Fast Fourier transform: Difference between revisions
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=={{header|SequenceL}}== |
=={{header|SequenceL}}== |
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{{trans|Python}} |
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<lang sequencel>import <Utilities/Complex.sl>; |
<lang sequencel>import <Utilities/Complex.sl>; |
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import <Utilities/Math.sl>; |
import <Utilities/Math.sl>; |
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Revision as of 16:53, 20 September 2016
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Calculate the FFT (Fast Fourier Transform) of an input sequence.
The most general case allows for complex numbers at the input and results in a sequence of equal length, again of complex numbers. If you need to restrict yourself to real numbers, the output should be the magnitude (i.e. sqrt(re²+im²)) of the complex result.
The classic version is the recursive Cooley–Tukey FFT. Wikipedia has pseudo-code for that.
Further optimizations are possible but not required.
Ada
The FFT function is defined as a generic function, instantiated upon a user instance of Ada.Numerics.Generic_Complex_Arrays.
<lang Ada> with Ada.Numerics.Generic_Complex_Arrays;
generic
with package Complex_Arrays is
new Ada.Numerics.Generic_Complex_Arrays (<>);
use Complex_Arrays;
function Generic_FFT (X : Complex_Vector) return Complex_Vector;
</lang>
<lang Ada> with Ada.Numerics; with Ada.Numerics.Generic_Complex_Elementary_Functions;
function Generic_FFT (X : Complex_Vector) return Complex_Vector is
package Complex_Elementary_Functions is
new Ada.Numerics.Generic_Complex_Elementary_Functions
(Complex_Arrays.Complex_Types);
use Ada.Numerics;
use Complex_Elementary_Functions;
use Complex_Arrays.Complex_Types;
function FFT (X : Complex_Vector; N, S : Positive)
return Complex_Vector is
begin
if N = 1 then
return (1..1 => X (X'First));
else
declare
F : constant Complex := exp (Pi * j / Real_Arrays.Real (N/2));
Even : Complex_Vector := FFT (X, N/2, 2*S);
Odd : Complex_Vector := FFT (X (X'First + S..X'Last), N/2, 2*S);
begin
for K in 0..N/2 - 1 loop
declare
T : constant Complex := Odd (Odd'First + K) / F ** K;
begin
Odd (Odd'First + K) := Even (Even'First + K) - T;
Even (Even'First + K) := Even (Even'First + K) + T;
end;
end loop;
return Even & Odd;
end;
end if;
end FFT;
begin
return FFT (X, X'Length, 1);
end Generic_FFT; </lang>
Example:
<lang Ada> with Ada.Numerics.Complex_Arrays; use Ada.Numerics.Complex_Arrays; with Ada.Complex_Text_IO; use Ada.Complex_Text_IO; with Ada.Text_IO; use Ada.Text_IO;
with Ada.Numerics.Complex_Elementary_Functions; with Generic_FFT;
procedure Example is
function FFT is new Generic_FFT (Ada.Numerics.Complex_Arrays); X : Complex_Vector := (1..4 => (1.0, 0.0), 5..8 => (0.0, 0.0)); Y : Complex_Vector := FFT (X);
begin
Put_Line (" X FFT X ");
for I in Y'Range loop
Put (X (I - Y'First + X'First), Aft => 3, Exp => 0);
Put (" ");
Put (Y (I), Aft => 3, Exp => 0);
New_Line;
end loop;
end; </lang>
- Output:
X FFT X ( 1.000, 0.000) ( 4.000, 0.000) ( 1.000, 0.000) ( 1.000,-2.414) ( 1.000, 0.000) ( 0.000, 0.000) ( 1.000, 0.000) ( 1.000,-0.414) ( 0.000, 0.000) ( 0.000, 0.000) ( 0.000, 0.000) ( 1.000, 0.414) ( 0.000, 0.000) ( 0.000, 0.000) ( 0.000, 0.000) ( 1.000, 2.414)
ALGOL 68
Note: This specimen retains the original Python coding style.
File: Template.Fast_Fourier_transform.a68<lang algol68>PRIO DICE = 9; # ideally = 11 #
OP DICE = ([]SCALAR in, INT step)[]SCALAR: (
### Dice the array, extract array values a "step" apart ###
IF step = 1 THEN
in
ELSE
INT upb out := 0;
[(UPB in-LWB in)%step+1]SCALAR out;
FOR index FROM LWB in BY step TO UPB in DO
out[upb out+:=1] := in[index] OD;
out[@LWB in]
FI
);
PROC fft = ([]SCALAR in t)[]SCALAR: (
### The Cooley-Tukey FFT algorithm ###
IF LWB in t >= UPB in t THEN
in t[@0]
ELSE
[]SCALAR t = in t[@0];
INT n = UPB t + 1, half n = n % 2;
[LWB t:UPB t]SCALAR coef;
[]SCALAR even = fft(t DICE 2),
odd = fft(t[1:]DICE 2);
COMPL i = 0 I 1;
REAL w = 2*pi / n;
FOR k FROM LWB t TO half n-1 DO
COMPL cis t = scalar exp(0 I (-w * k))*odd[k];
coef[k] := even[k] + cis t;
coef[k + half n] := even[k] - cis t
OD;
coef
FI
);</lang>File: test.Fast_Fourier_transform.a68<lang algol68>#!/usr/local/bin/a68g --script #
- -*- coding: utf-8 -*- #
MODE SCALAR = COMPL; PROC (COMPL)COMPL scalar exp = complex exp; PR READ "Template.Fast_Fourier_transform.a68" PR
FORMAT real fmt := $g(0,3)$; FORMAT real array fmt := $f(real fmt)", "$; FORMAT compl fmt := $f(real fmt)"⊥"f(real fmt)$; FORMAT compl array fmt := $f(compl fmt)", "$;
test:(
[]COMPL
tooth wave ft = fft((1, 1, 1, 1, 0, 0, 0, 0)),
one and a quarter wave ft = fft((0, 0.924, 0.707,-0.383,-1,-0.383, 0.707, 0.924,
0,-0.924,-0.707, 0.383, 1, 0.383,-0.707,-0.924));
printf((
$"Tooth wave: "$,compl array fmt, tooth wave ft, $l$,
$"1¼ cycle wave: "$, compl array fmt, one and a quarter wave ft, $l$
))
)</lang>
- Output:
Tooth wave: 4.000⊥.000, 1.000⊥-2.414, .000⊥.000, 1.000⊥-.414, .000⊥.000, 1.000⊥.414, .000⊥.000, 1.000⊥2.414, 1¼ cycle wave: .000⊥.000, .000⊥.001, .000⊥.000, .000⊥-8.001, .000⊥.000, -.000⊥-.001, .000⊥.000, .000⊥.001, .000⊥.000, .000⊥-.001, .000⊥.000, -.000⊥.001, .000⊥.000, -.000⊥8.001, .000⊥.000, -.000⊥-.001,
BBC BASIC
<lang bbcbasic> @% = &60A
DIM Complex{r#, i#}
DIM in{(7)} = Complex{}, out{(7)} = Complex{}
DATA 1, 1, 1, 1, 0, 0, 0, 0
PRINT "Input (real, imag):"
FOR I% = 0 TO 7
READ in{(I%)}.r#
PRINT in{(I%)}.r# "," in{(I%)}.i#
NEXT
PROCfft(out{()}, in{()}, 0, 1, DIM(in{()},1)+1)
PRINT "Output (real, imag):"
FOR I% = 0 TO 7
PRINT out{(I%)}.r# "," out{(I%)}.i#
NEXT
END
DEF PROCfft(b{()}, o{()}, B%, S%, N%)
LOCAL I%, t{} : DIM t{} = Complex{}
IF S% < N% THEN
PROCfft(o{()}, b{()}, B%, S%*2, N%)
PROCfft(o{()}, b{()}, B%+S%, S%*2, N%)
FOR I% = 0 TO N%-1 STEP 2*S%
t.r# = COS(-PI*I%/N%)
t.i# = SIN(-PI*I%/N%)
PROCcmul(t{}, o{(B%+I%+S%)})
b{(B%+I% DIV 2)}.r# = o{(B%+I%)}.r# + t.r#
b{(B%+I% DIV 2)}.i# = o{(B%+I%)}.i# + t.i#
b{(B%+(I%+N%) DIV 2)}.r# = o{(B%+I%)}.r# - t.r#
b{(B%+(I%+N%) DIV 2)}.i# = o{(B%+I%)}.i# - t.i#
NEXT
ENDIF
ENDPROC
DEF PROCcmul(c{},d{})
LOCAL r#, i#
r# = c.r#*d.r# - c.i#*d.i#
i# = c.r#*d.i# + c.i#*d.r#
c.r# = r#
c.i# = i#
ENDPROC
</lang>
- Output:
Input (real, imag):
1, 0
1, 0
1, 0
1, 0
0, 0
0, 0
0, 0
0, 0
Output (real, imag):
4, 0
1, -2.41421
0, 0
1, -0.414214
0, 0
1, 0.414214
0, 0
1, 2.41421
C
Inplace FFT with O(n) memory usage.
Note: array size is assumed to be power of 2 and not checked by code;
you can just pad it with 0 otherwise.
