Set consolidation: Difference between revisions

Add Refal
m (C# fixed tiny mistake)
(Add Refal)
Line 2,957:
set(H, I, K) set(A, B) set(C, D) set(D, B) set(F, G, H)
==> set(A, B, C, D) set(H, I, K, F, G)</pre>
 
=={{header|Refal}}==
<syntaxhighlight lang="refal">$ENTRY Go {
= <Test (A B) (C D)>
<Test (A B) (B D)>
<Test (A B) (C D) (D B)>
<Test (H I K) (A B) (C D) (D B) (F G H)>;
};
 
Test {
e.S = <Prout e.S ' -> ' <Consolidate e.S>>;
};
 
Consolidate {
e.SS, <Consolidate1 () e.SS>: {
e.SS = e.SS;
e.SS2 = <Consolidate e.SS2>;
};
};
 
Consolidate1 {
(e.CSS) = e.CSS;
(e.CSS) (e.S) e.SS,
<Consolidate2 (e.CSS) (e.S)>: e.CSS2 =
<Consolidate1 (e.CSS2) e.SS>;
};
 
Consolidate2 {
() (e.S) = (e.S);
((e.S1) e.SS) (e.S), <Overlap (e.S1) (e.S)>: {
True = (<Set e.S1 e.S>) e.SS;
False = (e.S1) <Consolidate2 (e.SS) (e.S)>;
};
};
 
Overlap {
(e.S1) () = False;
(e.S1) (s.I e.S2), e.S1: {
e.L s.I e.R = True;
e.S1 = <Overlap (e.S1) (e.S2)>;
};
};
 
Set {
= ;
s.I e.S, e.S: {
e.L s.I e.R = <Set e.S>;
e.S = s.I <Set e.S>;
};
};</syntaxhighlight>
{{out}}
<pre>(A B )(C D ) -> (A B )(C D )
(A B )(B D ) -> (A B D )
(A B )(C D )(D B ) -> (A B C D )
(H I K )(A B )(C D )(D B )(F G H ) -> (I K F G H )(A B C D )</pre>
 
=={{header|REXX}}==
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