Talk:Special pythagorean triplet: Difference between revisions
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(Some observation) |
(Some observations) |
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if i<sup>2</sup>-g<sup>2</sup> is greater than n<sup>2</sup> then there can be no solution for this n with a smaller g |
if i<sup>2</sup>-g<sup>2</sup> is greater than n<sup>2</sup> then there can be no solution for this n with a smaller g |
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--[[User:Nigel Galloway|Nigel Galloway]] ([[User talk:Nigel Galloway|talk]]) 14:11, 31 August 2021 (UTC) |
--[[User:Nigel Galloway|Nigel Galloway]] ([[User talk:Nigel Galloway|talk]]) 14:11, 31 August 2021 (UTC) |
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Isn't the task to print out abc? |
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Also, isn't using Euclid's formula (as in the XPL0 solution) going to be faster - less values to try ? --[[User:Tigerofdarkness|Tigerofdarkness]] ([[User talk:Tigerofdarkness|talk]]) 17:34, 31 August 2021 (UTC) |
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Revision as of 17:35, 31 August 2021
For those paying "attention to timings" and more importantly for those paying attention to other comments I have made on these Euler tasks about filling RC with solutions worse than I would expect from a schoolboy with a pencil, considering n2+g2=i2 and n+g+i=1000 n<g<i note the following:
the largest value n can take is 332 with g=333 and i=335 the smallest value of i2-g2 is when g=(999-n)/2 and i=1000-g if i2-g2 is greater than n2 then there can be no solution for this n with a smaller g
--Nigel Galloway (talk) 14:11, 31 August 2021 (UTC)
Isn't the task to print out abc? Also, isn't using Euclid's formula (as in the XPL0 solution) going to be faster - less values to try ? --Tigerofdarkness (talk) 17:34, 31 August 2021 (UTC)