle of beer"
put "Take one down, pass it around"
put "No more bottles of beer on the wall"
put

put "No more bottles of beer on the wall"
put "No more bottles of beer"
put "Go to the store and buy some more"
put "99 bottles of beer on the wall"

## Logo

to bottles :n
if :n = 0 [output [No more bottles]]
if :n = 1 [output [1 bottle]]
output sentence :n "bottles
end
to verse :n
print sentence bottles :n [of beer on the wall]
print sentence bottles :n [of beer]
print [Take one down, pass it around]
print sentence bottles :n-1 [of beer on the wall]
end
for [n 99 1] [verse :n  (print)]

## Logtalk

:- object(bottles).

:- initialization(sing(99)).

sing(0) :-
write('No more bottles of beer on the wall, no more bottles of beer.'), nl,
write('Go to the store and buy some more, 99 bottles of beer on the wall.'), nl, nl.
sing(N) :-
N > 0,
N2 is N -1,
beers(N), write(' of beer on the wall, '), beers(N), write(' of beer.'), nl,
write('Take one down and pass it around, '), beers(N2), write(' of beer on the wall.'), nl, nl,
sing(N2).

beers(0) :-
write('no more bottles').
beers(1) :-
write('1 bottle').
beers(N) :-
N > 1,
write(N), write(' bottles').

:- end_object.


## Lua

local bottles = 99

local function plural (bottles) if bottles == 1 then return '' end return 's' end
while bottles > 0 do
print (bottles..' bottle'..plural(bottles)..' of beer on the wall')
print (bottles..' bottle'..plural(bottles)..' of beer')
print ('Take one down, pass it around')
bottles = bottles - 1
print (bottles..' bottle'..plural(bottles)..' of beer on the wall')
print ()
end


With a numeric for-loop and string formatting:

verse = [[%i bottle%s of beer on the wall
%i bottle%s of beer
Take one down, pass it around
%i bottle%s of beer on the wall
]]
function suffix(i) return i ~= 1 and 's' or '' end

for i = 99, 1, -1 do
print(verse:format(i, suffix(i), i, suffix(i), i-1, suffix(i-1)))
end


Using Lua relational operators and multiple return values:

function bottles(i)
local s = i == 1 and "1 bottle of beer" or
i == 0 and "no more bottles of beer" or
tostring(i) .. " bottles of beer"
return s, s
end

for i = 99, 1, -1 do
print( string.format("%s on the wall,\n%s,\ntake one down, pass it around,", bottles(i)),
string.format("\n%s on the wall.\n", bottles(i-1)) )
end


## Lucid

// Run luval with -s inside the lucid shell script
// The print out is a list of lines. So the output is not separated by new lines, rather
// by '[' and ']' -- I cant figure out how to do string concatenation with numbers in lucid.
// beer(N) ^ bottle(N) ^ wall ^ beer(N) ^ bottle(N) ^ pass ^ beer(N-1) ^ bottle(N-1) ^ wall
// should have worked but doesn't
[%beer(N),bottle(N),wall,beer(N),bottle(N),pass,beer(N-1),bottle(N-1),wall%]
where
N = 100 fby N - 1;
wall = if N > 0 then  On the wall ' else eod fi;
pass = Take one down and pass it around.';
beer(A) = if A > 0 then A else No more' fi;
bottle(A) = if A eq 1 then bottle of beer' else bottles of beer' fi;
end

## NATURAL

El código es de Chris Bednara

DEFINE DATA
LOCAL
01 #BOTTLES  (I2)
END-DEFINE
*
FOR #BOTTLES 99 TO 2 STEP -1
IF #BOTTLES < 98
WRITE #BOTTLES ' BOTTLES OF BEER ON THE WALL'
WRITE ' '
END-IF
*
WRITE #BOTTLES ' BOTTLES OF BEER ON THE WALL'
WRITE #BOTTLES ' BOTTLES OF BEER'
WRITE 'TAKE ONE DOWN, PASS IT AROUND'
END-FOR
*
WRITE '1 BOTTLE OF BEER ON THE WALL'
WRITE ' '
WRITE '1 BOTTLE OF BEER ON THE WALL'
WRITE '1 BOTTLE OF BEER'
WRITE 'TAKE IT DOWN, PASS IT AROUND'
WRITE 'NO MORE BOTTLES OF BEER ON THE WALL'
WRITE ' '
WRITE 'NO MORE BOTTLES OF BEER ON THE WALL'
WRITE 'NO MORE BOTTLES OF BEER'
WRITE 'GO TO THE STORE AND BUY SOME MORE'
WRITE '99 BOTTLES OF BEER'
END
WRITE 'TAKE ONE DOWN, PASS IT AROUND'
*
END

## M4

define(BOTTLES', bottles of beer')dnl
define(BOTTLE', bottle of beer')dnl
define(WALL', on the wall')dnl
define(TAKE', take one down, pass it around')dnl
define(NINETEEN', $1 ifelse($1',1',BOTTLE,BOTTLES) WALL
$1 ifelse($1',1',BOTTLE,BOTTLES)
ifelse($1',0',,TAKE') ifelse($1',0',,NINETEEN(eval($1-1))')')dnl NINETEEN(99) ## MACRO-11 ; ; 99 BOTTLES OF BEER ; WRITTEN BY: BILL GUNSHANNON ; .MCALL .PRINT .EXIT .RADIX 10 MESG1: CNUM1: .ASCII " " .ASCII " BOTTLES OF BEER ON THE WALL, " CNUM2: .ASCII " " .ASCII " BOTTLES OF BEER."<13><10> .ASCII "TAKE ONE DOWN AND PASS IT AROUND, " CNUM3: .ASCII " " .ASCIZ " BOTTLES OF BEER ON THE WALL."<13><10><10> MESG2: .ASCII " 2 BOTTLES OF BEER ON THE WALL, " .ASCII " 2 BOTTLES OF BEER."<13><10> .ASCII "TAKE ONE DOWN AND PASS IT AROUND, " .ASCIZ " 1 BOTTLE OF BEER ON THE WALL."<13><10><10> MESG3: .ASCII " 1 BOTTLE OF BEER ON THE WALL, " .ASCII " 1 BOTTLE OF BEER."<13><10> .ASCII "TAKE ONE DOWN AND PASS IT AROUND, " .ASCIZ "NO MORE BOTTLES OF BEER ON THE WALL."<13><10><10> MESG4: .ASCII "NO MORE BOTTLES OF BEER ON THE WALL, " .ASCII "NO MORE BOTTLES OF BEER."<13><10> .ASCII "GO TO THE STORE AND BUY SOME MORE, " .ASCIZ "99 BOTTLES OF BEER ON THE WALL."<13><10><10> .EVEN COUNT1: .WORD 99 ; STARTING NUMBER OF BOTTLES PV: .WORD 10.,1, ; POSITION VALUES FOR 2 DIGITS START: MOV COUNT1, R0 MOV R0, R5 DEC R5 AGAIN: MOV #CNUM1, R1 ; CONVERT NUMBER OF BOTTLES TO ASCII FOR THE FIRST FIELD MOV R0,-(SP) MOV R1,-(SP) MOV R2,-(SP) MOV R3,-(SP) MOV R4,-(SP) MOV R5,-(SP) MOV #PV, R3 MOV #2, R2 A1$:       MOV     #-1,R4
A2$: INC R4 SUB (R3), R0 BCC A2$
MOVB    R4, (R1)+
A21$: SOB R2, A1$

;   REMOVE LEADING ZERO - JUST LOOKS BETTER THAT WAY

MOV     #CNUM1, R1
CMPB    (R1), #48
BNE     CONT1
MOVB    #32, (R1)
CONT1:     MOV     #CNUM2, R0

;    MOVE THE ASCII NUMBER TO FIELD TWO RATHER THAN COMPUTING IT AGAIN

MOVB    (R1)+, (R0)+
MOVB    (R1), (R0)

MOV     R5, R0
MOV     #CNUM3, R1

;       CONVERT NUMBER OF BOTTLES TO ASCII FOR THE THIRD FIELD

MOV     #PV, R3
MOV     #2, R2
B1$: MOV #-1,R4 B2$:       INC     R4
SUB     (R3), R0
BCC     B2$ADD (R3)+, R0 ADD #48, R4 MOVB R4, (R1)+ B21$:      SOB     R2, B1$; REMOVE LEADING ZERO - JUST LOOKS BETTER THAT WAY MOV #CNUM3, R1 CMPB (R1), #48 BNE CONT2 MOVB #32, (R1) CONT2: MOV (SP)+,R5 MOV (SP)+,R4 MOV (SP)+,R3 MOV (SP)+,R2 MOV (SP)+,R1 MOV (SP)+,R0 ; HANDLE SPECIAL GRAMMER CASES CMP R0, #2 BNE ONE .PRINT #MESG2 BR DONE ONE: CMP R0, #1 BNE GREATER .PRINT #MESG3 BR DONE GREATER: .PRINT #MESG1 DONE: ; DECREMENT THE COUNT AND START AGAIN MOV R5, R0 DEC R5 TST R0 BNE AGAIN ; OUT OF BEER, SEND THEM TO THE STORE .PRINT #MESG4 ; CLEAN UP AND GO BACK TO KMON .EXIT .END START ## MAD  NORMAL MODE IS INTEGER BOTLES = 99 VERSE WALL.(BOTLES) BOTL.(BOTLES) PRINT FORMAT TKDWN BOTLES = BOTLES - 1 WALL.(BOTLES) PRINT FORMAT EMPTY WHENEVER BOTLES .G. 0, TRANSFER TO VERSE INTERNAL FUNCTION(B) ENTRY TO BOTL. WHENEVER B .E. 1 PRINT FORMAT ONEBTL OTHERWISE PRINT FORMAT BBTL,B END OF CONDITIONAL FUNCTION RETURN END OF FUNCTION INTERNAL FUNCTION(B) ENTRY TO WALL. WHENEVER B .E. 0 PRINT FORMAT NOMORE OR WHENEVER B .E. 1 PRINT FORMAT ONEOTW OTHERWISE PRINT FORMAT BBOTW,B END OF CONDITIONAL FUNCTION RETURN END OF FUNCTION VECTOR VALUES BBOTW =$I2,S1,27HBOTTLES OF BEER ON THE WALL*$VECTOR VALUES BBTL =$I2,S1,15HBOTTLES OF BEER*$VECTOR VALUES TKDWN =$32HTAKE ONE DOWN AND PASS IT AROUND*$VECTOR VALUES ONEOTW =$S1,29H 1 BOTTLE OF BEER ON THE WALL*$VECTOR VALUES ONEBTL =$S1,17H 1 BOTTLE OF BEER*$VECTOR VALUES NOMORE =$35HNO MORE BOTTLES OF BEER ON THE WALL*$VECTOR VALUES EMPTY =$*$END OF PROGRAM ## make ### BSD make Library: jot Works with: BSD make START = 99 UP != jot - 2 expr$(START) - 1 1

0-bottles-of-beer: 1-bottle-of-beer
@echo No more bottles of beer on the wall!

1-bottle-of-beer: 2-bottles-of-beer
@echo One last bottle of beer on the wall!
@echo
@echo One last bottle of beer on the wall,
@echo One last bottle of beer,
@echo Take it down, pass it around.

.for COUNT in $(UP) ONE_MORE != expr 1 +$(COUNT)
$(COUNT)-bottles-of-beer:$(ONE_MORE)-bottles-of-beer
@echo $(COUNT) bottles of beer on the wall! @echo @echo$(COUNT) bottles of beer on the wall,
@echo $(COUNT) bottles of beer, @echo Take one down, pass it around. .endfor$(START)-bottles-of-beer:
@echo $(START) bottles of beer on the wall, @echo$(START) bottles of beer.
@echo Take one down, pass it around.


Usage: make or make START=99

### GNU make

Works with: GNU make version 3.81
PRED=expr $* - 1 1-bottles: 1-beer pass @echo "No more bottles of beer on the wall" %-bottles: %-beer pass @echo "$(PRED) bottles of beer on the wall\n"
@-$(MAKE)$(PRED)-bottles

1-beer:
@echo "One bottle of beer on the wall, One bottle of beer"

%-beer:
@echo "$* bottles of beer on the wall,$* bottles of beer"

pass:
@echo "Take one down and pass it around,"


Usage: make 99-bottles

This will fork 99 make processes. You might need to raise your process limit (ulimit -p).

### GNU make

##### Without using a shell command to decrement the counter
Works with: GNU make version 3.81
digits:=9 8 7 6 5 4 3 2 1 0
numbers:=$(foreach x,$(filter-out 0,$(digits)),$(foreach y,$(digits),$x$y)) numbers+=$(digits)

bottles=bottle$(if$(findstring /1/,$@),,s) num=$(if $(findstring /0/,$@),$(empty),$(@F))
action=$(if$(findstring /0/,$@),$(buy),$(pass)) beer:=of beer wall:=on the wall empty:=No more pass:=Take one down and pass it around. buy:=Go to the store and buy some more. # Function to generate targets for each verse of the song. define verse .PHONY:$1
$1: verse/$1/$1 prelude/$2/$2$2

.PHONY: $1-bottles$1-bottles: $1 most?=$1
endef

# Recursive function that loops through the 100 numbers.
define verses
$$(eval$$(call verse,$$(word 1,1),$$(word 2,$1))) $$(if$$(word 2,$1),$$(eval$$(call verses,$$(filter-out$$(word 1,$1),$1))))
endef

