10001th prime: Difference between revisions
→{{header|EasyLang}}
Line 586:
=={{header|EasyLang}}==
<syntaxhighlight lang="easylang">
fastfunc
if num mod 2 = 0 and num > 2
return 0
Line 599:
return 1
.
if isprim i = 1
▲ repeat
.
until nprim = 10001
i += 1
.
print
</syntaxhighlight>
{{out}}
|