Remove duplicate elements: Difference between revisions
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Given an Array, derive an Array containing only the unique elements; that is, derive an array in which all duplicate elements are removed. |
Given an Array, derive an Array containing only the unique elements; that is, derive an array in which all duplicate elements are removed. |
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==[[AppleScript]]== |
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[[Category:AppleScript]] |
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set array to {1, 2, 3, "a", "b", "c", 2, 3, 4, "b", "c", "d"} |
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set unique to {} |
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repeat with i in array |
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if (i is not in unique) then |
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set unique to unique & i |
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end if |
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end repeat |
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==[[C++]]== |
==[[C++]]== |
Revision as of 20:42, 24 January 2007
Remove duplicate elements
You are encouraged to solve this task according to the task description, using any language you may know.
You are encouraged to solve this task according to the task description, using any language you may know.
Given an Array, derive an Array containing only the unique elements; that is, derive an array in which all duplicate elements are removed.
AppleScript
set array to {1, 2, 3, "a", "b", "c", 2, 3, 4, "b", "c", "d"} set unique to {} repeat with i in array if (i is not in unique) then set unique to unique & i end if end repeat
C++
#include <set> #include <iostream> using namespace std; int main( int argc, char* argv[] ) { typedef set<int> TyHash; int data[] = {1, 2, 3, 2, 3, 4}; TyHash hash(data, data + 6); cout << "Set items:" << endl; for (TyHash::iterator iter = hash.begin(); iter != hash.end(); iter++) cout << *iter << " "; cout << endl; }
Java
//Using Java 1.5/5.0 Object[] data = new Object[] {1, 2, 3, "a", "b", "c", 2, 3, 4, "b", "c", "d"}; Set uniqueSet = new HashSet(Arrays.asList(data)); Object[] unique = uniqueSet.toArray();
Perl
Interpeter: Perl
my %hash; my @list = (1, 2, 3, 'a', 'b', 'c', 2, 3, 4, 'b', 'c', 'd'); @hash{@list} = 1; # the keys of %hash now contain the unique list my @unique_list = keys(%hash);
PHP
$list = array(1, 2, 3, 'a', 'b', 'c', 2, 3, 4, 'b', 'c', 'd'); $unique_list = array_unique($list);
Python
data = [1, 2, 3, 'a', 'b', 'c', 2, 3, 4, 'b', 'c', 'd']
Using sets
unique = list(set(data))
See also http://www.peterbe.com/plog/uniqifiers-benchmark and http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/52560
Ruby
ary = [1,1,2,1,'redundant',[1,2,3],[1,2,3],'redundant'] uniq_ary = ary.uniq # => [1, 2, "redundant", [1, 2, 3]]
D
void main() { int[] data = [1, 2, 3, 2, 3, 4]; int[int] hash; foreach(el; data) hash[el] = 0; }