Also, complex is C99 standard.<lang C>
- include <stdio.h>
- include <math.h>
- include <complex.h>
double PI; typedef double complex cplx;
void _fft(cplx buf[], cplx out[], int n, int step) { if (step < n) { _fft(out, buf, n, step * 2); _fft(out + step, buf + step, n, step * 2);
for (int i = 0; i < n; i += 2 * step) { cplx t = cexp(-I * PI * i / n) * out[i + step]; buf[i / 2] = out[i] + t; buf[(i + n)/2] = out[i] - t; } } }
void fft(cplx buf[], int n) { cplx out[n]; for (int i = 0; i < n; i++) out[i] = buf[i];
_fft(buf, out, n, 1); }
void show(const char * s, cplx buf[]) {
printf("%s", s);
for (int i = 0; i < 8; i++)
if (!cimag(buf[i]))
printf("%g ", creal(buf[i]));
else
printf("(%g, %g) ", creal(buf[i]), cimag(buf[i]));
}
int main() { PI = atan2(1, 1) * 4; cplx buf[] = {1, 1, 1, 1, 0, 0, 0, 0};
show("Data: ", buf); fft(buf, 8); show("\nFFT : ", buf);
return 0; }
</lang>
- Output:
Data: 1 1 1 1 0 0 0 0 FFT : 4 (1, -2.41421) 0 (1, -0.414214) 0 (1, 0.414214) 0 (1, 2.41421)
OS X / iOS
OS X 10.7+ / iOS 4+ <lang C>#include <stdio.h>
- include <Accelerate/Accelerate.h>
void fft(DSPComplex buf[], int n) {
float inputMemory[2*n];
float outputMemory[2*n];
// half for real and half for complex
DSPSplitComplex inputSplit = {inputMemory, inputMemory + n};
DSPSplitComplex outputSplit = {outputMemory, outputMemory + n};
vDSP_ctoz(buf, 2, &inputSplit, 1, n);
vDSP_DFT_Setup setup = vDSP_DFT_zop_CreateSetup(NULL, n, vDSP_DFT_FORWARD);
vDSP_DFT_Execute(setup,
inputSplit.realp, inputSplit.imagp,
outputSplit.realp, outputSplit.imagp);
vDSP_ztoc(&outputSplit, 1, buf, 2, n);
}
void show(const char *s, DSPComplex buf[], int n) {
printf("%s", s);
for (int i = 0; i < n; i++)
if (!buf[i].imag)
printf("%g ", buf[i].real);
else
printf("(%g, %g) ", buf[i].real, buf[i].imag);
printf("\n");
}
int main() {
DSPComplex buf[] = {{1,0}, {1,0}, {1,0}, {1,0}, {0,0}, {0,0}, {0,0}, {0,0}};
show("Data: ", buf, 8);
fft(buf, 8);
show("FFT : ", buf, 8);
return 0;
}</lang>
- Output:
Data: 1 1 1 1 0 0 0 0 FFT : 4 (1, -2.41421) 0 (1, -0.414214) 0 (1, 0.414214) 0 (1, 2.41421)
C++
<lang cpp>#include <complex>
- include <iostream>
- include <valarray>
const double PI = 3.141592653589793238460;
typedef std::complex<double> Complex; typedef std::valarray<Complex> CArray;
// Cooley–Tukey FFT (in-place, divide-and-conquer) // Higher memory requirements and redundancy although more intuitive void fft(CArray& x) {
const size_t N = x.size(); if (N <= 1) return;
// divide CArray even = x[std::slice(0, N/2, 2)]; CArray odd = x[std::slice(1, N/2, 2)];
// conquer fft(even); fft(odd);
// combine
for (size_t k = 0; k < N/2; ++k)
{
Complex t = std::polar(1.0, -2 * PI * k / N) * odd[k];
x[k ] = even[k] + t;
x[k+N/2] = even[k] - t;
}
}
// Cooley-Tukey FFT (in-place, breadth-first, decimation-in-frequency) // Better optimized but less intuitive void fft(CArray &x) { // DFT unsigned int N = x.size(), k = N, n; double thetaT = 3.14159265358979323846264338328L / N; Complex phiT = Complex(cos(thetaT), sin(thetaT)), T; while (k > 1) { n = k; k >>= 1; phiT = phiT * phiT; T = 1.0L; for (unsigned int l = 0; l < k; l++) { for (unsigned int a = l; a < N; a += n) { unsigned int b = a + k; Complex t = x[a] - x[b]; x[a] += x[b]; x[b] = t * T; } T *= phiT; } } // Decimate unsigned int m = (unsigned int)log2(N); for (unsigned int a = 0; a < N; a++) { unsigned int b = a; // Reverse bits b = (((b & 0xaaaaaaaa) >> 1) | ((b & 0x55555555) << 1)); b = (((b & 0xcccccccc) >> 2) | ((b & 0x33333333) << 2)); b = (((b & 0xf0f0f0f0) >> 4) | ((b & 0x0f0f0f0f) << 4)); b = (((b & 0xff00ff00) >> 8) | ((b & 0x00ff00ff) << 8)); b = ((b >> 16) | (b << 16)) >> (32 - m); if (b > a) { Complex t = x[a]; x[a] = x[b]; x[b] = t; } } //// Normalize (This section make it not working correctly) //Complex f = 1.0 / sqrt(N); //for (unsigned int i = 0; i < N; i++) // x[i] *= f; }
// inverse fft (in-place) void ifft(CArray& x) {
// conjugate the complex numbers x = x.apply(std::conj);
// forward fft fft( x );
// conjugate the complex numbers again x = x.apply(std::conj);
// scale the numbers x /= x.size();
}
int main() {
const Complex test[] = { 1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0 };
CArray data(test, 8);
// forward fft fft(data);
std::cout << "fft" << std::endl;
for (int i = 0; i < 8; ++i)
{
std::cout << data[i] << std::endl;
}
// inverse fft ifft(data);
std::cout << std::endl << "ifft" << std::endl;
for (int i = 0; i < 8; ++i)
{
std::cout << data[i] << std::endl;
}
return 0;
}</lang>
- Output:
fft (4,0) (1,-2.41421) (0,0) (1,-0.414214) (0,0) (1,0.414214) (0,0) (1,2.41421) ifft (1,-0) (1,-5.55112e-017) (1,2.4895e-017) (1,-5.55112e-017) (5.55112e-017,0) (5.55112e-017,5.55112e-017) (0,-2.4895e-017) (5.55112e-017,5.55112e-017)
C#
<lang c#>using System; using System.Numerics; using System.Linq; using System.Diagnostics;
// Fast Fourier Transform in C# public class Program {
/* Performs a Bit Reversal Algorithm on a postive integer
* for given number of bits
* e.g. 011 with 3 bits is reversed to 110 */
public static int BitReverse(int n, int bits) {
int reversedN = n;
int count = bits - 1;
n >>= 1;
while (n > 0) {
reversedN = (reversedN << 1) | (n & 1);
count--;
n >>= 1;
}
return ((reversedN << count) & ((1 << bits) - 1)); }
/* Uses Cooley-Tukey iterative in-place algorithm with radix-2 DIT case
* assumes no of points provided are a power of 2 */
public static void FFT(Complex[] buffer) {
int bits = (int)Math.Log(buffer.Length, 2);
for (int j = 1; j < buffer.Length / 2; j++) {
int swapPos = BitReverse(j, bits);
var temp = buffer[j];
buffer[j] = buffer[swapPos];
buffer[swapPos] = temp;
}
for (int N = 2; N <= buffer.Length; N <<= 1) {
for (int i = 0; i < buffer.Length; i += N) {
for (int k = 0; k < N / 2; k++) {
int evenIndex = i + k;
int oddIndex = i + k + (N / 2);
var even = buffer[evenIndex];
var odd = buffer[oddIndex];
double term = -2 * Math.PI * k / (double)N;
Complex exp = new Complex(Math.Cos(term), Math.Sin(term)) * odd;
buffer[evenIndex] = even + exp;
buffer[oddIndex] = even - exp;
}
}
}
}
public static void Main(string[] args) {
Complex[] input = {1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0};
FFT(input);
Console.WriteLine("Results:");
foreach (Complex c in input) {
Console.WriteLine(c);
}
}
}</lang>
- Output:
Results: (4, 0) (1, -2.41421356237309) (0, 0) (1, -0.414213562373095) (0, 0) (1, 0.414213562373095) (0, 0) (1, 2.41421356237309)
Common Lisp
<lang lisp> (defun fft (x)
(if (<= (length x) 1) x
(let*
(
(even (fft (loop for i from 0 below (length x) by 2 collect (nth i x))))
(odd (fft (loop for i from 1 below (length x) by 2 collect (nth i x))))
(aux (loop for k from 0 below (/ (length x) 2) collect (* (exp (/ (* (complex 0 -2) pi k ) (length x))) (nth k odd))))
)
(append (mapcar #'+ even aux) (mapcar #'- even aux))
)
)
)
(mapcar (lambda (x) (format t "~a~&" x)) (fft '(1 1 1 1 0 0 0 0)))
</lang>
- Output:
#C(4.0d0 0.0d0) #C(1.0d0 -2.414213562373095d0) #C(0.0d0 0.0d0) #C(1.0d0 -0.4142135623730949d0) #C(0.0d0 0.0d0) #C(0.9999999999999999d0 0.4142135623730949d0) #C(0.0d0 0.0d0) #C(0.9999999999999997d0 2.414213562373095d0)
Crystal
<lang ruby>def fft(x : Array(Float64)) : Array(Complex)
return [x[0].to_c] if x.size <= 1
