Floyd's triangle: Difference between revisions

Line 263:
}</lang>
Output identical to D's.
 
===Simpler version by flarn2006===
<lang c>#include <stdio.h>
 
int main(int argc, char *argv[])
{
int value = 1;
int row;
 
for (row=1; row<=5; row++) {
int i; for (i=0; i<row; i++) {
printf("%-2d ", value++);
}
putchar('\n');
}
return 0;
}</lang>
 
=={{header|C++}}==
Anonymous user