Remove duplicate elements: Difference between revisions
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uniq_ary = ary.uniq |
uniq_ary = ary.uniq |
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# => [1, 2, "redundant", [1, 2, 3]] |
# => [1, 2, "redundant", [1, 2, 3]] |
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==[[Java]]== |
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//Using Java 1.5/5.0 |
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Object[] data = new Object[] {1, 2, 3, "a", "b", "c", 2, 3, 4, "b", "c", "d"}; |
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Set uniqueSet = new HashSet(Arrays.asList(data)); |
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Object[] unique = uniqueSet.toArray(); |
Revision as of 16:25, 23 January 2007
Remove duplicate elements
You are encouraged to solve this task according to the task description, using any language you may know.
You are encouraged to solve this task according to the task description, using any language you may know.
Given a Array, create a derived Array containing only the unique elements
Perl
Interpeter: Perl
my %hash; my @list = (1, 2, 3, 'a', 'b', 'c', 2, 3, 4, 'b', 'c', 'd'); @hash{@list} = 1; # the keys of %hash now contain the unique list
Python
data = [1, 2, 3, 'a', 'b', 'c', 2, 3, 4, 'b', 'c', 'd']
Using sets
unique = list(set(data))
See also http://www.peterbe.com/plog/uniqifiers-benchmark and http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/52560
Ruby
ary = [1,1,2,1,'redundant',[1,2,3],[1,2,3],'redundant'] uniq_ary = ary.uniq # => [1, 2, "redundant", [1, 2, 3]]
Java
//Using Java 1.5/5.0 Object[] data = new Object[] {1, 2, 3, "a", "b", "c", 2, 3, 4, "b", "c", "d"}; Set uniqueSet = new HashSet(Arrays.asList(data)); Object[] unique = uniqueSet.toArray();