even = fft(Array.new(x.size / 2) { |k| x[2 * k] })
odd = fft(Array.new(x.size / 2) { |k| x[2 * k + 1] })
c = Array.new(x.size / 2) { |k| Complex.new(0, -2 * Math::PI * k / x.size).exp }
codd = Array.new(x.size / 2) { |k| c[k] * odd[k] }
return Array.new(x.size / 2) { |k| even[k] + codd[k] } + Array.new(x.size / 2) { |k| even[k] - codd[k] }
end</lang>
D
Standard Version
<lang d>void main() {
import std.stdio, std.numeric;
[1.0, 1, 1, 1, 0, 0, 0, 0].fft.writeln;
}</lang>
- Output:
[4+0i, 1-2.41421i, 0-0i, 1-0.414214i, 0+0i, 1+0.414214i, 0+0i, 1+2.41421i]
creals Version
Built-in complex numbers will be deprecated. <lang d>import std.stdio, std.algorithm, std.range, std.math;
const(creal)[] fft(in creal[] x) pure /*nothrow*/ @safe {
immutable N = x.length; if (N <= 1) return x; const ev = x.stride(2).array.fft; const od = x[1 .. $].stride(2).array.fft; auto l = iota(N / 2).map!(k => ev[k] + expi(-2*PI * k/N) * od[k]); auto r = iota(N / 2).map!(k => ev[k] - expi(-2*PI * k/N) * od[k]); return l.chain(r).array;
}
void main() @safe {
[1.0L+0i, 1, 1, 1, 0, 0, 0, 0].fft.writeln;
}</lang>
- Output:
[4+0i, 1+-2.41421i, 0+0i, 1+-0.414214i, 0+0i, 1+0.414214i, 0+0i, 1+2.41421i]
Phobos Complex Version
<lang d>import std.stdio, std.algorithm, std.range, std.math, std.complex;
auto fft(T)(in T[] x) pure /*nothrow @safe*/ {
immutable N = x.length; if (N <= 1) return x; const ev = x.stride(2).array.fft; const od = x[1 .. $].stride(2).array.fft; alias E = std.complex.expi; auto l = iota(N / 2).map!(k => ev[k] + T(E(-2* PI * k/N)) * od[k]); auto r = iota(N / 2).map!(k => ev[k] - T(E(-2* PI * k/N)) * od[k]); return l.chain(r).array;
}
void main() {
[1.0, 1, 1, 1, 0, 0, 0, 0].map!complex.array.fft.writeln;
}</lang>
- Output:
[4+0i, 1-2.41421i, 0+0i, 1-0.414214i, 0+0i, 1+0.414214i, 0+0i, 1+2.41421i]
EchoLisp
<lang scheme> (define -∏*2 (complex 0 (* -2 PI)))
(define (fft xs N) (if (<= N 1) xs (let* [ (N/2 (/ N 2)) (even (fft (for/vector ([i (in-range 0 N 2)]) [xs i]) N/2)) (odd (fft (for/vector ([i (in-range 1 N 2)]) [xs i]) N/2)) ] (for ((k N/2)) (vector*= odd k (exp (/ (* -∏*2 k) N )))) (vector-append (vector-map + even odd) (vector-map - even odd)))))
(define data #( 1 1 1 1 0 0 0 0 ))
(fft data 8)
→ #( 4+0i 1-2.414213562373095i 0+0i 1-0.4142135623730949i
0+0i 1+0.4142135623730949i 0+0i 1+2.414213562373095i)
</lang>
ERRE
<lang ERRE> PROGRAM FFT
CONST CNT=8
!$DYNAMIC DIM REL[0],IMG[0],CMP[0],V[0]
BEGIN
SIG=INT(LOG(CNT)/LOG(2)+0.9999) REAL1=2^SIG
REAL=REAL1-1 REAL2=INT(REAL1/2) REAL4=INT(REAL1/4) REAL3=REAL4+REAL2
!$DIM REL[REAL1],IMG[REAL1],CMP[REAL3]
FOR I=0 TO CNT-1 DO
READ(REL[I],IMG[I])
END FOR
DATA(1,0,1,0,1,0,1,0,0,0,0,0,0,0,0,0)
SIG2=INT(SIG/2) SIG1=SIG-SIG2 CNT1=2^SIG1 CNT2=2^SIG2
!$DIM V[CNT1-1] V[0]=0 DV=1 PTR=CNT1
FOR J=1 TO SIG1 DO
HLFPTR=INT(PTR/2) PT=CNT1-HLFPTR FOR I=HLFPTR TO PT STEP PTR DO V[I]=V[I-HLFPTR]+DV END FOR DV=2*DV PTR=HLFPTR
END FOR
K=2*π/REAL1
FOR X=0 TO REAL4 DO
CMP[X]=COS(K*X) CMP[REAL2-X]=-CMP[X] CMP[REAL2+X]=-CMP[X]
END FOR
PRINT("FFT: BIT REVERSAL")
FOR I=0 TO CNT1-1 DO
IP=I*CNT2
FOR J=0 TO CNT2-1 DO
H=IP+J
G=V[J]*CNT2+V[I]
IF G>H THEN
SWAP(REL[G],REL[H])
SWAP(IMG[G],IMG[H])
END IF
END FOR
END FOR
T=1 FOR STAGE=1 TO SIG DO
PRINT("STAGE:";STAGE)
D=INT(REAL2/T)
FOR II=0 TO T-1 DO
L=D*II
LS=L+REAL4
FOR I=0 TO D-1 DO
A=2*I*T+II
B=A+T
F1=REL[A]
F2=IMG[A]
CNT1=CMP[L]*REL[B]
CNT2=CMP[LS]*IMG[B]
CNT3=CMP[LS]*REL[B]
CNT4=CMP[L]*IMG[B]
REL[A]=F1+CNT1-CNT2
IMG[A]=F2+CNT3+CNT4
REL[B]=F1-CNT1+CNT2
IMG[B]=F2-CNT3-CNT4
END FOR
END FOR
T=2*T
END FOR
PRINT("NUM REAL IMAG") FOR I=0 TO REAL DO
IF ABS(REL[I])<1E-5 THEN REL[I]=0 END IF
IF ABS(IMG[I])<1E-5 THEN IMG[I]=0 END IF
PRINT(I;"";)
WRITE("##.###### ##.######";REL[I];IMG[I])
END FOR END PROGRAM </lang>
- Output:
FFT: BIT REVERSAL STAGE: 1 STAGE: 2 STAGE: 3 NUM REAL IMAG 0 4.000000 0.000000 1 1.000000 -2.414214 2 0.000000 0.000000 3 1.000000 -0.414214 4 0.000000 0.000000 5 1.000000 0.414214 6 0.000000 0.000000 7 1.000000 2.414214
Factor
<lang Factor> IN: USE math.transforms.fft IN: { 1 1 1 1 0 0 0 0 } fft . {
C{ 4.0 0.0 }
C{ 1.0 -2.414213562373095 }
C{ 0.0 0.0 }
C{ 1.0 -0.4142135623730949 }
C{ 0.0 0.0 }
C{ 0.9999999999999999 0.4142135623730949 }
C{ 0.0 0.0 }
C{ 0.9999999999999997 2.414213562373095 }
} </lang>
Fortran
<lang Fortran> module fft_mod
implicit none integer, parameter :: dp=selected_real_kind(15,300) real(kind=dp), parameter :: pi=3.141592653589793238460_dp
contains
! In place Cooley-Tukey FFT recursive subroutine fft(x) complex(kind=dp), dimension(:), intent(inout) :: x complex(kind=dp) :: t integer :: N integer :: i complex(kind=dp), dimension(:), allocatable :: even, odd
N=size(x)
if(N .le. 1) return
allocate(odd((N+1)/2)) allocate(even(N/2))
! divide odd =x(1:N:2) even=x(2:N:2)
! conquer call fft(odd) call fft(even)
! combine
do i=1,N/2
t=exp(cmplx(0.0_dp,-2.0_dp*pi*real(i-1,dp)/real(N,dp),kind=dp))*even(i)
x(i) = odd(i) + t
x(i+N/2) = odd(i) - t
end do
deallocate(odd) deallocate(even)
end subroutine fft
end module fft_mod
program test
use fft_mod implicit none complex(kind=dp), dimension(8) :: data = (/1.0, 1.0, 1.0, 1.0, 0.0,
0.0, 0.0, 0.0/)
integer :: i
call fft(data)
do i=1,8
write(*,'("(", F20.15, ",", F20.15, "i )")') data(i)
end do
end program test</lang>
- Output:
( 4.000000000000000, 0.000000000000000i ) ( 1.000000000000000, -2.414213562373095i ) ( 0.000000000000000, 0.000000000000000i ) ( 1.000000000000000, -0.414213562373095i ) ( 0.000000000000000, 0.000000000000000i ) ( 1.000000000000000, 0.414213562373095i ) ( 0.000000000000000, 0.000000000000000i ) ( 1.000000000000000, 2.414213562373095i )
GAP
<lang gap># Here an implementation with no optimization (O(n^2)).
- In GAP, E(n) = exp(2*i*pi/n), a primitive root of the unity.
Fourier := function(a) local n, z; n := Size(a); z := E(n); return List([0 .. n - 1], k -> Sum([0 .. n - 1], j -> a[j + 1]*z^(-k*j))); end;
InverseFourier := function(a) local n, z; n := Size(a); z := E(n); return List([0 .. n - 1], k -> Sum([0 .. n - 1], j -> a[j + 1]*z^(k*j)))/n; end;
Fourier([1, 1, 1, 1, 0, 0, 0, 0]);
- [ 4, 1-E(8)-E(8)^2-E(8)^3, 0, 1-E(8)+E(8)^2-E(8)^3,
- 0, 1+E(8)-E(8)^2+E(8)^3, 0, 1+E(8)+E(8)^2+E(8)^3 ]
InverseFourier(last);
- [ 1, 1, 1, 1, 0, 0, 0, 0 ]</lang>
Go
<lang go>package main
import (
"fmt" "math" "math/cmplx"
)
func ditfft2(x []float64, y []complex128, n, s int) {
if n == 1 {
y[0] = complex(x[0], 0)
return
}
ditfft2(x, y, n/2, 2*s)
ditfft2(x[s:], y[n/2:], n/2, 2*s)
for k := 0; k < n/2; k++ {
tf := cmplx.Rect(1, -2*math.Pi*float64(k)/float64(n)) * y[k+n/2]
y[k], y[k+n/2] = y[k]+tf, y[k]-tf
}
}
func main() {
x := []float64{1, 1, 1, 1, 0, 0, 0, 0}
y := make([]complex128, len(x))
ditfft2(x, y, len(x), 1)
for _, c := range y {
fmt.Printf("%8.4f\n", c)
}
}</lang>
- Output:
( 4.0000 +0.0000i) ( 1.0000 -2.4142i) ( 0.0000 +0.0000i) ( 1.0000 -0.4142i) ( 0.0000 +0.0000i) ( 1.0000 +0.4142i) ( 0.0000 +0.0000i) ( 1.0000 +2.4142i)
Haskell
<lang haskell>import Data.Complex
-- Cooley-Tukey fft [] = [] fft [x] = [x] fft xs = zipWith (+) ys ts ++ zipWith (-) ys ts
where n = length xs
ys = fft evens
zs = fft odds
(evens, odds) = split xs
split [] = ([], [])
split [x] = ([x], [])
split (x:y:xs) = (x:xt, y:yt) where (xt, yt) = split xs
ts = zipWith (\z k -> exp' k n * z) zs [0..]