# Generate the targets for the 100 numbers.
$(eval$(call verses,$(numbers))) # Main lines in the verse. .PHONY: verse/% verse/%: @echo "$(num) $(bottles)$(beer) $(wall)." @echo "$(num) $(bottles)$(beer)."
@echo "$(action)" # Last line of a verse, which is a prelude to the next verse. .PHONY: prelude/% prelude/%: @echo "$(num) $(bottles)$(beer) $(wall)." @echo "" # Special target for the last line of the song. .PHONY: prelude/ prelude/: @echo "$(most) $(bottles)$(beer) $(wall)!" @echo ""  Usage: make or make N-bottles or make N A version of this script with more comments and an automated test can be found on github.com. ## Malbolge Long version (a real loop version made by Hisashi Iizawa): b';$9!=IlXFiVwwvtPO0)pon%IHGFDV|dd@Q=+^:('&Y$#m!1S|.QOO=v('98$65aCB}0i.Tw+QPU'7qK#I20jiDVgG
S(bt<%@#!7~|4{y1xv.us+rp(om%lj"ig}fd"cxuz]rwvYnslkTonPfOjiKgJeG]\EC_X]@[Z<R;VU7S6QP2N1LK-I
,GF(D'BA#?>7~;:9y16w43s10)p-,l*#(i&%e#d!~{tyxZpuXsrTTongOkdMhgHd]ba_^W@[ZYXW9UNSRQPOHMLK
J-++FE''<A$?>=<;:387xw43s10/(-&m*)('&}${d!~}|^zyxwvutmVqpiRQlkjiKafedc\E_^@\[ZYX;V9NMRQ42NG
LK.IH*F?DCBA$#>7~;{{8xx5uu2rr/oo,ll)ii&f|e"!aw{z\r[vXnmVTpongPkNihgJ_dcFaB^]\UZ=RWV8TSLQ4O N0LE.IHA)E>'BA:?!7~5|38y6/v321q).-&m*)i'&%|{d!~}_{zs\wvutsUqTonPlOjiKgJedFbE_A]@[Z<X;VU7S6Q P22GL/JIB+FEDC%;@?>7~;:987w5v32r0)p-,+k)('~g$#"b~w|uz]xwvutsrqTinQlOjLhgfeH]bECB]\>ZSXWVUTS
RQPON1LE.I,+*((&&$$""~~||zzxxv4u210/(-n+l)(i&gddy~}u^]\ZvutVlUjSQQOOdMKgfeG]F[DBB@@>><<:VU T6L5JO200EJ-HG*E>'B%9>=<|4{2y05v321r).o,mlj(igg|#d!~}uz]x[ZotWUUjoRmlkNibKJIGGEEZ_B]\?Z=XW PU876442NM/KD-B+))''%%##!!}}{{yyw5v32s0q.-&+l)j'hff{"caav{^yxwZutslUpSnQOOdiLgfHHcbaY^A\?Z= ;;PU8SRQ4ONMLEJ-,+))''%%##!=<;{3z1xvvttrrppnnll#j!&g#d!b}|{zyr[vYtsrTjShQfkNihgJedcbaY^A\? Z=;WV9TSRQPOHM0K.-++)ED&B;9"~<;:z2y0wuussqqoom+ljj!&%dzcx}{zy\wvutsrqjSnQPNNLhgIedG\EZCA] \[=S<Q:886644220L/JIHA*)(&&@?!=6}4{yywwuus10/o'n%lj('&f|ezcaa__]][wvuWmVkTRnQlkNLLaJIHFbE_ B]@U>Y<;P9775533H1/KJ,HA*?(&&$$">=<|4{2ywwu321q)p'nl*k('gg${"c~a^z]xwvYtmrUpSRPlOMMbKIGGEE Z_^]?U>S<::8866442200.JIH*@)>C&A@?"=<5|{8y65vtt10/(-n+lk"'&%e{dyb^^\\ZvutVlUjSQmlkMcLaJHHF bECCX]\[=S<Q:886R5PON1LKJCH+F)(=BA@"8!6}{{2y0543s+r)pnnlljjhhffddbb|_zyx[vutslUTSQQOOMihgI_ H]FDDBB@@>><XWV8N7L5331MLK-C,A*(D'BA$""=<;:927xwvt2s0/p-n+*)('~%f#dcaa__]y\ZZotsrTjShQOkjiKa
J_HFFDDBB@@>><X;99NS6QPO2MLKJIHA*E('%%:#8=~;:9z7654321*/p-,m*k(hh}$#dyb}{zy[qZoXVVTTRnmlNdM bKIIGGEECCAA?[>YXWP9T76K42200.JI+G@)>'%A@?!7~5|zzx654t,s*qo-n+*jj!h%fec!b}|{^s\[vYWWlqTonQlO jchKfIHFFDDB^]\>T=R;P9NS6QPO2MLE.-,*FED&<%:#!!}}{{yyw543s+r)pnnl*kii~%f#"caa|{zsx[ZutVrkTinQ lkNiLgfe^cFEDYBW\[=YR;P977553O200EJIH*@)>C&$$9>!<;|9z7654-tsrppnnll#('&f|ezca}|{]s\qZXtsrTjS hQOOMihgI_H]FDDB^A\[><<WVUTSLQ43NM/KD-BG*ED'B%@?>=<5:{zy0wuussqqoommki'hff{"c~}{t]\wvuWmVk pSnmPNNcLKfIGG\aD_^A\?T=<;99775QPO1G0E.,HG)E>'<%#?"~~5:98x0w.ussq/pnn%*k('hff#z!ba|{z\r[puXs rUpSnglONihgI_H]FDDYBW\[Z<R;P977553311//--++))'CBA#9"7<}:9z7x54-t1rq(ommkkiiggeecca}|{]s\qZX tsrTjShQOkjiKaJ_HFFDDB^A\[==XWVOT7R542N1LKJ-HGF?D'B%""7~5|zzxxv43s1*q(ommk)jhh}e"!~a|{zyr[ vYXVVTTRRPPNNLLJJHH]FD_A]V?TY<WVU8SRQPOHM0K.-++))''%%#?"~~5:9y70w.us1r/.-n+*)('~%fedbbwu^\ xwvXnWlUSSQQOOMMKKIIGGEa_AW@UZ=XW:U8SRQPONG0/.C,*FED&<%:#!!}}{{yywwuussqqo-n+*k(!h%f#"!awu ^\\ZZoXVrqpRhQfOMMKgfeG]F[DBB@\[Z<R;P97S6QP22GL/J-,*F)DCB%:?"!~||zz1x/432r*q(ommkkiiggeeccaa _{^yx[vYtmVqTSQQOOMMKKIeHFF[_A]V?T=;;9977553O2MLK.IHAF)('%%##!=~||3876v.u,sq/pnn%*)(h~g|ecc aa__]][[YuXsrUSSnmleNMhgfH^G\aD_^A\?ZYXQ:98M644220LK-IB+@)''%%#?>=}5|3zxxv4u21r/p-,+*#(i&g# c!~av_t][[YutsUkTiRPPNNLLJJHHFFDDB^A\[Z=XWVUTM6Q43HM0..CH+FE''BA@?>=6;|9z765u-t+0q.-,m*)('&% |#dcbuzy[wpYnWUUSonmOeNcLJJHHFFDDBB@\?ZY<W:UTSRQPOH1L/.,,**(D'%%:?>=}5|3zxxvvttrrppn,m*)ii &%#"!~}v{^y\wvuWmVkpSnmlOjihgfedc\aD_BAV[Z<XQ:OT7RQPI2M0/--++)EDC%;9"~~||zz1xvv-trrppn,m*) (!hg#c!xav_]yxwYoXmVTTRRPPNjihJI^GEECCAA??=Y<::OT7RQ4O2G0K.-BGFE'=&;9"7<}:98y6/4ut10/o'n% *kii~%f#"c~a|{t]x[ZXXVrqpRhQfOMMKKIIGGEECCA]@[Z<<WVUNS6Q431M0KJI,GFE>C&%""7~|:9y70w.us10/o' n%ljjhhffddb~a|{^\\wvutmVUTRnQlkNiLgfed]FE_A]V?TY<WV977RQPONMF/.I,**?D'BA?"=<;:981x5vussq/ .-m%l#jh&%dzcxa_{zy[qZoXVrqpRhQfOMMKgJHH]baBXAV?=Y<WV88SRQPONMFK.I,+)E(CBA?>=<;:927x5vuss qqo-,+k#j!hffddbb^^s\qZXXVVTpSQQfkNihgIHcbaCYBW\?==RW:UT755J321FK.IH+F)>'B%9"~~||zzxxvvt 210p(o&mkki'&%e{dyb^z]xwvYtmrUTSQmlkMcLaJHdcbDZCXA?[><<QVUT6L5J31MLK-C,A*((&&$$""~<}:9zxx5 4-tsrp.o,+l)j'&}f#d!~}_u^s\ZZXXVrqpRhQfOMihJf_H]FDDB^]\>T=R;99775Q4ON00KJIBG*E('%A$?>=~;:927
xwvttr0/.n,m$)('g}f{"c~}{^yxwvoXsVUSShQOkjLhaJ_HFbaBXAV?=YX:VO8M644220L/JI++FEDCB;@#>!<;:z 2y05v321r/.-,+$)j'hgeeccaa__]][wZXXmVkTiRPPNjMhgfIdcba_XA@?==;;9977L5J31MLK-C,A*((&BA@"8!6}
{{y765u-t+rppn,m*)j'h%$#"!~}v{^y\[YutsUkTiRPPNNLhgfH^G\ECCAA??==;;9UTS5K4IN1LKJC,G*)''%%#?>= }5|3zxxvvttrrppnnl*k('gg|e"c~a__ty\wvuXmVUTinmlNdMbKIedFb[DYB@\?==RWVU7M6K42N1LK.,,G@E('&$@#
>=~;|927xw4uss*/.n,%l#(i&%f#d!~w{^][[YYWWlUjonmOeNcLJJHHFFDDB^A\[==XWVOT7R542N1LKJ-HGF?D'&%
:?"=<}:3z7xwuussqqo-,+k#j!h}fddb~}_{t]r[YYWWUqpoQgPeNLLJJHHFFDDBB@@>Z=XWV9N7R54I2GLKJ,B+@)''
''%%##!=~;:zz765.3t1rq(-,+k#j!&g$#"c~}|uz]x[ZXtsrTjShQOOMMKKIIGGEECCAA?[><<QV9TSR5PONMF/.-+G FE'=&;$""~~||zzxxvvttrrp.o,+ljj'&%$#z!ba|_]]rwZutWrUponmlejMLKIIGGEECCX]\[=S<Q:8TSR4J3H1F/DI ,GF)D'BA@?>=6}|9zxx/432r*q(o&mk)j'&g$e"!~}|{zsx[vYXVVTponPfOdMbKIIGG\ECCAA??=YXW9O8MR5PONG0K
.I,**?D'BA@9"=~}4{yywwuussqqoommkki'h%$ddyb}_ty\ZZotsrTjShmPkjiLaJIHFbaBXAV?==;;9977553311 //-IHG)?(=B%@?"=~;49z7x543s+r)pnnl*)(h~g|ec!buzyxZpYnWUqpoQgPeNLLJJHHFFDC^]??ZYR;V986R5PO N1LKD-,+))''%%##!=<;{3z1xvvttrrppn,mkk"'&f${dy~a|{^\\wvunsVUpSQQfkNihKfIdcb[C^A\[Z<R;PUT6RQ
4I2GL/JIH+FEDC<%@#"~~|:98x0w.ussqqoommkkiigge#"!awuz]xwYYtsrqpinQlOjMKKeHcbaD_^]\[TY<;:O86
R5PO2MF/J-,A*((&BA@"8!6}{{yywwu3trr).-,l$k"igge#dbbw|{z\r[pYWsVqpRRgPkNMKgJedcF[D_B]\>ZS<QV9 TS55POH1L/J-++@E(CBA$?>7~;|{y76v4-t+rp.-,l$k"iggeecca}{z\\wvunsVqTonPleNchKfedGbaY^A@?==;W VU7M6K42N1//DIHG)?(=&$$""~~||zzxxv4u21rpp-,+*#ji&geez!b}|_z]xwvunWrUpSQQfkjiKaJ_HFbE_AA\[ZY XQV9T764P3NML/JIHGF?D'&%##!=<;{3z1x/v-2s0/p-n+*)('&}f#d!buz][[pYnsrqSiRgPNNLLJfedF\EZCA]\[ =S<Q:886644220L/JI++FEDCBA@9>!<}:{yy05v321r/.-,+*)"'hge"!b{zyxwvutmVqToRPlkNihgfedcb[DCBW @>><<::8TSR4J3H1//--++))''%A@?!7~5:{87x5.u2s0/o-&m)j'&ff{"c~a|_]]rwZutsVkpSnQPeNchgfH^G\ECC AA??==;;997S6QPO2MF/J-,A*((&&$$""~~||zzxx/4u210q.-&+l)jig%$d"ybw|_zyx[vunsVUTRnmlNdMbKIIGGEa
B^W@U><<::88664PON0F/DI,GF)D'BA@9"=~}4{yy0wuus10/o'n%ljjh&%$dzcxa__]][wvXtmVkTRRPPNjMhgIIdc baZ_B]@[ZY;Q:OT7RQP3NMLKDI,+FED&<%:#!=<|:3z1xvvttrrppnnlljjh&g$#d!b}|{zyr[vYXVrqpRhQfOMMKKII
GGEECCAA??=Y<WV88SRQPONGL/J-HGF(>'<A$?>=~;:9876/4utsq/pnn%*)i'~g|ec!b}|_z]xwvutsrkToRQOkjiKa J_HFFDDBB@\?==RWV8TM6K42NML.D-B+))'C&A@""=<;:9876/4u2s0/o-&m$)j'&%f#"!~}|{zsx[vuXsVqSShmlOdM
hKJ_HFFDDBB@\[Z<R;P977553311//--++)E(CBA:#"!6}{{yyww.us10/o'n%ljjhhf$#"bxav_]yxwYoXmVTTRRPPN NLhKfeHFF[DC^]\>T=RW:UT7R5J32M0KJ-++F?D'&A@">7~5:{87xvv32+rq.omm$)j'&g$e"!xa|_^\xwYunWlUSonm OeNcLJJHHFFDDBB@@>Z=XW99TSRKP3N10.J-HGF)DCB;@#"!6}{{y765u-t+rppn,+*j"i~geeccaa__]][wZutWUUpo nmfONihgI_H]bE_B]@[ZYXQ:9T755JO200E.CHGF(>'<A$?>!<}:9876/4utsq/.-m%l#jhhf$#c!xav_]][[YuXsrU pSnmlkjchKJIGGEa_AW@U><<::8TS5QJ3H1/KJI+A*?(&&$@#>=~||9876543,1rq.-m+$k"'h%$e"c~}|{zyxqvYXs
VTTinmlNdMbgJedGbE_^]\[ZYR;:9775QPO1M0EJ-HG*E>'B%$9"~~||zzxxvvttrrppn,m*)ii~%f#d!buz]xwvY nsVqTSQQOkjiKaJ_HFFDDBB@@>><<::886R5PON1LE.-H+))>'<A@?!7~5|z8y65v3t10).onmkkiiggeec!~}_u^s\Z ZXXVrqSohQfOMMKKIeHcbEC^]V[>Y<;P977553311//--++)EDC%;$9"7~5:{876w432+rqpnn%lj('g%|ezcaa__]y
\wvYtWrqpohmPkNMKKIIGGEECCAA??==;W:88MR5PON1LKJIHA*)(=&$$">!<;|zz765432+0qpo&+*)i!h}fd"!~v_ t][[YutsUkTiRPPNNLLJJHdGbaD_B]\[ZYXQV9T76KP3NM//JIHGFED=&A#8=~||3876v.u,1r/.-n+*)('&%|edcx} |^zs\qZXXVrqSohQfkNihKf_HGF[_^@V?TY<::OT7RQ4OH10K.IH+F)>'B%@#!=<}4{z765u-t+r).o,+l)j'~%fedb ~a__ty\wvYtWrkpSRQfkNLLafIdcFaD_^W@?Z=;;PU8SR533NMLEJ-,G*((=B%@?"=~;:927xw43s10q(-,+k#j!hffd db~}_{t]r[YYWWUUSSQQOkNihKfIdcbaZCBA?[><<QVU7SL5J311//--++))''%%#?"=<}{{87654-2srqo-n+*k(i&% #"y~a|_^sxwYunWlUSSQQOkjiKaJ_HFFDDBB@@>><<:V9TSR5PONMLKD-,+@)>C&$$9>!<;|92yx543s+r)p'n%lj(i
&%f#zc~au^\\ZZXXVVTTRRPPNNLLafIdcbEZ_B]@?=Y<::OT7RQP3HM0K.-BG*((=B%@?>!<5|{z1xvvt2sqq(-,+k#
