Matrix transposition

Matrix transposition
You are encouraged to solve this task according to the task description, using any language you may know.

Transpose an arbitrarily sized rectangular Matrix.

ALGOL 68

main:(

  [,]REAL m=((1,  1,  1,   1),
             (2,  4,  8,  16),
             (3,  9, 27,  81),
             (4, 16, 64, 256),
             (5, 25,125, 625));

  OP ZIP = ([,]REAL in)[,]REAL:(
    [2 LWB in:2 UPB in,1 LWB in:1UPB in]REAL out;
    FOR i FROM LWB in TO UPB in DO
      out[,i]:=in[i,] 
    OD;
    out
  );

  PROC pprint = ([,]REAL m)VOID:(
    FORMAT real fmt = $g(-6,2)$; # width of 6, with no '+' sign, 2 decimals #
    FORMAT vec fmt = $"("n(2 UPB m-1)(f(real fmt)",")f(real fmt)")"$;
    FORMAT matrix fmt = $x"("n(UPB m-1)(f(vec fmt)","lxx)f(vec fmt)");"$;
    # finally print the result #
    printf((matrix fmt,m))
  );

  printf(($x"Transpose:"l$));
  pprint((ZIP m))
)

Output:

Transpose:
((  1.00,  2.00,  3.00,  4.00,  5.00),
 (  1.00,  4.00,  9.00, 16.00, 25.00),
 (  1.00,  8.00, 27.00, 64.00,125.00),
 (  1.00, 16.00, 81.00,256.00,625.00));

Java

import java.util.Arrays;
public class Transpose{
	public static void main(String[] args){
		double[][] m = {{1, 1, 1, 1},
				{2, 4, 8, 16},
				{3, 9, 27, 81},
				{4, 16, 64, 256},
				{5, 25, 125, 625}};
		double[][] ans = new double[m[0].length][m.length];
		for(int rows = 0; rows < m.length; rows++){
			for(int cols = 0; cols < m[0].length; cols++){
				ans[cols][rows] = m[rows][cols];
			}
		}
		for(double[] i:ans){//2D arrays are arrays of arrays
			System.out.println(Arrays.toString(i));
		}
	}
}

Python

#!/usr/bin/env python
from pprint import pprint
m=((1,  1,  1,   1),
   (2,  4,  8,  16),
   (3,  9, 27,  81),
   (4, 16, 64, 256),
   (5, 25,125, 625));
pprint(zip(*m))

Output:

[(1, 2, 3, 4, 5),
 (1, 4, 9, 16, 25),
 (1, 8, 27, 64, 125),
 (1, 16, 81, 256, 625)]