exp' k n = cis $ -2 * pi * (fromIntegral k) / (fromIntegral n)
main = mapM_ print $ fft [1,1,1,1,0,0,0,0]</lang>
- Output:
4.0 :+ 0.0 1.0 :+ (-2.414213562373095) 0.0 :+ 0.0 1.0 :+ (-0.4142135623730949) 0.0 :+ 0.0 0.9999999999999999 :+ 0.4142135623730949 0.0 :+ 0.0 0.9999999999999997 :+ 2.414213562373095
Idris
<lang>module Main
import Data.Complex
concatPair : List (a, a) -> List (a)
concatPair xs with (unzip xs)
| (xs1, xs2) = xs1 ++ xs2
fft' : List (Complex Double) -> Nat -> Nat -> List (Complex Double) fft' (x::xs) (S Z) _ = [x] fft' xs n s = concatPair $ map (\(x1,x2,k) =>
let eTerm = ((cis (-2 * pi * ((cast k) - 1) / (cast n))) * x2) in
(x1 + eTerm, x1 - eTerm)) $ zip3 left right [1..n `div` 2]
where
left : List (Complex Double)
right : List (Complex Double)
left = fft' (xs) (n `div` 2) (2 * s)
right = fft' (drop s xs) (n `div` 2) (2 * s)
-- Recursive Cooley-Tukey with radix-2 DIT case -- assumes no of points provided are a power of 2 fft : List (Complex Double) -> List (Complex Double) fft [] = [] fft xs = fft' xs (length xs) 1
main : IO()
main = traverse_ printLn $ fft [1,1,1,1,0,0,0,0]</lang>
- Output:
4 :+ 0 1 :+ -2.414213562373095 0 :+ 0 1 :+ -0.4142135623730949 0 :+ 0 0.9999999999999999 :+ 0.4142135623730949 0 :+ 0 0.9999999999999997 :+ 2.414213562373095
J
Based on j:Essays/FFT, with some simplifications -- sacrificing accuracy, optimizations and convenience which are not relevant to the task requirements, for clarity:
<lang j>cube =: ($~ q:@#) :. , rou =: ^@j.@o.@(% #)@i.@-: NB. roots of unity floop =: 4 : 'for_r. i.#$x do. (y=.{."1 y) ] x=.(+/x) ,&,:"r (-/x)*y end.' fft =: ] floop&.cube rou@#</lang>
Example (first row of result is sine, second row of result is fft of the first row, (**+)&.+. cleans an irrelevant least significant bit of precision from the result so that it displays nicely):
<lang j> (**+)&.+. (,: fft) 1 o. 2p1*3r16 * i.16 0 0.92388 0.707107 0.382683 1 0.382683 0.707107 0.92388 0 0.92388 0.707107 0.382683 1 0.382683 0.707107 0.92388 0 0 0 0j8 0 0 0 0 0 0 0 0 0 0j8 0 0</lang>
Here is a representation of an example which appears in some of the other implementations, here: <lang J> Re=: {.@+.@fft
Im=: {:@+.@fft
M=: 4#1 0
M
1 1 1 1 0 0 0 0
Re M
4 1 0 1 0 1 0 1
Im M
0 2.41421 0 0.414214 0 _0.414214 0 _2.41421</lang>
Note that Re and Im are not functions of 1 and 0 but are functions of the complete sequence.
Also note that J uses a different character for negative sign than for subtraction, to eliminate ambiguity (is this a single list of numbers or are lists being subtracted?).
Java
<lang java>import static java.lang.Math.*;
public class FastFourierTransform {
public static int bitReverse(int n, int bits) {
int reversedN = n;
int count = bits - 1;
n >>= 1;
while (n > 0) {
reversedN = (reversedN << 1) | (n & 1);
count--;
n >>= 1;
}
return ((reversedN << count) & ((1 << bits) - 1)); }
static void fft(Complex[] buffer) {
int bits = (int) (log(buffer.length) / log(2));
for (int j = 1; j < buffer.length / 2; j++) {
int swapPos = bitReverse(j, bits);
Complex temp = buffer[j];
buffer[j] = buffer[swapPos];
buffer[swapPos] = temp;
}
for (int N = 2; N <= buffer.length; N <<= 1) {
for (int i = 0; i < buffer.length; i += N) {
for (int k = 0; k < N / 2; k++) {
int evenIndex = i + k;
int oddIndex = i + k + (N / 2);
Complex even = buffer[evenIndex];
Complex odd = buffer[oddIndex];
double term = (-2 * PI * k) / (double) N;
Complex exp = (new Complex(cos(term), sin(term)).mult(odd));
buffer[evenIndex] = even.add(exp);
buffer[oddIndex] = even.sub(exp);
}
}
}
}
public static void main(String[] args) {
double[] input = {1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0};
Complex[] cinput = new Complex[input.length];
for (int i = 0; i < input.length; i++)
cinput[i] = new Complex(input[i], 0.0);
fft(cinput);
System.out.println("Results:");
for (Complex c : cinput) {
System.out.println(c);
}
}
}
class Complex {
public final double re; public final double im;
public Complex() {
this(0, 0);
}
public Complex(double r, double i) {
re = r;
im = i;
}
public Complex add(Complex b) {
return new Complex(this.re + b.re, this.im + b.im);
}
public Complex sub(Complex b) {
return new Complex(this.re - b.re, this.im - b.im);
}
public Complex mult(Complex b) {
return new Complex(this.re * b.re - this.im * b.im,
this.re * b.im + this.im * b.re);
}
@Override
public String toString() {
return String.format("(%f,%f)", re, im);
}
}</lang>
Results: (4,000000 + 0,000000 i) (1,000000 + -2,414214 i) (0,000000 + 0,000000 i) (1,000000 + -0,414214 i) (0,000000 + 0,000000 i) (1,000000 + 0,414214 i) (0,000000 + 0,000000 i) (1,000000 + 2,414214 i)
JavaScript
Complex fourier transform & it's inverse reimplemented from the C++ & Python variants on this page.
<lang javascript>/* complex fast fourier transform and inverse from http://rosettacode.org/wiki/Fast_Fourier_transform#C.2B.2B
- /
function icfft(amplitudes) { var N = amplitudes.length; var iN = 1 / N;
//conjugate if imaginary part is not 0 for(var i = 0 ; i < N; ++i) if(amplitudes[i] instanceof Complex) amplitudes[i].im = -amplitudes[i].im;
//apply fourier transform amplitudes = cfft(amplitudes)
for(var i = 0 ; i < N; ++i) { //conjugate again amplitudes[i].im = -amplitudes[i].im; //scale amplitudes[i].re *= iN; amplitudes[i].im *= iN; } return amplitudes; }
function cfft(amplitudes) { var N = amplitudes.length; if( N <= 1 ) return amplitudes;
var hN = N / 2; var even = []; var odd = []; even.length = hN; odd.length = hN; for(var i = 0; i < hN; ++i) { even[i] = amplitudes[i*2]; odd[i] = amplitudes[i*2+1]; } even = cfft(even); odd = cfft(odd);
var a = -2*Math.PI; for(var k = 0; k < hN; ++k) { if(!(even[k] instanceof Complex)) even[k] = new Complex(even[k], 0); if(!(odd[k] instanceof Complex)) odd[k] = new Complex(odd[k], 0); var p = k/N; var t = new Complex(0, a * p); t.cexp(t).mul(odd[k], t); amplitudes[k] = even[k].add(t, odd[k]); amplitudes[k + hN] = even[k].sub(t, even[k]); } return amplitudes; }
//test code //console.log( cfft([1,1,1,1,0,0,0,0]) ); //console.log( icfft(cfft([1,1,1,1,0,0,0,0])) );</lang> Very very basic Complex number that provides only the components required by the code above. <lang javascript>/* basic complex number arithmetic from http://rosettacode.org/wiki/Fast_Fourier_transform#Scala
- /
function Complex(re, im) { this.re = re; this.im = im || 0.0; } Complex.prototype.add = function(other, dst) { dst.re = this.re + other.re; dst.im = this.im + other.im; return dst; } Complex.prototype.sub = function(other, dst) { dst.re = this.re - other.re; dst.im = this.im - other.im; return dst; } Complex.prototype.mul = function(other, dst) { //cache re in case dst === this var r = this.re * other.re - this.im * other.im; dst.im = this.re * other.im + this.im * other.re; dst.re = r; return dst; } Complex.prototype.cexp = function(dst) { var er = Math.exp(this.re); dst.re = er * Math.cos(this.im); dst.im = er * Math.sin(this.im); return dst; } Complex.prototype.log = function() { /* although 'It's just a matter of separating out the real and imaginary parts of jw.' is not a helpful quote the actual formula I found here and the rest was just fiddling / testing and comparing with correct results. http://cboard.cprogramming.com/c-programming/89116-how-implement-complex-exponential-functions-c.html#post637921 */ if( !this.re ) console.log(this.im.toString()+'j'); else if( this.im < 0 ) console.log(this.re.toString()+this.im.toString()+'j'); else console.log(this.re.toString()+'+'+this.im.toString()+'j'); }</lang>
jq
Currently jq has no support for complex numbers, so the following implementation uses [x,y] to represent the complex number x+iy.
Complex number arithmetic
<lang jq>
- multiplication of real or complex numbers
def cmult(x; y):
if (x|type) == "number" then
if (y|type) == "number" then [ x*y, 0 ]
else [x * y[0], x * y[1]]
end
elif (y|type) == "number" then cmult(y;x)
else [ x[0] * y[0] - x[1] * y[1], x[0] * y[1] + x[1] * y[0]]
end;
def cplus(x; y):
if (x|type) == "number" then
if (y|type) == "number" then [ x+y, 0 ]
else [ x + y[0], y[1]]
end
elif (y|type) == "number" then cplus(y;x)
else [ x[0] + y[0], x[1] + y[1] ]
end;
def cminus(x; y): cplus(x; cmult(-1; y));
- e(ix) = cos(x) + i sin(x)
def expi(x): [ (x|cos), (x|sin) ];</lang>
FFT
<lang jq>def fft:
length as $N
| if $N <= 1 then .
