Talk:Peaceful chess queen armies

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Revision as of 07:40, 19 January 2020 by rosettacode>Pers (→‎Error in solution?: new section)

Original Python exhaustive search

I was experimenting with various things when doing the Python. This is the original:

Exhaustive search. <lang python>from itertools import combinations, count from functools import lru_cache, reduce


  1. n-by-n board

n = 5

def _2d(n=n):

 for i in range(n):
     print('  '.join(f'{i},{j}' for j in range(n)))

def _1d(n=n):

 for i in range(0, n*n, n):
     print(',  '.join(f'{i+j:2}' for j in range(n)))

_bbullet, _wbullet = '\u2022\u25E6'

  1. _bqueen, _wqueen = 'BW'

_bqueen, _wqueen = '\u265B\u2655' _bqueenh, _wqueenh = '♛', '' _or = set.__or__


def place(m, n):

   "Place m black and white queens, peacefully, on an n-by-n board"
   
   # 2-D Board as 1-D array:  2D(x, y) == 1D(t%n, t//n)
   board = set(range(n*n))
   #placements = list(combinations(board, m))
   placements = {frozenset(c) for c in combinations(board, m)}
   for blacks in placements:
       black_attacks = reduce(_or, 
                              (queen_attacks_from(pos, n) for pos in blacks), 
                              set())
       #for whites in placements:
       for whites in {frozenset(c) for c in combinations(board - black_attacks, m)}:
           if not black_attacks & whites:
               return blacks, whites
   return set(), set()

@lru_cache(maxsize=None) def queen_attacks_from(pos, n=n):

   a = set([pos])    # Its position
   a.update(range(pos//n*n, pos//n*n+n))    # Its row
   a.update(range(pos%n, n*n, n))           # Its column
   # Diagonals
   x0, y0 = pos%n, pos//n
   for x1 in range(n):
       # l-to-r diag
       y1 = y0 -x0 +x1
       if 0 <= y1 < n: 
           a.add(x1 + y1 * n)
       # r-to-l diag
       y1 = y0 +x0 -x1
       if 0 <= y1 < n: 
           a.add(x1 + y1 * n)
   return a

def pboard(black_white=None, n=n):

   if black_white is None: 
       blk, wht = set(), set()
   else:
       blk, wht = black_white
   print(f"## {len(blk)} black and {len(wht)} white queens "
         f"on a {n}-by-{n} board:", end=)
   for xy in range(n*n):
       if xy %n == 0:
           print()
       ch = ('?' if xy in blk and xy in wht 
             else _bqueen if xy in blk
             else _wqueen if xy in wht
             else _bbullet if (xy%n + xy//n)%2 else _wbullet)
       print('%s' % ch, end=)
   print()

def hboard(black_white=None, n=n):

   if black_white is None: 
       blk, wht = set(), set()
   else:
       blk, wht = black_white
   out = (f"
## {len(blk)} black and {len(wht)} white queens " f"on a {n}-by-{n} board:
\n")

out += "

\n " tbl = for xy in range(n*n): if xy %n == 0: tbl += '\n \n' ch = ('?' if xy in blk and xy in wht else _bqueenh if xy in blk else _wqueenh if xy in wht else "") bg = "" if (xy%n + xy//n)%2 else ' bgcolor="silver"' tbl += f' \n'
   out += tbl[7:]
out += '\n
{ch}

\n
\n'

   return out

if __name__ == '__main__':

   n=2
   html = 
   for n in range(2, 7):
       print()
       queen_attacks_from.cache_clear()    # memoization cache
       #
       for m in count(1):
           ans = place(m, n)
           if ans[0]:
               pboard(ans, n)
               html += hboard(ans, n)
           else:
               comment = f"# Can't place {m}+ queens on a {n}-by-{n} board"
               print (comment)
               html += f"{comment}

\n\n" break print('\n') html += '
\n' # m, n = 5, 7 queen_attacks_from.cache_clear() ans = place(m, n) pboard(ans, n) html += hboard(ans, n) with open('peaceful_queen_armies.htm', 'w') as f: f.write(html)</lang>
Output:

The console output Unicode queen characters display wider than other characters in monospace font so the alternative HTML output is shown below.

# Can't place 1+ queens on a 2-by-2 board


## 1 black and 1 white queens on a 3-by-3 board:


# Can't place 2+ queens on a 3-by-3 board


## 1 black and 1 white queens on a 4-by-4 board:



## 2 black and 2 white queens on a 4-by-4 board:


# Can't place 3+ queens on a 4-by-4 board


## 1 black and 1 white queens on a 5-by-5 board:



## 2 black and 2 white queens on a 5-by-5 board:



## 3 black and 3 white queens on a 5-by-5 board:



## 4 black and 4 white queens on a 5-by-5 board:


# Can't place 5+ queens on a 5-by-5 board


## 1 black and 1 white queens on a 6-by-6 board:



## 2 black and 2 white queens on a 6-by-6 board:



## 3 black and 3 white queens on a 6-by-6 board:



## 4 black and 4 white queens on a 6-by-6 board:



## 5 black and 5 white queens on a 6-by-6 board:


# Can't place 6+ queens on a 6-by-6 board



## 5 black and 5 white queens on a 7-by-7 board:


--Paddy3118 (talk) 10:08, 27 March 2019 (UTC)

Error in solution?

No solutions for {8,9},{10,14} and some other boards. For {9, 12} correctly:

12 black and 12 white queens on a 9 x 9 board:
B * x * B * x * B
* x W x * x W x *
B * x * B * x * B
* x W x * x W x *
B * x * B * x * B
* x W x * x W x *
B * x * B * x * B
* x W x * x W x *
x W x W x W x W x

I checked C and C++ codes and compare results from https://oeis.org/A250000