j!hffddbb^^\\ZvuWslUjoRmlOMMhgeHGbECCX]@[Z=X;VUNS6Q4O200EJ-++@E(CBA$?>=6}:{8yww.3t10pp-,+ *#(i&g$eccx}{zy\wvutmrUpSnQOOdiLJJ_dGbaC^]\[ZS<W:U866KP3NM//JIHGFE>C&A$?"~~5:{876w43210/(- n+l)jhh}$eccx}{zy\wvutsrqjSnQlOMMbgJedFFa_^]\[ZSX;V9T755JO2MLK.IHGFEDCB;@#"!6}{{y765u3t+0q
.-n+$k(i&geez!buz]xwvYnWrUpSQQfkNihJJe^cFaD_B@@UZ=XWV9TMR5P3200..,,**((&&$$""~<;:z2y0w.3t1 0/p-,%l)jiggeecca}|{]s\qZXXVVTponPfOdMKgfeG]F[DBB@@>><<:V9TS55PONGL/J-H+))>C&A@?"=<;49zy6w43 tr*qp-n+*kii~ge"ca}|_t]x[vuWslUjoRmlNNibgJeHcFDDY^A\[Z=XQV9T76K4INML.D-B+))''%%##!!}}{9z765 v32+rqp'nllj('&f|ezca}|{]s\qZXtsrTjShmPkjMKKfed]bEDCA]@[Z=X;VUTMR5P320LKJ,B+@)''%%##!!}}{{yy wwu321q)p',m*)(i&%#zc~a|{]yr[pYWsVqpohQlOjMKKI^cbDYBW\?ZYX;PU8S653311//--+GFE'=&;""~~|:9 y70w.ussqqo-n+*)j!&ge"!~v{zyx[voXWrUpoRmPkdMhKJHdGEEZ_^]?U>S<:VUT6L5J311//--++))''%A?>~~; :38y6wvt2s0/.o,+)j'hgeeccaa_{zy[qZoXmVTTRRPPeNLLJJHdGbaC^]\U>=X;VU86L5P32GLKJ,B+@)''%%##!= ~||3876v.u,sqqo-,+k#j!&g#ccx}{^y\ZZotWrqpShmPkNMKKedFb[DYB@@>><<::88664PON0F/D-BG*EDC&A:# "!}}{{yyw543s+r)p'n%*k('h%f#"y~a|_^\\ZZXXmrqpRhQfOMiLJJ_dcEaZCXA?[ZY;Q:O8664PO1MF/DI,GFE(CBA :#"=~||38y65v3,srq(-n+*k(i~%f#dcaav_t][wvuWmVkTRRPPNNLLJJHHFFDCAAV[>YXW:UN7R542N1//D-BG*((= B%@?>!<;49z7x5vtt+r).-,lk"'h%#d!~w|_z]\ZZoXVrqSohQfOMMKgfeG]F[DBB@@>ZYX:P9N75QPO1G0E.,,**( (&B%@?!!<;:3z7xwu3t10/p-,+kj'h%ecc~}|{ty\wZutVrkTinQlkMMhgfed]FaD_B@@UZ=XWV9TSRQPI21LKJ,B+ @)''%%##!!}}{{yyw5v32sqq.-,+*)"'hg#"bxav{^yx[vYtsrqpohmPONchKII^cFaC^W@?Z=;;PU8SR5PI2M0/D- ++)EDC%;9"~~||z876v.u,sqqoommk)j'&ff{d!ba_{^yxwZoXWVkTinmlNdMbgJedGbEY^A@?=YXW9O8M6442NM/K D-B+))''%A?>!<}:38y6wv-21q/(o&mk)(h&}f{dbb^^\\ZZXXVVTpSnmOOjihafIdGFDC^]\?ZYXQV9T7R533HM LK-C,AF)DCB%@?>=6}|{2ywwuuss*q(om+*)i!h}fddbb^^\\ZvYtsVTTonmlkdiLKJHdGbaD_B]\[ZYRW:U87L5J3 H1/KJI+A*?D'BA@9"!<}{{2765u-t+0q.-n+l#jih}f{dy~a|{^y\qZuXWlUjonmOeNcLJfIdcbEY^A\?><<::88664 PON0F/D-++))'CB@9"7~||zzx6w432s0).onmk)(h&}f{db~}|^t]r[YYWWUUSSQQOOMMKgJHH]bE_B]@[ZS<W:977 L53ON0LE.C,**((&B%@?>!<;:38y6w432r*/.-,m*)('~gf#d!~a|_zyxwpYXWUqpoQgPeNLLJJHHFFDDBB@@UZ=XW:U 8SRQPOHM0/.,HG)E>'<%#?"~~5:98x0w.ussq/p-,m*k('&%{"c~au^\\qZotWrqSSnmlkjibKfIdcbDZCX]@[ZY<W VUTSRK4O21//--++)E(&&;@?!=6}4{yywwuussq/p-,+kjiggeec!~}_u^s\ZZXtsUqjShQOkNihKII^cFEDY^]\>T= RW:UT7R5JO21L/JI,G*E>'&A?>!<}:3z7xwu321q)p'nlljjhhffddbb^zyxZpYnsVqpRRmlejMhKfIGG\aD_^]@[ ZSX;:977553311//--++)E(&&;@?>~6}49z76w4u210)po,mkk"'h%ecc~}|{ty\[vuWslUjoRmlOjMhgfe^cFaDCXA ?[><<Q:O8MRQP2H1F/--++))''%%##!!};|987x54321*qp-n+*ki!hgfd"!~|_ty\wvYtmVqTSQmPkjiLafIHG\ECC AA??==RWVU7M6K42NML.D-B+))'CBA#9"7~||zzxxvvttr0q.-nll)"ih%fddy~a|{^y\wpYXWUUSonmOeNcLJJHHFba BXAV?==;;997S6QP311LKDI,+*(D'BA?"=<5:{z7x54uss0/.'n+l)jh&%f#"!xa{z\xqZotWrqTRRmlkjchKJeHF F[C^]@[>YXWVOT7R542200..,HGF(>'<%:#8!}}{987w/v-2sqq(-n+*)j'&%#zcb}{z]x[vutsrqjoRQlOjiLgJe dcbaY^A@?=YXW9O8M6K4I20L/--BGFE'=&;@#>=~;|9876543,s0qpnnlljjhhffddbb|_]]rwZutVVqponmlkjchK fIdcbDZCX]@[ZY<WVUTSRQPIN1L/.,HGF(>'<%:#!!}}{{2ywwuussq/pnn%*k('&}f#d!buz]xwvoXsVUjonPlkNc LafedF\EZCAA??==;;997SRQ3I2G0..,H+FED'<%#!!};:9y1x/vttrrppnnlljjh&g#dbb}v{^]\ZvYtsVqTohmPO NchgIe^G\EC_^]?U>SX;VU8S6QPI210..,,*FED&<%:#!!}}{{yywwu3t10qoo,+*#(ihge#d!~a|_zyxqvYtWVTTinm OkdMbKIedFbaDY^]\>T=R;997SR4PI2G0..,HG)E>'<A?>~~;:981x5vus1r/.-n+*)(!hge"!b{zyxwpuXsVqTR nmPkjihgeHcFaB^W@UZ=XW99TSRQPOH1L/J-++@E(CBA?>=<;:3zy654t,s*/p-,m*#jih}#"b~av{^yx[voXWVT TRRPPNNLhgfH^G\ECCA]\[=S<QV9TS644IN10K.,,AF)DC&A9>!~;|98y6w4-ts0q.-n+l)"i&gfd"!~v_t]r[pYWs VqpoRmlejMLKIIGGEECCAA??==;W:88MRQP2H1FK.IH+F)DCB;?"!6;|zz16w43ss0/.-&+l)j'hff{"c~}|_zyxwpu XWVTpSQQfOdMbgfeG]F[DBB@@>><<::88664P311FKJI+A*?D'BA?"=<;:92yx54t2+r).o,+l)"i&gfd"!~|_ty\w vuXmrUTShQOOMMKKIIGGEECCAA?[ZY;Q:OT7RQ4O2MF/.-B+@EDC%;9>!<;|9z76/4uts*qoommkki'&f{dyb|{]y r[pYWsVqpSnQlkdiLKJ_dcbDZCXA??==;;99775QPO1G0E.,,*F)''<A@?!7~5|z8y65vtt10/(onmk)j'&ge"!~w_ zyxZpYnWUUSonmOeNcLJfedF\EZCXA??=Y<WV977RQPOHM0/J-++@E(CB%@#>=<;49zyxvvttrrp.-,lk"iggeeccaa __]][wvuWmVkpSnmPkNihgfe^GbEDYBW\[Z<R;P97S6QPO2MLKJIHAF)D'&$$""~~||z876v.u,sqqoom+*j(!h}fddb b|_zyx[vutsrqjoRQlOMMbgfeG]F[C^]@[T=<WV8TS6K4IN1LK.IB+*)'CBA#9"7~||zzx654t,s*qoommkkiigge# d!~a__t]\wvXtmVkpSnmPkNcLKJHHFFD_^@V?T=;WVU7M6K42200..,,**(D'BA$""=6;|{zx6w43t1r/(-nmljjhhf
fd"caav{zy[qZoXVrqpRhQfOMMKgJHH]baBXAV?=Y<WV977RQJ321/K.IH+F)DC<%@#"7~||zzxxvvtt+0qoo&+l)('
h%$#z!b}_]][[YYWWUqTRRglkMibKIGcFa_B]\[TY<W:9N7L533HMLK-C,A*((&&$$""~~||zzx6wuu,1r/.nn+*) (!h%f#"!awuz]xwvYtsrqjSRQOkjiKaJ_H]F[DBB@@>Z=XW:U8SRQPOHM0/.,,**((&&@?>~6}4{yyw5vtt+0/.n&m kiig%#cybw|_]]rwZutWrUponmlkdMhgJeHcEEZ_^AV?Z=XW9UN7LQ422GL/JIHA*E('%%##!!}}{987w/v-trrppn nlljjh&g#ccx}{^yxZvoXmrUponQfkNMLaJHHFbaBXAV?==;WVU7M6K4220L/--BGFE'=&;@#>=~;|92y6wvttrrp .-,l*k"'h%#d!~w|_^yxZvoXmrUSShmPkjMhKfed]FaD_^]?U>S<::8866442200..,H+FE''BA@?8=~;|{y7x543t1 0/.',m*kjh&geez!b}|{t]\wZXXmrqpRhQfOdMKgfeG]F[DBB@\[Z<R;P977553311//-I,**?D'BA""7~}:98x0w.3 t10q.o&m*kjhhf#"bxav_]][[YYWWUUSSQmPkjLLgeHcFaDBBW\?ZYX;VOT7R54I2GLKJ,B+@)''%A""7<;:z2y0w uus1r/.-n+*#jihfe"!b{zyrwZYXmrUSShmlkMcLaJHHFFDDBB@\?==RW:UT7R5PONGL/J-,**(DCB:#8!};:9y1 x/vttrrppnnlljjh&geez!b}|^^yxwvoXsVqpoQgPejMhgfIdcbaZCB]@[Z=;;VUTSRKP3N1LK-IB+@E(CB$$?>=<;:3 z7x5vtt+0q.-,m*)('&%|e"!b}{]]rwvYnWVUSSQQOOMihJf_H]bE_B]V?Z=<Q:8T755JON0LE.C,*F)DC%%:?"=~; :9y1x/4u210q(-nml#jh&g$#dbb}|uz]\wvuWmVkpSnmPkNihafIdGFDDBB@\?==R;PUTS5K4I200.JIH*@)>'%%##!=
<|:3z1xvvttr0q.-mm*)(!h%f#"!awuz]xwvYtsrkTSRPPNNLhgfH^G\ECCAA??==;;997S6QP311LKJIBG*)DCB$:# 8=~;:{8y6543,1rqp'nl*)i'~g|ec!~}_u^s\ZZXXVVTTRRPPNNLhKfeHcFa_^]V?>Y<WV97M6542NML.J-BG*ED'B;$?"!}}{{y76v43t+0/o-&m$kiig%fddy~}_{t]rwZutVVkpSnQPNjMhgfI^cFECAAV[ZY;Q:OT755JO2ML/J-HA*)D' BA$""=<5:{8y654t,10/.o,+$)jihffddbb^^\\ZZXXVrqpRhQfkNLLafIdcFaD_^]V?>YXW9O8M6442200.JIH*@) >'%A$?>!}}:98705vutr0q.-n+l)('&}$e"cbw^zyxZpYnWUUSonmOeNcLJJHdcEaZCXA??==;W:UT66QPONMF/J-HG F(>'<A$?>=~;:9870w4ut+0/o-&m$kiiggeeccaa__]yxwYoXmrUponQlkjihgeHcFECCX]@>>SX;VUT7RQPONMFK.I ,+@E(&&;@?>~6}49zxx/4u210)p-n+ljj!&g$#"yb}_t][wvuWmVkTRRPPNNLLJJHHFFDDB^A\[Z=R;:97SRQ3I2G0.
.,,**((&&;$">=};4{2yw5v32s0q.',m*k('g%|ezcaa__]][[YYWWUUSSQmPNNchKfeGGbaZC^A\[Z<R;PU8SRQ4ONG 0/JIH*@)>'%%:?>=}5|3zx654t,s*qo-n+*k(i&%${"cb}|{]s\qZXXmrqSohQfkNihKfIdcb[CBAV?=YXW9O8MR5PO
200KJIHA*)(=B%@?"=~;:981xwvt210p(o&+l)(i&}f#dcaa__]][[pYWWUqpRngPeNLLJfedF\EZCAA??==R;9U8SRQ
4IN10/--++)E(CB%##>7~}|3876v.u,sqqoommkkiig%$#cybw|_zy\wZunWVUSoRPPejiKgI^GEECCAA??=YXW9O8M 64P3NM0..IHAF)('%A$?>!<}:927x5vussqqoom+*j(!h}fddb~}|^t]r[pYnWUqTonPPkjibKfIdcbDZCX]@[ZY<WVU
N7653ONM/K.CH+FE(C&A@?>7<}|{yywwu321q)p'nlljjhhf$#"bxav_]][wZXXmrqpRhQfOMMKgJedGbE_^]\U>=X; VU86L5P32GL/JIHA*E('<%:#8=~;:9z16wvus10p.-n%*)i'~g|ecca}^^sxwYunWlUSoRmlOjMhaJIHFbaBXAV?== ;WV8TM6K4220LKJ,B+@)''%%##!!};|98yww43,1rq.omm$)j'&g$e"!x}{^yxwYoXmVTTRRPlkjLbKIGcbaCYBW@> ><<::88664P3NM//JIHA*E(C&$$9>!<;:{876/vutrrppn,m*)jhh%#"y~a_tyxwYoXmVTTRnmlNdMbKIIGGEECCA] @[Z=X;VUTSLQ4O21//-IHG)?(=&@?>~6}4{yywwuussqqo-n+*jj'&%#zc~a^z]xwvYtsrqpiRmPkjiKaJ_HFF[DY B@\[=YR;PU8SRQJ321/K.,,AFED&<%:#!!}}{{yywwuussq/p-,mkk"'hgfd"c~}{^sx[ZYWsrqSiRgPNNLLJJHHFFD _^@V?T=;;9U8SR5P3NMLKJC,+*((&&$$""~~5:9y70w.3t10q.o,+*)('~%fe"caav_ty\ZZotWrqToRmlkjihafIdG F[DBB@@U><XWV8N7L53311//--++))'C&$$9>!<;:{8765432+rqpnnl*)(h~g|eccaa__]][[YutsUkTinQlkNibKJe HFF[C^]@[T=X;:88M64PON0F/D-++))''%%##!!};|98xx/4u2s0qoo&+l)('h}edcx}|^zy\qvYtsVqTohQlOjMKK eHcbDD_^W\?Z=X;99NS6QPO2MLEJ-,G*((=BA#?8!6;|98y6w432+r/p-nll#(i&%ee"!~}v{^y\wZXXmrUponQlkji bgJIdGbaD_B]\[ZYR;VU8S6Q332MLKJIB+F)D'%%:?"=<||987654-2s0q.omm)j'&%f#"!~}|uz]x[vYWWlqpoQgPe NLLJJHHFFDDBB@@>><X;VUTM65PON0F/D-+GFE'=&;">=};4{2ywwuussqqoommk)('g}f{"c~}{^s\wZYWsrTpiRg lOjiKKf_dGbECAAV[>YXW:UNS65P311FKJ,HA*?D'BA?"=<5|9z7xvv-2s0/oo,+*#(i&geccx}{zy\wvunsVUpS QQfkjiKaJ_dGbaD_B]\[ZS<W:U866KP3NM//JIHGF?D'B%@#!!6;|987x54321*/po,+*j"i~ge#"b~wu^\\ZZXXVVT TRRPPNNLhKfeHcFa_^]\U>Y<W:88MR5PO11LKJIHGF?D'B%@#!!6;|987x543210/(-nm*kii~%fddybw|{z\r[puXs rUpiRmPOMMbgfHd]F[DBB@\[Z<R;P977553311//--++)E(CBA9"!~5|zzxxvv-21q/(o&mkkiiggeeccaa_{^yx[YY tmrUTonmOeNchKfeHcFaZ_B]@[><<QVUT6L5JO2MLK.IHA*)(&BA@"8!6}{{yywwuussqqoommk)j'&gee"!~w|_^y\Z ZotWrqToRmlkdiLgJIGGEa_AW@U><<::8866442200.JIH*@)>C&A@?"=<;:3z7xwuussqqoommkk"iggeec!buzy xZpYnsVqpoRmlkjibgJIH]FDDY^]\>T=R;9977553311//--++)EDC%;9>!<;|9z765432+rq.o,+l)j'&%#"!x}_ ^s\ZZXXVVkTRRPlkMibKIGGEECCAA??=Y<::OT7RQ4O2MLKJIHGF?(CB%@#>~~5:9z1x5vussqqoommk)('g}f{dbb ^^\\ZvYWWlqTonmfONiLgfIdG\aDC^A\[>Y<QV9875QPO1G0E.,,**((&&$$""~~||z876v.u,1r/.o,m*#j'h%fddy ~a__t]r[puXsrqTonglONiLJJ_dGEEZ_B]\?Z=XWVO8S6Q422GL/--BG*EDC&A@?>7<}|{yywwuussqqoom+ljj!h}$e
