Order two numerical lists: Difference between revisions

→‎{{header|Kotlin}}: More condensed version
(Added Kotlin)
(→‎{{header|Kotlin}}: More condensed version)
Line 822:
 
fun main(args: Array<String>) {
val list1lists = listOf(1, 2, 3, 4, 5)
val list2 = listOf(1, 2, 13, 54, 25), 2)
val list3 = listOf(1, 2, 1, 5, 2, 2),
val list4 = listOf(1, 2, 1, 5, 2),
val list5 = listOf(1, 2, 1, 35, 2),
val list6 = listOf(1, 2, 01, 43, 42), 0, 0, 0)
val list7 = listOf(1, 2, 0, 4, 4, 10, 0, 0),
listOf(1, 2, 0, 4, 4, 1, 0, 0)
println("list1 : $list1")
)
println("list2 : $list2")
for (i in 0 until lists.size) println("list3list${i + 1} : $list3{lists[i]}")
println("list4 : $list4")
println("list5 : $list5")
println("list6 : $list6")
println("list7 : $list7")
println()
for (i in 0 until lists.size - 1) println("list1list${i + 1} > list2list${i + 2} = ${list1lists[i] > list2lists[i + 1]}")
println("list2 > list3 = ${list2 > list3}")
println("list3 > list4 = ${list3 > list4}")
println("list4 > list5 = ${list4 > list5}")
println("list5 > list6 = ${list5 > list6}")
println("list6 > list7 = ${list6 > list7}")
}</lang>
 
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