User:Coderjoe/Sandbox2: Difference between revisions
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=={{header| |
=={{header|Perl}}== |
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<lang perl>use Math::Complex ':trig'; |
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To be executed in the REPL. |
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sub compose { |
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<lang oz>declare |
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my ($f, $g) = @_; |
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sub { |
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$f -> ($g -> (@_)); |
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}; |
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my $cube = sub { $_[0] ** (3) }; |
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fun {Compose F G} |
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my $croot = sub { $_[0] ** (1/3) }; |
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{F {G X}} |
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end |
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my @flist1 = ( \&Math::Complex::sin, \&Math::Complex::cos, $cube ); |
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fun {Cube X} X*X*X end |
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my @flist2 = ( \&asin, \&acos, $croot ); |
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print join "\n", map { |
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fun {CubeRoot X} {Number.pow X 1.0/3.0} end |
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compose($flist1[$_], $flist2[$_]) -> (0.5) |
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in |
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<lang perl6>sub compose (&g, &f) { return { g f $^x } } |
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for |
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F in [Float.sin Float.cos Cube] |
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I in [Float.asin Float.acos CubeRoot] |
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{Show {{Compose I F} 0.5}} |
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end |
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</lang> |
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my $x = *.sin; |
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my $xi = *.asin; |
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my $y = *.cos; |
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<lang parigp>compose(f,g)={ |
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my $yi = *.acos; |
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x -> f(g(x)) |
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my $z = * ** 3; |
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my $zi = * ** (1/3); |
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fcf()={ |
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my @functions = $x, $y, $z; |
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my(A,B); |
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my @inverses = $xi, $yi, $zi; |
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A=[x->sin(x), x->cos(x), x->x^2]; |
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B=[x->asin(x), x->acos(x), x->sqrt(x)]; |
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for @functions Z @inverses { say compose($^g, $^f)(.5) }</lang> |
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for(i=1,#A, |
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Output: |
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print(compose(A[i],B[i])(.5)) |
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<pre>0.5 |
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) |
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0.5 |
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0.5</pre> |
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Usage note: In Pari/GP 2.4.3 the vectors can be written as |
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<lang parigp> A=[sin, cos, x->x^2]; |
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B=[asin, acos, x->sqrt(x)];</lang> |
Revision as of 20:37, 16 July 2011
Perl
<lang perl>use Math::Complex ':trig';
sub compose {
my ($f, $g) = @_; sub { $f -> ($g -> (@_)); };
}
my $cube = sub { $_[0] ** (3) }; my $croot = sub { $_[0] ** (1/3) };
my @flist1 = ( \&Math::Complex::sin, \&Math::Complex::cos, $cube ); my @flist2 = ( \&asin, \&acos, $croot );
print join "\n", map {
compose($flist1[$_], $flist2[$_]) -> (0.5)
} 0..2;</lang>
Perl 6
<lang perl6>sub compose (&g, &f) { return { g f $^x } }
my $x = *.sin; my $xi = *.asin; my $y = *.cos; my $yi = *.acos; my $z = * ** 3; my $zi = * ** (1/3);
my @functions = $x, $y, $z; my @inverses = $xi, $yi, $zi;
for @functions Z @inverses { say compose($^g, $^f)(.5) }</lang> Output:
0.5 0.5 0.5