"!b}{zyxwpYtWrUSShmPNNchKfedGba_^]V[>=<:VUT6L5J311//-IHG)?(=&$$""~~||z8yww.321q)p',m*)j'h% #"!~}v_z]x[YYnsVTTinQlkjMhgfedcbaZ_BA@U>S<QVUT6L5JO2ML/JC,G*)>'%%:?>=}5|3zxxv4uss*/.n,%l#jh hffddbb^^\x[YYnsVqpoRgPONLLJfedF\EZCAA?[Z<XQ:O86644220L/JI,**E>C&%@#!!6;|98y6w4-2sr/.-m%l# jhhffddbb^^\\ZZXXmrUSShmlkMcLafIdcFaD_^W@?><<::88664422G0..,,*F)''<A@?!7~5:{87x5v321*/p-n+ ljj!&%dzcxav_ty\wvuXsrqpiRQlOMMbgJHH]bE_B]@[ZYXWPU8S65331MLK-C,A*(DCB:#8!}}{{yywwuussq/p- ,+l)('&%{dc~a__ty\ZZotWrqToRmlkjihgeHcFECCXAV[ZY;Q:OT755JO2MLK.IHGFEDCB;#>!}}49z76w4-ts0q oo&+l)(i&g|#d!ba__]][[YYWWUUSSQQOkNLLafedF\EZ_B]\[>YR;:U8SR5P3NMFK.I,+@)''%%:?>=}5|3zxxvvttr rppnnllj('&f|ez!b}|{^yxwpYtWVkTinQlkjcLKfIGG\aDBBW\?ZY<W:OT7R542200EJIH*@)>'%%##!!}}{{yywwu3 21q)p',m*)(i&}fe"caav{^\\qvYtsVqTonglOjMLJJHHFFDDB^]?[T=R;997755331MLK-C,A*(D'BA@#>=<5|{8yww .3trr).o,+l)j'&%{"cba__]yxwYoXmVTponPfOdMKKIIGGEECCA]@[Z=;;VUTSRQJO210.J-HG*E(CBA@?>7<}:{zx xv43s1*q(om+*)i!h}fddbb^^\\ZZXXVrUponQlkjihgf_HGFD_A]V?T=;;9UTS5K4I200..,,**((&&@#>=~;4{ z7xvv-2s0/p-&m*kjhhffddbb^^s\ZZXXVrUSShmlkMcLafIdcbEZ_BA\[Z<R;P977553311//--++))'C&$$9"7<}
:9z7x5.u2s0qoo&+ljj!&g$#"c~}v{^]xwvXnWlUSonmOeNcLJJHHFFDDBB@@>><<:V9TS6Q4ONMF/J-H+))>C&$$9>! <;:{8765.3tsr)pnn%*)(h~g|#dbbw|_zy\wZutsrqjSnQlOMMbgJHH]bE_^A\[ZYXWPU87644220LKJ,B+@)''<%## !!}}{{yy05v32s0)p-nmkki'&f{dyb|{]yx[putVrkTiRPlkMibKIGGEECCAA??=Y<WVU8M6Q4311//--B+)ED&B; 9"~~||zzxxv432r*q(-n+*)j'~%fedbbuzyxZpYnWUUSSQQOOMMKKIIGcbaCYBW\?ZY<W:UTM65P3NM0K.IHG@E(' &@#!!6;:9y1x/vttrrppnnlljjhhffd"c~}{^yxwvoXsVqTRRglOMMbgJedcFa_^]V[>=XWV8N7L53ONM/K.CHGF( >'<A?>!<}:98765.u2s0qoo&+ljj!&g#"c~}|{zyxqvYtWrqpRhQfkNihgIdGF[DBBW\[=YR;P977553311//--+G FE'=&;@#>=<}4{8yxvvttrrppn,+*j"i~ge#"!awu^s\qZXtWrqpSnglONMKKIIGGEECCAA??==;WV8TM6KP311FK.I H+F)DC<%?"=<}:{876/4ut10/o'n%ljjhhffddbb^^sx[vuXsVqpongPkNiLJJ_dGEEZ_B]\[>YXWVUNS65P311FK .,,AF)DC&A?>=<;:3z7x5vtt+0qoo&+l)('h%#"!~}v{^y\[YYnWUUSonPleNcLJJHdGbaYB]@[ZY;Q:O866K4IN1 LKJC,+F)''<A""7~5:98x0w.3t10qoo&+lk(igg|#d!~a|_ty\[ZXXVVkponPfOdMKKIIGGEECCAA??==;WVU7M6KP3 NM0K.IB+F)(&&@?!=6}4{yywwuussqqoom+*)i!h}e"!~a|{ty\[ZoXVVTTinQlkNiLgfe^GbECAAV[><<QV9TSR5 PONMFK.I,+))'CBA#9"7~|:98x0w.ussqqoommkki'h%dd!~}|{zsx[vYXVrUponQlkjihgeHcFECCAA??TYXW9O8M 6442200..,,**(DCB:#8!};|987x543210/(o,ml#jh&%e#zcxa__]][[YYWWUUSSQmlkMcLaJ_dGbaC^]\[ZYXWPU 8S6QP2NG0E.,H+FED=&%@#!!6;|zz16w43t1r)p-nmkkiiggeeccaa__]][wvuWmVkpSnmlOjchKJeHFF[CAAV[>YX; V9TSL5P3N1//DI,**?D'BA@#>=<5:{8yxvv-trrp.-m+k"igge#d!~{zyxwpuXsVqpoQgPejMhgfIdcbaY^A@[ZY ;Q:O86R533HML.JC,A*((&&$$""~~||zzx654t,s*/p-,m*k('&%$#zc~a^^\\ZvuWslUjSQQOOMMKKIIGGEaDBBW\?
ZYX;VUTSRQPIN10/D-++))>C&A@#>!<;:98765.u2srp.-,l$k"iggeeccaa__]][[YutsUkTinQlkjcLgJI^cbDYBW @>Z=XWV9NS6Q4311F/--+GF(D=&;$">=<|4{2ywwuussqqo-n+*)j'~g$e"!a}v_t][[YutsUkTiRPPNNLLJJHH]FDDB B@\?ZYX;VUNS6Q4311FKJI+A*?(&&$$""~~||zzxxvvt2sqq(-n+*)j'&%|ed!b}|_z]xwvunsVqTSQQOOMMKgJHH]ba C_^AV[Z<XQ:O866442200..,H+FED'BA@?>7~}:{87x5v3210/.',ml)('g}f{dbb^^\\ZZXXVVTponPfOdiLgfIdG ba_^]\U>Y<W:88MR533H1FK.IHG*EDCBA@?>7<}:9z7x5uu,10q(onmki'&%e{dyb^^\\ZvutVlUjSQQOOMMKKIe HFF[C^]@[T=X;VUT6L5J31M0..C,AFED&<%:?"~~5:{876w.utsqq(ommkkii~%#cybw^^\\ZZXXVVTpSnmPkNibg JeHGEECCAA?[Z<XQ:O866442200..,HGF(>'<A?>=~;:3zy6wuu,1rpp',m*)j'h%#z!b}{zy[qZoXVrqpRhQfOMM KKIIGGEECCAA??=Y<WVU8SRQPI21L/--BG*((=B%@?"=~;:98705v3tsqqo-,+k#j!hf#"bxav_]][[YYWWUUSSQmPk jiLgfedcb[DC^A??TY<::OT7RQ4O2MLKJIHG@E(C&A@?!7~5|z876v4u,10/o'n%*k('&g#"!~}|{t]\[pYWsrqSoRg lOjiLgIdGFDDBB@@>><<::O866442N1//DIHG)?(=B%@?>!6;|9zyww.3trr).-,lk"ig%#cybw^^\\ZZXXVVTTR RPlOMMbgJedcFaZCBAV?TY<WV9T7RQJO2M0/--++)ED&B;9"~<;:z2y0wuussqqoo&mkk"'h%#d!~}v_^y\wvYWmVU pSQQfkNLLafIdcFaDY^A@?==;;997SRQ3I2G0..,,**(D'%%:#8=~||3876v.u,1r/.o,m*#jihffddbb^zyxZpYnW UqpoQgPeNcLaJHdGbaD_B]\UZ=X;VUT6L5J31MLK-C,A*((&&$$""~~||zzxxv4u210q.-,%lk(igg|#dbbw|_zy\wZu tsrkpSnQPNjihJI^GEaDBBW\[=YR;P9775QPO1G0E.,,**((&&$$">!<;:{87654-ts0qoo&+ljj!&g#d!b}|{zyxq vYtWVkTRRPPNNcLafedF\EZCAA??==;;997755331M0KJIB+*EDC%;9"~<}{{2y0543s+r).omm)j'&gezc~a^^\ \ZZXtsrTjShQOOMMKKIIGGEaD_^]@[TY<;:8866442NM/KD-B+))''%%##!!};:z81x/4u21r/p-,%l)j'hff{"caav{ ^yxwZutslqToRQOOdihgI_H]FDDBB@@>><<::88664P311FK.IHG*EDCB;#>!<;|9z76543,1rq.o,+lj"i&g#"b~a v{^yxwpYXWUqpoQgPeNLLJJHHFFDDBB@@>><X;99NS6QP3N1F/.-++))''<%#?>~<5|3zxxvvttrrp.-,lk"'h%e"c ~w|_^][[putsUkTiRPlkjLbKIGcbDYBW@>><<::8866442N1//DI,GF)D'BA:#"!}}{{yy0wu32r0)p'nlljjhhffd "!~v_ty\wvYtWrqpinQPkjiKaJ_HFbECCXAV[ZY;Q:OT755JO2ML/J-HGFE>'&%##!!}}{{yyww.ussqqo-nll#('&f |ez!b}|_z]xwvutmrUTSQQOkjLhaJ_HFbaC_^AV[Z<XQ:O86RQP2H1F/--++))''%A?>!<}:98765.ut10p.'n%*kii ~g|#d!~a|_zyxwvutmrUpoRmPkMMbgfI^GFEC_^]?U>S<::8866442200..,H+FE(C<%@#"7~5:98x0w.us10/o'n%lj jh&%e#zcxa__]][[YYWWUqpoQgPejMhgfI^GFEC_B@@UZ=XW:U8SLQ4O21F/--BG*((=BA@"8!6;|987x54-ts0qoo&+ ljj!&g#d!b}|{ty\wZYWWUUSSQQOOMMKKIIGcbDYBW\?==RW:UTS6QPONG0/J-HG*E(CBA@?8=~;|987w5v-2s0/.' nmljj!&%dzcxa_{zy[qZoXVrqSohQfOMMKKIIGGEECCA]\[=S<QV9TS6Q4I2M0KJI+A*?(&&@?>~6}4{yyw543s+r) pnnlljjhhffd"c~}|_zsx[ZuXVVkpSQQfOdMbgJedGbE_XA\?Z=;;PU866KP3NML/JIHAF)D'&$$">=<|4{2ywwu321 q)p'nlljjhhff{"c~}|_zyxwpYtWVTTRRPPNNLLJJ_dcbDZCXA??==;;99775Q4ONM0KJIHG@E('BA@"8!6}{987w/v- trrppnnlljjhhffddb~a|{^y\wvutsrkToRQOkNLLaJ_H]baBXAV?==;;9977553311//-I,GFE>'B%$""~~||z876v
.u,sqqoommkkiig%f#"!bw|_z]\ZZoXVrqpRhQfOMMKKIIGGEECCAA?[><<QV9TSR5PI2M0/-IH*F?(=&$$""~~||zzx 6wuu,s*qoommk)j'&%f#"y~a_]yxwYoXmVTpSQQfkjLhaJ_HFFD_^@V?T=;;997755331M0KJ-H+FED=&A?"~~5:{ yy05v321r/.-,%*kji~geeccx}{z]x[vutsrkToRmPNNchKII^cFa_B]\[ZYXQV9TS6Q4O11FKJ-B+F)(&&$$">=<|
4{2yw543s+r)pnnlljjhhf$e"!~w_z][[puXVVkTinQlkNLLafIHcbDYBW\?ZY<W:OT7R5P311FKJ,HG*?D'BA@#>7 ~;|{yywwuussqq(-,+k#j!hffddbb^^\x[vutWrqjoRmPOMihgI_H]FDDB^]\>T=R;9977553311//--BG*EDC&A@? 8!~}4{2ywwuus10p.'n%ljjhhffddbb^zyxZpYnsVqpSnQlkjibgJIdcbDZCXA?[><<Q:OTSR4J3HM0..CH+FE(C&A @?>=6}|{yywwuussqqoo&mkkiig%fddy~}|^t]rwZutWrUponmlkdiLgJedFb[DYB@\[Z<R;P977553311//--++))'C &A@?"=<;:9870wv32r0)p'nl*kii~%f#"c~w_^\\ZZXXVVTTRRPPNNLhKII^cbaCYBW\?ZY<W:OT7R54220LK-IB+@) ''%A@?!7~5|zzxxvvttr0q.-,m*#ji&geez!buz]xwZuXsrkpSnQPNjihJI^GEECCAA??==;;99775Q422GL/JIH+ FED=&A$#8!6;|9870wv3trr).omm$)j'&g$ez!b}_]]rwvuWmVkTRRPPNjihJI^GEECCAA??=Y<::OTSR4J3HM0KJI
,G@)(C&$$9>!}}49z76w4u21*/ponlljjh&geez!~}_u^s\ZvutVlUjSQQOOMMKKIeHcbECC^]\[TY<;:8T7RQ4O2MLK JCH+FE(C&A##8=<}4{8y65u3,10/.'nml#jhhff{"!~v_t][[YutsUkTiRPPNNLLJJHHFFDC^]@[>S<;V977LQ4ON1 //JCHGF)D&&;@#>=~;|92765vussq/.-m%l#jhhf#"bxav_]y\ZZoXW2qjiR.-e=)KgJ%^]F!~C}W@[ZY;WPbTSqK#m 2k}ih,gTF)bPO%:"K7I54zW7gvv-sr*N.'JI[6FE&fUeAR>P+u:9[[pYW3lkS/.QyON*bKJ%dcF!m_^W@>-<;W:sN6%4 ]n[MjEWz,GFd'&s#L]~6;|WW7UBeuc1qNpLJIk6FEgD1{zyQ=|*:([775WVrUSoAQ,Od*KJJ%HFF!!}}|?.Z=;QPtTq %4o31kj/WIyfSRbC<MLo\<|k{2V0fv-Qb=q.o&JH#G4~VBdy>P_;](x8vH5"3UpSh.fe=ib(J%7cF!2B{i.Z<wuPt 'qLQn"2~YK-hBG)ccC<NM]K7}|Y{i1U/Ad2sO/LoJIkZFEhfTA!~>+{]]88Y6XslT0B.zl,=<;(J%d]F!}BW@yyY+d tO8Mq5PINkjih-BTecQCaqp>J~5XzW165eR,bO/L^m8[6j'D%UBdc>}N^9x&vonF2qCSRmf>M*;J&8^]\n~}}@?[xY +:Pt8S6o]3l~Y..,,*@RQ Short version (a just printing out the lyrics version made by Johannes E. Schindelin): DCBA@?>!}}{{yywwuussqqL-,+*)('&%#c!a>v{z99wv5Ws3DpoA-lON*hg_dc#a~_^Az>Z<;;uUN7 R5nO2~L/JzHe@ED'N?\7<;:W87C54us1N.-nm*GF43gU#dRx=_N)sK&vo4Vrqji.z,Odvh'&e7Fb" DlkAVhZS+Q9(7M_o"110EhzgxFccbBNqLo\}}Y9z7gT4us1*/LKn87G(!&VeT/c?w|_M(xwY5XmVTjo QP-O*LLt9rHGF4C}k@@y-YXut(87p5oON1Li.zf*)?DaO%@^]~~5X9zh05eu?sO/.oJlHGi'~ff0z?? |{tL\[YYnWVkjihP,ON<L'r^]F!~_^|V>y,<utbNSR5Pn[kY|.h+eFccCs@?"!}|:WW7gT4t210/.o K+kkihWf|B"bx};tyK86uGWU~S|{g-edihK9_76o[~_X0?>yweW:sNSRo#31GLi.CB+*?u&Or@]]=~} {9zy6Setc1r/o-JII)jh~%B#dyb=|_tsxJZYnV2kSSRQ,k+<ugf_d]Fn~Y1|z[>x<Q:sT6%Qo"Nk/.-- fG))bPB__9\!Z}{ziy6BvtQsq)M',l7)(!3%f{/y-a<_)]\[Y5#WUDjRnz,Od)btfe^cb!3~1{@?=xvu cUr7p5oIl0FKJI,Gd)b';#?\[~}{3y705vuc+0q_L]Il#"i~Ce{A@?Pv{MyK7It3V1Co{-Pxjiu'_ G]"E3B1jV>-fwQtU7qL4]2HMLEW,gGdcbta$$]\~~5Y9W70vu@csONLnm8*)iX&De#@cxav_]]\qpYnW