else ( [ .[ range(0; $N; 2) ] ] | fft) as $even
| ( [ .[ range(1; $N; 2) ] ] | fft) as $odd
| (1|atan * 4) as $pi
| [ range(0; $N/2) | cplus($even[.]; cmult( expi(-2*$pi*./$N); $odd[.] )) ] +
[ range(0; $N/2) | cminus($even[.]; cmult( expi(-2*$pi*./$N); $odd[.] )) ]
end;</lang>
Example: <lang jq>[1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0] | fft </lang>
- Output:
[[4,-0],[1,-2.414213562373095], [0,0],[1,-0.4142135623730949], [0,0],[0.9999999999999999,0.4142135623730949], [0,0],[0.9999999999999997,2.414213562373095]]
Julia
Julia has a built-in FFT function: <lang julia>fft([1,1,1,1,0,0,0,0])</lang>
- Output:
<lang julia>8-element Array{Complex{Float64},1}:
4.0+0.0im
1.0-2.41421im
0.0+0.0im
1.0-0.414214im
0.0+0.0im
1.0+0.414214im
0.0+0.0im
1.0+2.41421im</lang>
Kotlin
From Scala. <lang scala>package fft
import java.lang.Math.*
class Complex(val re: Double, val im: Double) {
operator infix fun plus(x: Complex) = Complex(re + x.re, im + x.im)
operator infix fun minus(x: Complex) = Complex(re - x.re, im - x.im)
operator infix fun times(x: Double) = Complex(re * x, im * x)
operator infix fun times(x: Complex) = Complex(re * x.re - im * x.im, re * x.im + im * x.re)
operator infix fun div(x: Double) = Complex(re / x, im / x)
val exp: Complex by lazy { Complex(cos(im), sin(im)) * (cosh(re) + sinh(re)) }
override fun toString() = when {
b == "0.000" -> a
a == "0.000" -> b + 'i'
im > 0 -> a + " + " + b + 'i'
else -> a + " - " + b + 'i'
}
private final val a = "%1.3f".format(re) private final val b = "%1.3f".format(abs(im))
}</lang>
<lang scala>package fft
object FFT {
fun fft(a: Array<Complex>) = _fft(a, Complex(0.0, 2.0), 1.0) fun rfft(a: Array<Complex>) = _fft(a, Complex(0.0, -2.0), 2.0)
private fun _fft(a: Array<Complex>, direction: Complex, scalar: Double): Array<Complex> =
if (a.size == 1)
a
else {
val n = a.size
require(n % 2 == 0, { "The Cooley-Tukey FFT algorithm only works when the length of the input is even." })
var (evens, odds) = Pair(emptyArray<Complex>(), emptyArray<Complex>())
for (i in a.indices)
if (i % 2 == 0) evens += a[i]
else odds += a[i]
evens = _fft(evens, direction, scalar)
odds = _fft(odds, direction, scalar)
val pairs = (0 until n / 2).map {
val offset = (direction * (java.lang.Math.PI * it / n)).exp * odds[it] / scalar
val base = evens[it] / scalar
Pair(base + offset, base - offset)
}
var (left, right) = Pair(emptyArray<Complex>(), emptyArray<Complex>())
for ((l, r) in pairs) { left += l; right += r }
left + right
}
}</lang>
<lang scala>package fft
fun Array<*>.println() = println(joinToString(prefix = "[", postfix = "]"))
fun main(args: Array<String>) {
val data = arrayOf(Complex(1.0, 0.0), Complex(1.0, 0.0), Complex(1.0, 0.0), Complex(1.0, 0.0),
Complex(0.0, 0.0), Complex(0.0, 2.0), Complex(0.0, 0.0), Complex(0.0, 0.0))
val a = FFT.fft(data) a.println() FFT.rfft(a).println()
}</lang>
- Output:
[4.000 + 2.000i, 2.414 + 1.000i, -2.000, 2.414 + 1.828i, 2.000i, -0.414 + 1.000i, 2.000, -0.414 - 3.828i] [1.000, 1.000, 1.000, 1.000, 0.000, 2.000i, 0.000, 0.000]
Liberty BASIC
<lang lb>
P =8 S =int( log( P) /log( 2) +0.9999)
Pi =3.14159265 R1 =2^S
R =R1 -1 R2 =div( R1, 2) R4 =div( R1, 4) R3 =R4 +R2
Dim Re( R1), Im( R1), Co( R3)
for N =0 to P -1
read dummy: Re( N) =dummy
read dummy: Im( N) =dummy
next N
data 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0
S2 =div( S, 2) S1 =S -S2 P1 =2^S1 P2 =2^S2
dim V( P1 -1) V( 0) =0 DV =1 DP =P1
for J =1 to S1
HA =div( DP, 2)
PT =P1 -HA
for I =HA to PT step DP
V( I) =V( I -HA) +DV
next I
DV =DV +DV
DP =HA
next J
K =2 *Pi /R1
for X =0 to R4
COX =cos( K *X)
Co( X) =COX
Co( R2 -X) =0 -COX
Co( R2 +X) =0 -COX
next X
print "FFT: bit reversal"
for I =0 to P1 -1
IP =I *P2
for J =0 to P2 -1
H =IP +J
G =V( J) *P2 +V( I)
if G >H then temp =Re( G): Re( G) =Re( H): Re( H) =temp
if G >H then temp =Im( G): Im( G) =Im( H): Im( H) =temp
next J
next I
T =1
for stage =0 to S -1
print " Stage:- "; stage
D =div( R2, T)
for Z =0 to T -1
L =D *Z
LS =L +R4
for I =0 to D -1
A =2 *I *T +Z
B =A +T
F1 =Re( A)
F2 =Im( A)
P1 =Co( L) *Re( B)
P2 =Co( LS) *Im( B)
P3 =Co( LS) *Re( B)
P4 =Co( L) *Im( B)
Re( A) =F1 +P1 -P2
Im( A) =F2 +P3 +P4
Re( B) =F1 -P1 +P2
Im( B) =F2 -P3 -P4
next I
next Z
T =T +T
next stage
print " M Re( M) Im( M)"
for M =0 to R
if abs( Re( M)) <10^-5 then Re( M) =0
if abs( Im( M)) <10^-5 then Im( M) =0
print " "; M, Re( M), Im( M)
next M
end
wait
function div( a, b)
div =int( a /b)
end function
end
</lang>
M Re( M) Im( M) 0 4 0 1 1.0 -2.41421356 2 0 0 3 1.0 -0.41421356 4 0 0 5 1.0 0.41421356 6 0 0 7 1.0 2.41421356
Lua
<lang Lua>-- operations on complex number complex = {__mt={} }
function complex.new (r, i)
local new={r=r, i=i or 0}
setmetatable(new,complex.__mt)
return new
end
function complex.__mt.__add (c1, c2)
return complex.new(c1.r + c2.r, c1.i + c2.i)
end
function complex.__mt.__sub (c1, c2)
return complex.new(c1.r - c2.r, c1.i - c2.i)
end
function complex.__mt.__mul (c1, c2)
return complex.new(c1.r*c2.r - c1.i*c2.i,
c1.r*c2.i + c1.i*c2.r)
end
function complex.expi (i)
return complex.new(math.cos(i),math.sin(i))
end
function complex.__mt.__tostring(c)
return "("..c.r..","..c.i..")"
end
-- Cooley–Tukey FFT (in-place, divide-and-conquer)
-- Higher memory requirements and redundancy although more intuitive
function fft(vect)
local n=#vect if n<=1 then return vect end
-- divide
local odd,even={},{}
for i=1,n,2 do
odd[#odd+1]=vect[i]
even[#even+1]=vect[i+1]
end
-- conquer
fft(even); fft(odd);
-- combine
for k=1,n/2 do local t=even[k] * complex.expi(-2*math.pi*(k-1)/n) vect[k] = odd[k] + t; vect[k+n/2] = odd[k] - t; end return vect
end
function toComplex(vectr)
vect={}
for i,r in ipairs(vectr) do
vect[i]=complex.new(r)
end
return vect
end
-- test data = toComplex{1, 1, 1, 1, 0, 0, 0, 0};
print("orig:", unpack(data)) print("fft:", unpack(fft(data)))</lang>
Maple
Maple has a built-in package DiscreteTransforms, and FourierTransform and InverseFourierTransform are in the commands available from that package. The FourierTransform command offers an FFT method by default.
<lang Maple> with( DiscreteTransforms ):
FourierTransform( <1,1,1,1,0,0,0,0>, normalization=none ); </lang>
[ 4. + 0. I ]
[ ]
[1. - 2.41421356237309 I ]
[ ]
[ 0. + 0. I ]
[ ]
[1. - 0.414213562373095 I]
[ ]
[ 0. + 0. I ]
[ ]
[1. + 0.414213562373095 I]
[ ]
[ 0. + 0. I ]
[ ]
[1. + 2.41421356237309 I ]
Optionally, the FFT may be performed inplace on a Vector of hardware double-precision complex floats. <lang Maple> v := Vector( [1,1,1,1,0,0,0,0], datatype=complex[8] ):
FourierTransform( v, normalization=none, inplace ):
v; </lang>
[ 4. + 0. I ]
[ ]
[1. - 2.41421356237309 I ]
[ ]
[ 0. + 0. I ]
[ ]
[1. - 0.414213562373095 I]
[ ]
[ 0. + 0. I ]
[ ]
[1. + 0.414213562373095 I]
[ ]
[ 0. + 0. I ]
[ ]
[1. + 2.41421356237309 I ]
<lang Maple> InverseFourierTransform( v, normalization=full, inplace ):
v; </lang>
[ 1. + 0. I ]
[ ]
[ 1. + 0. I ]
[ ]
[ 1. + 0. I ]
[ ]
[ 1. + 0. I ]
[ ]
[ 0. + 0. I ]
[ ]
[ 0. + 0. I ]
[ ]
[ -17 ]
[5.55111512312578 10 + 0. I]
[ ]
[ 0. + 0. I ]
Mathematica / Wolfram Language
Mathematica has a built-in FFT function which uses a proprietary algorithm developed at Wolfram Research. It also has an option to tune the algorithm for specific applications. The options shown below, while not default, produce output that is consistent with most other FFT routines.
<lang Mathematica> Fourier[{1,1,1,1,0,0,0,0}, FourierParameters->{1,-1}] </lang>
- Output:
{4. + 0. I, 1. - 2.4142136 I, 0. + 0. I, 1. - 0.41421356 I, 0. + 0. I, 1. + 0.41421356 I, 0. + 0. I, 1. + 2.4142136 I}
MATLAB / Octave
Matlab/Octave have a builtin FFT function.
