Last Friday of each month: Difference between revisions
New post using C++20 syntax and without using external libraries, in addition to an existing post.
George2000 (talk | contribs) No edit summary |
(New post using C++20 syntax and without using external libraries, in addition to an existing post.) |
||
Line 999:
2012-Nov-30
2012-Dec-28
</pre>
===Using C++20===
Using C++20 this task can be completed without external libraries.
<syntaxhighlight lang="c++">
#include <chrono>
#include <iostream>
int main() {
std::cout << "The dates of the last Friday in each month of 2023:" << std::endl;
for ( unsigned int m = 1; m <= 12; ++m ) {
std::chrono::days days_in_month = std::chrono::sys_days{std::chrono::year{2023}/m/std::chrono::last}
- std::chrono::sys_days{std::chrono::year{2023}/m/1} + std::chrono::days{1};
const unsigned int last_day = days_in_month / std::chrono::days{1};
std::chrono::year_month_day ymd{std::chrono::year{2023}, std::chrono::month{m}, std::chrono::day{last_day}};
while ( std::chrono::weekday{ymd} != std::chrono::Friday ) {
ymd = std::chrono::sys_days{ymd} - std::chrono::days{1};
}
std::cout << ymd << std::endl;
}
}
</syntaxhighlight>
{{ out }}
<pre>
2023-01-27
2023-02-24
2023-03-31
2023-04-28
2023-05-26
2023-06-30
2023-07-28
2023-08-25
2023-09-29
2023-10-27
2023-11-24
2023-12-29
</pre>
| |||