!~SinmPkMi(K&eHp"E~CA0\.Zf+:PsrqLK33N10.h,yGSEDPO$$98=mZ|XWD6S43cOqq_:,+lk(E&C|{ A!bav_]y'[vHnFrTjS.Q,+N)KK9edc#!~~^0V>gwvd)98rqp3mN1L|Jz+G@?(ar@9"!~5{{2hxwAdsr q<p-JJl#i'hDBd!-}{z\rJvYXW3T10R@,+N*;(f_76E4Z}^A{?g,wu)88Spp3nNGYKi-U+@(ua:" K7ZZY3EVxBedcbNq_:n+*ZiiWg|Tc!ba^tyK[6Y4F2qTi.Pfxj)LJs%q]Fn3}X]?zT,;;:9N7qQ]nN0 }KhIUedcu=&_:#][<H:XiyxTA-,Orq.K&8l)ih~}eezc~>=*:\\JI64WlTSS{Q?e=iLJJecF!D_X@?> y=vW9sTSRQ#ON0FKWgU+F)bC<$$?\\IYGWz7x5uut1*q;nKI*Z5'Wg${cb?}<;:y\qY6nmVUToQQ?k+i KKs_$c5D~2}@/.>=+::9N&RQ#I!l}ihCHe*E''B_$9"!}HY{Eyx5.3ts0/_-KmlZY'EVCB/b~}^zLKq voGm!qjRQQy,NLbKJ&Hc5EmB|{{?g<Xdu9N&RQ#32~LEWC,xS(D'&;M#>\<Z|{zVwTv@2srL:,+l)jF ~fUBd?Q=_^^L9qZons3qpo.@lewiKJ'ed#bE~CX{?>-x;utb7Mp$4"l1}i{,yG))Da:]"n<;{{EUx/
4-QOrq;n,+*jjF3gBT"!Q,*)sKJv5XFr~TRnQ,xj<bJJ_qcEDm~k|/[Tw<ut(rS55J2!k0i{CHf))('
B_:]]=65:{W10T43c1*q_LnIl)F!h}|#dc>av^:yr[7onF31poh@lNdi;as%7cEE~BXA{UxY<:t8NSqQ
4n!1F..-,GFEDC&Nq?!7~Zk9WygTAt2baM.Kn8*kj'EV$eA.><ML[JZYWFlk0R.@f>*)ha'I7c#!!l ^A@.-x<dVO7764P3!1jE.,BTF)(&%%M">!}HkFiyxTS3Qbr<L-Km7)YX~%$Tz!~a<^]]9J%u5W31S0RQ
lxdMuaIrH#\!!2^]zzTwXd:98rR5JmHkjjJIHfev(aNML!=<Y:9iyx/4@2rNponnI7ZYhhV$T/RxwvN ^99wZX4s2D}/AmlNMvh''eH]"!D~XA?hTf;W:s87p5PO!1LXJg+G*((a&#9K![l|zz7xv4-P1rN_K]m *ZY'~ffezRbav*]9r[ZuGWUqj/A@l,NMu:'ed6#4~|]?UZfe::8s6p4JO21Lii-H**E'=&_^\~}ZYX y7wv4uQbO/L-,mkkj'EV|B@!bw;^y\ZYoX"EqT/{mlxj*)gfrqG"[~~}{{y-x;ucUNS5^o3N~Li.-ff *)cPa%@?Kn}}kX8ywv4uQb0/Ln,mlkjiEVUB@!bw;z99ZYYX"rqT/h-lxN*):'rqc"a~~^{{[-x;QcU NS6^o3N~ki.,fA*)c'a%M^Kn6YkXVV6v4utO=<o-J\kH5'Wff#"?a}*)y8ZYY4V!qTB{m?ej*u:f_^6 En~~|{{ygYXuVtTM6Q3I!ZFKhzBeFcbt<;:?"[<l:zzUxwuts1rMM-,mlG"!~%$0@!b,v_]\rJZ55FrT
}0RzPN*c)'98dc5"~_|A?U>=XW:UNSp4PI[l}KiCffwEbPBA^]>=Z}GFW105vuQr0/;:Klkj('h}${z! ~w+u]9xq%YX43q0o/Q,xNM)KfHG#5ECC|j\hZSeu)8TSp53nNGYihgB+*Eu'B%#9>7<Z|3EVwBetcbrq _:9lHHiiDg|A/b>aO;^y[[I5t"2qpi.PlkjiLJseGpEaZ}^j\y>YvQ)UN7qQ]nN0}KJIUGFE(C&_:?>~ }5:9z7x/Rt21*q.^m+lZ"'EC$Adb~}<zy[qpo5sUk1oQg-Nd*hJ&G]\"BX|VUy<Rv9ONr5KJIm0Fj
-Cg*@d'=<:98\}543W10T43s+Op(L&%Ij"!Ef|Bcyx>_u;sr8Yon4lkj0Qgf,dc)a_%]\"ZY}WVz=S
RvV8Nr5Ko2HGkEi,Bf)?>=a$:^!76Z43Wx0T.-Q+Op(Lm%Ij"Fg}|Bzyx>_u;yrqp6Wml2pi/Pf,Mc)J _%F\[!YX|?UTx;QPtNMqQ3Im0FEiIH*@d'=<#98\}54Xy1Uv.-Q+*N.n&Jk#"Fg}|{A!~=^ts9wp6 tm3Tjih.Oed*Ka'H^]#aCY}WVzZSRvPOs6Lp3Im0Fj-CBAe(>bB;:^!76Z432Vw/S3s+Op(Lm%Ij"F&f |Bcy?}_ut:[q7Xnm3Tji/gfe+Lb(_%cE[!BX|\>TxX:PtTS5Ko2HGkEiCBf@d'=a$:^>~[54Xy10Tu-
Qr*N.-m%Ij(!E}|B"!aw=^t:[qp6tVl2ji/Pf,dc)J&G]#DZ~XW{UTSwW9Os6LKJnNM/EiCBf)?>b%;
:^!76Z{3Wx0Tu-Qr*No'K%$Hi!~De{z@aw=^ts9Zp6Wm3Tjih.Oed*hgI_%F\"CY}@VzZY;Qu8NMLp3I m0FEiIBf)?>b<;_"8\<|43Wx0Tu-,+Op(Lm%I#G!~D|{z@aw=^t:xZpo5m3Tjih.lNd*hJ&G]#DZY}] ?Uy<RQuONr5KoImGFEi,Bf@?c=<@?!\}5Yz2V6v.Rs+O)(L&Jk#"Fg}C#"bx>vu;sr8Yo5Vlkj0Qg-N d*Ka'H^]#DZY}@Vz=SRv9Os6LKoIHlFEi,BAe?>b<;_9]=65Yz21Uv.Rs+*N(L,l$#Gh~}Cdz@aw=^ts
9Zpon4rTj0Qg-kMc)a&G]\"ZYX|?UySRvPOs6Lp3ImGFEi,Bf@?>b%;_"87[;{X21Uv.Rs+O)M'&%Ij
"!E}|B"bx>v<]s9wYo5sUkj0hg-Nd*hJ_%F\[!BX|VzZ<Rv9ONMqQ3IHlFEi,Bf@?c=<#98\<|4X81
0Tu-Qr*No'Kl$Hi!~D|{Abx>_u;\r8Yonm3Tji/Pfe+iKa&d]#DZY}]?UTxXQuOs6LpJIm0FEiCBf)? >bB;_?!7[|43Wx0T.-Qr*No'&J$#"Fg}|B"bxw=ut:r8po5ml2poQg-kMc)J&d]#[Z~^]?zTSwQuOsS
R4o2HlLK-Cg*@dD&<#98\<;{3Wx0/S3s+*N.nK%$H"!Ef|{Ayx>_u;\r8vXnm3kj0hg-Nd*hJ&G]#D ZY}]VUy<RvVONr5KJn1GFj-CgA@d>=aA#9]~65Y32Vw/.R,+Op('K%$H"!Ef|Bcy?v<]s9Z7on4Ukj0
Qgf,jLb(I_%]\"CYX|VUySRv9ONMq4Jn1GFj-Cg*@?c&<;_"8\}54X21U/.R,P*)Mn&%IjGh~}Cdz@x>
_ut:[q7Xn4Ukj0hg-ed*Ka'eG]#DZY}@Vz=SRv9ONr5KJnHGkK-Cg*@?>b<;_"87[|43W10/St,+OpM-
m%Ij"F~D|{Abxw=^t:xZp6Wm3kj0Qgf,Mcb(I_^$E[Z~AW{>TSw:PtT6Lp3IHlLEiCg*@d'=aA#9]~65 Y9y10T4-Qr*No'&J*j"Fg}|Bcyx>vu;sr8pon4rTj0Qgf,dc)a&G]#[!BXW{UTx;QPt7Mq4JIHl/EiC Bf)?>b%;:^87[|43Wx0/S-Qr*No'&Jk#G'g}|Bzy?v<]sr8Yon4Ukj0nPfe+Lb(_%F\"CY}]?UyY;v POsMq4JnHGk.Dh+Ae(>=a$:9]76Z{32Vw/.R2r*No'Kl$H"!Ef|{Ayx>|^t:xZp6tVlk1oQ.fed*Ka'e G]#DZY}@VUySw:PtT6LpJIHl/jDCg*@dD=a$:^!7[|43W10T.-Qr*)M'&Jk#"F~}C#cy?v<]s9Zpo5m
lk1Rhg-ed*Ka&G]\"CY}WVz=SRvV8NrRKo2HGk.DCg*@?cC%;_"8\}543Wx0Tu-,P*)M-m%$Hi!E}|B cy?=^zs9Zp6Wml2ji/gfe+Lba'_^$bD!YX|VUy<RvV8NrLKo2HGk.DCgA@d>=aA#9]~65Y9y1Uv.Rs+
Op(Lm%$H"!E}|Bcy?v<]sr8Yon4rqSi/Pf,jLb(feG$E[!_AW{UySRv9Os6LKoIm0Fj-CgG)d>=a$_9 87[|4X8x0T4t,P0p(Lm%$H"!E}|Bcy?v<]sr8Yon4rqSi/Pf,jLb(feG$E[!_AW{UySRv9Os6LKoIm0 Fj-CgG)d>=a$_987[|4X8x0T4t,P0/oLm%$Hi!E}|{Ay?v<zy[q7uWm3qSi/gfe+Lba'H^$E[Z~XW{>
Tx;Qu8NMqQ3nHlFEi,BAe?>bB$:^!7[|43W10Tu-,Pq)Mn&%I#"!E%e{z@xw={]sr8po5Vlk1Rhg-kMc )J_%cE[!YX|?Uy<RQu8NrLKo2HGk.DCgG)?cC<#98\65Yz2V6v.-Qr*)M'&Jk#G!~De{z@~v<]sr8 po5ml2ji/Pfe+Lb(I_^$E[Z~AWVz=SRvPt7MqQ3IHlFEi,Bf@?c&<;_?>~[;:3W10Tu-Qr*No'Kl$Hi! ~DeB"bx>_u;\rq7onm3qSih.fe+iKa&d]#DZY}@VUy<RvPtNMqKJIm0FEiCBf)?>bB;_"87[|43W7w/ .R,+Op('&J*j"Fg}Cdzy?wv<tsr8vXnWlk1oQgfe+iba_^$ba_AWVzZY;WVUTSRKJnNGFEDhHGFE'=
aA:^!765Y9210T43,+*No-&Jk#"!E%${A!~|{zsr8po5srqpoQg-kjihgfH%cE[ZY}@\[ZYRvV8NMq4 POHGFEiCBfFE'C<@987[|43Wx0/.-Q10/.-,+kH('&%|{A!~wvu;yxwYonm3qSihgfe+iK(_^]\[Z~ AWVUTxXWPOsS5KJIHlLKJI+Ae(DC<@?>=<;{3210T43s1*)M-,l$#"!Ef$#"yx>|ut:[qpo5slkj0nm lkjLb(fedcba_AWVUyYRQPt7MLKJnHGkKJ,BAeEDCBA@?!765Y9y10T.-,+*N.-,+*jG'&}|Bcy?}|{ zyxZpo5Vrqj0hgfed*Kgfe^$E[ZYX|VUTSwQPtT6LKJnNM/EiIHGFE>=<@?>=<;:98x0/.-Q10/o'&J
*j"!~De#zyxwvu;yxwvutsUk1onPfedc)a&d]\[!B^WVz=SRvPONrRQJnHGkK-CBA@?cCBA#987[543
2V65432r*N.-,+*jG'~}C#cyxwv<]srq7uWml2Sihgf,jihJ'H^]\"CY}W{UTSRQuUTS5KJn1MLKDhBA
@d'=aA@98\}54X210/S-,+O/('K%$H"!~D$#"b?v<tsrqp6tsUqj0nmlN+iKa'edF\[Z~^WVUyYXWVU
TSRQJImMFEDCBfFE>=a$:98\<;{321U5.-Q10/o'&%$H(!~}|B"!~|ut:xwvutsUqji/mlkjiha'edc
bDZ~^]?[TSRvV8NMqQPO1GkK-CBf@?cC<;_987[;:z2Vw/.R21*)Mn&%$H(h~}|Bc!~wv<zyr8vXnm3T pi/mlNd*hgfedcbaC_^WVzZY;QPONr5Ko2HGFj-IHA@?cC<;:987[;:z810/.R2r*)M'&J*j"!~D$dzy
xw=^tsrqp6Wm3kj0hgfe+ihgfedcEaY}@\Uy<RQPOsSLKo2HGFjJ,BA@?cC<;:9]=<;:z21U/.-Q1q)
M'&%I)('g}|{A!~v<zyxwvX5srqSihgf,jiba'_^]#DZY}]?Uy<RvV8TMq4JIHGk.Dh+A@dDCB;_?>=
<|43W70/.R,+Op(L,l$#"!E%$dAyx>vu;yr8vun4rk1oh.Oe+ihgfeG]\"ZYXW{[=SRvVUTS5KoO1GFE
DhH*@?>=aA@?!=6543Wx0T4321q)(L,l*#"!E}|{z@~|ut:xwvXnm3qjih.fe+iKg&dcbDYX|\>TS
RvV8NMq4POHGFEiIHG)?>=aA@?!765Y9210TuR210/.n&%$H"!~}C#z@~}v<t:xwvuWmlk1oQgfed*hJ fed]#a_^]\>Tx;WVUNMqQPO1GFEDhH*@?c&<;:98\65Y921U54321*)Mn&%I)(h~}|{z@a}vuts9wYo n4rqSihg-kjLhg&dcbaBXWVzZYXWPOs6LKJnNM/EDCg*@?cC<;_?!76Z:z870/S3s10/('K+k#"Fg% |{A!~w=uts9wvXtmlkji/mlNdcba'e^]#aBXW{>ZYXQuUNrRKoOHGFjJCBfFED&B;:9]=654321U543 210/.-,+k#"!E}|{Ab~}|{t:xwvXn4lk1ongfe+Lha'edF\"C_XWVUyYRQPOsS5KJnHGkKJCBf)?>=aA #?87[;{9810T43s1*)M-,+*)i!~D$dA!~}|^;yxwvutsrT1ohg-kMcb(_^]#DZ~AWVUTxRQPtTS5KJI
HlFEi,BA@dD&B;_?>765Yz21U54t,+*N.-&%I)('&%$dz@~}|{z\9Zpon4lkj0nmOe+iKa'edcba_^@ VzZ<w:PONrRQPImM/EDhBA@dD=<#?>=<;432V65432r0/.'&J*j"!~}|{z@~}|^;y[qpo5srqS0Qmf, jL)gf_^]#D_^]VUTxXQPtNMLpPIHGk.DhHGFE>bBA#9876Z:9810T43210/o'K+k#"!~D$#"!a}vut:
xwvo5srqpih.Oedcba'Hd]\"BX|VUy<RvVUT6qQJIHlLEiI+A@?>=aA@"8\654X87w5.R21*N.-,+k#
"F&%e{zyx>|{zsr8vXtslkji/Pfe+ihgI_^$E[Z~^]?UTxX:VUNMq4oONMLKJIHG)?>=aA@"876Z{3W7 w/.Rs1*)('&J*j"F&f|B"!~|ut:xZvonm3qji/mlkMc)gf_%cE[!_^]\[=SwWV8NMqQ3IHGkK-CBA@d DCBA@">=<54X8x0T4321q)M-,+k#"F&f$#zyx>|{]s9wvonmlk1ongfedcb(feG]\[Z~^]?UyY;QuONr
RQPO1GFEDh+A@dDCBA@98\65Y9y1Uv.-,+*N.-,%Ij(!~}C#zyxw=^zsrqp6nm3qpoQmlkd*Ka&G]\[
Z~^]\UyYX:VOs6qQJIm0k.DhHG)?cCBA#98\<|432V65.-Q+*No-&%I)('g}Cdzyxw=^zyxq7on4rTji
h.ledcba'_^$o ## Maple seq( printf( "%d %s of beer on the wall,\n%d %s of beer.\nTake one down, pass it around,\n%d %s of beer on the wall.\n\n", i, if( i<>1, "bottles", "bottle" ), i, if( i<>1, "bottles", "bottle" ), i-1, if( i-1<>1, "bottles", "bottle") ), i = 99..1, -1 ); ## Mathematica / Wolfram Language Bottle[n_] := ToString[n] <> If[n==1," bottle"," bottles"] <> " of beer" BottleSong[n_] := Speak[ Bottle[n] <> " on the wall," <> Bottle[n] <> ", take one down, pass it around," <> Bottle[n-1] <> " on the wall." ] BottleSong /@ Range[99,1,-1]  ## MATLAB function ninetyNineBottlesOfBeer() disp( [ sprintf(['%d bottles of beer on the wall, %d bottles of beer.\n'... 'Take one down, pass it around...\n'],[(99:-1:2);(99:-1:2)])... sprintf(['1 bottle of beer on the wall, 1 bottle of beer.\nTake'... 'one down, pass it around;\nNo more bottles of beer on the wall.']) ] ); %The end of this song makes me sad. The shelf should always have more %beer...like college. end  ## Maxima bottles(n) := for i from n thru 1 step -1 do ( printf(true, "~d bottle~p of beer on the wall~%", i, i), printf(true, "~d bottle~p of beer~%", i, i), printf(true, "Take one down, pass it around~%"), printf(true, "~d bottle~p of beer on the wall~%", i - 1, i - 1), disp(""))$

