Literals/Integer: Difference between revisions
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Note: this should '''not''' involve the calling of any functions/methods but should be interpreted by the compiler or interpreter as an integer written to a given base. |
Note: this should '''not''' involve the calling of any functions/methods but should be interpreted by the compiler or interpreter as an integer written to a given base. |
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=={{header|AWK}}== |
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<lang>BEGIN { |
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if ( (0x2d7 == 727) && |
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(01327 == 727) ) { |
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print "true" |
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} |
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}</lang> |
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=={{header|C}}== |
=={{header|C}}== |
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standard) |
standard) |
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=={{header|Fortran}}== |
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<lang fortran>program IntegerLiteral |
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implicit none |
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integer, parameter :: dec = 727 |
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integer, parameter :: hex = Z'2d7' |
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integer, parameter :: oct = O'1327' |
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integer, parameter :: bin = B'1011010111' |
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print *, dec, hex, oct, bin |
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end program IntegerLiteral</lang> |
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Outputs: |
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<pre> |
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727 727 727 727 |
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</pre> |
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=={{header|Perl}}== |
=={{header|Perl}}== |
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Revision as of 23:52, 1 February 2009
You are encouraged to solve this task according to the task description, using any language you may know.
Some programming languages have ways of expressing integer literals in bases other than the normal base ten.
Show how integer literals can be expressed in as many bases as your language allows.
Note: this should not involve the calling of any functions/methods but should be interpreted by the compiler or interpreter as an integer written to a given base.
AWK
<lang>BEGIN {
if ( (0x2d7 == 727) &&
(01327 == 727) ) {
print "true"
}
}</lang>
C
Leading 0 means octal, 0x or 0X means hexadecimal. Otherwise, it is just decimal.
<lang c>#include <stdio.h>
int main() {
printf("%s\n",
( (727 == 0x2d7) && (727 == 01327) ) ? "true" : "false"); }</lang>
C has no way of specifying integers in binary (if there's something like 0b..., it is not standard)
Fortran
<lang fortran>program IntegerLiteral
implicit none integer, parameter :: dec = 727 integer, parameter :: hex = Z'2d7' integer, parameter :: oct = O'1327' integer, parameter :: bin = B'1011010111'
print *, dec, hex, oct, bin
end program IntegerLiteral</lang>
Outputs:
727 727 727 727
Perl
<lang perl> print "true\n" if ( (727 == 0x2d7) && (727 == 01327) && (727 == 0b1011010111) ); </lang>
Python
<lang python>>>> # Oct(leading 0), Dec, Hex(leading 0x or 0X), in order: >>> 01327 == 727 == 0x2d7 True >>> </lang>
<lang python>>>> # Bin(leading 0b or 0B), Oct(leading 0o or 0O), Dec, Hex(leading 0x or 0X), in order: >>> 0b1011010111 == 0o1327 == 727 == 0x2d7 True >>> </lang>
Ruby
(This is an interactive ruby session)
irb(main):001:0> 727 == 0b1011010111 => true irb(main):002:0> 727 == 0x2d7 => true irb(main):003:0> 727 == 01327 => true