<lang MATLAB> fft([1,1,1,1,0,0,0,0]') </lang>
- Output:
ans = 4.00000 + 0.00000i 1.00000 - 2.41421i 0.00000 + 0.00000i 1.00000 - 0.41421i 0.00000 + 0.00000i 1.00000 + 0.41421i 0.00000 - 0.00000i 1.00000 + 2.41421i
Maxima
<lang maxima>load(fft)$ fft([1, 2, 3, 4]); [2.5, -0.5 * %i - 0.5, -0.5, 0.5 * %i - 0.5]</lang>
Nim
<lang nim>import math, complex, strutils
proc toComplex(x: float): TComplex = result.re = x proc toComplex(x: TComplex): TComplex = x
- Works with floats and complex numbers as input
proc fft[T](x: openarray[T]): seq[TComplex] =
let n = x.len result = newSeq[TComplex]() if n <= 1: for v in x: result.add toComplex(v) return var evens, odds = newSeq[T]() for i, v in x: if i mod 2 == 0: evens.add v else: odds.add v var (even, odd) = (fft(evens), fft(odds))
for k in 0 .. < n div 2: result.add(even[k] + exp((0.0, -2*pi*float(k)/float(n))) * odd[k])
for k in 0 .. < n div 2: result.add(even[k] - exp((0.0, -2*pi*float(k)/float(n))) * odd[k])
for i in fft(@[1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0]):
echo formatFloat(abs(i), ffDecimal, 3)</lang>
- Output:
4.000 2.613 -0.000 1.082 -0.000 1.082 -0.000 2.613
OCaml
This is a simple implementation of the Cooley-Tukey pseudo-code <lang OCaml>open Complex
let fac k n =
let m2pi = -4.0 *. acos 0.0 in polar 1.0 (m2pi*.(float k)/.(float n))
let merge l r n =
let f (k,t) x = (succ k, (mul (fac k n) x) :: t) in let z = List.rev (snd (List.fold_left f (0,[]) r)) in (List.map2 add l z) @ (List.map2 sub l z)
let fft lst =
let rec ditfft2 a n s =
if n = 1 then [List.nth lst a] else
let odd = ditfft2 a (n/2) (2*s) in
let even = ditfft2 (a+s) (n/2) (2*s) in
merge odd even n in
ditfft2 0 (List.length lst) 1;;
let show l =
let pr x = Printf.printf "(%f %f) " x.re x.im in (List.iter pr l; print_newline ()) in
let indata = [one;one;one;one;zero;zero;zero;zero] in show indata; show (fft indata)</lang>
- Output:
(1.000000 0.000000) (1.000000 0.000000) (1.000000 0.000000) (1.000000 0.000000) (0.000000 0.000000) (0.000000 0.000000) (0.000000 0.000000) (0.000000 0.000000) (4.000000 0.000000) (1.000000 -2.414214) (0.000000 0.000000) (1.000000 -0.414214) (0.000000 0.000000) (1.000000 0.414214) (0.000000 0.000000) (1.000000 2.414214)
ooRexx
Output as shown in REXX
<lang oorexx>Numeric Digits 16 list='1 1 1 1 0 0 0 0' n=words(list) x=.array~new(n) Do i=1 To n
x[i]=.complex~new(word(list,i),0) End
Call show 'FFT in',x call fft x Call show 'FFT out',x Exit
show: Procedure
Use Arg data,x Say '---data--- num real-part imaginary-part' Say '---------- --- --------- --------------' Do i=1 To x~size say data right(i,7)' ' x[i]~string End Return
fft: Procedure
Use Arg in Numeric Digits 16 n=in~size If n=1 Then Return odd=.array~new(n/2) even=.array~new(n/2) Do j=1 To n By 2; odd[(j+1)/2]=in[j]; End Do j=2 To n By 2; even[j/2]=in[j]; End Call fft odd Call fft even pi=3.14159265358979323E0 n_2=n/2 Do i=1 To n_2 w=-2*pi*(i-1)/N t=.complex~new(rxCalcCos(w,,'R'),rxCalcSin(w,,'R'))*even[i] in[i]=odd[i]+t in[i+n_2]=odd[i]-t End Return
- class complex
- method init
expose r i use strict arg r, i = 0
-- complex instances are immutable, so these are -- read only attributes
- attribute r GET
- attribute i GET
- method add
expose r i
Numeric Digits 16
use strict arg other
if other~isa(.complex) then
return self~class~new(r + other~r, i + other~i)
else return self~class~new(r + other, i)
- method subtract
expose r i
Numeric Digits 16
use strict arg other
if other~isa(.complex) then
return self~class~new(r - other~r, i - other~i)
else return self~class~new(r - other, i)
- method "+"
Numeric Digits 16
-- need to check if this is a prefix plus or an addition
if arg() == 0 then
return self -- we can return this copy since it is immutable
else
forward message("ADD")
- method "-"
Numeric Digits 16
-- need to check if this is a prefix minus or a subtract
if arg() == 0 then
forward message("NEGATIVE")
else
forward message("SUBTRACT")
- method times
expose r i
Numeric Digits 16
use strict arg other
if other~isa(.complex) then
return self~class~new(r * other~r - i * other~i, r * other~i + i * other~r)
else return self~class~new(r * other, i * other)
- method "*"
Numeric Digits 16
forward message("TIMES")
- method string
expose r i
Numeric Digits 12
Select
When i=0 Then
If r=0 Then
Return '0'
Else
Return format(r,1,9)
When i>0 Then
Return format(r,1,9)' +'format(i,1,9)'i'
Otherwise
Return format(r,1,9)' -'format(abs(i),1,9)'i'
End
- method formatnumber private
use arg value Numeric Digits 16 if value > 0 then return "+" value else return "-" value~abs
- requires rxMath library</lang>
- Output:
---data--- num real-part imaginary-part ---------- --- --------- -------------- FFT in 1 1.000000000 FFT in 2 1.000000000 FFT in 3 1.000000000 FFT in 4 1.000000000 FFT in 5 0 FFT in 6 0 FFT in 7 0 FFT in 8 0 ---data--- num real-part imaginary-part ---------- --- --------- -------------- FFT out 1 4.000000000 FFT out 2 1.000000000 -2.414213562i FFT out 3 0 FFT out 4 1.000000000 -0.414213562i FFT out 5 0 FFT out 6 1.000000000 +0.414213562i FFT out 7 0 FFT out 8 1.000000000 +2.414213562i
PARI/GP
Naive implementation, using the same testcase as Ada: <lang parigp>FFT(v)=my(t=-2*Pi*I/#v,tt);vector(#v,k,tt=t*(k-1);sum(n=0,#v-1,v[n+1]*exp(tt*n))); FFT([1,1,1,1,0,0,0,0])</lang>
- Output:
[4.0000000000000000000000000000000000000, 1.0000000000000000000000000000000000000 - 2.4142135623730950488016887242096980786*I, 0.E-37 + 0.E-38*I, 1.0000000000000000000000000000000000000 - 0.41421356237309504880168872420969807856*I, 0.E-38 + 0.E-37*I, 0.99999999999999999999999999999999999997 + 0.41421356237309504880168872420969807860*I, 4.701977403289150032 E-38 + 0.E-38*I, 0.99999999999999999999999999999999999991 + 2.4142135623730950488016887242096980785*I]
Perl
<lang Perl>use strict; use warnings; use Math::Complex;
sub fft {
return @_ if @_ == 1;
my @evn = fft(@_[grep { not $_ % 2 } 0 .. $#_ ]);
my @odd = fft(@_[grep { $_ % 2 } 1 .. $#_ ]);
my $twd = 2*i* pi / @_;
$odd[$_] *= exp( $_ * $twd ) for 0 .. $#odd;
return
(map { $evn[$_] + $odd[$_] } 0 .. $#evn ),
(map { $evn[$_] - $odd[$_] } 0 .. $#evn );
}
my @seq = 0 .. 15;
my $cycles = 3;
my @wave = map { sin( $_ * 2*pi/ @seq * $cycles ) } @seq;
print "wave: ", join " ", map { sprintf "%7.3f", $_ } @wave;
print "\n";
print "fft: ", join " ", map { sprintf "%7.3f", abs $_ } fft(@wave);</lang>
- Output:
wave: 0.000 0.924 0.707 -0.383 -1.000 -0.383 0.707 0.924 0.000 -0.924 -0.707 0.383 1.000 0.383 -0.707 -0.924 fft: 0.000 0.000 0.000 8.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 8.000 0.000 0.000
Perl 6
<lang perl6>sub fft {
return @_ if @_ == 1; my @evn = fft( @_[0, 2 ... *] ); my @odd = fft( @_[1, 3 ... *] ) Z* map &cis, (0, tau / @_ ... *); return flat @evn »+« @odd, @evn »-« @odd;
}
my @seq = ^16; my $cycles = 3; my @wave = map { sin( tau * $_ / @seq * $cycles ) }, @seq; say "wave: ", @wave.fmt("%7.3f");
say "fft: ", fft(@wave)».abs.fmt("%7.3f");</lang>
- Output:
wave: 0.000 0.924 0.707 -0.383 -1.000 -0.383 0.707 0.924 0.000 -0.924 -0.707 0.383 1.000 0.383 -0.707 -0.924 fft: 0.000 0.000 0.000 8.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 8.000 0.000 0.000
PicoLisp
<lang PicoLisp># apt-get install libfftw3-dev
(scl 4)
(de FFTW_FORWARD . -1) (de FFTW_ESTIMATE . 64)
(de fft (Lst)
(let
(Len (length Lst)
In (native "libfftw3.so" "fftw_malloc" 'N (* Len 16))
Out (native "libfftw3.so" "fftw_malloc" 'N (* Len 16))
P (native "libfftw3.so" "fftw_plan_dft_1d" 'N
Len In Out FFTW_FORWARD FFTW_ESTIMATE ) )
(struct In NIL (cons 1.0 (apply append Lst)))
(native "libfftw3.so" "fftw_execute" NIL P)
(prog1 (struct Out (make (do Len (link (1.0 . 2)))))
(native "libfftw3.so" "fftw_destroy_plan" NIL P)
(native "libfftw3.so" "fftw_free" NIL Out)
(native "libfftw3.so" "fftw_free" NIL In) ) ) )</lang>
Test: <lang PicoLisp>(for R (fft '((1.0 0) (1.0 0) (1.0 0) (1.0 0) (0 0) (0 0) (0 0) (0 0)))
(tab (6 8)
(round (car R))
(round (cadr R)) ) )</lang>
- Output:
4.000 0.000 1.000 -2.414 0.000 0.000 1.000 -0.414 0.000 0.000 1.000 0.414 0.000 0.000 1.000 2.414
PL/I
<lang PL/I>test: PROCEDURE OPTIONS (MAIN, REORDER); /* Derived from Fortran Rosetta Code */
/* In-place Cooley-Tukey FFT */
FFT: PROCEDURE (x) RECURSIVE;
DECLARE x(*) COMPLEX FLOAT (18); DECLARE t COMPLEX FLOAT (18); DECLARE ( N, Half_N ) FIXED BINARY (31); DECLARE ( i, j ) FIXED BINARY (31); DECLARE (even(*), odd(*)) CONTROLLED COMPLEX FLOAT (18); DECLARE pi FLOAT (18) STATIC INITIAL ( 3.14159265358979323E0);
N = HBOUND(x);
if N <= 1 THEN return;
allocate odd((N+1)/2), even(N/2);
/* divide */ do j = 1 to N by 2; odd((j+1)/2) = x(j); end; do j = 2 to N by 2; even(j/2) = x(j); end;
/* conquer */ call fft(odd); call fft(even);
/* combine */
half_N = N/2;
do i=1 TO half_N;
t = exp(COMPLEX(0, -2*pi*(i-1)/N))*even(i);
x(i) = odd(i) + t;
x(i+half_N) = odd(i) - t;
end;
FREE odd, even;
END fft;
DECLARE data(8) COMPLEX FLOAT (18) STATIC INITIAL (
1, 1, 1, 1, 0, 0, 0, 0);
DECLARE ( i ) FIXED BINARY (31);
call fft(data);
do i=1 TO 8;
PUT SKIP LIST ( fixed(data(i), 25, 12) );
end;
END test;</lang>
- Output:
4.000000000000+0.000000000000I
1.000000000000-2.414213562373I
0.000000000000+0.000000000000I
1.000000000000-0.414213562373I
0.000000000000+0.000000000000I
0.999999999999+0.414213562373I
0.000000000000+0.000000000000I
0.999999999999+2.414213562373I
Prolog
Note: Similar algorithmically to the python example.