bottles(3);
/*

3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall

2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall

1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
0 bottles of beer on the wall

*/


## MAXScript

escapeEnable  = true
resetMaxFile #noPrompt
viewport.setType #view_top
max tool maximize
viewport.SetRenderLevel #smoothhighlights
delay = 1.6
a = text size:30
a.wirecolor = white
theMod = extrude()

for i in 99 to 1 by -1 do -- this will iterate through 99 times use the escape key to terminate.
(
a.text = (i as string + " bottles of beer on the wall")
redrawViews()
sleep delay
a.text = (i as string + " bottles of beer")
redrawViews()
sleep delay
a.text = "Take one down, pass it around"
redrawViews()
sleep delay
a.text = ((i-1) as string + " bottles of beer on the wall")
redrawViews()
sleep delay
)

### A one-line version

Since MAXscript is an expression based language (everything returns a value), it is relatively easy to write long expressions that are only one line long. the following single-line snippet (broken for clarity on the webpage) produces a grammatically correct printout of the song.

for i = 99 to 1 by -1 do (print (i as string + (if i == 1 then " bottle" else " bottles") + " of beer on the wall\n" + i as string +\
(if i == 1 then " bottle" else " bottles") + " of beer\nTake one down, pass it around\n" + (i - 1) as string + (if i - 1 == 1 then "\
bottle" else " bottles") + " of beer on the wall\n" + (if i - 1 == 0 then "\nno more beer" else "")))

## Mercury

% file: beer.m
% author:
%   Fergus Henderson <fjh@cs.mu.oz.au> Thursday 9th November 1995
% Re-written with new syntax standard library calls:
%   Paul Bone <paul@mercurylang.org> 2015-11-20
%
% This beer song is more idiomatic Mercury than the original, I feel bad
% saying that since Fergus is a founder of the language.

:- module beer.
:- interface.
:- import_module io.

:- pred main(io::di, io::uo) is det.

:- implementation.

:- import_module int.
:- import_module list.
:- import_module string.

main(!IO) :-
beer(99, !IO).

:- pred beer(int::in, io::di, io::uo) is det.

beer(N, !IO) :-
io.write_string(beer_stanza(N), !IO),
( N > 0 ->
io.nl(!IO),
beer(N - 1, !IO)
;
true
).

:- func beer_stanza(int) = string.

beer_stanza(N) = Stanza :-
( N = 0 ->
Stanza = "Go to the store and buy some more!\n"
;
NBottles = bottles_line(N),
N1Bottles = bottles_line(N - 1),
Stanza =
NBottles ++ " on the wall.\n" ++
NBottles ++ ".\n" ++
"Take one down, pass it around,\n" ++
N1Bottles ++ " on the wall.\n"
).

:- func bottles_line(int) = string.

bottles_line(N) =
( N = 0 ->
"No more bottles of beer"
; N = 1 ->
"1 bottle of beer"
;
string.format("%d bottles of beer", [i(N)])
).

## min

Works with: min version 0.19.3
(swap quote interpolate puts!) :line

(
(
("$1 bottles of beer on the wall" line) ("$1 bottles of beer" line)
(pop "Take one down, pass it around" puts!)
(pred dup "$1 bottles of beer on the wall" line newline) ) cleave ) :verse 99 'verse over times ## MiniScript Going for the simple/obvious solution here... bottles = function(n) if n == 0 then return "no bottles" if n == 1 then return "1 bottle" return n + " bottles" end function verse = function(n) print bottles(n) + " of beer on the wall" print bottles(n) + " of beer" print "Take one down, pass it around" print bottles(n-1) + " of beer on the wall" print end function for i in range(99, 1) verse i end for  Output: 99 bottles of beer on the wall 99 bottles of beer Take one down, pass it around 98 bottles of beer on the wall 98 bottles of beer on the wall 98 bottles of beer Take one down, pass it around 97 bottles of beer on the wall ... 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around no bottles of beer on the wall ## MIPS Assembly ################################## # 99 bottles of beer on the wall # # MIPS Assembly targeting MARS # # By Keith Stellyes # # August 24, 2016 # ################################## #It is simple, a loop that goes as follows: #if accumulator is not 1: #PRINT INTEGER: accumulator #PRINT lyrica #PRINT INTEGER: accumulator #PRINT lyricb #PRINT INTEGER: accumulator #PRINT lyricc #DECREMENT accumulator #else: #PRINT FINAL LYRICS .data lyrica: .asciiz " bottles of beer on the wall, " lyricb: " bottles of beer.\nTake one down and pass it around, " lyricc: " bottles of beer on the wall. \n\n" #normally, I don't like going past 80 columns, but that was done here. # there's an argument to be had for breaking this up. I chose not to # for simpler instructions. final_lyrics: "1 bottle of beer on the wall, 1 bottle of beer.\nTake one down and pass it around, no more bottles of beer on the wall.\n\nNo more bottles of beer on the wall, no more bottles of beer.\nGo to the store and buy some more, 99 bottles of beer on the wall." .text #lw$a0,accumulator #load address of accumulator into $a0 (or is it getting val?) li$a1,99 #set the inital value of the counter to 99

loop:
###99
li $v0, 1 #specify print integer system service move$a0,$a1 syscall #print that integer ### bottles of beer on the wall, la$a0,lyrica
li $v0,4 syscall ###99 li$v0, 1 #specify print integer system service
move $a0,$a1
syscall #print that integer

### bottles of beer.\n Take one down and pass it around,
la $a0,lyricb li$v0,4
syscall

###99
li $v0, 1 #specify print integer system service move$a0,$a1 syscall #print that integer ### "bottles of beer on the wall. \n\n" la$a0,lyricc
li $v0,4 syscall #decrement counter, if at 1, print the final and exit. subi$a1,$a1,1 bne$a1,1,loop

### PRINT FINAL LYRIC, THEN TERMINATE.
final:  la $a0,final_lyrics li$v0,4
syscall

Write !,n," bottle",$Select(n=1:"",1:"s")," of beer." Write !,"Take one down, pass it around." Quit For ii=99:-1:0 Do beer(ii) ### Brain-damaging bottles set template1="i_n_""of beer on the wall. ""_i_n_"" of beer. """ set template2="""Take""_n2_""down, pass it around. """ set template3="j_n3_""of beer on the wall.""" for i=99:-1:1 do write ! hang 1 . set:i>1 n=" bottles ",n2=" one " set:i=1 n=" bottle ",n2=" it " . set n3=" bottle " set j=i-1 set:(j>1)!(j=0) n3=" bottles " set:j=0 j="No" . write @template1,@template2,@template3 repeat write "One more time!",! hang 5 goto bottles ## MyDef Compile with: mydef_page -mgeneral bottles.def It outputs bottles.txt, which contains the lyrics. bottles$(for:i in 99-1)
$(i) bottles of beer on the wall$(i) bottles of beer
Take one down, pass it around
$(set:i-=1)$(i) bottles of beer on the wall
NEWLINE

## N/t/roff

### Classical version (compatible with classical Bell Lab's TROFF)

Subroutine L1 calls upon itself recursively.

Works with: All TROFF
.nr BS 99 1
.de L1
.ie \\n(BS>1 \{ \
\\n(BS bottles of beer on the wall,
\\n(BS bottles of beer.\c
\}
.el \{ \
\\n(BS bottle of beer on the wall,
\\n(BS bottle of beer.\c
\}
Take one down, pass it around,
\\n-(BS bottles of beer on the wall.

.if \\n(BS>0 .L1
..
.nf
.L1
.fi

### New version (compatible only with GNU TROFF)

Instead of recursion, a while construct can be used instead, to achieve the same results. Technically, the program runs differently.

Works with: GNU TROFF version 1.22.2
.nr beers 99 1
.nf
.while \n[beers]>0 \{ \
.ie \n[beers]>1 \{ \
\n[beers] bottles of beer on the wall,
\n[beers] bottles of beer.\c
\} \" ie \n[beers]>1
.el \{ \
\n[beers] bottle of beer on the wall,
\n[beers] bottle of beer.\c
\} \" el
Take one down, pass it around,
\n-[beers] bottles of beer on the wall.
\} \" while \n[beers]>0
.fi

## Nanoquery

Translation of: Ursa
//
// 99 bottles of beer
//

for bottles in range(99, 1, -1)
bottlestr = ""

if bottles = 1
bottlestr = "bottle"
else
bottlestr = "bottles"
end if

println (bottles + " " + bottlestr + " of beer on the wall")
println (bottles + " " + bottlestr + " of beer")
println "Take one down, pass it around."

if !(bottles = 2)
println (bottles - 1 + " bottles of beer on the wall.\n")
else
println "1 bottle of beer on the wall.\n"
end if
end for

## NASL

bottles = 99;
repeat {
display(bottles, ' bottles of beer on the wall\n');
display(bottles, ' bottles of beer\n');
display('Take one down, pass it around\n');
display(--bottles, ' bottles of beer on the wall\n\n');
} until bottles < 1;

## Neko

/**
<doc>
<h3>Rosetta Code, 99 bottles of beer on the wall, in Neko</h3>

<pre>
Tectonics:
nekoc 99bottles.neko
neko 99bottles
</pre>
</doc>
**/

var message = " of beer on the wall\n";
var beers = 99;

var plural = function(n) {
return if (n == 1) " bottle" else " bottles";
}

var nonesome = function(n) {
return if (n > 0) n else "No more";
}

while (beers > 0) {
$print(nonesome(beers), plural(beers), message);$print(nonesome(beers), plural(beers), " of beer\n");
$print("Take one down, pass it around\n"); beers -= 1;$print(nonesome(beers), plural(beers), message);
if (beers > 0) $print("\n"); }  Output: prompt$ nekoc 99bottles.neko
prompt$neko 99bottles | { head -n 4; echo "..."; tail -n 4; } 99 bottles of beer on the wall 99 bottles of beer Take one down, pass it around 98 bottles of beer on the wall ... 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around No more bottles of beer on the wall ## Nemerle using System; using System.Console; module Bottles { Sing(x : int, bev = "beer", surface = "wall") : void { match(x) { |0 => WriteLine($"No more bottles of $bev on the$surface, no more bottles of $bev"); WriteLine($"Go to the store and get some more $bev, 99 bottles of$bev on the $surface") |1 => WriteLine($"One bottle of $bev on the$surface, one bottle of $bev"); WriteLine($"Take it down, pass it around, no more bottles of $bev on the$surface")
|_ => WriteLine($"$x bottles of $bev on the$surface, $x bottles of$bev");
WriteLine($"Take one down and pass it around,$(x-1) bottles of $bev on the$surface")
}
}

Main() : void
{
foreach (i in [99, 98 .. 0])
Sing(i)
}
}


## NetRexx

beer = "bottles of beer on the wall"
removeOne = "Take one down, pass it arround,"
say 99 beer","
say 99 beer.subword(1,3)","
loop i = 98 to 2 by -1
say removeOne
say i beer"."
say
say i beer","
say i beer.subword(1,3)","
end
lastCall = "bottle" beer.delword(1,1)
say removeOne
say i lastCall"."
say
say i lastCall","
say i lastCall.subword(1,3)","
say removeOne
say "No more" beer


## Nial

line is fork [
0=, 'No more bottles of beer' first,
1=, 'One bottle of beer' first,
link [string,' bottles of beer' first]
]

line, ' on the wall, ' first,line,
'. Take it down and pass it around, ' first,
line (-1+),'on the wall. ' first
]

bottles is iterate (write verse) reverse count

## Night

null bottles(int x) {
if(x == 1) {
print("1 bottle of beer on the wall,\n");
print("1 bottle of beer,\n");
print("Take it down, pass it around,\n");
print("No more bottles of beer.\n");
}
else {
print(x);
print(" bottles of beer on the wall,\n");
print(x);
print(" bottles of beer,\n");
print("Take one down, pass it around,\n");
print(x - 1);
print(" bottles of beer on the wall,");
bottles(x-1);
}
}
bottles(1);

This code should work according to the docs, but due to a few bugs in the current implementation it doesn't.

## Nim

proc getBottleNumber(n: int): string =
case n
of 0:
result = "No more bottles"
of 1:
result = "1 bottle"
else:
result = $n & " bottles" result &= " of beer" for bn in countdown(99, 1): let cur = getBottleNumber(bn) echo(cur, " on the wall, ", cur, ".") echo("Take one down and pass it around, ", getBottleNumber(bn-1), " on the wall.\n") echo "No more bottles of beer on the wall, no more bottles of beer." echo "Go to the store and buy some more, 99 bottles of beer on the wall."  other: from strutils import format for i in countdown(99, 1): case i of 3..99: echo format("""$1 bottles of beer on the wall
$1 bottles of beer Take one down, pass it around$2 bottles of beer on the wall""", i, i-1)
of 2:
echo format("""$1 bottles of beer on the wall$1 bottles of beer
Take one down, pass it around
$2 bottle of beer on the wall""", i, i-1) of 1: echo format("""$1 bottle of beer on the wall
$1 bottle of beer Take one down, pass it around No more bottles of beer on the wall""", i) else: discard  compact: from strutils import format proc pluralize(a: int): string = if a > 1 or a == 0: "s" else: "" for i in countdown(99, 1): echo format("""$1 bottle$3 of beer on the wall$1 bottle$3 of beer Take one down, pass it around$2 bottle$4 of beer on the wall""", i, i-1, pluralize(i), pluralize(i-1))  organized: from strutils import format var verse = """$1 bottle$3 of beer on the wall$1 bottle$3 of beer Take one down, pass it around$2 bottle$4 of beer on the wall""" proc pluralize(a: int): string = if a > 1 or a == 0: "s" else: "" for i in countdown(99, 1): echo format(verse, i, i-1, pluralize(i), pluralize(i-1))  ## Nix with builtins; let bottle = x: "${toString x} bottle${if (x == 1) then "" else "s"} of beer"; beer = { x ? 99 }: if (x == 0) then "" else ''${bottle x} on the wall
${bottle x} Take one down, pass it around${bottle (x - 1)} on the wall

${beer { x = x - 1; }}''; in beer { }  ## NS-HUBASIC With grammatical support for "1 bottle of beer" 10 WALL$=" ON THE WALL"
20 FOR BOTTLES=99 TO 1 STEP -1
30 BOTTLES$=" BOTTLES OF BEER" 40 IF BOTTLES=1 THEN BOTTLE$=" BOTTLE OF BEER"
50 PRINT BOTTLES BOTTLES$WALL$
60 PRINT BOTTLES BOTTLES$70 PRINT "TAKE ONE DOWN, PASS IT AROUND" 80 IF BOTTLES-1=1 THEN BOTTLE$=" BOTTLE OF BEER"
90 IF BOTTLES-1=0 THEN BOTTLE$=" BOTTLES OF BEER" 100 PRINT BOTTLES-1 BOTTLES$ WALL$110 NEXT Without grammatical support for "1 bottle of beer" 10 BOTTLES$=" BOTTLES OF BEER"
20 WALL$=" ON THE WALL" 30 FOR BOTTLES=99 TO 1 STEP -1 40 PRINT BOTTLES BOTTLES$ WALL$50 PRINT BOTTLES BOTTLES$
60 PRINT "TAKE ONE DOWN, PASS IT AROUND"
70 PRINT BOTTLES-1 BOTTLES$WALL$
80 NEXT

## OASYS

class player {}

int count

property int dummy

method quit verbs {{quit}} {
quit
}

method beer verbs {{beer}} {
count = 99
while count {
print count
print " bottles of beer on the wall.\n"
print count
print " bottles of beer.\nTake one down and pass it around,\n"
count = count - 1
if count {
print count
print " bottles of beer on the wall.\n\n"
}
}
print "No more bottles of beer on the wall.\n"
}

method init {
player = create player
print "Type 'beer' for beer.\nType 'quit' to quit.\n"
}

## Oberon-2

MODULE b99;

IMPORT  Out;

VAR     nr      : INTEGER;

BEGIN
nr := 99;
REPEAT
Out.Int (nr, 4);
Out.String (" bottles of beer on the wall");
Out.Ln;
Out.Int (nr, 4);
Out.String (" bottles of beer");
Out.Ln;
Out.String ("Take one down, pass it around");
Out.Ln;
DEC (nr);
Out.Int (nr, 4);
Out.String (" bottles of beer on the wall");
Out.Ln;
Out.Ln
UNTIL nr = 0
END b99.


## Objeck

class Bottles {
function : Main(args : String[]) ~ Nil {
bottles := 99;
do {
"{$bottles} bottles of beer on the wall"->PrintLine(); "{$bottles} bottles of beer"->PrintLine();
"Take one down, pass it around"->PrintLine();
bottles--;
"{$bottles} bottles of beer on the wall"->PrintLine(); } while(bottles > 0); } } ## Objective-C #import <Foundation/Foundation.h> int main() { @autoreleasepool { int bottles = 99; do { NSLog(@"%i bottles of beer on the wall\n", bottles); NSLog(@"%i bottles of beer\n", bottles); NSLog(@"Take one down, pass it around\n"); NSLog(@"%i bottles of beer on the wall\n\n", --bottles); } while (bottles > 0); } return 0; }  ## OCaml ### For-loop for n = 99 downto 1 do Printf.printf "%d bottles of beer on the wall\n" n; Printf.printf "%d bottles of beer\n" n; Printf.printf "Take one down, pass it around\n"; Printf.printf "%d bottles of beer on the wall\n\n" (pred n); done  ### Recursive Recursive version that handles plurals. let verse n = let line2 = function | 0 -> "No more bottles of beer" | 1 -> "1 bottle of beer" | n -> string_of_int n ^ " bottles of beer" in let line1or4 y = line2 y ^ " on the wall" in let line3 = function | 1 -> "Take it down, pass it around" | _ -> "Take one down, pass it around" in line1or4 n ^ "\n" ^ line2 n ^ "\n" ^ line3 n ^ "\n" ^ line1or4 (n-1) ^ "\n";; let rec beer n = print_endline (verse n); if n > 1 then beer (n-1);; beer 99;;  ### Monadic Monadic version, expressing actions which evolve the program state and log output. Special cases and grammar rules are handled. (* A basic "Writer" monoid with emit *) module Writer = struct type 'a t = 'a * string let ( >>= ) (x,s) f = let (y,s') = f x in (y, s ^ s') let return x = (x,"") let emit (x,s) = print_string s; x end (* Utility functions for handling strings and grammar *) let line s = (String.capitalize s) ^ ".\n" let count = function 0 -> "no more" | n -> string_of_int n let plural = function 1 -> "" | _ -> "s" let specify = function 1 -> "it" | _ -> "one" let bottles n = count n ^ " bottle" ^ plural n ^ " of beer" (* Actions, expressed as an int * string, for Writer *) let report n = (n, line (bottles n ^ " on the wall, " ^ bottles n)) let take n = (n-1, "Take " ^ specify n ^ " down and pass it around") let summary n = (n, ", " ^ bottles n ^ " on the wall.\n\n") let shop = (99, "Go to the store and buy some more") let rec verse state = Writer.(state >>= report >>= function 0 -> shop >>= summary (* ends here *) | n -> take n >>= summary |> verse) let sing start = Writer.(emit (verse (return start)))  Output for initial beer-count of two: # sing 2;; 2 bottles of beer on the wall, 2 bottles of beer. Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take it down and pass it around, no more bottles of beer on the wall. No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall. - : int = 99  Note the output value is 99... reflecting the state at termination. ## Octave function bottles(n) bottle = "bottle"; ofbeer = "of beer"; wall = "on the wall"; for i = n:-1:0 if ( i == 1 ) s = ""; else s = "s"; endif for j = 0:1 w = wall; if ( j == 1 ) w = ""; endif printf("%d %s%s %s %s\n",\ i, bottle, s, ofbeer, w); endfor printf("Take one down, pass it around\n"); endfor endfunction bottles(99);  ## Odin package main import "core:fmt" printf :: fmt.printf //Give fn on right an arbitrary name, or 9x fmt.printf("...") bob :: proc( n: int , x: int){ for i := x; i > 0 ; i -=1 { if n >= 2 do printf("%d bottles of beer",n) else if n == 1 do printf("1 bottle of beer") else if n == 0 do printf("No more bottles of beer") if i == 1 do printf(".\n") if i > 1 do printf(" on the wall.\n") if i > 2 do printf("\n") } } main :: proc(){ n := 99 bob(n, 2) for i := n - 1 ; i >= 0 ; i -= 1 { printf("Take one down; pass it around.\n") bob(i, 3) } printf ("Go to the store and buy some more.\n") printf ("%i bottles of beer on the wall.\n",n) }  ## Oforth "bottles of beer on the wall\n" const: B "bottles of beer\nTake one down, pass it around\n" const: T #[ 100 swap - dup . B print dup . T print 1- . B .cr ] 99 each ## Ol ## Onyx $Bottles {
dup cvs  bottle' cat exch 1 ne {s' cat} if
 of beer' cat
} def

$GetPronoun { 1 eq {it'}{one'} ifelse cat } def$WriteStanza {
dup dup Bottles  on the wall. ' cat exch Bottles .\n' cat cat
exch Take ' 1 idup GetPronoun  down. Pass it around.\n' cat
exch dec Bottles  on the wall.\n\n' 3 {cat} repeat print flush
} def

99 -1 1 {WriteStanza} for

Output:

99 bottles of beer on the wall. 99 bottles of beer.
Take one down. Pass it around.
98 bottles of beer on the wall.
. . .
2 bottles of beer on the wall. 2 bottles of beer.
Take one down. Pass it around.
1 bottle of beer on the wall.

1 bottle of beer on the wall. 1 bottle of beer.
Take it down. Pass it around.
0 bottles of beer on the wall.


## OOC

sing_line: func (b: Int, suffix: Bool) {
"#{b > 0 ? "#{b}" : "No more"} bottle#{b == 1 ? "" : "s"}" print()
" of beer#{suffix ? " on the wall" : ""}" println()
}

sing_verse: func (b: Int) {
println()
sing_line(b, true)
sing_line(b, false)
if (b > 0) {
"Take one down, pass it around" println()
} else {
"Go to the store and buy some more" println()
b += 100
}
sing_line(b-1, true)
}

main: func {
b := 100
while (b > 0) {
sing_verse(--b)
}
}


## ooRexx

The rexx example below runs unchanged on ooRexx

## OpenEdge/Progress

DEFINE VARIABLE amountofbottles AS INTEGER NO-UNDO INITIAL 99.
&GLOBAL-DEFINE bbm bottles of beer
&GLOBAL-DEFINE bbs bottle of beer
&GLOBAL-DEFINE otw on the wall
&GLOBAL-DEFINE tow Take one down and pass it around,
&GLOBAL-DEFINE gts Go to the store and buy some more,
FUNCTION drinkBottle RETURNS INTEGER PRIVATE (INPUT bc AS INTEGER) FORWARD.