<lang prolog>:- dynamic twiddles/2. %_______________________________________________________________ % Arithemetic for complex numbers; only the needed rules add(cx(R1,I1),cx(R2,I2),cx(R,I)) :- R is R1+R2, I is I1+I2. sub(cx(R1,I1),cx(R2,I2),cx(R,I)) :- R is R1-R2, I is I1-I2. mul(cx(R1,I1),cx(R2,I2),cx(R,I)) :- R is R1*R2-I1*I2, I is R1*I2+R2*I1. polar_cx(Mag, Theta, cx(R, I)) :- % Euler R is Mag * cos(Theta), I is Mag * sin(Theta). %___________________________________________________ % FFT Implementation. Note: K rdiv N is a rational number, % making the lookup in dynamic database predicate twiddles/2 very % efficient. Also, polar_cx/2 gets called only when necessary- in % this case (N=8), exactly 3 times: (where Tf=1/4, 1/8, or 3/8). tw(0,cx(1,0)) :- !. % Calculate e^(-2*pi*k/N) tw(Tf, Cx) :- twiddles(Tf, Cx), !. % dynamic match? tw(Tf, Cx) :- polar_cx(1.0, -2*pi*Tf, Cx), assert(twiddles(Tf, Cx)).
fftVals(N, Even, Odd, V0, V1) :- % solves all V0,V1 for N,Even,Odd nth0(K,Even,E), nth0(K,Odd,O), Tf is K rdiv N, tw(Tf,Cx), mul(Cx,O,M), add(E,M,V0), sub(E,M,V1).
split([],[],[]). % split [[a0,b0],[a1,b1],...] into [a0,a1,...] and [b0,b1,...] split([[V0,V1]|T], [V0|T0], [V1|T1]) :- !, split(T, T0, T1).
fft([H], [H]). fft([H|T], List) :- length([H|T],N), findall(Ve, (nth0(I,[H|T],Ve),I mod 2 =:= 0), EL), !, fft(EL, Even), findall(Vo, (nth0(I,T,Vo),I mod 2 =:= 0),OL), !, fft(OL, Odd), findall([V0,V1],fftVals(N,Even,Odd,V0,V1),FFTVals), % calc FFT split(FFTVals,L0,L1), append(L0,L1,List). %___________________________________________________ test :- D=[cx(1,0),cx(1,0),cx(1,0),cx(1,0),cx(0,0),cx(0,0),cx(0,0),cx(0,0)], time(fft(D,DRes)), writef('fft=['), P is 10^3, !, (member(cx(Ri,Ii), DRes), R is integer(Ri*P)/P, I is integer(Ii*P)/P, write(R), (I>=0, write('+'),fail;write(I)), write('j, '), fail; write(']'), nl). </lang>
- Output:
test. % 681 inferences, 0.000 CPU in 0.001 seconds (0% CPU, Infinite Lips) fft=[4+0j, 1-2.414j, 0+0j, 1-0.414j, 0+0j, 1+0.414j, 0+0j, 1+2.414j, ] true.
Python
Python: Recursive
<lang python>from cmath import exp, pi
def fft(x):
N = len(x)
if N <= 1: return x
even = fft(x[0::2])
odd = fft(x[1::2])
T= [exp(-2j*pi*k/N)*odd[k] for k in range(N//2)]
return [even[k] + T[k] for k in range(N//2)] + \
[even[k] - T[k] for k in range(N//2)]
print( ' '.join("%5.3f" % abs(f)
for f in fft([1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0])) )</lang>
- Output:
4.000 2.613 0.000 1.082 0.000 1.082 0.000 2.613
Python: Using module numpy
<lang python>>>> from numpy.fft import fft >>> from numpy import array >>> a = array([1.0, 1.0, 1.0, 1.0, 0.0, 0.0, 0.0, 0.0]) >>> print( ' '.join("%5.3f" % abs(f) for f in fft(a)) ) 4.000 2.613 0.000 1.082 0.000 1.082 0.000 2.613</lang>
R
The function "fft" is readily available in R <lang R>fft(c(1,1,1,1,0,0,0,0))</lang>
- Output:
4+0.000000i 1-2.414214i 0+0.000000i 1-0.414214i 0+0.000000i 1+0.414214i 0+0.000000i 1+2.414214i
Racket
<lang racket>
- lang racket
(require math) (array-fft (array #[1. 1. 1. 1. 0. 0. 0. 0.])) </lang>
- Output:
(fcarray #[4.0+0.0i 1.0-2.414213562373095i 0.0+0.0i 1.0-0.4142135623730949i 0.0+0.0i 0.9999999999999999+0.4142135623730949i 0.0+0.0i 0.9999999999999997+2.414213562373095i])
REXX
This REXX program is modeled after the Run BASIC version and is a radix-2 DIC (decimation-in-time)
form of the Cooley-Turkey FFT algorithm, and as such, this simplified form assumes that the number of
data points is equal to an exact power of two.
Note that the REXX language doesn't have any higher math functions, such as the functions COS and R2R
(cosine and reduce radians to a unit circle).
A normalization of radians function  ' (r2r) has been included here, as well as the constant pi.
This REXX program also adds zero values if the number of data points in the list doesn't exactly equal to a
power of two. This is known as zero-padding.
<lang rexx>/*REXX program performs a fast Fourier transform (FFT) on a set of complex numbers. */
numeric digits length( pi() ) - 1 /*limited by the PI function result. */
arg data /*ARG verb uppercases the DATA from CL.*/
if data= then data=1 1 1 1 0 /*Not specified? Then use the default.*/
size=words(data); pad=left(,6) /*PAD: for indenting and padding SAYs.*/
do p=0 until 2**p>=size ; end /*number of args exactly a power of 2? */ do j=size+1 to 2**p;data=data 0; end /*add zeroes to DATA 'til a power of 2.*/
size=words(data); ph=p%2; call hdr /*╔═══════════════════════════╗*/
/* [↓] TRANSLATE allows I & J*/ /*║ Numbers in data can be in ║*/
do j=0 for size /*║ seven formats: real ║*/
_=translate( word(data,j+1), 'J', "I") /*║ real,imag ║*/
parse var _ #.1.j $ 1 "," #.2.j /*║ ,imag ║*/
if $=='J' then parse var #.1.j #2.j "J" #.1.j /*║ nnnJ ║*/
/*║ nnnj ║*/
do m=1 for 2; #.m.j= word(#.m.j 0, 1) /*║ nnnI ║*/
end /*m*/ /*omitted part? [↑] */ /*║ nnni ║*/
/*╚═══════════════════════════╝*/
say pad ' FFT in ' center(j+1, 7) pad fmt(#.1.j) fmt(#.2.j, "i")
end /*j*/
say tran=pi()*2 / 2**p; !.=0; hp=2**p %2; A=2**(p-ph); ptr=A; dbl=1 say
do p-ph; halfPtr=ptr%2
do i=halfPtr by ptr to A-halfPtr; _=i-halfPtr; !.i=!._+dbl
end /*i*/
dbl=dbl*2; ptr=halfPtr
end /*p-ph*/
do j=0 to 2**p%4; cmp.j=cos(j*tran); _=hp - j; cmp._= -cmp.j
_=hp + j; cmp._= -cmp.j
end /*j*/
B=2**ph
do i=0 for A; q=i * B
do j=0 for B; h=q+j; _=!.j*B+!.i; if _<=h then iterate
parse value #.1._ #.1.h #.2._ #.2.h with #.1.h #.1._ #.2.h #.2._
end /*j*/ /* [↑] swap two sets of values. */
end /*i*/
dbl=1
do p ; w=hp % dbl
do k=0 for dbl ; Lb=w * k ; Lh=Lb + 2**p % 4
do j=0 for w ; a=j * dbl * 2 + k ; b= a + dbl
r=#.1.a; i=#.2.a ; c1=cmp.Lb * #.1.b ; c4=cmp.Lb * #.2.b
c2=cmp.Lh * #.2.b ; c3=cmp.Lh * #.1.b
#.1.a=r + c1 - c2 ; #.2.a=i + c3 + c4
#.1.b=r - c1 + c2 ; #.2.b=i - c3 - c4
end /*j*/
end /*k*/
dbl=dbl+dbl
end /*p*/
call hdr
do i=0 for size
say pad " FFT out " center(i+1,7) pad fmt(#.1.i) fmt(#.2.i,'j')
end /*i*/ /*[↑] #s are shown with 10 decimal digs*/
exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ cos: procedure; parse arg x; q=r2r(x)**2; z=1; _=1; p=1 /*bare bones COS. */
do k=2 by 2; _=-_*q/(k*(k-1)); z=z+_; if z=p then leave; p=z; end; return z
/*──────────────────────────────────────────────────────────────────────────────────────*/ fmt: procedure; parse arg y,j; y=y/1 /*prettifies complex numbers for show. */
if abs(y) < '1e-'digits()%4 then y=0; if y=0 & j\== then return
y=format(y, , 10); if pos(.,y)\==0 then y=strip(y, 'T', 0)
y=strip(y, , .); if y>=0 then y=' 'y; return left(y || j, 12)
/*──────────────────────────────────────────────────────────────────────────────────────*/ hdr: _='───data─── num real─part imaginary─part'; say pad _
say pad translate(_, " "copies('═',256), " "xrange()); return
/*──────────────────────────────────────────────────────────────────────────────────────*/ pi: return 3.1415926535897932384626433832795028841971693993751058209749445923078164062862 /*──────────────────────────────────────────────────────────────────────────────────────*/ r2r: return arg(1) // ( pi()*2 ) /*reduce the radians to a unit circle. */</lang> output when using the default input of: 1 1 1 1 0
───data─── num real─part imaginary─part
══════════ ═══ ═════════ ══════════════
FFT in 1 1
FFT in 2 1
FFT in 3 1
FFT in 4 1
FFT in 5 0
FFT in 6 0
FFT in 7 0
FFT in 8 0
───data─── num real─part imaginary─part
══════════ ═══ ═════════ ══════════════
FFT out 1 4
FFT out 2 1 -2.414213562
FFT out 3 0
FFT out 4 1 -0.414213562
FFT out 5 0
FFT out 6 1 0.414213562
FFT out 7 0
FFT out 8 1 2.414213562
Ruby
<lang ruby>def fft(vec)
return vec if vec.size <= 1
evens_odds = vec.partition.with_index{|_,i| i.even?}
evens, odds = evens_odds.map{|even_odd| fft(even_odd)*2}
evens.zip(odds).map.with_index do |(even, odd),i|