OUTPUT TO OUTPUT.txt.
drinkBottle(amountofbottles).
OUTPUT CLOSE.

FUNCTION drinkBottle RETURNS INTEGER.
IF bc >= 0 THEN DO:
CASE bc:
WHEN 2 THEN
PUT UNFORMATTED bc " {&bbm} {&otw}, " bc " {&bbm}" SKIP
"{&tow} " bc - 1 " {&bbs} {&otw}" SKIP.
WHEN 1 THEN
PUT UNFORMATTED bc " {&bbs} {&otw}, " bc " {&bbs}" SKIP
"{&tow} no more {&bbm} {&otw}" SKIP.
WHEN 0 THEN
PUT UNFORMATTED "no more" " {&bbm} {&otw}, no more {&bbm}" SKIP
"{&gts} " amountofbottles " {&bbm} {&otw}" SKIP.
OTHERWISE
PUT UNFORMATTED bc " {&bbm} {&otw}, " bc " {&bbm}" SKIP
"{&tow} " bc - 1 " {&bbm} {&otw}" SKIP.
END CASE.
drinkBottle(bc - 1).
RETURN bc.
END.
RETURN 0.
END FUNCTION.

El código es de Marc Vanlindt (marc@vanlindt.be)

num_bottles = 99;
s1 = " of beer";
s2 = " on the wall";
s3 = "Take one down and pass it around, ";
s4 = "No more";
s5 = "no more";
s6 = "Go to the store and buy some more, ";
b1 = " bottle";
b2 = " bottles";
beer(n = num_bottles);
module beer(n, biere) {
biere1 = str(n >= 1 ? n  : s4,n == 1 ? b1 :b2,s1, s2,", ",n >= 1 ? n : s5,n == 1 ? b1 :b2,s1,".");
biere2 = str(n == 0 ? s6 : s3,n == 0 ? num_bottles : n == 1 ? s5 : n-1,n == 0 ? b2 : n-1 == 1 ? b1 : b2,s1,s2,".");
biere3 = str(biere1," ",biere2);
echo(biere3);
if(n > 0) {
beer(n = n-1);
}
}

## Order

These examples are taken directly from a much longer tutorial in the Order documentation, which explains the construction of the solution to this problem in great detail.

### "Pure" Order

This solution uses only Order language constructs to generate and manipulate tokens:

#include "order/interpreter.h"

ORDER_PP
(8let((8B, 8fn(8N,
8cond((8greater(8N, 1),
8separate(8N, 8quote(bottles)))
(8equal(8N, 1),
8quote(1 bottle))
(8else,
8quote(no more bottles))))),
8for_each_in_range
(8fn(8N,
8print(8ap(8B, 8N) (of beer on the wall,) 8space
8ap(8B, 8N) (of beer,) 8space
(take one down, pass it around,) 8space
8ap(8B, 8dec(8N)) (of beer on the wall.))),
100, 1)))


### C Preprocessor

...but since most of the logic is simple substitution, it makes more sense (and is significantly more efficient) to make the C Preprocessor do most of the work without the help of the Order interpreter. This version shows how to integrate normal C Preprocessor macros into an Order program:

#include "order/interpreter.h"

#define GEN_phrase(N_bottles, N_minus_1_bottles)    \
N_bottles of beer on the wall,                    \
N_bottles of beer, take one down, pass it around, \
N_minus_1_bottles of beer on the wall.

#define ORDER_PP_DEF_8bottles                          \
ORDER_PP_FN(8fn(8N,                                    \
8cond((8greater(8N, 1),                \
8separate(8N, 8quote(bottles))) \
(8equal(8N, 1),                  \
8quote(1 bottle))               \
(8else,                          \
8quote(no more bottles)))))

ORDER_PP(8for_each_in_range
(8fn(8N,
8emit(8quote(GEN_phrase),
8tuple(8bottles(8N),
8bottles(8dec(8N))))),
100, 1))

#undef GEN_phrase


Either example could obviously also form the core of a C solution (demonstrating the intended use of Order).

## Oxygene

namespace ConsoleApplication2;

interface

type
ConsoleApp = class
public
class method Main(args: array of String);
end;

implementation

method bottles(number: Integer): String;
begin
if (number = 1) then
Result := "bottle"
else
Result := "bottles";
end;

class method ConsoleApp.Main(args: array of String);
begin
for n: Integer := 99 downto 1 do
begin
Console.WriteLine("{0} {1} of beer on the wall,",n,bottles(n));
Console.WriteLine("{0} {1} of beer,",n,bottles(n));
Console.WriteLine("Take one down, and pass it around,");
Console.WriteLine("{0} {1} of beer on the wall.",n-1,bottles(n-1));
Console.WriteLine();
end;
end;

end.

## Oz

### Constraint Programming

Note: In real life, you would never solve a simple iterative task like this with constraint programming. This is just for fun.

declare
%% describe the possible solutions of the beer 'puzzle'
proc {BeerDescription Solution}
N = {FD.int 1#99} %% N is an integer in [1, 99]
in
%% distribute starting with highest value
{FD.distribute generic(value:max) [N]}

Solution =
{Bottles N}#" of beer on the wall\n"#
{Bottles N}#" bottles of beer\n"#
"Take one down, pass it around\n"#
{Bottles N-1}#" of beer on the wall\n"
end

%% pluralization
proc {Bottles N Txt}
cond N = 1 then Txt ="1 bottle"
else Txt = N#" bottles"
end
end
in
%% show all solutions to the 'puzzle'
{ForAll {SearchAll BeerDescription}
System.showInfo}

### Iterative

declare
fun {Bottles N}
if N == 1 then "1 bottle"
else N#" bottles"
end
end
in
for I in 99..1;~1 do
{System.showInfo
{Bottles I}#" of beer on the wall\n"#
{Bottles I}#" bottles of beer\n"#
"Take one down, pass it around\n"#
{Bottles I-1}#" of beer on the wall\n"}
end

## PARI/GP

forstep(n=99,3,-1,
print(n" bottles of beer on the wall");
print(n" bottles of beer");
print("Take one down, pass it around");
print(n-1," bottles of beer on the wall\n")
);
print("2 bottles of beer on the wall\n2 bottles of beer\nTake one down, pass it around\n1 bottle of beer on the wall\n");
print("1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around\nNo more bottles of beer on the wall")

## Perl

#!/usr/bin/perl -w

my $verse = <<"VERSE"; 100 bottles of beer on the wall, 100 bottles of beer! Take one down, pass it around! 99 bottles of beer on the wall! VERSE {$verse =~ s/(\d+)/$1-1/ge;$verse =~ s/\b1 bottles/1 bottle/g;
my $done =$verse =~ s/\b0 bottle/No bottles/g; # if we make this replacement, we're also done.

print $verse; redo unless$done;
}


Alternatively:

for $n (reverse(0..99)) {$bottles = sprintf("%s bottle%s of beer on the wall\n",(($n==0)?"No":$n), (($n==1)?"":"s")); print( (($n==99)?"":"$bottles\n") . (($n==0)?"":(substr(${bottles}x2,0,-12) . "\nTake one down, pass it around\n")) ); }  Correct grammar and nice spacing in modern perl: use 5.10.0;$num = 99;
while ($num > 0) { my$s = "s" unless ($num == 1); say "$num bottle$s of beer on the wall,$num bottle$s of beer";$num--;
my $s = "s" unless ($num == 1);
$num = "No more" if ($num == 0);
say "Take one down, pass it around, $num bottle$s of beer on the wall\n"
}

say "No more bottles of beer on the wall, no more bottles of beer.";
say "Go to the store and buy some more, 99 bottles of beer on the wall.";


Using perl5 as a DSL factory leveraging $_'s global nature: #!/usr/bin/env perl use strict; use warnings; sub bottles() { sprintf qq{%s bottle%s of beer} ,$_ || 'No'
, $_==1 ? '' : 's'; } sub store() {$_=99; qq{Go to the store, buy some more...\n}; }
sub wall() { qq{ on the wall\n} }
sub take() { $_-- ? qq{Take one down, pass it around\n} : store } do { print bottles, wall , bottles, qq{\n} , take , bottles, qq{\n\n} } for reverse 0..99;  ## Phix constant ninetynine = 99 -- (set to 9 for testing) function bottles(integer count) if count=0 then return "no more bottles " elsif count=1 then return "1 bottle " end if if count=-1 then count = ninetynine end if return sprintf("%d bottles ",count) end function function bob(integer count) return bottles(count)&"of beer" end function function up1(string bob) -- Capitalise sentence start (needed just the once, "no more"=>"No more") bob[1] = upper(bob[1]) return bob end function string many = bob(ninetynine) string down = "Take one down, pass it around,\n" for i=ninetynine to 0 by -1 do puts(1,up1(many)&" on the wall,\n") puts(1,many&".\n") if i=0 then down = "Go to the store, buy some more,\n" elsif i=1 then down[6..8] = "it" end if many = bob(i-1) puts(1,down&many&" on the wall.\n\n") end for {} = wait_key()  ## Phixmonti def bottles dup if dup 1 == if "1 bottle" print else dup print " bottles" print endif else "No more bottles" print endif enddef def verse bottles " of beer on the wall" print nl bottles " of beer" print nl "Take one down, pass it around" print nl 1 - bottles " of beer on the wall" print nl nl enddef 99 1 -1 3 tolist for verse . endfor With syntactic sugar include ..\Utilitys.pmt def bottles dup 0 == if "no more bottles of beer" else dup 1 == if "1 bottle of beer" else dup tostr " bottles of beer" chain endif endif enddef ( 99 1 -1 ) for bottles print " on the wall," ? bottles "," chain ? "take one down, pass it around," ? 1 - bottles print " on the wall." ? nl drop endfor ## PHL Translation of: C module bottles; extern printf; @Integer main [ @Integer bottles = 99; do { printf("%u bottles of beer on the wall\n", bottles); printf("%u bottles of beer\n", bottles); printf("Take one down, pass it around\n"); bottles = bottles::dec; printf("%u bottles of beer on the wall\n\n", bottles); } while(bottles > 0); return 0; ] ## PHP <?php$plural = 's';
foreach (range(99, 1) as $i) { echo "$i bottle$plural of beer on the wall,\n"; echo "$i bottle$plural of beer!\n"; echo "Take one down, pass it around!\n"; if ($i - 1 == 1)
$plural = ''; if ($i > 1)
echo ($i - 1) . " bottle$plural of beer on the wall!\n\n";
else
echo "No more bottles of beer on the wall!\n";
}
?>


### shorter way

<?php
foreach(range(99,1) as $i) {$p = ($i>1)?"s":""; echo <<< EOV$i bottle$p of beer on the wall$i bottle$p of beer Take one down, pass it around EOV; } echo "No more Bottles of beer on the wall"; ?>  ### Tag syntax <?php foreach(range(99,1) as$i):?>
<?=$i?> bottle<?=$i==1 ? '' : 's'?> of beer on the wall,
<?=$i?> bottle<?=$i==1 ? '' : 's'?> of beer!
Take one down, pass it around...
<?php if($i > 1):?> <?=$i-1?> bottle<?=$i==1 ? '' : 's'?> of beer on the wall! <?php else:?> No more bottles of beer on the wall! <?php endif?> <?php endforeach?>  ### modifing way <?php$verse = <<<VERSE
100 bottles of beer on the wall,
100 bottles of beer!
Take one down, pass it around!
99 bottles of beer on the wall!

VERSE;

foreach (range(1,99) as $i) { // loop 99 times$verse = preg_replace('/\d+/e', '$0 - 1',$verse);
$verse = preg_replace('/\b1 bottles/', '1 bottle',$verse);
$verse = preg_replace('/\b0 bottle/', 'No bottles',$verse);

echo $verse; } ?>  ### ultra compact alternative supports grammar and has no leading and trailing new lines or spaces. Also one does not have to close the <?php tag, it is even recommended not to close it, if closing it is not necessary <?php for($i=100;$i>0;$i--){
$p2=$i." bottle".(($i>1)?"s":"")." of beer";$p1=$p2." on the wall\n";$p3="Take one down, pass it around\n";
echo (($i<100)?$p1."\n":"").$p1.$p2."\n".$p3.(($i<2)?($i-1).substr($p1,1,28):"");
}


### gettext alternative

supports grammar and translations.

<?php

$bottles = 99; while ($bottles > 0) {
printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer on the wall\n",$bottles);		//X bottles of beer on the wall
printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer\n",$bottles);				//X bottles of beer
printf("Take one down, pass it around\n");										//Take one down, pass it around

$bottles--; if ($bottles > 0) {
printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer on the wall\n\n",$bottles);	//X bottles of beer on the wall
}
}
printf('No more bottles of beer on the wall');											//No more bottles of beer on the wall


### Using printf

Fun with HEREDOC and printf placeholders

<?php

$lyrics = <<<ENDVERSE %2\$d bottle%1\$s of beer on the wall %2\$d bottle%1\$s of beer Take one down, pass it around %4\$s bottle%3\$s of beer on the wall ENDVERSE;$x = 99;
while ( $x > 0 ) { printf($lyrics, $x != 1 ? 's' : '',$x--, $x != 1 ? 's' : '',$x > 0 ? \$x : 'No more' );
}

Output:
99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall

98 bottles of beer on the wall
98 bottles of beer
Take one down, pass it around
97 bottles of beer on the wall

97 bottles of beer on the wall
97 bottles of beer
Take one down, pass it around
96 bottles of beer on the wall

96 bottles of beer on the wall
96 bottles of beer
Take one down, pass it around
95 bottles of beer on the wall

95 bottles of beer on the wall
95 bottles of beer
Take one down, pass it around
94 bottles of beer on the wall

4 bottles of beer on the wall
4 bottles of beer
Take one down, pass it around
3 bottles of beer on the wall

3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall

2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall

1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No more bottles of beer on the wall


## Picat

beer1(N) =>
Beer = N,
while (Beer > 0)
printf("%d bottles of beer on the wall,\n", Beer),
printf("%d bottles of beer.\n", Beer),
printf("Take one down, pass it around.\n"),
printf("%d bottles of beer.\n", Beer-1),
Beer := Beer -1
end,
print("0 more bottles of beer on the wall.\n"),
nl.

% With plurals.
beer2(B) = S =>
BS = B.to_string(),
BB = " bottle",
BT = BB,
if B > 1 then BB := BB ++ "s" end,
OB = " of beer",
NL = "\n",
BW = OB ++ " on the wall." ++ NL,
T = "Take one down, pass it around." ++ NL,
S1 =  BS ++ BT ++ BW ++ BS ++ BT ++ OB ++ T ++
cond(B > 0, (B-1).to_string() ++ BT ++ BW ++ NL, ""),
S = S1.

## Pike

int main(){
for(int i = 99; i > 0; i--){
write(i + `