even + odd * Math::E ** Complex(0, -2 * Math::PI * i / vec.size)
end
end
fft([1,1,1,1,0,0,0,0]).each{|c| puts "%9.6f %+9.6fi" % c.rect}</lang>
- Output:
4.000000 +0.000000i 1.000000 -2.414214i -0.000000 -0.000000i 1.000000 -0.414214i 0.000000 -0.000000i 1.000000 +0.414214i 0.000000 -0.000000i 1.000000 +2.414214i
Run BASIC
<lang runbasic>cnt = 8 sig = int(log(cnt) /log(2) +0.9999)
pi = 3.14159265 real1 = 2^sig
real = real1 -1 real2 = int(real1 / 2) real4 = int(real1 / 4) real3 = real4 +real2
dim rel(real1) dim img(real1) dim cmp(real3)
for i = 0 to cnt -1
read rel(i) read img(i)
next i
data 1,0, 1,0, 1,0, 1,0, 0,0, 0,0, 0,0, 0,0
sig2 = int(sig / 2) sig1 = sig -sig2 cnt1 = 2^sig1 cnt2 = 2^sig2
dim v(cnt1 -1) v(0) = 0 dv = 1 ptr = cnt1
for j = 1 to sig1
hlfPtr = int(ptr / 2)
pt = cnt1 - hlfPtr
for i = hlfPtr to pt step ptr
v(i) = v(i -hlfPtr) + dv
next i
dv = dv + dv
ptr = hlfPtr
next j
k = 2 *pi /real1
for x = 0 to real4
cmp(x) = cos(k *x) cmp(real2 - x) = 0 - cmp(x) cmp(real2 + x) = 0 - cmp(x)
next x
print "fft: bit reversal"
for i = 0 to cnt1 -1
ip = i *cnt2
for j = 0 to cnt2 -1
h = ip +j
g = v(j) *cnt2 +v(i)
if g >h then
temp = rel(g)
rel(g) = rel(h)
rel(h) = temp
temp = img(g)
img(g) = img(h)
img(h) = temp
end if
next j
next i
t = 1 for stage = 1 to sig
print " stage:- "; stage
d = int(real2 / t)
for ii = 0 to t -1
l = d *ii
ls = l +real4
for i = 0 to d -1
a = 2 *i *t +ii
b = a +t
f1 = rel(a)
f2 = img(a)
cnt1 = cmp(l) *rel(b)
cnt2 = cmp(ls) *img(b)
cnt3 = cmp(ls) *rel(b)
cnt4 = cmp(l) *img(b)
rel(a) = f1 + cnt1 - cnt2
img(a) = f2 + cnt3 + cnt4
rel(b) = f1 - cnt1 + cnt2
img(b) = f2 - cnt3 - cnt4
next i
next ii
t = t +t
next stage
print " Num real imag" for i = 0 to real
if abs(rel(i)) <10^-5 then rel(i) = 0
if abs(img(i)) <10^-5 then img(i) = 0
print " "; i;" ";using("##.#",rel(i));" ";img(i)
next i end</lang>
Num real imag 0 4.0 0 1 1.0 -2.41421356 2 0.0 0 3 1.0 -0.414213565 4 0.0 0 5 1.0 0.414213562 6 0.0 0 7 1.0 2.41421356
Scala
Imports and Complex arithmetic: <lang Scala>import scala.math.{ Pi, cos, sin, cosh, sinh, abs }
case class Complex(re: Double, im: Double) {
def +(x: Complex): Complex = Complex(re + x.re, im + x.im) def -(x: Complex): Complex = Complex(re - x.re, im - x.im) def *(x: Double): Complex = Complex(re * x, im * x) def *(x: Complex): Complex = Complex(re * x.re - im * x.im, re * x.im + im * x.re) def /(x: Double): Complex = Complex(re / x, im / x)
override def toString(): String = {
val a = "%1.3f" format re
val b = "%1.3f" format abs(im)
(a,b) match {
case (_, "0.000") => a
case ("0.000", _) => b + "i"
case (_, _) if im > 0 => a + " + " + b + "i"
case (_, _) => a + " - " + b + "i"
}
}
}
def exp(c: Complex) : Complex = {
val r = (cosh(c.re) + sinh(c.re)) Complex(cos(c.im), sin(c.im)) * r
}</lang>
The FFT definition itself: <lang Scala>def _fft(cSeq: Seq[Complex], direction: Complex, scalar: Int): Seq[Complex] = {
if (cSeq.length == 1) {
return cSeq
}
val n = cSeq.length
assume(n % 2 == 0, "The Cooley-Tukey FFT algorithm only works when the length of the input is even.")
val evenOddPairs = cSeq.grouped(2).toSeq
val evens = _fft(evenOddPairs map (_(0)), direction, scalar)
val odds = _fft(evenOddPairs map (_(1)), direction, scalar)
def leftRightPair(k: Int): Pair[Complex, Complex] = {
val base = evens(k) / scalar
val offset = exp(direction * (Pi * k / n)) * odds(k) / scalar
(base + offset, base - offset)
}
val pairs = (0 until n/2) map leftRightPair val left = pairs map (_._1) val right = pairs map (_._2) left ++ right
}
def fft(cSeq: Seq[Complex]): Seq[Complex] = _fft(cSeq, Complex(0, 2), 1) def rfft(cSeq: Seq[Complex]): Seq[Complex] = _fft(cSeq, Complex(0, -2), 2)</lang>
Usage: <lang Scala>val data = Seq(Complex(1,0), Complex(1,0), Complex(1,0), Complex(1,0),
Complex(0,0), Complex(0,2), Complex(0,0), Complex(0,0))
println(fft(data)) println(rfft(fft(data)))</lang>
- Output:
Vector(4.000 + 2.000i, 2.414 + 1.000i, -2.000, 2.414 + 1.828i, 2.000i, -0.414 + 1.000i, 2.000, -0.414 - 3.828i) Vector(1.000, 1.000, 1.000, 1.000, 0.000, 2.000i, 0.000, 0.000)
Scilab
Scilab has a builtin FFT function.
<lang Scilab>fft([1,1,1,1,0,0,0,0]')</lang>
Sidef
<lang ruby>func fft(arr) {
arr.len == 1 && return arr
var evn = fft([arr[^arr -> grep { .is_even }]])
var odd = fft([arr[^arr -> grep { .is_odd }]])
var twd = (Num.tau.i / arr.len)
^odd -> map {|n| odd[n] *= ::exp(twd * n)}
(evn »+« odd) + (evn »-« odd)
}
var cycles = 3 var sequence = 0..15 var wave = sequence.map {|n| ::sin(n * Num.tau / sequence.len * cycles) } say "wave:#{wave.map{|w| '%6.3f' % w }.join(' ')}" say "fft: #{fft(wave).map { '%6.3f' % .abs }.join(' ')}"</lang>
- Output:
wave: 0.000 0.924 0.707 -0.383 -1.000 -0.383 0.707 0.924 0.000 -0.924 -0.707 0.383 1.000 0.383 -0.707 -0.924 fft: 0.000 0.000 0.000 8.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 8.000 0.000 0.000
SequenceL
<lang sequencel>import <Utilities/Complex.sl>; import <Utilities/Math.sl>; import <Utilities/Sequence.sl>;
fft(x(1)) :=
let
n := size(x);
top := fft(x[range(1,n-1,2)]);
bottom := fft(x[range(2,n,2)]);
d[i] := makeComplex(cos(2.0*pi*i/n), -sin(2.0*pi*i/n)) foreach i within 0...(n / 2 - 1);
z := complexMultiply(d, bottom);
in
x when n <= 1
else
complexAdd(top,z) ++ complexSubtract(top,z);</lang>
- Output:
cmd:>fft(makeComplex([1,1,1,1,0,0,0,0],0)) [(Imaginary:0.00000000,Real:4.00000000),(Imaginary:-2.41421356,Real:1.00000000),(Imaginary:0.00000000,Real:0.00000000),(Imaginary:-0.41421356,Real:1.00000000),(Imaginary:0.00000000,Real:0.00000000),(Imaginary:0.41421356,Real:1.00000000),(Imaginary:0.00000000,Real:0.00000000),(Imaginary:2.41421356,Real:1.00000000)]
Tcl
<lang tcl>package require math::constants package require math::fourier
math::constants::constants pi
- Helper functions
proc wave {samples cycles} {
global pi
set wave {}
set factor [expr {2*$pi * $cycles / $samples}]
for {set i 0} {$i < $samples} {incr i} {
lappend wave [expr {sin($factor * $i)}]
} return $wave
} proc printwave {waveName {format "%7.3f"}} {
upvar 1 $waveName wave
set out [format "%-6s" ${waveName}:]
foreach value $wave {
append out [format $format $value]
} puts $out
} proc waveMagnitude {wave} {
set out {}
foreach value $wave {
lassign $value re im lappend out [expr {hypot($re, $im)}]
} return $out
}
set wave [wave 16 3] printwave wave
- Uses FFT if input length is power of 2, and a less efficient algorithm otherwise
set fft [math::fourier::dft $wave]
- Convert to magnitudes for printing
set fft2 [waveMagnitude $fft] printwave fft2</lang>
- Output:
wave: 0.000 0.924 0.707 -0.383 -1.000 -0.383 0.707 0.924 0.000 -0.924 -0.707 0.383 1.000 0.383 -0.707 -0.924 fft2: 0.000 0.000 0.000 8.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 8.000 0.000 0.000
Ursala
The fftw library is callable from Ursala using the syntax ..u_fw_dft for a one dimensional forward discrete Fourier transform operating on a list of complex numbers. Ordinarily the results are scaled so that the forward and reverse transforms are inverses of each other, but additional scaling can be performed as shown below to conform to convention.
<lang ursala>#import nat
- import flo
f = <1+0j,1+0j,1+0j,1+0j,0+0j,0+0j,0+0j,0+0j> # complex sequence of 4 1's and 4 0's
g = c..mul^*D(sqrt+ float+ length,..u_fw_dft) f # its fft
- cast %jLW
t = (f,g)</lang>
- Output:
(
<
1.000e+00+0.000e+00j,
1.000e+00+0.000e+00j,
1.000e+00+0.000e+00j,
1.000e+00+0.000e+00j,
0.000e+00+0.000e+00j,
0.000e+00+0.000e+00j,
0.000e+00+0.000e+00j,
0.000e+00+0.000e+00j>,
<
4.000e+00+0.000e+00j,
1.000e+00-2.414e+00j,
0.000e+00+0.000e+00j,
1.000e+00-4.142e-01j,
0.000e+00+0.000e+00j,
1.000e+00+4.142e-01j,
0.000e+00+0.000e+00j,
1.000e+00+2.414e+00j>)- Programming Tasks
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